3.27 \(\int \cos ^{-1}(a+b x) \, dx\)

Optimal. Leaf size=36 \[ \frac {(a+b x) \cos ^{-1}(a+b x)}{b}-\frac {\sqrt {1-(a+b x)^2}}{b} \]

[Out]

(b*x+a)*arccos(b*x+a)/b-(1-(b*x+a)^2)^(1/2)/b

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Rubi [A]  time = 0.02, antiderivative size = 36, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {4804, 4620, 261} \[ \frac {(a+b x) \cos ^{-1}(a+b x)}{b}-\frac {\sqrt {1-(a+b x)^2}}{b} \]

Antiderivative was successfully verified.

[In]

Int[ArcCos[a + b*x],x]

[Out]

-(Sqrt[1 - (a + b*x)^2]/b) + ((a + b*x)*ArcCos[a + b*x])/b

Rule 261

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a + b*x^n)^(p + 1)/(b*n*(p + 1)), x] /; FreeQ
[{a, b, m, n, p}, x] && EqQ[m, n - 1] && NeQ[p, -1]

Rule 4620

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.), x_Symbol] :> Simp[x*(a + b*ArcCos[c*x])^n, x] + Dist[b*c*n, Int[
(x*(a + b*ArcCos[c*x])^(n - 1))/Sqrt[1 - c^2*x^2], x], x] /; FreeQ[{a, b, c}, x] && GtQ[n, 0]

Rule 4804

Int[((a_.) + ArcCos[(c_) + (d_.)*(x_)]*(b_.))^(n_.), x_Symbol] :> Dist[1/d, Subst[Int[(a + b*ArcCos[x])^n, x],
x, c + d*x], x] /; FreeQ[{a, b, c, d, n}, x]

Rubi steps

\begin {align*} \int \cos ^{-1}(a+b x) \, dx &=\frac {\operatorname {Subst}\left (\int \cos ^{-1}(x) \, dx,x,a+b x\right )}{b}\\ &=\frac {(a+b x) \cos ^{-1}(a+b x)}{b}+\frac {\operatorname {Subst}\left (\int \frac {x}{\sqrt {1-x^2}} \, dx,x,a+b x\right )}{b}\\ &=-\frac {\sqrt {1-(a+b x)^2}}{b}+\frac {(a+b x) \cos ^{-1}(a+b x)}{b}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 47, normalized size = 1.31 \[ x \cos ^{-1}(a+b x)-\frac {\sqrt {-a^2-2 a b x-b^2 x^2+1}+a \sin ^{-1}(a+b x)}{b} \]

Antiderivative was successfully verified.

[In]

Integrate[ArcCos[a + b*x],x]

[Out]

x*ArcCos[a + b*x] - (Sqrt[1 - a^2 - 2*a*b*x - b^2*x^2] + a*ArcSin[a + b*x])/b

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fricas [A]  time = 0.47, size = 41, normalized size = 1.14 \[ \frac {{\left (b x + a\right )} \arccos \left (b x + a\right ) - \sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccos(b*x+a),x, algorithm="fricas")

[Out]

((b*x + a)*arccos(b*x + a) - sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1))/b

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giac [A]  time = 1.98, size = 32, normalized size = 0.89 \[ \frac {{\left (b x + a\right )} \arccos \left (b x + a\right ) - \sqrt {-{\left (b x + a\right )}^{2} + 1}}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccos(b*x+a),x, algorithm="giac")

[Out]

((b*x + a)*arccos(b*x + a) - sqrt(-(b*x + a)^2 + 1))/b

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maple [A]  time = 0.00, size = 33, normalized size = 0.92 \[ \frac {\left (b x +a \right ) \arccos \left (b x +a \right )-\sqrt {1-\left (b x +a \right )^{2}}}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(arccos(b*x+a),x)

[Out]

1/b*((b*x+a)*arccos(b*x+a)-(1-(b*x+a)^2)^(1/2))

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maxima [A]  time = 0.42, size = 32, normalized size = 0.89 \[ \frac {{\left (b x + a\right )} \arccos \left (b x + a\right ) - \sqrt {-{\left (b x + a\right )}^{2} + 1}}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccos(b*x+a),x, algorithm="maxima")

[Out]

((b*x + a)*arccos(b*x + a) - sqrt(-(b*x + a)^2 + 1))/b

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mupad [B]  time = 0.54, size = 88, normalized size = 2.44 \[ x\,\mathrm {acos}\left (a+b\,x\right )-\frac {\sqrt {-a^2-2\,a\,b\,x-b^2\,x^2+1}}{b}-\frac {a\,\ln \left (\sqrt {-a^2-2\,a\,b\,x-b^2\,x^2+1}-\frac {x\,b^2+a\,b}{\sqrt {-b^2}}\right )}{\sqrt {-b^2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(acos(a + b*x),x)

[Out]

x*acos(a + b*x) - (1 - b^2*x^2 - 2*a*b*x - a^2)^(1/2)/b - (a*log((1 - b^2*x^2 - 2*a*b*x - a^2)^(1/2) - (a*b +
b^2*x)/(-b^2)^(1/2)))/(-b^2)^(1/2)

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sympy [A]  time = 0.15, size = 46, normalized size = 1.28 \[ \begin {cases} \frac {a \operatorname {acos}{\left (a + b x \right )}}{b} + x \operatorname {acos}{\left (a + b x \right )} - \frac {\sqrt {- a^{2} - 2 a b x - b^{2} x^{2} + 1}}{b} & \text {for}\: b \neq 0 \\x \operatorname {acos}{\relax (a )} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(acos(b*x+a),x)

[Out]

Piecewise((a*acos(a + b*x)/b + x*acos(a + b*x) - sqrt(-a**2 - 2*a*b*x - b**2*x**2 + 1)/b, Ne(b, 0)), (x*acos(a
), True))

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