3.4 \(\int (a+b \sin ^{-1}(c x)) \, dx\)

Optimal. Leaf size=30 \[ a x+\frac {b \sqrt {1-c^2 x^2}}{c}+b x \sin ^{-1}(c x) \]

[Out]

a*x+b*x*arcsin(c*x)+b*(-c^2*x^2+1)^(1/2)/c

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Rubi [A]  time = 0.01, antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {4619, 261} \[ a x+\frac {b \sqrt {1-c^2 x^2}}{c}+b x \sin ^{-1}(c x) \]

Antiderivative was successfully verified.

[In]

Int[a + b*ArcSin[c*x],x]

[Out]

a*x + (b*Sqrt[1 - c^2*x^2])/c + b*x*ArcSin[c*x]

Rule 261

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a + b*x^n)^(p + 1)/(b*n*(p + 1)), x] /; FreeQ
[{a, b, m, n, p}, x] && EqQ[m, n - 1] && NeQ[p, -1]

Rule 4619

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.), x_Symbol] :> Simp[x*(a + b*ArcSin[c*x])^n, x] - Dist[b*c*n, Int[
(x*(a + b*ArcSin[c*x])^(n - 1))/Sqrt[1 - c^2*x^2], x], x] /; FreeQ[{a, b, c}, x] && GtQ[n, 0]

Rubi steps

\begin {align*} \int \left (a+b \sin ^{-1}(c x)\right ) \, dx &=a x+b \int \sin ^{-1}(c x) \, dx\\ &=a x+b x \sin ^{-1}(c x)-(b c) \int \frac {x}{\sqrt {1-c^2 x^2}} \, dx\\ &=a x+\frac {b \sqrt {1-c^2 x^2}}{c}+b x \sin ^{-1}(c x)\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 30, normalized size = 1.00 \[ a x+\frac {b \sqrt {1-c^2 x^2}}{c}+b x \sin ^{-1}(c x) \]

Antiderivative was successfully verified.

[In]

Integrate[a + b*ArcSin[c*x],x]

[Out]

a*x + (b*Sqrt[1 - c^2*x^2])/c + b*x*ArcSin[c*x]

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fricas [A]  time = 0.41, size = 31, normalized size = 1.03 \[ \frac {b c x \arcsin \left (c x\right ) + a c x + \sqrt {-c^{2} x^{2} + 1} b}{c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(a+b*arcsin(c*x),x, algorithm="fricas")

[Out]

(b*c*x*arcsin(c*x) + a*c*x + sqrt(-c^2*x^2 + 1)*b)/c

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giac [A]  time = 0.29, size = 29, normalized size = 0.97 \[ a x + \frac {{\left (c x \arcsin \left (c x\right ) + \sqrt {-c^{2} x^{2} + 1}\right )} b}{c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(a+b*arcsin(c*x),x, algorithm="giac")

[Out]

a*x + (c*x*arcsin(c*x) + sqrt(-c^2*x^2 + 1))*b/c

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maple [A]  time = 0.00, size = 30, normalized size = 1.00 \[ a x +\frac {b \left (c x \arcsin \left (c x \right )+\sqrt {-c^{2} x^{2}+1}\right )}{c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(a+b*arcsin(c*x),x)

[Out]

a*x+b/c*(c*x*arcsin(c*x)+(-c^2*x^2+1)^(1/2))

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maxima [A]  time = 0.42, size = 29, normalized size = 0.97 \[ a x + \frac {{\left (c x \arcsin \left (c x\right ) + \sqrt {-c^{2} x^{2} + 1}\right )} b}{c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(a+b*arcsin(c*x),x, algorithm="maxima")

[Out]

a*x + (c*x*arcsin(c*x) + sqrt(-c^2*x^2 + 1))*b/c

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mupad [B]  time = 0.28, size = 28, normalized size = 0.93 \[ a\,x+\frac {b\,\sqrt {1-c^2\,x^2}}{c}+b\,x\,\mathrm {asin}\left (c\,x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(a + b*asin(c*x),x)

[Out]

a*x + (b*(1 - c^2*x^2)^(1/2))/c + b*x*asin(c*x)

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sympy [A]  time = 0.12, size = 26, normalized size = 0.87 \[ a x + b \left (\begin {cases} x \operatorname {asin}{\left (c x \right )} + \frac {\sqrt {- c^{2} x^{2} + 1}}{c} & \text {for}\: c \neq 0 \\0 & \text {otherwise} \end {cases}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(a+b*asin(c*x),x)

[Out]

a*x + b*Piecewise((x*asin(c*x) + sqrt(-c**2*x**2 + 1)/c, Ne(c, 0)), (0, True))

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