3.85 \(\int \frac {\text {csch}^2(x)}{a+b \tanh (x)} \, dx\)

Optimal. Leaf size=29 \[ -\frac {b \log (\tanh (x))}{a^2}+\frac {b \log (a+b \tanh (x))}{a^2}-\frac {\coth (x)}{a} \]

[Out]

-coth(x)/a-b*ln(tanh(x))/a^2+b*ln(a+b*tanh(x))/a^2

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Rubi [A]  time = 0.05, antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {3516, 44} \[ -\frac {b \log (\tanh (x))}{a^2}+\frac {b \log (a+b \tanh (x))}{a^2}-\frac {\coth (x)}{a} \]

Antiderivative was successfully verified.

[In]

Int[Csch[x]^2/(a + b*Tanh[x]),x]

[Out]

-(Coth[x]/a) - (b*Log[Tanh[x]])/a^2 + (b*Log[a + b*Tanh[x]])/a^2

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 3516

Int[sin[(e_.) + (f_.)*(x_)]^(m_)*((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist[b/f, Subst[Int
[(x^m*(a + x)^n)/(b^2 + x^2)^(m/2 + 1), x], x, b*Tan[e + f*x]], x] /; FreeQ[{a, b, e, f, n}, x] && IntegerQ[m/
2]

Rubi steps

\begin {align*} \int \frac {\text {csch}^2(x)}{a+b \tanh (x)} \, dx &=b \operatorname {Subst}\left (\int \frac {1}{x^2 (a+x)} \, dx,x,b \tanh (x)\right )\\ &=b \operatorname {Subst}\left (\int \left (\frac {1}{a x^2}-\frac {1}{a^2 x}+\frac {1}{a^2 (a+x)}\right ) \, dx,x,b \tanh (x)\right )\\ &=-\frac {\coth (x)}{a}-\frac {b \log (\tanh (x))}{a^2}+\frac {b \log (a+b \tanh (x))}{a^2}\\ \end {align*}

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Mathematica [A]  time = 0.10, size = 28, normalized size = 0.97 \[ -\frac {-b \log (a \cosh (x)+b \sinh (x))+a \coth (x)+b \log (\sinh (x))}{a^2} \]

Antiderivative was successfully verified.

[In]

Integrate[Csch[x]^2/(a + b*Tanh[x]),x]

[Out]

-((a*Coth[x] + b*Log[Sinh[x]] - b*Log[a*Cosh[x] + b*Sinh[x]])/a^2)

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fricas [B]  time = 0.87, size = 122, normalized size = 4.21 \[ \frac {{\left (b \cosh \relax (x)^{2} + 2 \, b \cosh \relax (x) \sinh \relax (x) + b \sinh \relax (x)^{2} - b\right )} \log \left (\frac {2 \, {\left (a \cosh \relax (x) + b \sinh \relax (x)\right )}}{\cosh \relax (x) - \sinh \relax (x)}\right ) - {\left (b \cosh \relax (x)^{2} + 2 \, b \cosh \relax (x) \sinh \relax (x) + b \sinh \relax (x)^{2} - b\right )} \log \left (\frac {2 \, \sinh \relax (x)}{\cosh \relax (x) - \sinh \relax (x)}\right ) - 2 \, a}{a^{2} \cosh \relax (x)^{2} + 2 \, a^{2} \cosh \relax (x) \sinh \relax (x) + a^{2} \sinh \relax (x)^{2} - a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(x)^2/(a+b*tanh(x)),x, algorithm="fricas")

[Out]

((b*cosh(x)^2 + 2*b*cosh(x)*sinh(x) + b*sinh(x)^2 - b)*log(2*(a*cosh(x) + b*sinh(x))/(cosh(x) - sinh(x))) - (b
*cosh(x)^2 + 2*b*cosh(x)*sinh(x) + b*sinh(x)^2 - b)*log(2*sinh(x)/(cosh(x) - sinh(x))) - 2*a)/(a^2*cosh(x)^2 +
2*a^2*cosh(x)*sinh(x) + a^2*sinh(x)^2 - a^2)

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giac [B]  time = 0.14, size = 78, normalized size = 2.69 \[ \frac {{\left (a b + b^{2}\right )} \log \left ({\left | a e^{\left (2 \, x\right )} + b e^{\left (2 \, x\right )} + a - b \right |}\right )}{a^{3} + a^{2} b} - \frac {b \log \left ({\left | e^{\left (2 \, x\right )} - 1 \right |}\right )}{a^{2}} + \frac {b e^{\left (2 \, x\right )} - 2 \, a - b}{a^{2} {\left (e^{\left (2 \, x\right )} - 1\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(x)^2/(a+b*tanh(x)),x, algorithm="giac")

[Out]

(a*b + b^2)*log(abs(a*e^(2*x) + b*e^(2*x) + a - b))/(a^3 + a^2*b) - b*log(abs(e^(2*x) - 1))/a^2 + (b*e^(2*x) -
2*a - b)/(a^2*(e^(2*x) - 1))

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maple [A]  time = 0.12, size = 56, normalized size = 1.93 \[ -\frac {\tanh \left (\frac {x}{2}\right )}{2 a}+\frac {b \ln \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )+2 \tanh \left (\frac {x}{2}\right ) b +a \right )}{a^{2}}-\frac {1}{2 a \tanh \left (\frac {x}{2}\right )}-\frac {b \ln \left (\tanh \left (\frac {x}{2}\right )\right )}{a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csch(x)^2/(a+b*tanh(x)),x)

[Out]

-1/2/a*tanh(1/2*x)+1/a^2*b*ln(a*tanh(1/2*x)^2+2*tanh(1/2*x)*b+a)-1/2/a/tanh(1/2*x)-1/a^2*b*ln(tanh(1/2*x))

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maxima [B]  time = 0.32, size = 65, normalized size = 2.24 \[ \frac {b \log \left (-{\left (a - b\right )} e^{\left (-2 \, x\right )} - a - b\right )}{a^{2}} - \frac {b \log \left (e^{\left (-x\right )} + 1\right )}{a^{2}} - \frac {b \log \left (e^{\left (-x\right )} - 1\right )}{a^{2}} + \frac {2}{a e^{\left (-2 \, x\right )} - a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(x)^2/(a+b*tanh(x)),x, algorithm="maxima")

[Out]

b*log(-(a - b)*e^(-2*x) - a - b)/a^2 - b*log(e^(-x) + 1)/a^2 - b*log(e^(-x) - 1)/a^2 + 2/(a*e^(-2*x) - a)

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mupad [B]  time = 1.51, size = 323, normalized size = 11.14 \[ \frac {2\,\mathrm {atan}\left (\frac {b\,\left (a^4\,{\left (b^2\right )}^{3/2}-a^6\,\sqrt {b^2}\right )\,\left (a\,b^5\,\sqrt {-a^4}-b^6\,\sqrt {-a^4}+a^2\,b^4\,\sqrt {-a^4}-a^3\,b^3\,\sqrt {-a^4}+b^6\,{\mathrm {e}}^{2\,x}\,\sqrt {-a^4}-2\,a^2\,b^4\,{\mathrm {e}}^{2\,x}\,\sqrt {-a^4}+a^4\,b^2\,{\mathrm {e}}^{2\,x}\,\sqrt {-a^4}\right )+b^2\,\left (a^3\,{\left (b^2\right )}^{3/2}-a^5\,\sqrt {b^2}\right )\,\left (a\,b^5\,\sqrt {-a^4}-b^6\,\sqrt {-a^4}+a^2\,b^4\,\sqrt {-a^4}-a^3\,b^3\,\sqrt {-a^4}+b^6\,{\mathrm {e}}^{2\,x}\,\sqrt {-a^4}-2\,a^2\,b^4\,{\mathrm {e}}^{2\,x}\,\sqrt {-a^4}+a^4\,b^2\,{\mathrm {e}}^{2\,x}\,\sqrt {-a^4}\right )}{-a^{12}\,b^4+3\,a^{10}\,b^6-3\,a^8\,b^8+a^6\,b^{10}}\right )\,\sqrt {b^2}}{\sqrt {-a^4}}-\frac {2}{a\,\left ({\mathrm {e}}^{2\,x}-1\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(sinh(x)^2*(a + b*tanh(x))),x)

[Out]

(2*atan((b*(a^4*(b^2)^(3/2) - a^6*(b^2)^(1/2))*(a*b^5*(-a^4)^(1/2) - b^6*(-a^4)^(1/2) + a^2*b^4*(-a^4)^(1/2) -
a^3*b^3*(-a^4)^(1/2) + b^6*exp(2*x)*(-a^4)^(1/2) - 2*a^2*b^4*exp(2*x)*(-a^4)^(1/2) + a^4*b^2*exp(2*x)*(-a^4)^
(1/2)) + b^2*(a^3*(b^2)^(3/2) - a^5*(b^2)^(1/2))*(a*b^5*(-a^4)^(1/2) - b^6*(-a^4)^(1/2) + a^2*b^4*(-a^4)^(1/2)
- a^3*b^3*(-a^4)^(1/2) + b^6*exp(2*x)*(-a^4)^(1/2) - 2*a^2*b^4*exp(2*x)*(-a^4)^(1/2) + a^4*b^2*exp(2*x)*(-a^4
)^(1/2)))/(a^6*b^10 - 3*a^8*b^8 + 3*a^10*b^6 - a^12*b^4))*(b^2)^(1/2))/(-a^4)^(1/2) - 2/(a*(exp(2*x) - 1))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {csch}^{2}{\relax (x )}}{a + b \tanh {\relax (x )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(x)**2/(a+b*tanh(x)),x)

[Out]

Integral(csch(x)**2/(a + b*tanh(x)), x)

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