3.181 \(\int \cot ^{-1}(c-(1+i c) \cot (a+b x)) \, dx\)
Optimal. Leaf size=86 \[ \frac {\text {Li}_2\left (-i c e^{2 i a+2 i b x}\right )}{4 b}+\frac {1}{2} i x \log \left (1+i c e^{2 i a+2 i b x}\right )+x \cot ^{-1}(c-(1+i c) \cot (a+b x))+\frac {b x^2}{2} \]
[Out]
1/2*b*x^2+x*(Pi-arccot(-c+(1+I*c)*cot(b*x+a)))+1/2*I*x*ln(1+I*c*exp(2*I*a+2*I*b*x))+1/4*polylog(2,-I*c*exp(2*I
*a+2*I*b*x))/b
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Rubi [A] time = 0.13, antiderivative size = 86, normalized size of antiderivative = 1.00,
number of steps used = 5, number of rules used = 5, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used =
{5166, 2184, 2190, 2279, 2391} \[ \frac {\text {PolyLog}\left (2,-i c e^{2 i a+2 i b x}\right )}{4 b}+\frac {1}{2} i x \log \left (1+i c e^{2 i a+2 i b x}\right )+x \cot ^{-1}(c-(1+i c) \cot (a+b x))+\frac {b x^2}{2} \]
Antiderivative was successfully verified.
[In]
Int[ArcCot[c - (1 + I*c)*Cot[a + b*x]],x]
[Out]
(b*x^2)/2 + x*ArcCot[c - (1 + I*c)*Cot[a + b*x]] + (I/2)*x*Log[1 + I*c*E^((2*I)*a + (2*I)*b*x)] + PolyLog[2, (
-I)*c*E^((2*I)*a + (2*I)*b*x)]/(4*b)
Rule 2184
Int[((c_.) + (d_.)*(x_))^(m_.)/((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[(c
+ d*x)^(m + 1)/(a*d*(m + 1)), x] - Dist[b/a, Int[((c + d*x)^m*(F^(g*(e + f*x)))^n)/(a + b*(F^(g*(e + f*x)))^n)
, x], x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
Rule 2190
Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/((a_) + (b_.)*((F_)^((g_.)*((e_.) +
(f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[((c + d*x)^m*Log[1 + (b*(F^(g*(e + f*x)))^n)/a])/(b*f*g*n*Log[F]), x]
- Dist[(d*m)/(b*f*g*n*Log[F]), Int[(c + d*x)^(m - 1)*Log[1 + (b*(F^(g*(e + f*x)))^n)/a], x], x] /; FreeQ[{F,
a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
Rule 2279
Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Dist[1/(d*e*n*Log[F]), Subst[Int
[Log[a + b*x]/x, x], x, (F^(e*(c + d*x)))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]
Rule 2391
Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]
Rule 5166
Int[ArcCot[(c_.) + Cot[(a_.) + (b_.)*(x_)]*(d_.)], x_Symbol] :> Simp[x*ArcCot[c + d*Cot[a + b*x]], x] + Dist[I
*b, Int[x/(c - I*d - c*E^(2*I*a + 2*I*b*x)), x], x] /; FreeQ[{a, b, c, d}, x] && EqQ[(c - I*d)^2, -1]
Rubi steps
\begin {align*} \int \cot ^{-1}(c-(1+i c) \cot (a+b x)) \, dx &=x \cot ^{-1}(c-(1+i c) \cot (a+b x))+(i b) \int \frac {x}{-i (-1-i c)+c-c e^{2 i a+2 i b x}} \, dx\\ &=\frac {b x^2}{2}+x \cot ^{-1}(c-(1+i c) \cot (a+b x))+(b c) \int \frac {e^{2 i a+2 i b x} x}{-i (-1-i c)+c-c e^{2 i a+2 i b x}} \, dx\\ &=\frac {b x^2}{2}+x \cot ^{-1}(c-(1+i c) \cot (a+b x))+\frac {1}{2} i x \log \left (1+i c e^{2 i a+2 i b x}\right )-\frac {1}{2} i \int \log \left (1-\frac {c e^{2 i a+2 i b x}}{-i (-1-i c)+c}\right ) \, dx\\ &=\frac {b x^2}{2}+x \cot ^{-1}(c-(1+i c) \cot (a+b x))+\frac {1}{2} i x \log \left (1+i c e^{2 i a+2 i b x}\right )-\frac {\operatorname {Subst}\left (\int \frac {\log \left (1-\frac {c x}{-i (-1-i c)+c}\right )}{x} \, dx,x,e^{2 i a+2 i b x}\right )}{4 b}\\ &=\frac {b x^2}{2}+x \cot ^{-1}(c-(1+i c) \cot (a+b x))+\frac {1}{2} i x \log \left (1+i c e^{2 i a+2 i b x}\right )+\frac {\text {Li}_2\left (-i c e^{2 i a+2 i b x}\right )}{4 b}\\ \end {align*}
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Mathematica [B] time = 2.84, size = 872, normalized size = 10.14 \[ x \cot ^{-1}(c+(-i c-1) \cot (a+b x))-\frac {i x \csc (a+b x) \left (2 b x \log (2 \cos (b x) (\cos (b x)-i \sin (b x)))+i \log \left (\frac {\sec (b x) (\cos (a)-i \sin (a)) ((c-i) \cos (a+b x)+i (c+i) \sin (a+b x))}{2 c}\right ) \log (1-i \tan (b x))-i \log \left (\frac {1}{2} \sec (b x) (\cos (a)+i \sin (a)) ((i c+1) \cos (a+b x)-(c+i) \sin (a+b x))\right ) \log (i \tan (b x)+1)+i \text {Li}_2(i \sin (2 b x)-\cos (2 b x))+i \text {Li}_2\left (\frac {\sec (b x) ((c+i) \cos (a)+(i c+1) \sin (a)) (\cos (a+b x)-i \sin (a+b x))}{2 c}\right )-i \text {Li}_2\left (\frac {1}{2} (\cos (a)+i \sin (a)) ((c+i) \cos (a)+(i c+1) \sin (a)) (\tan (b x)-i)\right )\right ) (\cos (b x)-i \sin (b x)) (\cos (b x)+i \sin (b x))}{(\cot (a+b x)+i) ((c-i) \cos (a+b x)+i (c+i) \sin (a+b x)) \left (\frac {\log \left (\frac {1}{2} \sec (b x) (\cos (a)+i \sin (a)) ((i c+1) \cos (a+b x)-(c+i) \sin (a+b x))\right ) \sec ^2(b x)}{i \tan (b x)+1}+\frac {i \log \left (1-\frac {1}{2} (\cos (a)+i \sin (a)) ((c+i) \cos (a)+(i c+1) \sin (a)) (\tan (b x)-i)\right ) \sec ^2(b x)}{\tan (b x)-i}+\frac {i \log \left (\frac {\sec (b x) (\cos (a)-i \sin (a)) ((c-i) \cos (a+b x)+i (c+i) \sin (a+b x))}{2 c}\right ) \sec ^2(b x)}{\tan (b x)+i}-2 i b x-\log \left (1-\frac {\sec (b x) ((c+i) \cos (a)+(i c+1) \sin (a)) (\cos (a+b x)-i \sin (a+b x))}{2 c}\right )-2 b x \tan (b x)-i \log \left (1-\frac {\sec (b x) ((c+i) \cos (a)+(i c+1) \sin (a)) (\cos (a+b x)-i \sin (a+b x))}{2 c}\right ) \tan (b x)+i \log (1-i \tan (b x)) \tan (b x)-i \log (i \tan (b x)+1) \tan (b x)-\frac {\log (1-i \tan (b x)) ((c+i) \cos (a+b x)+(i c+1) \sin (a+b x))}{(c-i) \cos (a+b x)+i (c+i) \sin (a+b x)}+\frac {\log (i \tan (b x)+1) ((c+i) \cos (a+b x)+(i c+1) \sin (a+b x))}{(c-i) \cos (a+b x)+i (c+i) \sin (a+b x)}\right )} \]
Warning: Unable to verify antiderivative.
[In]
Integrate[ArcCot[c - (1 + I*c)*Cot[a + b*x]],x]
[Out]
x*ArcCot[c + (-1 - I*c)*Cot[a + b*x]] - (I*x*Csc[a + b*x]*(2*b*x*Log[2*Cos[b*x]*(Cos[b*x] - I*Sin[b*x])] + I*L
og[(Sec[b*x]*(Cos[a] - I*Sin[a])*((-I + c)*Cos[a + b*x] + I*(I + c)*Sin[a + b*x]))/(2*c)]*Log[1 - I*Tan[b*x]]
- I*Log[(Sec[b*x]*(Cos[a] + I*Sin[a])*((1 + I*c)*Cos[a + b*x] - (I + c)*Sin[a + b*x]))/2]*Log[1 + I*Tan[b*x]]
+ I*PolyLog[2, -Cos[2*b*x] + I*Sin[2*b*x]] + I*PolyLog[2, (Sec[b*x]*((I + c)*Cos[a] + (1 + I*c)*Sin[a])*(Cos[a
+ b*x] - I*Sin[a + b*x]))/(2*c)] - I*PolyLog[2, ((Cos[a] + I*Sin[a])*((I + c)*Cos[a] + (1 + I*c)*Sin[a])*(-I
+ Tan[b*x]))/2])*(Cos[b*x] - I*Sin[b*x])*(Cos[b*x] + I*Sin[b*x]))/((I + Cot[a + b*x])*((-I + c)*Cos[a + b*x] +
I*(I + c)*Sin[a + b*x])*((-2*I)*b*x - Log[1 - (Sec[b*x]*((I + c)*Cos[a] + (1 + I*c)*Sin[a])*(Cos[a + b*x] - I
*Sin[a + b*x]))/(2*c)] - (Log[1 - I*Tan[b*x]]*((I + c)*Cos[a + b*x] + (1 + I*c)*Sin[a + b*x]))/((-I + c)*Cos[a
+ b*x] + I*(I + c)*Sin[a + b*x]) + (Log[1 + I*Tan[b*x]]*((I + c)*Cos[a + b*x] + (1 + I*c)*Sin[a + b*x]))/((-I
+ c)*Cos[a + b*x] + I*(I + c)*Sin[a + b*x]) + (Log[(Sec[b*x]*(Cos[a] + I*Sin[a])*((1 + I*c)*Cos[a + b*x] - (I
+ c)*Sin[a + b*x]))/2]*Sec[b*x]^2)/(1 + I*Tan[b*x]) - 2*b*x*Tan[b*x] - I*Log[1 - (Sec[b*x]*((I + c)*Cos[a] +
(1 + I*c)*Sin[a])*(Cos[a + b*x] - I*Sin[a + b*x]))/(2*c)]*Tan[b*x] + I*Log[1 - I*Tan[b*x]]*Tan[b*x] - I*Log[1
+ I*Tan[b*x]]*Tan[b*x] + (I*Log[1 - ((Cos[a] + I*Sin[a])*((I + c)*Cos[a] + (1 + I*c)*Sin[a])*(-I + Tan[b*x]))/
2]*Sec[b*x]^2)/(-I + Tan[b*x]) + (I*Log[(Sec[b*x]*(Cos[a] - I*Sin[a])*((-I + c)*Cos[a + b*x] + I*(I + c)*Sin[a
+ b*x]))/(2*c)]*Sec[b*x]^2)/(I + Tan[b*x])))
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fricas [A] time = 0.82, size = 115, normalized size = 1.34 \[ \frac {2 \, b^{2} x^{2} + 4 \, \pi b x + 2 i \, b x \log \left (\frac {{\left (c - i\right )} e^{\left (2 i \, b x + 2 i \, a\right )}}{c e^{\left (2 i \, b x + 2 i \, a\right )} - i}\right ) - 2 \, a^{2} + {\left (2 i \, b x + 2 i \, a\right )} \log \left (i \, c e^{\left (2 i \, b x + 2 i \, a\right )} + 1\right ) - 2 i \, a \log \left (\frac {c e^{\left (2 i \, b x + 2 i \, a\right )} - i}{c}\right ) + {\rm Li}_2\left (-i \, c e^{\left (2 i \, b x + 2 i \, a\right )}\right )}{4 \, b} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(pi-arccot(-c+(1+I*c)*cot(b*x+a)),x, algorithm="fricas")
[Out]
1/4*(2*b^2*x^2 + 4*pi*b*x + 2*I*b*x*log((c - I)*e^(2*I*b*x + 2*I*a)/(c*e^(2*I*b*x + 2*I*a) - I)) - 2*a^2 + (2*
I*b*x + 2*I*a)*log(I*c*e^(2*I*b*x + 2*I*a) + 1) - 2*I*a*log((c*e^(2*I*b*x + 2*I*a) - I)/c) + dilog(-I*c*e^(2*I
*b*x + 2*I*a)))/b
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \pi - \operatorname {arccot}\left ({\left (i \, c + 1\right )} \cot \left (b x + a\right ) - c\right )\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(pi-arccot(-c+(1+I*c)*cot(b*x+a)),x, algorithm="giac")
[Out]
integrate(pi - arccot((I*c + 1)*cot(b*x + a) - c), x)
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maple [B] time = 0.76, size = 1756, normalized size = 20.42 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(Pi-arccot(-c+(1+I*c)*cot(b*x+a)),x)
[Out]
1/(1+I*c)/b*arccot(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(-c-(1+I*c)*cot(b*x+a)+I)+1/4/(1+I*c)/b/(I-c)*ln(I-c+(1+
I*c)*cot(b*x+a))^2*c+1/2/(1+I*c)/b/(I-c)*dilog(-1/2*I*(I-c+(1+I*c)*cot(b*x+a)))*c+1/2/(1+I*c)/b/(I-c)*dilog(1/
2*(c-(1+I*c)*cot(b*x+a)+I)/c)*c-1/2/(1+I*c)/b/(I-c)*dilog((c-(1+I*c)*cot(b*x+a)-I)/(-2*I+2*c))*c-1/4*I/(1+I*c)
/b/(I-c)*dilog(1/2*(c-(1+I*c)*cot(b*x+a)+I)/c)+1/4*I/(1+I*c)/b/(I-c)*dilog((c-(1+I*c)*cot(b*x+a)-I)/(-2*I+2*c)
)-1/8*I/(1+I*c)/b/(I-c)*ln(I-c+(1+I*c)*cot(b*x+a))^2+1/(1+I*c)/b*arccot(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(I-
c+(1+I*c)*cot(b*x+a))*c^2-1/(1+I*c)/b*arccot(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(-c-(1+I*c)*cot(b*x+a)+I)*c^2+
1/4*I/(1+I*c)/b/(I-c)*dilog(1/2*(c-(1+I*c)*cot(b*x+a)+I)/c)*c^2-1/4*I/(1+I*c)/b/(I-c)*dilog((c-(1+I*c)*cot(b*x
+a)-I)/(-2*I+2*c))*c^2-1/(1+I*c)/b*arccot(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(I-c+(1+I*c)*cot(b*x+a))+1/4*I/(1
+I*c)/b/(I-c)*dilog(-1/2*I*(I-c+(1+I*c)*cot(b*x+a)))*c^2+1/4*I/(1+I*c)/b/(I-c)*ln(-c-(1+I*c)*cot(b*x+a)+I)*ln(
(c-(1+I*c)*cot(b*x+a)-I)/(-2*I+2*c))+1/4*I/(1+I*c)/b/(I-c)*ln(I-c+(1+I*c)*cot(b*x+a))*ln(-1/2*I*(c-(1+I*c)*cot
(b*x+a)+I))-1/4*I/(1+I*c)/b/(I-c)*ln(-1/2*I*(I-c+(1+I*c)*cot(b*x+a)))*ln(-1/2*I*(c-(1+I*c)*cot(b*x+a)+I))-1/4*
I/(1+I*c)/b/(I-c)*ln(-c-(1+I*c)*cot(b*x+a)+I)*ln(1/2*(c-(1+I*c)*cot(b*x+a)+I)/c)-1/2/(1+I*c)/b/(I-c)*ln(-c-(1+
I*c)*cot(b*x+a)+I)*ln((c-(1+I*c)*cot(b*x+a)-I)/(-2*I+2*c))*c+Pi*x+1/8*I/(1+I*c)/b/(I-c)*ln(I-c+(1+I*c)*cot(b*x
+a))^2*c^2+1/2/(1+I*c)/b/(I-c)*ln(-1/2*I*(I-c+(1+I*c)*cot(b*x+a)))*ln(-1/2*I*(c-(1+I*c)*cot(b*x+a)+I))*c-1/2/(
1+I*c)/b/(I-c)*ln(I-c+(1+I*c)*cot(b*x+a))*ln(-1/2*I*(c-(1+I*c)*cot(b*x+a)+I))*c+1/2/(1+I*c)/b/(I-c)*ln(-c-(1+I
*c)*cot(b*x+a)+I)*ln(1/2*(c-(1+I*c)*cot(b*x+a)+I)/c)*c-2*I/(1+I*c)/b*arccot(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*l
n(I-c+(1+I*c)*cot(b*x+a))*c+2*I/(1+I*c)/b*arccot(-c+(1+I*c)*cot(b*x+a))/(2*I-2*c)*ln(-c-(1+I*c)*cot(b*x+a)+I)*
c-1/4*I/(1+I*c)/b/(I-c)*ln(I-c+(1+I*c)*cot(b*x+a))*ln(-1/2*I*(c-(1+I*c)*cot(b*x+a)+I))*c^2+1/4*I/(1+I*c)/b/(I-
c)*ln(-1/2*I*(I-c+(1+I*c)*cot(b*x+a)))*ln(-1/2*I*(c-(1+I*c)*cot(b*x+a)+I))*c^2+1/4*I/(1+I*c)/b/(I-c)*ln(-c-(1+
I*c)*cot(b*x+a)+I)*ln(1/2*(c-(1+I*c)*cot(b*x+a)+I)/c)*c^2-1/4*I/(1+I*c)/b/(I-c)*ln(-c-(1+I*c)*cot(b*x+a)+I)*ln
((c-(1+I*c)*cot(b*x+a)-I)/(-2*I+2*c))*c^2-1/4*I/(1+I*c)/b/(I-c)*dilog(-1/2*I*(I-c+(1+I*c)*cot(b*x+a)))
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(pi-arccot(-c+(1+I*c)*cot(b*x+a)),x, algorithm="maxima")
[Out]
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(c-1>0)', see `assume?` for mor
e details)Is c-1 zero or nonzero?
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \Pi +\mathrm {acot}\left (c-\mathrm {cot}\left (a+b\,x\right )\,\left (1+c\,1{}\mathrm {i}\right )\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(Pi + acot(c - cot(a + b*x)*(c*1i + 1)),x)
[Out]
int(Pi + acot(c - cot(a + b*x)*(c*1i + 1)), x)
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sympy [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: CoercionFailed} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(pi-acot(-c+(1+I*c)*cot(b*x+a)),x)
[Out]
Exception raised: CoercionFailed
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