3.4 \(\int \cosh ^4(a+b x) \, dx\)

Optimal. Leaf size=46 \[ \frac {\sinh (a+b x) \cosh ^3(a+b x)}{4 b}+\frac {3 \sinh (a+b x) \cosh (a+b x)}{8 b}+\frac {3 x}{8} \]

[Out]

3/8*x+3/8*cosh(b*x+a)*sinh(b*x+a)/b+1/4*cosh(b*x+a)^3*sinh(b*x+a)/b

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Rubi [A]  time = 0.02, antiderivative size = 46, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2635, 8} \[ \frac {\sinh (a+b x) \cosh ^3(a+b x)}{4 b}+\frac {3 \sinh (a+b x) \cosh (a+b x)}{8 b}+\frac {3 x}{8} \]

Antiderivative was successfully verified.

[In]

Int[Cosh[a + b*x]^4,x]

[Out]

(3*x)/8 + (3*Cosh[a + b*x]*Sinh[a + b*x])/(8*b) + (Cosh[a + b*x]^3*Sinh[a + b*x])/(4*b)

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 2635

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> -Simp[(b*Cos[c + d*x]*(b*Sin[c + d*x])^(n - 1))/(d*n),
x] + Dist[(b^2*(n - 1))/n, Int[(b*Sin[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && Integer
Q[2*n]

Rubi steps

\begin {align*} \int \cosh ^4(a+b x) \, dx &=\frac {\cosh ^3(a+b x) \sinh (a+b x)}{4 b}+\frac {3}{4} \int \cosh ^2(a+b x) \, dx\\ &=\frac {3 \cosh (a+b x) \sinh (a+b x)}{8 b}+\frac {\cosh ^3(a+b x) \sinh (a+b x)}{4 b}+\frac {3 \int 1 \, dx}{8}\\ &=\frac {3 x}{8}+\frac {3 \cosh (a+b x) \sinh (a+b x)}{8 b}+\frac {\cosh ^3(a+b x) \sinh (a+b x)}{4 b}\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 33, normalized size = 0.72 \[ \frac {12 (a+b x)+8 \sinh (2 (a+b x))+\sinh (4 (a+b x))}{32 b} \]

Antiderivative was successfully verified.

[In]

Integrate[Cosh[a + b*x]^4,x]

[Out]

(12*(a + b*x) + 8*Sinh[2*(a + b*x)] + Sinh[4*(a + b*x)])/(32*b)

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fricas [A]  time = 0.81, size = 49, normalized size = 1.07 \[ \frac {\cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{3} + 3 \, b x + {\left (\cosh \left (b x + a\right )^{3} + 4 \, \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right )}{8 \, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)^4,x, algorithm="fricas")

[Out]

1/8*(cosh(b*x + a)*sinh(b*x + a)^3 + 3*b*x + (cosh(b*x + a)^3 + 4*cosh(b*x + a))*sinh(b*x + a))/b

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giac [A]  time = 0.12, size = 60, normalized size = 1.30 \[ \frac {3}{8} \, x + \frac {e^{\left (4 \, b x + 4 \, a\right )}}{64 \, b} + \frac {e^{\left (2 \, b x + 2 \, a\right )}}{8 \, b} - \frac {e^{\left (-2 \, b x - 2 \, a\right )}}{8 \, b} - \frac {e^{\left (-4 \, b x - 4 \, a\right )}}{64 \, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)^4,x, algorithm="giac")

[Out]

3/8*x + 1/64*e^(4*b*x + 4*a)/b + 1/8*e^(2*b*x + 2*a)/b - 1/8*e^(-2*b*x - 2*a)/b - 1/64*e^(-4*b*x - 4*a)/b

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maple [A]  time = 0.21, size = 39, normalized size = 0.85 \[ \frac {\left (\frac {\left (\cosh ^{3}\left (b x +a \right )\right )}{4}+\frac {3 \cosh \left (b x +a \right )}{8}\right ) \sinh \left (b x +a \right )+\frac {3 b x}{8}+\frac {3 a}{8}}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cosh(b*x+a)^4,x)

[Out]

1/b*((1/4*cosh(b*x+a)^3+3/8*cosh(b*x+a))*sinh(b*x+a)+3/8*b*x+3/8*a)

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maxima [A]  time = 0.31, size = 60, normalized size = 1.30 \[ \frac {3}{8} \, x + \frac {e^{\left (4 \, b x + 4 \, a\right )}}{64 \, b} + \frac {e^{\left (2 \, b x + 2 \, a\right )}}{8 \, b} - \frac {e^{\left (-2 \, b x - 2 \, a\right )}}{8 \, b} - \frac {e^{\left (-4 \, b x - 4 \, a\right )}}{64 \, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)^4,x, algorithm="maxima")

[Out]

3/8*x + 1/64*e^(4*b*x + 4*a)/b + 1/8*e^(2*b*x + 2*a)/b - 1/8*e^(-2*b*x - 2*a)/b - 1/64*e^(-4*b*x - 4*a)/b

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mupad [B]  time = 0.08, size = 31, normalized size = 0.67 \[ \frac {3\,x}{8}+\frac {\frac {\mathrm {sinh}\left (2\,a+2\,b\,x\right )}{4}+\frac {\mathrm {sinh}\left (4\,a+4\,b\,x\right )}{32}}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cosh(a + b*x)^4,x)

[Out]

(3*x)/8 + (sinh(2*a + 2*b*x)/4 + sinh(4*a + 4*b*x)/32)/b

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sympy [A]  time = 0.85, size = 95, normalized size = 2.07 \[ \begin {cases} \frac {3 x \sinh ^{4}{\left (a + b x \right )}}{8} - \frac {3 x \sinh ^{2}{\left (a + b x \right )} \cosh ^{2}{\left (a + b x \right )}}{4} + \frac {3 x \cosh ^{4}{\left (a + b x \right )}}{8} - \frac {3 \sinh ^{3}{\left (a + b x \right )} \cosh {\left (a + b x \right )}}{8 b} + \frac {5 \sinh {\left (a + b x \right )} \cosh ^{3}{\left (a + b x \right )}}{8 b} & \text {for}\: b \neq 0 \\x \cosh ^{4}{\relax (a )} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)**4,x)

[Out]

Piecewise((3*x*sinh(a + b*x)**4/8 - 3*x*sinh(a + b*x)**2*cosh(a + b*x)**2/4 + 3*x*cosh(a + b*x)**4/8 - 3*sinh(
a + b*x)**3*cosh(a + b*x)/(8*b) + 5*sinh(a + b*x)*cosh(a + b*x)**3/(8*b), Ne(b, 0)), (x*cosh(a)**4, True))

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