3.312 \(\int f^{a+c x^2} \cosh ^2(d+e x) \, dx\)

Optimal. Leaf size=161 \[ -\frac {\sqrt {\pi } f^a e^{-\frac {e^2}{c \log (f)}-2 d} \text {erfi}\left (\frac {e-c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}+\frac {\sqrt {\pi } f^a e^{2 d-\frac {e^2}{c \log (f)}} \text {erfi}\left (\frac {c x \log (f)+e}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}+\frac {\sqrt {\pi } f^a \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}} \]

[Out]

1/8*exp(-2*d-e^2/c/ln(f))*f^a*erfi((-e+c*x*ln(f))/c^(1/2)/ln(f)^(1/2))*Pi^(1/2)/c^(1/2)/ln(f)^(1/2)+1/8*exp(2*
d-e^2/c/ln(f))*f^a*erfi((e+c*x*ln(f))/c^(1/2)/ln(f)^(1/2))*Pi^(1/2)/c^(1/2)/ln(f)^(1/2)+1/4*f^a*erfi(x*c^(1/2)
*ln(f)^(1/2))*Pi^(1/2)/c^(1/2)/ln(f)^(1/2)

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Rubi [A]  time = 0.22, antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 4, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {5513, 2204, 2287, 2234} \[ -\frac {\sqrt {\pi } f^a e^{-\frac {e^2}{c \log (f)}-2 d} \text {Erfi}\left (\frac {e-c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}+\frac {\sqrt {\pi } f^a e^{2 d-\frac {e^2}{c \log (f)}} \text {Erfi}\left (\frac {c x \log (f)+e}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}+\frac {\sqrt {\pi } f^a \text {Erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}} \]

Antiderivative was successfully verified.

[In]

Int[f^(a + c*x^2)*Cosh[d + e*x]^2,x]

[Out]

(f^a*Sqrt[Pi]*Erfi[Sqrt[c]*x*Sqrt[Log[f]]])/(4*Sqrt[c]*Sqrt[Log[f]]) - (E^(-2*d - e^2/(c*Log[f]))*f^a*Sqrt[Pi]
*Erfi[(e - c*x*Log[f])/(Sqrt[c]*Sqrt[Log[f]])])/(8*Sqrt[c]*Sqrt[Log[f]]) + (E^(2*d - e^2/(c*Log[f]))*f^a*Sqrt[
Pi]*Erfi[(e + c*x*Log[f])/(Sqrt[c]*Sqrt[Log[f]])])/(8*Sqrt[c]*Sqrt[Log[f]])

Rule 2204

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erfi[(c + d*x)*Rt[b*Log[F], 2
]])/(2*d*Rt[b*Log[F], 2]), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2234

Int[(F_)^((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[F^(a - b^2/(4*c)), Int[F^((b + 2*c*x)^2/(4*c))
, x], x] /; FreeQ[{F, a, b, c}, x]

Rule 2287

Int[(u_.)*(F_)^(v_)*(G_)^(w_), x_Symbol] :> With[{z = v*Log[F] + w*Log[G]}, Int[u*NormalizeIntegrand[E^z, x],
x] /; BinomialQ[z, x] || (PolynomialQ[z, x] && LeQ[Exponent[z, x], 2])] /; FreeQ[{F, G}, x]

Rule 5513

Int[Cosh[v_]^(n_.)*(F_)^(u_), x_Symbol] :> Int[ExpandTrigToExp[F^u, Cosh[v]^n, x], x] /; FreeQ[F, x] && (Linea
rQ[u, x] || PolyQ[u, x, 2]) && (LinearQ[v, x] || PolyQ[v, x, 2]) && IGtQ[n, 0]

Rubi steps

\begin {align*} \int f^{a+c x^2} \cosh ^2(d+e x) \, dx &=\int \left (\frac {1}{2} f^{a+c x^2}+\frac {1}{4} e^{-2 d-2 e x} f^{a+c x^2}+\frac {1}{4} e^{2 d+2 e x} f^{a+c x^2}\right ) \, dx\\ &=\frac {1}{4} \int e^{-2 d-2 e x} f^{a+c x^2} \, dx+\frac {1}{4} \int e^{2 d+2 e x} f^{a+c x^2} \, dx+\frac {1}{2} \int f^{a+c x^2} \, dx\\ &=\frac {f^a \sqrt {\pi } \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}}+\frac {1}{4} \int e^{-2 d-2 e x+a \log (f)+c x^2 \log (f)} \, dx+\frac {1}{4} \int e^{2 d+2 e x+a \log (f)+c x^2 \log (f)} \, dx\\ &=\frac {f^a \sqrt {\pi } \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}}+\frac {1}{4} \left (e^{-2 d-\frac {e^2}{c \log (f)}} f^a\right ) \int e^{\frac {(-2 e+2 c x \log (f))^2}{4 c \log (f)}} \, dx+\frac {1}{4} \left (e^{2 d-\frac {e^2}{c \log (f)}} f^a\right ) \int e^{\frac {(2 e+2 c x \log (f))^2}{4 c \log (f)}} \, dx\\ &=\frac {f^a \sqrt {\pi } \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )}{4 \sqrt {c} \sqrt {\log (f)}}-\frac {e^{-2 d-\frac {e^2}{c \log (f)}} f^a \sqrt {\pi } \text {erfi}\left (\frac {e-c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}+\frac {e^{2 d-\frac {e^2}{c \log (f)}} f^a \sqrt {\pi } \text {erfi}\left (\frac {e+c x \log (f)}{\sqrt {c} \sqrt {\log (f)}}\right )}{8 \sqrt {c} \sqrt {\log (f)}}\\ \end {align*}

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Mathematica [A]  time = 0.23, size = 131, normalized size = 0.81 \[ \frac {\sqrt {\pi } f^a e^{-\frac {e^2}{c \log (f)}} \left ((\cosh (2 d)-\sinh (2 d)) \text {erfi}\left (\frac {c x \log (f)-e}{\sqrt {c} \sqrt {\log (f)}}\right )+(\sinh (2 d)+\cosh (2 d)) \text {erfi}\left (\frac {c x \log (f)+e}{\sqrt {c} \sqrt {\log (f)}}\right )+2 e^{\frac {e^2}{c \log (f)}} \text {erfi}\left (\sqrt {c} x \sqrt {\log (f)}\right )\right )}{8 \sqrt {c} \sqrt {\log (f)}} \]

Antiderivative was successfully verified.

[In]

Integrate[f^(a + c*x^2)*Cosh[d + e*x]^2,x]

[Out]

(f^a*Sqrt[Pi]*(2*E^(e^2/(c*Log[f]))*Erfi[Sqrt[c]*x*Sqrt[Log[f]]] + Erfi[(-e + c*x*Log[f])/(Sqrt[c]*Sqrt[Log[f]
])]*(Cosh[2*d] - Sinh[2*d]) + Erfi[(e + c*x*Log[f])/(Sqrt[c]*Sqrt[Log[f]])]*(Cosh[2*d] + Sinh[2*d])))/(8*Sqrt[
c]*E^(e^2/(c*Log[f]))*Sqrt[Log[f]])

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fricas [A]  time = 0.60, size = 242, normalized size = 1.50 \[ -\frac {2 \, \sqrt {-c \log \relax (f)} {\left (\sqrt {\pi } \cosh \left (a \log \relax (f)\right ) + \sqrt {\pi } \sinh \left (a \log \relax (f)\right )\right )} \operatorname {erf}\left (\sqrt {-c \log \relax (f)} x\right ) + \sqrt {-c \log \relax (f)} {\left (\sqrt {\pi } \cosh \left (\frac {a c \log \relax (f)^{2} + 2 \, c d \log \relax (f) - e^{2}}{c \log \relax (f)}\right ) + \sqrt {\pi } \sinh \left (\frac {a c \log \relax (f)^{2} + 2 \, c d \log \relax (f) - e^{2}}{c \log \relax (f)}\right )\right )} \operatorname {erf}\left (\frac {{\left (c x \log \relax (f) + e\right )} \sqrt {-c \log \relax (f)}}{c \log \relax (f)}\right ) + \sqrt {-c \log \relax (f)} {\left (\sqrt {\pi } \cosh \left (\frac {a c \log \relax (f)^{2} - 2 \, c d \log \relax (f) - e^{2}}{c \log \relax (f)}\right ) + \sqrt {\pi } \sinh \left (\frac {a c \log \relax (f)^{2} - 2 \, c d \log \relax (f) - e^{2}}{c \log \relax (f)}\right )\right )} \operatorname {erf}\left (\frac {{\left (c x \log \relax (f) - e\right )} \sqrt {-c \log \relax (f)}}{c \log \relax (f)}\right )}{8 \, c \log \relax (f)} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(c*x^2+a)*cosh(e*x+d)^2,x, algorithm="fricas")

[Out]

-1/8*(2*sqrt(-c*log(f))*(sqrt(pi)*cosh(a*log(f)) + sqrt(pi)*sinh(a*log(f)))*erf(sqrt(-c*log(f))*x) + sqrt(-c*l
og(f))*(sqrt(pi)*cosh((a*c*log(f)^2 + 2*c*d*log(f) - e^2)/(c*log(f))) + sqrt(pi)*sinh((a*c*log(f)^2 + 2*c*d*lo
g(f) - e^2)/(c*log(f))))*erf((c*x*log(f) + e)*sqrt(-c*log(f))/(c*log(f))) + sqrt(-c*log(f))*(sqrt(pi)*cosh((a*
c*log(f)^2 - 2*c*d*log(f) - e^2)/(c*log(f))) + sqrt(pi)*sinh((a*c*log(f)^2 - 2*c*d*log(f) - e^2)/(c*log(f))))*
erf((c*x*log(f) - e)*sqrt(-c*log(f))/(c*log(f))))/(c*log(f))

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giac [A]  time = 0.16, size = 150, normalized size = 0.93 \[ -\frac {\sqrt {\pi } f^{a} \operatorname {erf}\left (-\sqrt {-c \log \relax (f)} x\right )}{4 \, \sqrt {-c \log \relax (f)}} - \frac {\sqrt {\pi } \operatorname {erf}\left (-\sqrt {-c \log \relax (f)} {\left (x + \frac {e}{c \log \relax (f)}\right )}\right ) e^{\left (\frac {a c \log \relax (f)^{2} + 2 \, c d \log \relax (f) - e^{2}}{c \log \relax (f)}\right )}}{8 \, \sqrt {-c \log \relax (f)}} - \frac {\sqrt {\pi } \operatorname {erf}\left (-\sqrt {-c \log \relax (f)} {\left (x - \frac {e}{c \log \relax (f)}\right )}\right ) e^{\left (\frac {a c \log \relax (f)^{2} - 2 \, c d \log \relax (f) - e^{2}}{c \log \relax (f)}\right )}}{8 \, \sqrt {-c \log \relax (f)}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(c*x^2+a)*cosh(e*x+d)^2,x, algorithm="giac")

[Out]

-1/4*sqrt(pi)*f^a*erf(-sqrt(-c*log(f))*x)/sqrt(-c*log(f)) - 1/8*sqrt(pi)*erf(-sqrt(-c*log(f))*(x + e/(c*log(f)
)))*e^((a*c*log(f)^2 + 2*c*d*log(f) - e^2)/(c*log(f)))/sqrt(-c*log(f)) - 1/8*sqrt(pi)*erf(-sqrt(-c*log(f))*(x
- e/(c*log(f))))*e^((a*c*log(f)^2 - 2*c*d*log(f) - e^2)/(c*log(f)))/sqrt(-c*log(f))

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maple [A]  time = 0.25, size = 139, normalized size = 0.86 \[ \frac {\sqrt {\pi }\, f^{a} {\mathrm e}^{-\frac {2 d \ln \relax (f ) c +e^{2}}{\ln \relax (f ) c}} \erf \left (\sqrt {-c \ln \relax (f )}\, x +\frac {e}{\sqrt {-c \ln \relax (f )}}\right )}{8 \sqrt {-c \ln \relax (f )}}-\frac {\sqrt {\pi }\, f^{a} {\mathrm e}^{\frac {2 d \ln \relax (f ) c -e^{2}}{\ln \relax (f ) c}} \erf \left (-\sqrt {-c \ln \relax (f )}\, x +\frac {e}{\sqrt {-c \ln \relax (f )}}\right )}{8 \sqrt {-c \ln \relax (f )}}+\frac {f^{a} \sqrt {\pi }\, \erf \left (\sqrt {-c \ln \relax (f )}\, x \right )}{4 \sqrt {-c \ln \relax (f )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(c*x^2+a)*cosh(e*x+d)^2,x)

[Out]

1/8*Pi^(1/2)*f^a*exp(-(2*d*ln(f)*c+e^2)/ln(f)/c)/(-c*ln(f))^(1/2)*erf((-c*ln(f))^(1/2)*x+e/(-c*ln(f))^(1/2))-1
/8*Pi^(1/2)*f^a*exp((2*d*ln(f)*c-e^2)/ln(f)/c)/(-c*ln(f))^(1/2)*erf(-(-c*ln(f))^(1/2)*x+e/(-c*ln(f))^(1/2))+1/
4*f^a*Pi^(1/2)/(-c*ln(f))^(1/2)*erf((-c*ln(f))^(1/2)*x)

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maxima [A]  time = 0.33, size = 131, normalized size = 0.81 \[ \frac {\sqrt {\pi } f^{a} \operatorname {erf}\left (\sqrt {-c \log \relax (f)} x - \frac {e}{\sqrt {-c \log \relax (f)}}\right ) e^{\left (2 \, d - \frac {e^{2}}{c \log \relax (f)}\right )}}{8 \, \sqrt {-c \log \relax (f)}} + \frac {\sqrt {\pi } f^{a} \operatorname {erf}\left (\sqrt {-c \log \relax (f)} x + \frac {e}{\sqrt {-c \log \relax (f)}}\right ) e^{\left (-2 \, d - \frac {e^{2}}{c \log \relax (f)}\right )}}{8 \, \sqrt {-c \log \relax (f)}} + \frac {\sqrt {\pi } f^{a} \operatorname {erf}\left (\sqrt {-c \log \relax (f)} x\right )}{4 \, \sqrt {-c \log \relax (f)}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(c*x^2+a)*cosh(e*x+d)^2,x, algorithm="maxima")

[Out]

1/8*sqrt(pi)*f^a*erf(sqrt(-c*log(f))*x - e/sqrt(-c*log(f)))*e^(2*d - e^2/(c*log(f)))/sqrt(-c*log(f)) + 1/8*sqr
t(pi)*f^a*erf(sqrt(-c*log(f))*x + e/sqrt(-c*log(f)))*e^(-2*d - e^2/(c*log(f)))/sqrt(-c*log(f)) + 1/4*sqrt(pi)*
f^a*erf(sqrt(-c*log(f))*x)/sqrt(-c*log(f))

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int f^{c\,x^2+a}\,{\mathrm {cosh}\left (d+e\,x\right )}^2 \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(a + c*x^2)*cosh(d + e*x)^2,x)

[Out]

int(f^(a + c*x^2)*cosh(d + e*x)^2, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int f^{a + c x^{2}} \cosh ^{2}{\left (d + e x \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f**(c*x**2+a)*cosh(e*x+d)**2,x)

[Out]

Integral(f**(a + c*x**2)*cosh(d + e*x)**2, x)

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