3.36 \(\int \frac {\csc ^{-1}(a+b x)^3}{x} \, dx\)

Optimal. Leaf size=448 \[ -3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+6 i \text {Li}_4\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+6 i \text {Li}_4\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+\frac {3}{2} i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (e^{2 i \csc ^{-1}(a+b x)}\right )-\frac {3}{2} \csc ^{-1}(a+b x) \text {Li}_3\left (e^{2 i \csc ^{-1}(a+b x)}\right )-\frac {3}{4} i \text {Li}_4\left (e^{2 i \csc ^{-1}(a+b x)}\right )-\csc ^{-1}(a+b x)^3 \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right ) \]

[Out]

-arccsc(b*x+a)^3*ln(1-(I/(b*x+a)+(1-1/(b*x+a)^2)^(1/2))^2)+arccsc(b*x+a)^3*ln(1+I*a*(I/(b*x+a)+(1-1/(b*x+a)^2)
^(1/2))/(1-(-a^2+1)^(1/2)))+arccsc(b*x+a)^3*ln(1+I*a*(I/(b*x+a)+(1-1/(b*x+a)^2)^(1/2))/(1+(-a^2+1)^(1/2)))+3/2
*I*arccsc(b*x+a)^2*polylog(2,(I/(b*x+a)+(1-1/(b*x+a)^2)^(1/2))^2)-3*I*arccsc(b*x+a)^2*polylog(2,-I*a*(I/(b*x+a
)+(1-1/(b*x+a)^2)^(1/2))/(1-(-a^2+1)^(1/2)))-3*I*arccsc(b*x+a)^2*polylog(2,-I*a*(I/(b*x+a)+(1-1/(b*x+a)^2)^(1/
2))/(1+(-a^2+1)^(1/2)))-3/2*arccsc(b*x+a)*polylog(3,(I/(b*x+a)+(1-1/(b*x+a)^2)^(1/2))^2)+6*arccsc(b*x+a)*polyl
og(3,-I*a*(I/(b*x+a)+(1-1/(b*x+a)^2)^(1/2))/(1-(-a^2+1)^(1/2)))+6*arccsc(b*x+a)*polylog(3,-I*a*(I/(b*x+a)+(1-1
/(b*x+a)^2)^(1/2))/(1+(-a^2+1)^(1/2)))-3/4*I*polylog(4,(I/(b*x+a)+(1-1/(b*x+a)^2)^(1/2))^2)+6*I*polylog(4,-I*a
*(I/(b*x+a)+(1-1/(b*x+a)^2)^(1/2))/(1-(-a^2+1)^(1/2)))+6*I*polylog(4,-I*a*(I/(b*x+a)+(1-1/(b*x+a)^2)^(1/2))/(1
+(-a^2+1)^(1/2)))

________________________________________________________________________________________

Rubi [A]  time = 0.54, antiderivative size = 448, normalized size of antiderivative = 1.00, number of steps used = 20, number of rules used = 10, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.833, Rules used = {5259, 4552, 4529, 3717, 2190, 2531, 6609, 2282, 6589, 4519} \[ -3 i \csc ^{-1}(a+b x)^2 \text {PolyLog}\left (2,-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )-3 i \csc ^{-1}(a+b x)^2 \text {PolyLog}\left (2,-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+6 \csc ^{-1}(a+b x) \text {PolyLog}\left (3,-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+6 \csc ^{-1}(a+b x) \text {PolyLog}\left (3,-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+6 i \text {PolyLog}\left (4,-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+6 i \text {PolyLog}\left (4,-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+\frac {3}{2} i \csc ^{-1}(a+b x)^2 \text {PolyLog}\left (2,e^{2 i \csc ^{-1}(a+b x)}\right )-\frac {3}{2} \csc ^{-1}(a+b x) \text {PolyLog}\left (3,e^{2 i \csc ^{-1}(a+b x)}\right )-\frac {3}{4} i \text {PolyLog}\left (4,e^{2 i \csc ^{-1}(a+b x)}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )-\csc ^{-1}(a+b x)^3 \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right ) \]

Antiderivative was successfully verified.

[In]

Int[ArcCsc[a + b*x]^3/x,x]

[Out]

ArcCsc[a + b*x]^3*Log[1 + (I*a*E^(I*ArcCsc[a + b*x]))/(1 - Sqrt[1 - a^2])] + ArcCsc[a + b*x]^3*Log[1 + (I*a*E^
(I*ArcCsc[a + b*x]))/(1 + Sqrt[1 - a^2])] - ArcCsc[a + b*x]^3*Log[1 - E^((2*I)*ArcCsc[a + b*x])] - (3*I)*ArcCs
c[a + b*x]^2*PolyLog[2, ((-I)*a*E^(I*ArcCsc[a + b*x]))/(1 - Sqrt[1 - a^2])] - (3*I)*ArcCsc[a + b*x]^2*PolyLog[
2, ((-I)*a*E^(I*ArcCsc[a + b*x]))/(1 + Sqrt[1 - a^2])] + ((3*I)/2)*ArcCsc[a + b*x]^2*PolyLog[2, E^((2*I)*ArcCs
c[a + b*x])] + 6*ArcCsc[a + b*x]*PolyLog[3, ((-I)*a*E^(I*ArcCsc[a + b*x]))/(1 - Sqrt[1 - a^2])] + 6*ArcCsc[a +
 b*x]*PolyLog[3, ((-I)*a*E^(I*ArcCsc[a + b*x]))/(1 + Sqrt[1 - a^2])] - (3*ArcCsc[a + b*x]*PolyLog[3, E^((2*I)*
ArcCsc[a + b*x])])/2 + (6*I)*PolyLog[4, ((-I)*a*E^(I*ArcCsc[a + b*x]))/(1 - Sqrt[1 - a^2])] + (6*I)*PolyLog[4,
 ((-I)*a*E^(I*ArcCsc[a + b*x]))/(1 + Sqrt[1 - a^2])] - ((3*I)/4)*PolyLog[4, E^((2*I)*ArcCsc[a + b*x])]

Rule 2190

Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/((a_) + (b_.)*((F_)^((g_.)*((e_.) +
 (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[((c + d*x)^m*Log[1 + (b*(F^(g*(e + f*x)))^n)/a])/(b*f*g*n*Log[F]), x]
 - Dist[(d*m)/(b*f*g*n*Log[F]), Int[(c + d*x)^(m - 1)*Log[1 + (b*(F^(g*(e + f*x)))^n)/a], x], x] /; FreeQ[{F,
a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]

Rule 2282

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Dist[v/D[v, x], Subst[Int[FunctionOfExponentialFu
nction[u, x]/x, x], x, v], x]] /; FunctionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; F
reeQ[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x))*(F_)[v_] /; FreeQ[{a, b, c}, x
] && InverseFunctionQ[F[x]]]

Rule 2531

Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> -Simp[((
f + g*x)^m*PolyLog[2, -(e*(F^(c*(a + b*x)))^n)])/(b*c*n*Log[F]), x] + Dist[(g*m)/(b*c*n*Log[F]), Int[(f + g*x)
^(m - 1)*PolyLog[2, -(e*(F^(c*(a + b*x)))^n)], x], x] /; FreeQ[{F, a, b, c, e, f, g, n}, x] && GtQ[m, 0]

Rule 3717

Int[((c_.) + (d_.)*(x_))^(m_.)*tan[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol] :> Simp[(I*(c + d*x)^(m + 1))/(d*
(m + 1)), x] - Dist[2*I, Int[((c + d*x)^m*E^(2*I*k*Pi)*E^(2*I*(e + f*x)))/(1 + E^(2*I*k*Pi)*E^(2*I*(e + f*x)))
, x], x] /; FreeQ[{c, d, e, f}, x] && IntegerQ[4*k] && IGtQ[m, 0]

Rule 4519

Int[(Cos[(c_.) + (d_.)*(x_)]*((e_.) + (f_.)*(x_))^(m_.))/((a_) + (b_.)*Sin[(c_.) + (d_.)*(x_)]), x_Symbol] :>
-Simp[(I*(e + f*x)^(m + 1))/(b*f*(m + 1)), x] + (Int[((e + f*x)^m*E^(I*(c + d*x)))/(a - Rt[a^2 - b^2, 2] - I*b
*E^(I*(c + d*x))), x] + Int[((e + f*x)^m*E^(I*(c + d*x)))/(a + Rt[a^2 - b^2, 2] - I*b*E^(I*(c + d*x))), x]) /;
 FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0] && PosQ[a^2 - b^2]

Rule 4529

Int[(Cot[(c_.) + (d_.)*(x_)]^(n_.)*((e_.) + (f_.)*(x_))^(m_.))/((a_) + (b_.)*Sin[(c_.) + (d_.)*(x_)]), x_Symbo
l] :> Dist[1/a, Int[(e + f*x)^m*Cot[c + d*x]^n, x], x] - Dist[b/a, Int[((e + f*x)^m*Cos[c + d*x]*Cot[c + d*x]^
(n - 1))/(a + b*Sin[c + d*x]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0] && IGtQ[n, 0]

Rule 4552

Int[(((e_.) + (f_.)*(x_))^(m_.)*(F_)[(c_.) + (d_.)*(x_)]^(n_.)*(G_)[(c_.) + (d_.)*(x_)]^(p_.))/(Csc[(c_.) + (d
_.)*(x_)]*(b_.) + (a_)), x_Symbol] :> Int[((e + f*x)^m*Sin[c + d*x]*F[c + d*x]^n*G[c + d*x]^p)/(b + a*Sin[c +
d*x]), x] /; FreeQ[{a, b, c, d, e, f}, x] && TrigQ[F] && TrigQ[G] && IntegersQ[m, n, p]

Rule 5259

Int[((a_.) + ArcCsc[(c_) + (d_.)*(x_)]*(b_.))^(p_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> -Dist[(d^(m + 1))
^(-1), Subst[Int[(a + b*x)^p*Csc[x]*Cot[x]*(d*e - c*f + f*Csc[x])^m, x], x, ArcCsc[c + d*x]], x] /; FreeQ[{a,
b, c, d, e, f}, x] && IGtQ[p, 0] && IntegerQ[m]

Rule 6589

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rule 6609

Int[((e_.) + (f_.)*(x_))^(m_.)*PolyLog[n_, (d_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(p_.)], x_Symbol] :> Simp
[((e + f*x)^m*PolyLog[n + 1, d*(F^(c*(a + b*x)))^p])/(b*c*p*Log[F]), x] - Dist[(f*m)/(b*c*p*Log[F]), Int[(e +
f*x)^(m - 1)*PolyLog[n + 1, d*(F^(c*(a + b*x)))^p], x], x] /; FreeQ[{F, a, b, c, d, e, f, n, p}, x] && GtQ[m,
0]

Rubi steps

\begin {align*} \int \frac {\csc ^{-1}(a+b x)^3}{x} \, dx &=-\operatorname {Subst}\left (\int \frac {x^3 \cot (x) \csc (x)}{-a+\csc (x)} \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=-\operatorname {Subst}\left (\int \frac {x^3 \cot (x)}{1-a \sin (x)} \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=-\left (a \operatorname {Subst}\left (\int \frac {x^3 \cos (x)}{1-a \sin (x)} \, dx,x,\csc ^{-1}(a+b x)\right )\right )-\operatorname {Subst}\left (\int x^3 \cot (x) \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=2 i \operatorname {Subst}\left (\int \frac {e^{2 i x} x^3}{1-e^{2 i x}} \, dx,x,\csc ^{-1}(a+b x)\right )-a \operatorname {Subst}\left (\int \frac {e^{i x} x^3}{1-\sqrt {1-a^2}+i a e^{i x}} \, dx,x,\csc ^{-1}(a+b x)\right )-a \operatorname {Subst}\left (\int \frac {e^{i x} x^3}{1+\sqrt {1-a^2}+i a e^{i x}} \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )-\csc ^{-1}(a+b x)^3 \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )-3 \operatorname {Subst}\left (\int x^2 \log \left (1+\frac {i a e^{i x}}{1-\sqrt {1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )-3 \operatorname {Subst}\left (\int x^2 \log \left (1+\frac {i a e^{i x}}{1+\sqrt {1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )+3 \operatorname {Subst}\left (\int x^2 \log \left (1-e^{2 i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )-\csc ^{-1}(a+b x)^3 \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )+\frac {3}{2} i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (e^{2 i \csc ^{-1}(a+b x)}\right )-3 i \operatorname {Subst}\left (\int x \text {Li}_2\left (e^{2 i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )+6 i \operatorname {Subst}\left (\int x \text {Li}_2\left (-\frac {i a e^{i x}}{1-\sqrt {1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )+6 i \operatorname {Subst}\left (\int x \text {Li}_2\left (-\frac {i a e^{i x}}{1+\sqrt {1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )-\csc ^{-1}(a+b x)^3 \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )+\frac {3}{2} i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (e^{2 i \csc ^{-1}(a+b x)}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )-\frac {3}{2} \csc ^{-1}(a+b x) \text {Li}_3\left (e^{2 i \csc ^{-1}(a+b x)}\right )+\frac {3}{2} \operatorname {Subst}\left (\int \text {Li}_3\left (e^{2 i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )-6 \operatorname {Subst}\left (\int \text {Li}_3\left (-\frac {i a e^{i x}}{1-\sqrt {1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )-6 \operatorname {Subst}\left (\int \text {Li}_3\left (-\frac {i a e^{i x}}{1+\sqrt {1-a^2}}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )\\ &=\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )-\csc ^{-1}(a+b x)^3 \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )+\frac {3}{2} i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (e^{2 i \csc ^{-1}(a+b x)}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )-\frac {3}{2} \csc ^{-1}(a+b x) \text {Li}_3\left (e^{2 i \csc ^{-1}(a+b x)}\right )-\frac {3}{4} i \operatorname {Subst}\left (\int \frac {\text {Li}_3(x)}{x} \, dx,x,e^{2 i \csc ^{-1}(a+b x)}\right )+6 i \operatorname {Subst}\left (\int \frac {\text {Li}_3\left (\frac {i a x}{-1+\sqrt {1-a^2}}\right )}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )+6 i \operatorname {Subst}\left (\int \frac {\text {Li}_3\left (-\frac {i a x}{1+\sqrt {1-a^2}}\right )}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )\\ &=\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )-\csc ^{-1}(a+b x)^3 \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )+\frac {3}{2} i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (e^{2 i \csc ^{-1}(a+b x)}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )-\frac {3}{2} \csc ^{-1}(a+b x) \text {Li}_3\left (e^{2 i \csc ^{-1}(a+b x)}\right )+6 i \text {Li}_4\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1-\sqrt {1-a^2}}\right )+6 i \text {Li}_4\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{1+\sqrt {1-a^2}}\right )-\frac {3}{4} i \text {Li}_4\left (e^{2 i \csc ^{-1}(a+b x)}\right )\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.33, size = 554, normalized size = 1.24 \[ -3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}-1}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}-1}\right )+6 \csc ^{-1}(a+b x) \text {Li}_3\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+6 i \text {Li}_4\left (\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}-1}\right )+6 i \text {Li}_4\left (-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )+\csc ^{-1}(a+b x)^3 \log \left (1-\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}-1}\right )+\csc ^{-1}(a+b x)^3 \log \left (1+\frac {i a e^{i \csc ^{-1}(a+b x)}}{\sqrt {1-a^2}+1}\right )-3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (e^{-i \csc ^{-1}(a+b x)}\right )+3 i \csc ^{-1}(a+b x)^2 \text {Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )-6 \csc ^{-1}(a+b x) \text {Li}_3\left (e^{-i \csc ^{-1}(a+b x)}\right )-6 \csc ^{-1}(a+b x) \text {Li}_3\left (-e^{i \csc ^{-1}(a+b x)}\right )+6 i \text {Li}_4\left (e^{-i \csc ^{-1}(a+b x)}\right )-6 i \text {Li}_4\left (-e^{i \csc ^{-1}(a+b x)}\right )-\frac {1}{4} i \csc ^{-1}(a+b x)^4-\csc ^{-1}(a+b x)^3 \log \left (1-e^{-i \csc ^{-1}(a+b x)}\right )-\csc ^{-1}(a+b x)^3 \log \left (1+e^{i \csc ^{-1}(a+b x)}\right )+\frac {i \pi ^4}{8} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[ArcCsc[a + b*x]^3/x,x]

[Out]

(I/8)*Pi^4 - (I/4)*ArcCsc[a + b*x]^4 - ArcCsc[a + b*x]^3*Log[1 - E^((-I)*ArcCsc[a + b*x])] - ArcCsc[a + b*x]^3
*Log[1 + E^(I*ArcCsc[a + b*x])] + ArcCsc[a + b*x]^3*Log[1 - (I*a*E^(I*ArcCsc[a + b*x]))/(-1 + Sqrt[1 - a^2])]
+ ArcCsc[a + b*x]^3*Log[1 + (I*a*E^(I*ArcCsc[a + b*x]))/(1 + Sqrt[1 - a^2])] - (3*I)*ArcCsc[a + b*x]^2*PolyLog
[2, E^((-I)*ArcCsc[a + b*x])] + (3*I)*ArcCsc[a + b*x]^2*PolyLog[2, -E^(I*ArcCsc[a + b*x])] - (3*I)*ArcCsc[a +
b*x]^2*PolyLog[2, (I*a*E^(I*ArcCsc[a + b*x]))/(-1 + Sqrt[1 - a^2])] - (3*I)*ArcCsc[a + b*x]^2*PolyLog[2, ((-I)
*a*E^(I*ArcCsc[a + b*x]))/(1 + Sqrt[1 - a^2])] - 6*ArcCsc[a + b*x]*PolyLog[3, E^((-I)*ArcCsc[a + b*x])] - 6*Ar
cCsc[a + b*x]*PolyLog[3, -E^(I*ArcCsc[a + b*x])] + 6*ArcCsc[a + b*x]*PolyLog[3, (I*a*E^(I*ArcCsc[a + b*x]))/(-
1 + Sqrt[1 - a^2])] + 6*ArcCsc[a + b*x]*PolyLog[3, ((-I)*a*E^(I*ArcCsc[a + b*x]))/(1 + Sqrt[1 - a^2])] + (6*I)
*PolyLog[4, E^((-I)*ArcCsc[a + b*x])] - (6*I)*PolyLog[4, -E^(I*ArcCsc[a + b*x])] + (6*I)*PolyLog[4, (I*a*E^(I*
ArcCsc[a + b*x]))/(-1 + Sqrt[1 - a^2])] + (6*I)*PolyLog[4, ((-I)*a*E^(I*ArcCsc[a + b*x]))/(1 + Sqrt[1 - a^2])]

________________________________________________________________________________________

fricas [F]  time = 0.71, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\operatorname {arccsc}\left (b x + a\right )^{3}}{x}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccsc(b*x+a)^3/x,x, algorithm="fricas")

[Out]

integral(arccsc(b*x + a)^3/x, x)

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {arccsc}\left (b x + a\right )^{3}}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccsc(b*x+a)^3/x,x, algorithm="giac")

[Out]

integrate(arccsc(b*x + a)^3/x, x)

________________________________________________________________________________________

maple [F]  time = 2.08, size = 0, normalized size = 0.00 \[ \int \frac {\mathrm {arccsc}\left (b x +a \right )^{3}}{x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(arccsc(b*x+a)^3/x,x)

[Out]

int(arccsc(b*x+a)^3/x,x)

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {arccsc}\left (b x + a\right )^{3}}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccsc(b*x+a)^3/x,x, algorithm="maxima")

[Out]

integrate(arccsc(b*x + a)^3/x, x)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\mathrm {asin}\left (\frac {1}{a+b\,x}\right )}^3}{x} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(asin(1/(a + b*x))^3/x,x)

[Out]

int(asin(1/(a + b*x))^3/x, x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {acsc}^{3}{\left (a + b x \right )}}{x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(acsc(b*x+a)**3/x,x)

[Out]

Integral(acsc(a + b*x)**3/x, x)

________________________________________________________________________________________