Optimal. Leaf size=205 \[ -\frac {\sqrt [4]{1+i (a+b x)} (a+b x+i)}{(a+i) x \sqrt [4]{1-i (a+b x)}}+\frac {i b \tan ^{-1}\left (\frac {\sqrt [4]{a+i} \sqrt [4]{1+i (a+b x)}}{\sqrt [4]{-a+i} \sqrt [4]{1-i (a+b x)}}\right )}{(-a+i)^{3/4} (a+i)^{5/4}}+\frac {i b \tanh ^{-1}\left (\frac {\sqrt [4]{a+i} \sqrt [4]{1+i (a+b x)}}{\sqrt [4]{-a+i} \sqrt [4]{1-i (a+b x)}}\right )}{(-a+i)^{3/4} (a+i)^{5/4}} \]
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Rubi [A] time = 0.10, antiderivative size = 205, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {5094, 263, 288, 212, 208, 205} \[ -\frac {\sqrt [4]{1+i (a+b x)} (a+b x+i)}{(a+i) x \sqrt [4]{1-i (a+b x)}}+\frac {i b \tan ^{-1}\left (\frac {\sqrt [4]{a+i} \sqrt [4]{1+i (a+b x)}}{\sqrt [4]{-a+i} \sqrt [4]{1-i (a+b x)}}\right )}{(-a+i)^{3/4} (a+i)^{5/4}}+\frac {i b \tanh ^{-1}\left (\frac {\sqrt [4]{a+i} \sqrt [4]{1+i (a+b x)}}{\sqrt [4]{-a+i} \sqrt [4]{1-i (a+b x)}}\right )}{(-a+i)^{3/4} (a+i)^{5/4}} \]
Antiderivative was successfully verified.
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Rule 205
Rule 208
Rule 212
Rule 263
Rule 288
Rule 5094
Rubi steps
\begin {align*} \int \frac {e^{\frac {1}{2} i \tan ^{-1}(a+b x)}}{x^2} \, dx &=(8 i b) \operatorname {Subst}\left (\int \frac {1}{\left (1-i a-\frac {1+i a}{x^4}\right )^2 x^4} \, dx,x,\frac {\sqrt [4]{1+i (a+b x)}}{\sqrt [4]{1-i (a+b x)}}\right )\\ &=(8 i b) \operatorname {Subst}\left (\int \frac {x^4}{\left (-1-i a+(1-i a) x^4\right )^2} \, dx,x,\frac {\sqrt [4]{1+i (a+b x)}}{\sqrt [4]{1-i (a+b x)}}\right )\\ &=-\frac {(i+a+b x) \sqrt [4]{1+i (a+b x)}}{(i+a) x \sqrt [4]{1-i (a+b x)}}-\frac {(2 b) \operatorname {Subst}\left (\int \frac {1}{-1-i a+(1-i a) x^4} \, dx,x,\frac {\sqrt [4]{1+i (a+b x)}}{\sqrt [4]{1-i (a+b x)}}\right )}{i+a}\\ &=-\frac {(i+a+b x) \sqrt [4]{1+i (a+b x)}}{(i+a) x \sqrt [4]{1-i (a+b x)}}+\frac {b \operatorname {Subst}\left (\int \frac {1}{\sqrt {i-a}-\sqrt {i+a} x^2} \, dx,x,\frac {\sqrt [4]{1+i (a+b x)}}{\sqrt [4]{1-i (a+b x)}}\right )}{\sqrt {i-a} (1-i a)}+\frac {b \operatorname {Subst}\left (\int \frac {1}{\sqrt {i-a}+\sqrt {i+a} x^2} \, dx,x,\frac {\sqrt [4]{1+i (a+b x)}}{\sqrt [4]{1-i (a+b x)}}\right )}{\sqrt {i-a} (1-i a)}\\ &=-\frac {(i+a+b x) \sqrt [4]{1+i (a+b x)}}{(i+a) x \sqrt [4]{1-i (a+b x)}}+\frac {i b \tan ^{-1}\left (\frac {\sqrt [4]{i+a} \sqrt [4]{1+i (a+b x)}}{\sqrt [4]{i-a} \sqrt [4]{1-i (a+b x)}}\right )}{(i-a)^{3/4} (i+a)^{5/4}}+\frac {i b \tanh ^{-1}\left (\frac {\sqrt [4]{i+a} \sqrt [4]{1+i (a+b x)}}{\sqrt [4]{i-a} \sqrt [4]{1-i (a+b x)}}\right )}{(i-a)^{3/4} (i+a)^{5/4}}\\ \end {align*}
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Mathematica [C] time = 0.03, size = 110, normalized size = 0.54 \[ \frac {(-i (a+b x+i))^{3/4} \left (2 i b x \, _2F_1\left (\frac {3}{4},1;\frac {7}{4};\frac {a^2+b x a-i b x+1}{a^2+b x a+i b x+1}\right )+3 (a+i) (a+b x-i)\right )}{3 (a+i)^2 x (i a+i b x+1)^{3/4}} \]
Warning: Unable to verify antiderivative.
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fricas [B] time = 0.61, size = 612, normalized size = 2.99 \[ \frac {\left (-\frac {b^{4}}{16 \, a^{8} + 32 i \, a^{7} + 32 \, a^{6} + 96 i \, a^{5} + 96 i \, a^{3} - 32 \, a^{2} + 32 i \, a - 16}\right )^{\frac {1}{4}} {\left (-i \, a + 1\right )} x \log \left (\frac {b \sqrt {\frac {i \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}} + 2 \, \left (-\frac {b^{4}}{16 \, a^{8} + 32 i \, a^{7} + 32 \, a^{6} + 96 i \, a^{5} + 96 i \, a^{3} - 32 \, a^{2} + 32 i \, a - 16}\right )^{\frac {1}{4}} {\left (a^{2} + 1\right )}}{b}\right ) + \left (-\frac {b^{4}}{16 \, a^{8} + 32 i \, a^{7} + 32 \, a^{6} + 96 i \, a^{5} + 96 i \, a^{3} - 32 \, a^{2} + 32 i \, a - 16}\right )^{\frac {1}{4}} {\left (i \, a - 1\right )} x \log \left (\frac {b \sqrt {\frac {i \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}} - 2 \, \left (-\frac {b^{4}}{16 \, a^{8} + 32 i \, a^{7} + 32 \, a^{6} + 96 i \, a^{5} + 96 i \, a^{3} - 32 \, a^{2} + 32 i \, a - 16}\right )^{\frac {1}{4}} {\left (a^{2} + 1\right )}}{b}\right ) + \left (-\frac {b^{4}}{16 \, a^{8} + 32 i \, a^{7} + 32 \, a^{6} + 96 i \, a^{5} + 96 i \, a^{3} - 32 \, a^{2} + 32 i \, a - 16}\right )^{\frac {1}{4}} {\left (a + i\right )} x \log \left (\frac {b \sqrt {\frac {i \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}} + \left (-\frac {b^{4}}{16 \, a^{8} + 32 i \, a^{7} + 32 \, a^{6} + 96 i \, a^{5} + 96 i \, a^{3} - 32 \, a^{2} + 32 i \, a - 16}\right )^{\frac {1}{4}} {\left (2 i \, a^{2} + 2 i\right )}}{b}\right ) - \left (-\frac {b^{4}}{16 \, a^{8} + 32 i \, a^{7} + 32 \, a^{6} + 96 i \, a^{5} + 96 i \, a^{3} - 32 \, a^{2} + 32 i \, a - 16}\right )^{\frac {1}{4}} {\left (a + i\right )} x \log \left (\frac {b \sqrt {\frac {i \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}} + \left (-\frac {b^{4}}{16 \, a^{8} + 32 i \, a^{7} + 32 \, a^{6} + 96 i \, a^{5} + 96 i \, a^{3} - 32 \, a^{2} + 32 i \, a - 16}\right )^{\frac {1}{4}} {\left (-2 i \, a^{2} - 2 i\right )}}{b}\right ) - {\left (b x + a + i\right )} \sqrt {\frac {i \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b x + a + i}}}{{\left (a + i\right )} x} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.17, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {\frac {1+i \left (b x +a \right )}{\sqrt {1+\left (b x +a \right )^{2}}}}}{x^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {\frac {i \, b x + i \, a + 1}{\sqrt {{\left (b x + a\right )}^{2} + 1}}}}{x^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\sqrt {\frac {1+a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}}{\sqrt {{\left (a+b\,x\right )}^2+1}}}}{x^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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