Optimal. Leaf size=101 \[ -\frac {b^2 \left (3 a^2+b^2\right ) \tanh (c+d x)}{d}+\frac {4 a b \left (a^2+b^2\right ) \log (\cosh (c+d x))}{d}+x \left (a^4+6 a^2 b^2+b^4\right )-\frac {b (a+b \tanh (c+d x))^3}{3 d}-\frac {a b (a+b \tanh (c+d x))^2}{d} \]
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Rubi [A] time = 0.12, antiderivative size = 101, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3482, 3528, 3525, 3475} \[ -\frac {b^2 \left (3 a^2+b^2\right ) \tanh (c+d x)}{d}+\frac {4 a b \left (a^2+b^2\right ) \log (\cosh (c+d x))}{d}+x \left (6 a^2 b^2+a^4+b^4\right )-\frac {b (a+b \tanh (c+d x))^3}{3 d}-\frac {a b (a+b \tanh (c+d x))^2}{d} \]
Antiderivative was successfully verified.
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Rule 3475
Rule 3482
Rule 3525
Rule 3528
Rubi steps
\begin {align*} \int (a+b \tanh (c+d x))^4 \, dx &=-\frac {b (a+b \tanh (c+d x))^3}{3 d}+\int (a+b \tanh (c+d x))^2 \left (a^2+b^2+2 a b \tanh (c+d x)\right ) \, dx\\ &=-\frac {a b (a+b \tanh (c+d x))^2}{d}-\frac {b (a+b \tanh (c+d x))^3}{3 d}+\int (a+b \tanh (c+d x)) \left (a \left (a^2+3 b^2\right )+b \left (3 a^2+b^2\right ) \tanh (c+d x)\right ) \, dx\\ &=\left (a^4+6 a^2 b^2+b^4\right ) x-\frac {b^2 \left (3 a^2+b^2\right ) \tanh (c+d x)}{d}-\frac {a b (a+b \tanh (c+d x))^2}{d}-\frac {b (a+b \tanh (c+d x))^3}{3 d}+\left (4 a b \left (a^2+b^2\right )\right ) \int \tanh (c+d x) \, dx\\ &=\left (a^4+6 a^2 b^2+b^4\right ) x+\frac {4 a b \left (a^2+b^2\right ) \log (\cosh (c+d x))}{d}-\frac {b^2 \left (3 a^2+b^2\right ) \tanh (c+d x)}{d}-\frac {a b (a+b \tanh (c+d x))^2}{d}-\frac {b (a+b \tanh (c+d x))^3}{3 d}\\ \end {align*}
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Mathematica [A] time = 0.36, size = 91, normalized size = 0.90 \[ -\frac {6 b^2 \left (6 a^2+b^2\right ) \tanh (c+d x)+12 a b^3 \tanh ^2(c+d x)-3 (a-b)^4 \log (\tanh (c+d x)+1)+3 (a+b)^4 \log (1-\tanh (c+d x))+2 b^4 \tanh ^3(c+d x)}{6 d} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.83, size = 1389, normalized size = 13.75 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.16, size = 152, normalized size = 1.50 \[ \frac {3 \, {\left (a^{4} - 4 \, a^{3} b + 6 \, a^{2} b^{2} - 4 \, a b^{3} + b^{4}\right )} {\left (d x + c\right )} + 12 \, {\left (a^{3} b + a b^{3}\right )} \log \left (e^{\left (2 \, d x + 2 \, c\right )} + 1\right ) + \frac {4 \, {\left (9 \, a^{2} b^{2} + 2 \, b^{4} + 3 \, {\left (3 \, a^{2} b^{2} + 2 \, a b^{3} + b^{4}\right )} e^{\left (4 \, d x + 4 \, c\right )} + 3 \, {\left (6 \, a^{2} b^{2} + 2 \, a b^{3} + b^{4}\right )} e^{\left (2 \, d x + 2 \, c\right )}\right )}}{{\left (e^{\left (2 \, d x + 2 \, c\right )} + 1\right )}^{3}}}{3 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.01, size = 246, normalized size = 2.44 \[ -\frac {b^{4} \left (\tanh ^{3}\left (d x +c \right )\right )}{3 d}-\frac {2 \left (\tanh ^{2}\left (d x +c \right )\right ) a \,b^{3}}{d}-\frac {6 \tanh \left (d x +c \right ) a^{2} b^{2}}{d}-\frac {\tanh \left (d x +c \right ) b^{4}}{d}-\frac {a^{4} \ln \left (\tanh \left (d x +c \right )-1\right )}{2 d}-\frac {2 \ln \left (\tanh \left (d x +c \right )-1\right ) a^{3} b}{d}-\frac {3 \ln \left (\tanh \left (d x +c \right )-1\right ) a^{2} b^{2}}{d}-\frac {2 \ln \left (\tanh \left (d x +c \right )-1\right ) a \,b^{3}}{d}-\frac {\ln \left (\tanh \left (d x +c \right )-1\right ) b^{4}}{2 d}+\frac {\ln \left (1+\tanh \left (d x +c \right )\right ) a^{4}}{2 d}-\frac {2 \ln \left (1+\tanh \left (d x +c \right )\right ) a^{3} b}{d}+\frac {3 \ln \left (1+\tanh \left (d x +c \right )\right ) a^{2} b^{2}}{d}-\frac {2 \ln \left (1+\tanh \left (d x +c \right )\right ) a \,b^{3}}{d}+\frac {\ln \left (1+\tanh \left (d x +c \right )\right ) b^{4}}{2 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.42, size = 201, normalized size = 1.99 \[ \frac {1}{3} \, b^{4} {\left (3 \, x + \frac {3 \, c}{d} - \frac {4 \, {\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + 2\right )}}{d {\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )} + 1\right )}}\right )} + 4 \, a b^{3} {\left (x + \frac {c}{d} + \frac {\log \left (e^{\left (-2 \, d x - 2 \, c\right )} + 1\right )}{d} + \frac {2 \, e^{\left (-2 \, d x - 2 \, c\right )}}{d {\left (2 \, e^{\left (-2 \, d x - 2 \, c\right )} + e^{\left (-4 \, d x - 4 \, c\right )} + 1\right )}}\right )} + 6 \, a^{2} b^{2} {\left (x + \frac {c}{d} - \frac {2}{d {\left (e^{\left (-2 \, d x - 2 \, c\right )} + 1\right )}}\right )} + a^{4} x + \frac {4 \, a^{3} b \log \left (\cosh \left (d x + c\right )\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.09, size = 113, normalized size = 1.12 \[ x\,\left (a^4+4\,a^3\,b+6\,a^2\,b^2+4\,a\,b^3+b^4\right )-\frac {b^4\,{\mathrm {tanh}\left (c+d\,x\right )}^3}{3\,d}-\frac {\ln \left (\mathrm {tanh}\left (c+d\,x\right )+1\right )\,\left (4\,a^3\,b+4\,a\,b^3\right )}{d}-\frac {2\,a\,b^3\,{\mathrm {tanh}\left (c+d\,x\right )}^2}{d}-\frac {b^2\,\mathrm {tanh}\left (c+d\,x\right )\,\left (6\,a^2+b^2\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.42, size = 144, normalized size = 1.43 \[ \begin {cases} a^{4} x + 4 a^{3} b x - \frac {4 a^{3} b \log {\left (\tanh {\left (c + d x \right )} + 1 \right )}}{d} + 6 a^{2} b^{2} x - \frac {6 a^{2} b^{2} \tanh {\left (c + d x \right )}}{d} + 4 a b^{3} x - \frac {4 a b^{3} \log {\left (\tanh {\left (c + d x \right )} + 1 \right )}}{d} - \frac {2 a b^{3} \tanh ^{2}{\left (c + d x \right )}}{d} + b^{4} x - \frac {b^{4} \tanh ^{3}{\left (c + d x \right )}}{3 d} - \frac {b^{4} \tanh {\left (c + d x \right )}}{d} & \text {for}\: d \neq 0 \\x \left (a + b \tanh {\relax (c )}\right )^{4} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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