3.5 \(\int x \cot ^{-1}(a x) \, dx\)

Optimal. Leaf size=31 \[ -\frac {\tan ^{-1}(a x)}{2 a^2}+\frac {1}{2} x^2 \cot ^{-1}(a x)+\frac {x}{2 a} \]

[Out]

1/2*x/a+1/2*x^2*arccot(a*x)-1/2*arctan(a*x)/a^2

________________________________________________________________________________________

Rubi [A]  time = 0.01, antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {4853, 321, 203} \[ -\frac {\tan ^{-1}(a x)}{2 a^2}+\frac {1}{2} x^2 \cot ^{-1}(a x)+\frac {x}{2 a} \]

Antiderivative was successfully verified.

[In]

Int[x*ArcCot[a*x],x]

[Out]

x/(2*a) + (x^2*ArcCot[a*x])/2 - ArcTan[a*x]/(2*a^2)

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 321

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^n
)^(p + 1))/(b*(m + n*p + 1)), x] - Dist[(a*c^n*(m - n + 1))/(b*(m + n*p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
c, n, m, p, x]

Rule 4853

Int[((a_.) + ArcCot[(c_.)*(x_)]*(b_.))^(p_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*ArcCo
t[c*x])^p)/(d*(m + 1)), x] + Dist[(b*c*p)/(d*(m + 1)), Int[((d*x)^(m + 1)*(a + b*ArcCot[c*x])^(p - 1))/(1 + c^
2*x^2), x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[p, 0] && (EqQ[p, 1] || IntegerQ[m]) && NeQ[m, -1]

Rubi steps

\begin {align*} \int x \cot ^{-1}(a x) \, dx &=\frac {1}{2} x^2 \cot ^{-1}(a x)+\frac {1}{2} a \int \frac {x^2}{1+a^2 x^2} \, dx\\ &=\frac {x}{2 a}+\frac {1}{2} x^2 \cot ^{-1}(a x)-\frac {\int \frac {1}{1+a^2 x^2} \, dx}{2 a}\\ &=\frac {x}{2 a}+\frac {1}{2} x^2 \cot ^{-1}(a x)-\frac {\tan ^{-1}(a x)}{2 a^2}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.00, size = 31, normalized size = 1.00 \[ -\frac {\tan ^{-1}(a x)}{2 a^2}+\frac {1}{2} x^2 \cot ^{-1}(a x)+\frac {x}{2 a} \]

Antiderivative was successfully verified.

[In]

Integrate[x*ArcCot[a*x],x]

[Out]

x/(2*a) + (x^2*ArcCot[a*x])/2 - ArcTan[a*x]/(2*a^2)

________________________________________________________________________________________

fricas [A]  time = 0.68, size = 23, normalized size = 0.74 \[ \frac {a x + {\left (a^{2} x^{2} + 1\right )} \operatorname {arccot}\left (a x\right )}{2 \, a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arccot(a*x),x, algorithm="fricas")

[Out]

1/2*(a*x + (a^2*x^2 + 1)*arccot(a*x))/a^2

________________________________________________________________________________________

giac [A]  time = 0.13, size = 36, normalized size = 1.16 \[ \frac {1}{2} \, {\left (\frac {x^{2} \arctan \left (\frac {1}{a x}\right )}{a} + \frac {x}{a^{2}} + \frac {\arctan \left (\frac {1}{a x}\right )}{a^{3}}\right )} a \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arccot(a*x),x, algorithm="giac")

[Out]

1/2*(x^2*arctan(1/(a*x))/a + x/a^2 + arctan(1/(a*x))/a^3)*a

________________________________________________________________________________________

maple [A]  time = 0.04, size = 26, normalized size = 0.84 \[ \frac {x}{2 a}+\frac {x^{2} \mathrm {arccot}\left (a x \right )}{2}-\frac {\arctan \left (a x \right )}{2 a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*arccot(a*x),x)

[Out]

1/2*x/a+1/2*x^2*arccot(a*x)-1/2*arctan(a*x)/a^2

________________________________________________________________________________________

maxima [A]  time = 0.41, size = 28, normalized size = 0.90 \[ \frac {1}{2} \, x^{2} \operatorname {arccot}\left (a x\right ) + \frac {1}{2} \, a {\left (\frac {x}{a^{2}} - \frac {\arctan \left (a x\right )}{a^{3}}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arccot(a*x),x, algorithm="maxima")

[Out]

1/2*x^2*arccot(a*x) + 1/2*a*(x/a^2 - arctan(a*x)/a^3)

________________________________________________________________________________________

mupad [B]  time = 0.76, size = 39, normalized size = 1.26 \[ \left \{\begin {array}{cl} \frac {\pi \,x^2}{4} & \text {\ if\ \ }a=0\\ \frac {x-\frac {\mathrm {atan}\left (a\,x\right )}{a}}{2\,a}+\frac {x^2\,\mathrm {acot}\left (a\,x\right )}{2} & \text {\ if\ \ }a\neq 0 \end {array}\right . \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*acot(a*x),x)

[Out]

piecewise(a == 0, (x^2*pi)/4, a ~= 0, (x - atan(a*x)/a)/(2*a) + (x^2*acot(a*x))/2)

________________________________________________________________________________________

sympy [A]  time = 0.34, size = 31, normalized size = 1.00 \[ \begin {cases} \frac {x^{2} \operatorname {acot}{\left (a x \right )}}{2} + \frac {x}{2 a} + \frac {\operatorname {acot}{\left (a x \right )}}{2 a^{2}} & \text {for}\: a \neq 0 \\\frac {\pi x^{2}}{4} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*acot(a*x),x)

[Out]

Piecewise((x**2*acot(a*x)/2 + x/(2*a) + acot(a*x)/(2*a**2), Ne(a, 0)), (pi*x**2/4, True))

________________________________________________________________________________________