3.131 \(\int \frac {\coth ^4(x)}{1+\coth (x)} \, dx\)

Optimal. Leaf size=37 \[ -\frac {3 x}{2}+\frac {\coth ^3(x)}{2 (\coth (x)+1)}-\coth ^2(x)+\frac {3 \coth (x)}{2}+2 \log (\sinh (x)) \]

[Out]

-3/2*x+3/2*coth(x)-coth(x)^2+1/2*coth(x)^3/(1+coth(x))+2*ln(sinh(x))

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Rubi [A]  time = 0.07, antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {3550, 3528, 3525, 3475} \[ -\frac {3 x}{2}+\frac {\coth ^3(x)}{2 (\coth (x)+1)}-\coth ^2(x)+\frac {3 \coth (x)}{2}+2 \log (\sinh (x)) \]

Antiderivative was successfully verified.

[In]

Int[Coth[x]^4/(1 + Coth[x]),x]

[Out]

(-3*x)/2 + (3*Coth[x])/2 - Coth[x]^2 + Coth[x]^3/(2*(1 + Coth[x])) + 2*Log[Sinh[x]]

Rule 3475

Int[tan[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[Log[RemoveContent[Cos[c + d*x], x]]/d, x] /; FreeQ[{c, d}, x]

Rule 3525

Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(a*c - b
*d)*x, x] + (Dist[b*c + a*d, Int[Tan[e + f*x], x], x] + Simp[(b*d*Tan[e + f*x])/f, x]) /; FreeQ[{a, b, c, d, e
, f}, x] && NeQ[b*c - a*d, 0] && NeQ[b*c + a*d, 0]

Rule 3528

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(d
*(a + b*Tan[e + f*x])^m)/(f*m), x] + Int[(a + b*Tan[e + f*x])^(m - 1)*Simp[a*c - b*d + (b*c + a*d)*Tan[e + f*x
], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && GtQ[m, 0]

Rule 3550

Int[((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_)/((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[((b
*c - a*d)*(c + d*Tan[e + f*x])^(n - 1))/(2*a*f*(a + b*Tan[e + f*x])), x] + Dist[1/(2*a^2), Int[(c + d*Tan[e +
f*x])^(n - 2)*Simp[a*c^2 + a*d^2*(n - 1) - b*c*d*n - d*(a*c*(n - 2) + b*d*n)*Tan[e + f*x], x], x], x] /; FreeQ
[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] && GtQ[n, 1]

Rubi steps

\begin {align*} \int \frac {\coth ^4(x)}{1+\coth (x)} \, dx &=\frac {\coth ^3(x)}{2 (1+\coth (x))}-\frac {1}{2} \int (3-4 \coth (x)) \coth ^2(x) \, dx\\ &=-\coth ^2(x)+\frac {\coth ^3(x)}{2 (1+\coth (x))}+\frac {1}{2} i \int (-4 i+3 i \coth (x)) \coth (x) \, dx\\ &=-\frac {3 x}{2}+\frac {3 \coth (x)}{2}-\coth ^2(x)+\frac {\coth ^3(x)}{2 (1+\coth (x))}+2 \int \coth (x) \, dx\\ &=-\frac {3 x}{2}+\frac {3 \coth (x)}{2}-\coth ^2(x)+\frac {\coth ^3(x)}{2 (1+\coth (x))}+2 \log (\sinh (x))\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 33, normalized size = 0.89 \[ \frac {1}{4} \left (-6 x-\sinh (2 x)+\cosh (2 x)+4 \coth (x)-2 \text {csch}^2(x)+8 \log (\sinh (x))\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[Coth[x]^4/(1 + Coth[x]),x]

[Out]

(-6*x + Cosh[2*x] + 4*Coth[x] - 2*Csch[x]^2 + 8*Log[Sinh[x]] - Sinh[2*x])/4

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fricas [B]  time = 0.41, size = 357, normalized size = 9.65 \[ -\frac {14 \, x \cosh \relax (x)^{6} + 84 \, x \cosh \relax (x) \sinh \relax (x)^{5} + 14 \, x \sinh \relax (x)^{6} - {\left (28 \, x + 1\right )} \cosh \relax (x)^{4} + {\left (210 \, x \cosh \relax (x)^{2} - 28 \, x - 1\right )} \sinh \relax (x)^{4} + 4 \, {\left (70 \, x \cosh \relax (x)^{3} - {\left (28 \, x + 1\right )} \cosh \relax (x)\right )} \sinh \relax (x)^{3} + 2 \, {\left (7 \, x + 5\right )} \cosh \relax (x)^{2} + 2 \, {\left (105 \, x \cosh \relax (x)^{4} - 3 \, {\left (28 \, x + 1\right )} \cosh \relax (x)^{2} + 7 \, x + 5\right )} \sinh \relax (x)^{2} - 8 \, {\left (\cosh \relax (x)^{6} + 6 \, \cosh \relax (x) \sinh \relax (x)^{5} + \sinh \relax (x)^{6} + {\left (15 \, \cosh \relax (x)^{2} - 2\right )} \sinh \relax (x)^{4} - 2 \, \cosh \relax (x)^{4} + 4 \, {\left (5 \, \cosh \relax (x)^{3} - 2 \, \cosh \relax (x)\right )} \sinh \relax (x)^{3} + {\left (15 \, \cosh \relax (x)^{4} - 12 \, \cosh \relax (x)^{2} + 1\right )} \sinh \relax (x)^{2} + \cosh \relax (x)^{2} + 2 \, {\left (3 \, \cosh \relax (x)^{5} - 4 \, \cosh \relax (x)^{3} + \cosh \relax (x)\right )} \sinh \relax (x)\right )} \log \left (\frac {2 \, \sinh \relax (x)}{\cosh \relax (x) - \sinh \relax (x)}\right ) + 4 \, {\left (21 \, x \cosh \relax (x)^{5} - {\left (28 \, x + 1\right )} \cosh \relax (x)^{3} + {\left (7 \, x + 5\right )} \cosh \relax (x)\right )} \sinh \relax (x) - 1}{4 \, {\left (\cosh \relax (x)^{6} + 6 \, \cosh \relax (x) \sinh \relax (x)^{5} + \sinh \relax (x)^{6} + {\left (15 \, \cosh \relax (x)^{2} - 2\right )} \sinh \relax (x)^{4} - 2 \, \cosh \relax (x)^{4} + 4 \, {\left (5 \, \cosh \relax (x)^{3} - 2 \, \cosh \relax (x)\right )} \sinh \relax (x)^{3} + {\left (15 \, \cosh \relax (x)^{4} - 12 \, \cosh \relax (x)^{2} + 1\right )} \sinh \relax (x)^{2} + \cosh \relax (x)^{2} + 2 \, {\left (3 \, \cosh \relax (x)^{5} - 4 \, \cosh \relax (x)^{3} + \cosh \relax (x)\right )} \sinh \relax (x)\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(coth(x)^4/(1+coth(x)),x, algorithm="fricas")

[Out]

-1/4*(14*x*cosh(x)^6 + 84*x*cosh(x)*sinh(x)^5 + 14*x*sinh(x)^6 - (28*x + 1)*cosh(x)^4 + (210*x*cosh(x)^2 - 28*
x - 1)*sinh(x)^4 + 4*(70*x*cosh(x)^3 - (28*x + 1)*cosh(x))*sinh(x)^3 + 2*(7*x + 5)*cosh(x)^2 + 2*(105*x*cosh(x
)^4 - 3*(28*x + 1)*cosh(x)^2 + 7*x + 5)*sinh(x)^2 - 8*(cosh(x)^6 + 6*cosh(x)*sinh(x)^5 + sinh(x)^6 + (15*cosh(
x)^2 - 2)*sinh(x)^4 - 2*cosh(x)^4 + 4*(5*cosh(x)^3 - 2*cosh(x))*sinh(x)^3 + (15*cosh(x)^4 - 12*cosh(x)^2 + 1)*
sinh(x)^2 + cosh(x)^2 + 2*(3*cosh(x)^5 - 4*cosh(x)^3 + cosh(x))*sinh(x))*log(2*sinh(x)/(cosh(x) - sinh(x))) +
4*(21*x*cosh(x)^5 - (28*x + 1)*cosh(x)^3 + (7*x + 5)*cosh(x))*sinh(x) - 1)/(cosh(x)^6 + 6*cosh(x)*sinh(x)^5 +
sinh(x)^6 + (15*cosh(x)^2 - 2)*sinh(x)^4 - 2*cosh(x)^4 + 4*(5*cosh(x)^3 - 2*cosh(x))*sinh(x)^3 + (15*cosh(x)^4
- 12*cosh(x)^2 + 1)*sinh(x)^2 + cosh(x)^2 + 2*(3*cosh(x)^5 - 4*cosh(x)^3 + cosh(x))*sinh(x))

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giac [A]  time = 0.13, size = 40, normalized size = 1.08 \[ -\frac {7}{2} \, x + \frac {{\left (e^{\left (4 \, x\right )} - 10 \, e^{\left (2 \, x\right )} + 1\right )} e^{\left (-2 \, x\right )}}{4 \, {\left (e^{\left (2 \, x\right )} - 1\right )}^{2}} + 2 \, \log \left ({\left | e^{\left (2 \, x\right )} - 1 \right |}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(coth(x)^4/(1+coth(x)),x, algorithm="giac")

[Out]

-7/2*x + 1/4*(e^(4*x) - 10*e^(2*x) + 1)*e^(-2*x)/(e^(2*x) - 1)^2 + 2*log(abs(e^(2*x) - 1))

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maple [A]  time = 0.07, size = 32, normalized size = 0.86 \[ -\frac {\left (\coth ^{2}\relax (x )\right )}{2}+\coth \relax (x )-\frac {\ln \left (\coth \relax (x )-1\right )}{4}-\frac {1}{2 \left (1+\coth \relax (x )\right )}-\frac {7 \ln \left (1+\coth \relax (x )\right )}{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(coth(x)^4/(1+coth(x)),x)

[Out]

-1/2*coth(x)^2+coth(x)-1/4*ln(coth(x)-1)-1/2/(1+coth(x))-7/4*ln(1+coth(x))

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maxima [A]  time = 0.31, size = 54, normalized size = 1.46 \[ \frac {1}{2} \, x + \frac {2 \, {\left (2 \, e^{\left (-2 \, x\right )} - 1\right )}}{2 \, e^{\left (-2 \, x\right )} - e^{\left (-4 \, x\right )} - 1} + \frac {1}{4} \, e^{\left (-2 \, x\right )} + 2 \, \log \left (e^{\left (-x\right )} + 1\right ) + 2 \, \log \left (e^{\left (-x\right )} - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(coth(x)^4/(1+coth(x)),x, algorithm="maxima")

[Out]

1/2*x + 2*(2*e^(-2*x) - 1)/(2*e^(-2*x) - e^(-4*x) - 1) + 1/4*e^(-2*x) + 2*log(e^(-x) + 1) + 2*log(e^(-x) - 1)

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mupad [B]  time = 0.07, size = 29, normalized size = 0.78 \[ \frac {x}{2}-2\,\ln \left (\mathrm {coth}\relax (x)+1\right )+\mathrm {coth}\relax (x)-\frac {{\mathrm {coth}\relax (x)}^2}{2}-\frac {1}{2\,\left (\mathrm {coth}\relax (x)+1\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(coth(x)^4/(coth(x) + 1),x)

[Out]

x/2 - 2*log(coth(x) + 1) + coth(x) - coth(x)^2/2 - 1/(2*(coth(x) + 1))

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sympy [B]  time = 1.18, size = 197, normalized size = 5.32 \[ \frac {x \tanh ^{3}{\relax (x )}}{2 \tanh ^{3}{\relax (x )} + 2 \tanh ^{2}{\relax (x )}} + \frac {x \tanh ^{2}{\relax (x )}}{2 \tanh ^{3}{\relax (x )} + 2 \tanh ^{2}{\relax (x )}} - \frac {4 \log {\left (\tanh {\relax (x )} + 1 \right )} \tanh ^{3}{\relax (x )}}{2 \tanh ^{3}{\relax (x )} + 2 \tanh ^{2}{\relax (x )}} - \frac {4 \log {\left (\tanh {\relax (x )} + 1 \right )} \tanh ^{2}{\relax (x )}}{2 \tanh ^{3}{\relax (x )} + 2 \tanh ^{2}{\relax (x )}} + \frac {4 \log {\left (\tanh {\relax (x )} \right )} \tanh ^{3}{\relax (x )}}{2 \tanh ^{3}{\relax (x )} + 2 \tanh ^{2}{\relax (x )}} + \frac {4 \log {\left (\tanh {\relax (x )} \right )} \tanh ^{2}{\relax (x )}}{2 \tanh ^{3}{\relax (x )} + 2 \tanh ^{2}{\relax (x )}} + \frac {3 \tanh ^{2}{\relax (x )}}{2 \tanh ^{3}{\relax (x )} + 2 \tanh ^{2}{\relax (x )}} + \frac {\tanh {\relax (x )}}{2 \tanh ^{3}{\relax (x )} + 2 \tanh ^{2}{\relax (x )}} - \frac {1}{2 \tanh ^{3}{\relax (x )} + 2 \tanh ^{2}{\relax (x )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(coth(x)**4/(1+coth(x)),x)

[Out]

x*tanh(x)**3/(2*tanh(x)**3 + 2*tanh(x)**2) + x*tanh(x)**2/(2*tanh(x)**3 + 2*tanh(x)**2) - 4*log(tanh(x) + 1)*t
anh(x)**3/(2*tanh(x)**3 + 2*tanh(x)**2) - 4*log(tanh(x) + 1)*tanh(x)**2/(2*tanh(x)**3 + 2*tanh(x)**2) + 4*log(
tanh(x))*tanh(x)**3/(2*tanh(x)**3 + 2*tanh(x)**2) + 4*log(tanh(x))*tanh(x)**2/(2*tanh(x)**3 + 2*tanh(x)**2) +
3*tanh(x)**2/(2*tanh(x)**3 + 2*tanh(x)**2) + tanh(x)/(2*tanh(x)**3 + 2*tanh(x)**2) - 1/(2*tanh(x)**3 + 2*tanh(
x)**2)

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