Optimal. Leaf size=247 \[ \frac {3 \sqrt {\pi } b^{3/2} x \left (\cos \left (\frac {a}{2 b}\right )-\sin \left (\frac {a}{2 b}\right )\right ) C\left (\frac {\sqrt {a+b \sin ^{-1}\left (d x^2+1\right )}}{\sqrt {b} \sqrt {\pi }}\right )}{\cos \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )-\sin \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )}+\frac {3 \sqrt {\pi } b^{3/2} x \left (\sin \left (\frac {a}{2 b}\right )+\cos \left (\frac {a}{2 b}\right )\right ) S\left (\frac {\sqrt {a+b \sin ^{-1}\left (d x^2+1\right )}}{\sqrt {b} \sqrt {\pi }}\right )}{\cos \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )-\sin \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )}+\frac {3 b \sqrt {-d^2 x^4-2 d x^2} \sqrt {a+b \sin ^{-1}\left (d x^2+1\right )}}{d x}+x \left (a+b \sin ^{-1}\left (d x^2+1\right )\right )^{3/2} \]
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Rubi [A] time = 0.08, antiderivative size = 247, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {4814, 4819} \[ \frac {3 \sqrt {\pi } b^{3/2} x \left (\cos \left (\frac {a}{2 b}\right )-\sin \left (\frac {a}{2 b}\right )\right ) \text {FresnelC}\left (\frac {\sqrt {a+b \sin ^{-1}\left (d x^2+1\right )}}{\sqrt {\pi } \sqrt {b}}\right )}{\cos \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )-\sin \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )}+\frac {3 \sqrt {\pi } b^{3/2} x \left (\sin \left (\frac {a}{2 b}\right )+\cos \left (\frac {a}{2 b}\right )\right ) S\left (\frac {\sqrt {a+b \sin ^{-1}\left (d x^2+1\right )}}{\sqrt {b} \sqrt {\pi }}\right )}{\cos \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )-\sin \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )}+\frac {3 b \sqrt {-d^2 x^4-2 d x^2} \sqrt {a+b \sin ^{-1}\left (d x^2+1\right )}}{d x}+x \left (a+b \sin ^{-1}\left (d x^2+1\right )\right )^{3/2} \]
Antiderivative was successfully verified.
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Rule 4814
Rule 4819
Rubi steps
\begin {align*} \int \left (a+b \sin ^{-1}\left (1+d x^2\right )\right )^{3/2} \, dx &=\frac {3 b \sqrt {-2 d x^2-d^2 x^4} \sqrt {a+b \sin ^{-1}\left (1+d x^2\right )}}{d x}+x \left (a+b \sin ^{-1}\left (1+d x^2\right )\right )^{3/2}-\left (3 b^2\right ) \int \frac {1}{\sqrt {a+b \sin ^{-1}\left (1+d x^2\right )}} \, dx\\ &=\frac {3 b \sqrt {-2 d x^2-d^2 x^4} \sqrt {a+b \sin ^{-1}\left (1+d x^2\right )}}{d x}+x \left (a+b \sin ^{-1}\left (1+d x^2\right )\right )^{3/2}+\frac {3 b^{3/2} \sqrt {\pi } x C\left (\frac {\sqrt {a+b \sin ^{-1}\left (1+d x^2\right )}}{\sqrt {b} \sqrt {\pi }}\right ) \left (\cos \left (\frac {a}{2 b}\right )-\sin \left (\frac {a}{2 b}\right )\right )}{\cos \left (\frac {1}{2} \sin ^{-1}\left (1+d x^2\right )\right )-\sin \left (\frac {1}{2} \sin ^{-1}\left (1+d x^2\right )\right )}+\frac {3 b^{3/2} \sqrt {\pi } x S\left (\frac {\sqrt {a+b \sin ^{-1}\left (1+d x^2\right )}}{\sqrt {b} \sqrt {\pi }}\right ) \left (\cos \left (\frac {a}{2 b}\right )+\sin \left (\frac {a}{2 b}\right )\right )}{\cos \left (\frac {1}{2} \sin ^{-1}\left (1+d x^2\right )\right )-\sin \left (\frac {1}{2} \sin ^{-1}\left (1+d x^2\right )\right )}\\ \end {align*}
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Mathematica [A] time = 0.43, size = 249, normalized size = 1.01 \[ \frac {3 \sqrt {\pi } b^{3/2} x \left (\cos \left (\frac {a}{2 b}\right )-\sin \left (\frac {a}{2 b}\right )\right ) C\left (\frac {\sqrt {a+b \sin ^{-1}\left (d x^2+1\right )}}{\sqrt {b} \sqrt {\pi }}\right )}{\cos \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )-\sin \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )}+\frac {3 \sqrt {\pi } b^{3/2} x \left (\sin \left (\frac {a}{2 b}\right )+\cos \left (\frac {a}{2 b}\right )\right ) S\left (\frac {\sqrt {a+b \sin ^{-1}\left (d x^2+1\right )}}{\sqrt {b} \sqrt {\pi }}\right )}{\cos \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )-\sin \left (\frac {1}{2} \sin ^{-1}\left (d x^2+1\right )\right )}+\frac {\sqrt {a+b \sin ^{-1}\left (d x^2+1\right )} \left (a d x^2+3 b \sqrt {-d x^2 \left (d x^2+2\right )}+b d x^2 \sin ^{-1}\left (d x^2+1\right )\right )}{d x} \]
Antiderivative was successfully verified.
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fricas [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \arcsin \left (d x^{2} + 1\right ) + a\right )}^{\frac {3}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.07, size = 0, normalized size = 0.00 \[ \int \left (a +b \arcsin \left (d \,x^{2}+1\right )\right )^{\frac {3}{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (a+b\,\mathrm {asin}\left (d\,x^2+1\right )\right )}^{3/2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a + b \operatorname {asin}{\left (d x^{2} + 1 \right )}\right )^{\frac {3}{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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