Optimal. Leaf size=83 \[ -\frac {2 b^2 \log (x)}{(1+i a)^3}+\frac {2 b^2 \log (-a-b x+i)}{(1+i a)^3}-\frac {2 i b}{(-a+i)^2 x}+\frac {-a-i}{2 (-a+i) x^2} \]
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Rubi [A] time = 0.05, antiderivative size = 81, normalized size of antiderivative = 0.98, number of steps used = 3, number of rules used = 2, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {5095, 77} \[ -\frac {2 b^2 \log (x)}{(1+i a)^3}+\frac {2 b^2 \log (-a-b x+i)}{(1+i a)^3}-\frac {2 i b}{(-a+i)^2 x}-\frac {a+i}{2 (-a+i) x^2} \]
Antiderivative was successfully verified.
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Rule 77
Rule 5095
Rubi steps
\begin {align*} \int \frac {e^{-2 i \tan ^{-1}(a+b x)}}{x^3} \, dx &=\int \frac {1-i a-i b x}{x^3 (1+i a+i b x)} \, dx\\ &=\int \left (\frac {-i-a}{(-i+a) x^3}+\frac {2 i b}{(-i+a)^2 x^2}-\frac {2 i b^2}{(-i+a)^3 x}+\frac {2 i b^3}{(-i+a)^3 (-i+a+b x)}\right ) \, dx\\ &=-\frac {i+a}{2 (i-a) x^2}-\frac {2 i b}{(i-a)^2 x}-\frac {2 b^2 \log (x)}{(1+i a)^3}+\frac {2 b^2 \log (i-a-b x)}{(1+i a)^3}\\ \end {align*}
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Mathematica [A] time = 0.04, size = 66, normalized size = 0.80 \[ \frac {(a-i) \left (a^2-4 i b x+1\right )+4 i b^2 x^2 \log (-a-b x+i)-4 i b^2 x^2 \log (x)}{2 (a-i)^3 x^2} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.46, size = 70, normalized size = 0.84 \[ \frac {-4 i \, b^{2} x^{2} \log \relax (x) + 4 i \, b^{2} x^{2} \log \left (\frac {b x + a - i}{b}\right ) + a^{3} - 4 \, {\left (i \, a + 1\right )} b x - i \, a^{2} + a - i}{{\left (2 \, a^{3} - 6 i \, a^{2} - 6 \, a + 2 i\right )} x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.14, size = 157, normalized size = 1.89 \[ \frac {2 \, b^{3} \log \left (-\frac {a i}{b i x + a i + 1} + \frac {i^{2}}{b i x + a i + 1} + 1\right )}{a^{3} b i + 3 \, a^{2} b - 3 \, a b i - b} - \frac {\frac {2 \, {\left (a b^{3} i - 3 \, b^{3}\right )} i^{2}}{{\left (b i x + a i + 1\right )} b} + \frac {a b^{2} i - 5 \, b^{2}}{a i + 1}}{2 \, {\left (a - i\right )}^{2} {\left (\frac {a i}{b i x + a i + 1} - \frac {i^{2}}{b i x + a i + 1} - 1\right )}^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.06, size = 246, normalized size = 2.96 \[ -\frac {2 i b^{2} \ln \relax (x ) a}{\left (i-a \right )^{4}}-\frac {2 b^{2} \ln \relax (x )}{\left (i-a \right )^{4}}-\frac {2 i b \,a^{2}}{\left (i-a \right )^{4} x}+\frac {2 i b}{\left (i-a \right )^{4} x}-\frac {4 b a}{\left (i-a \right )^{4} x}-\frac {i a^{3}}{\left (i-a \right )^{4} x^{2}}+\frac {a^{4}}{2 \left (i-a \right )^{4} x^{2}}-\frac {i a}{\left (i-a \right )^{4} x^{2}}-\frac {1}{2 \left (i-a \right )^{4} x^{2}}+\frac {i b^{2} \ln \left (b^{2} x^{2}+2 a b x +a^{2}+1\right ) a}{\left (i-a \right )^{4}}+\frac {b^{2} \ln \left (b^{2} x^{2}+2 a b x +a^{2}+1\right )}{\left (i-a \right )^{4}}-\frac {2 b^{2} \arctan \left (b x +a \right ) a}{\left (i-a \right )^{4}}+\frac {2 i b^{2} \arctan \left (b x +a \right )}{\left (i-a \right )^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.34, size = 163, normalized size = 1.96 \[ -\frac {2 \, {\left (-i \, a - 1\right )} b^{2} \log \left (i \, b x + i \, a + 1\right )}{a^{4} - 4 i \, a^{3} - 6 \, a^{2} + 4 i \, a + 1} - \frac {2 \, {\left (i \, a + 1\right )} b^{2} \log \relax (x)}{a^{4} - 4 i \, a^{3} - 6 \, a^{2} + 4 i \, a + 1} + \frac {4 \, {\left (-i \, a - 1\right )} b^{2} x^{2} + a^{4} - 2 i \, a^{3} + {\left (a^{3} - 5 i \, a^{2} - 7 \, a + 3 i\right )} b x - 2 i \, a - 1}{{\left (2 \, a^{3} - 6 i \, a^{2} - 6 \, a + 2 i\right )} b x^{3} + {\left (2 \, a^{4} - 8 i \, a^{3} - 12 \, a^{2} + 8 i \, a + 2\right )} x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.70, size = 156, normalized size = 1.88 \[ \frac {\frac {a+1{}\mathrm {i}}{2\,\left (a-\mathrm {i}\right )}-\frac {b\,x\,2{}\mathrm {i}}{{\left (a-\mathrm {i}\right )}^2}}{x^2}-\frac {b^2\,\mathrm {atanh}\left (\frac {-a^3+a^2\,3{}\mathrm {i}+3\,a-\mathrm {i}}{{\left (a-\mathrm {i}\right )}^3}-\frac {x\,\left (2\,a^8\,b^2+8\,a^6\,b^2+12\,a^4\,b^2+8\,a^2\,b^2+2\,b^2\right )}{{\left (a-\mathrm {i}\right )}^3\,\left (b\,a^6+2{}\mathrm {i}\,b\,a^5+b\,a^4+4{}\mathrm {i}\,b\,a^3-b\,a^2+2{}\mathrm {i}\,b\,a-b\right )}\right )\,4{}\mathrm {i}}{{\left (a-\mathrm {i}\right )}^3} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 0.96, size = 226, normalized size = 2.72 \[ - \frac {2 i b^{2} \log {\left (- \frac {2 a^{4} b^{2}}{\left (a - i\right )^{3}} + \frac {8 i a^{3} b^{2}}{\left (a - i\right )^{3}} + \frac {12 a^{2} b^{2}}{\left (a - i\right )^{3}} + 2 a b^{2} - \frac {8 i a b^{2}}{\left (a - i\right )^{3}} + 4 b^{3} x - 2 i b^{2} - \frac {2 b^{2}}{\left (a - i\right )^{3}} \right )}}{\left (a - i\right )^{3}} + \frac {2 i b^{2} \log {\left (\frac {2 a^{4} b^{2}}{\left (a - i\right )^{3}} - \frac {8 i a^{3} b^{2}}{\left (a - i\right )^{3}} - \frac {12 a^{2} b^{2}}{\left (a - i\right )^{3}} + 2 a b^{2} + \frac {8 i a b^{2}}{\left (a - i\right )^{3}} + 4 b^{3} x - 2 i b^{2} + \frac {2 b^{2}}{\left (a - i\right )^{3}} \right )}}{\left (a - i\right )^{3}} - \frac {a^{2} - 4 i b x + 1}{x^{2} \left (- 2 a^{2} + 4 i a + 2\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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