3.368 \(\int \frac {\sin ^{-1}(\sqrt {x})}{x^5} \, dx\)

Optimal. Leaf size=86 \[ -\frac {2 \sqrt {1-x}}{35 x^{3/2}}-\frac {3 \sqrt {1-x}}{70 x^{5/2}}-\frac {\sqrt {1-x}}{28 x^{7/2}}-\frac {\sin ^{-1}\left (\sqrt {x}\right )}{4 x^4}-\frac {4 \sqrt {1-x}}{35 \sqrt {x}} \]

[Out]

-1/4*arcsin(x^(1/2))/x^4-1/28*(1-x)^(1/2)/x^(7/2)-3/70*(1-x)^(1/2)/x^(5/2)-2/35*(1-x)^(1/2)/x^(3/2)-4/35*(1-x)
^(1/2)/x^(1/2)

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Rubi [A]  time = 0.03, antiderivative size = 86, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {4842, 12, 45, 37} \[ -\frac {2 \sqrt {1-x}}{35 x^{3/2}}-\frac {3 \sqrt {1-x}}{70 x^{5/2}}-\frac {\sqrt {1-x}}{28 x^{7/2}}-\frac {\sin ^{-1}\left (\sqrt {x}\right )}{4 x^4}-\frac {4 \sqrt {1-x}}{35 \sqrt {x}} \]

Antiderivative was successfully verified.

[In]

Int[ArcSin[Sqrt[x]]/x^5,x]

[Out]

-Sqrt[1 - x]/(28*x^(7/2)) - (3*Sqrt[1 - x])/(70*x^(5/2)) - (2*Sqrt[1 - x])/(35*x^(3/2)) - (4*Sqrt[1 - x])/(35*
Sqrt[x]) - ArcSin[Sqrt[x]]/(4*x^4)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n +
1))/((b*c - a*d)*(m + 1)), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*Simplify[m + n + 2])/((b*c - a*d)*(m + 1)), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rule 4842

Int[((a_.) + ArcSin[u_]*(b_.))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[((c + d*x)^(m + 1)*(a + b*ArcSin[
u]))/(d*(m + 1)), x] - Dist[b/(d*(m + 1)), Int[SimplifyIntegrand[((c + d*x)^(m + 1)*D[u, x])/Sqrt[1 - u^2], x]
, x], x] /; FreeQ[{a, b, c, d, m}, x] && NeQ[m, -1] && InverseFunctionFreeQ[u, x] &&  !FunctionOfQ[(c + d*x)^(
m + 1), u, x] &&  !FunctionOfExponentialQ[u, x]

Rubi steps

\begin {align*} \int \frac {\sin ^{-1}\left (\sqrt {x}\right )}{x^5} \, dx &=-\frac {\sin ^{-1}\left (\sqrt {x}\right )}{4 x^4}+\frac {1}{4} \int \frac {1}{2 \sqrt {1-x} x^{9/2}} \, dx\\ &=-\frac {\sin ^{-1}\left (\sqrt {x}\right )}{4 x^4}+\frac {1}{8} \int \frac {1}{\sqrt {1-x} x^{9/2}} \, dx\\ &=-\frac {\sqrt {1-x}}{28 x^{7/2}}-\frac {\sin ^{-1}\left (\sqrt {x}\right )}{4 x^4}+\frac {3}{28} \int \frac {1}{\sqrt {1-x} x^{7/2}} \, dx\\ &=-\frac {\sqrt {1-x}}{28 x^{7/2}}-\frac {3 \sqrt {1-x}}{70 x^{5/2}}-\frac {\sin ^{-1}\left (\sqrt {x}\right )}{4 x^4}+\frac {3}{35} \int \frac {1}{\sqrt {1-x} x^{5/2}} \, dx\\ &=-\frac {\sqrt {1-x}}{28 x^{7/2}}-\frac {3 \sqrt {1-x}}{70 x^{5/2}}-\frac {2 \sqrt {1-x}}{35 x^{3/2}}-\frac {\sin ^{-1}\left (\sqrt {x}\right )}{4 x^4}+\frac {2}{35} \int \frac {1}{\sqrt {1-x} x^{3/2}} \, dx\\ &=-\frac {\sqrt {1-x}}{28 x^{7/2}}-\frac {3 \sqrt {1-x}}{70 x^{5/2}}-\frac {2 \sqrt {1-x}}{35 x^{3/2}}-\frac {4 \sqrt {1-x}}{35 \sqrt {x}}-\frac {\sin ^{-1}\left (\sqrt {x}\right )}{4 x^4}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 49, normalized size = 0.57 \[ 2 \left (-\frac {\sin ^{-1}\left (\sqrt {x}\right )}{8 x^4}-\frac {\sqrt {1-x} \left (16 x^3+8 x^2+6 x+5\right )}{280 x^{7/2}}\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[ArcSin[Sqrt[x]]/x^5,x]

[Out]

2*(-1/280*(Sqrt[1 - x]*(5 + 6*x + 8*x^2 + 16*x^3))/x^(7/2) - ArcSin[Sqrt[x]]/(8*x^4))

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fricas [A]  time = 0.68, size = 38, normalized size = 0.44 \[ -\frac {{\left (16 \, x^{3} + 8 \, x^{2} + 6 \, x + 5\right )} \sqrt {x} \sqrt {-x + 1} + 35 \, \arcsin \left (\sqrt {x}\right )}{140 \, x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arcsin(x^(1/2))/x^5,x, algorithm="fricas")

[Out]

-1/140*((16*x^3 + 8*x^2 + 6*x + 5)*sqrt(x)*sqrt(-x + 1) + 35*arcsin(sqrt(x)))/x^4

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giac [B]  time = 0.23, size = 138, normalized size = 1.60 \[ -\frac {{\left (\sqrt {-x + 1} - 1\right )}^{7}}{3584 \, x^{\frac {7}{2}}} - \frac {7 \, {\left (\sqrt {-x + 1} - 1\right )}^{5}}{2560 \, x^{\frac {5}{2}}} - \frac {7 \, {\left (\sqrt {-x + 1} - 1\right )}^{3}}{512 \, x^{\frac {3}{2}}} - \frac {35 \, {\left (\sqrt {-x + 1} - 1\right )}}{512 \, \sqrt {x}} + \frac {{\left (\frac {1225 \, {\left (\sqrt {-x + 1} - 1\right )}^{6}}{x^{3}} + \frac {245 \, {\left (\sqrt {-x + 1} - 1\right )}^{4}}{x^{2}} + \frac {49 \, {\left (\sqrt {-x + 1} - 1\right )}^{2}}{x} + 5\right )} x^{\frac {7}{2}}}{17920 \, {\left (\sqrt {-x + 1} - 1\right )}^{7}} - \frac {\arcsin \left (\sqrt {x}\right )}{4 \, x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arcsin(x^(1/2))/x^5,x, algorithm="giac")

[Out]

-1/3584*(sqrt(-x + 1) - 1)^7/x^(7/2) - 7/2560*(sqrt(-x + 1) - 1)^5/x^(5/2) - 7/512*(sqrt(-x + 1) - 1)^3/x^(3/2
) - 35/512*(sqrt(-x + 1) - 1)/sqrt(x) + 1/17920*(1225*(sqrt(-x + 1) - 1)^6/x^3 + 245*(sqrt(-x + 1) - 1)^4/x^2
+ 49*(sqrt(-x + 1) - 1)^2/x + 5)*x^(7/2)/(sqrt(-x + 1) - 1)^7 - 1/4*arcsin(sqrt(x))/x^4

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maple [A]  time = 0.01, size = 59, normalized size = 0.69 \[ -\frac {\arcsin \left (\sqrt {x}\right )}{4 x^{4}}-\frac {\sqrt {1-x}}{28 x^{\frac {7}{2}}}-\frac {3 \sqrt {1-x}}{70 x^{\frac {5}{2}}}-\frac {2 \sqrt {1-x}}{35 x^{\frac {3}{2}}}-\frac {4 \sqrt {1-x}}{35 \sqrt {x}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(arcsin(x^(1/2))/x^5,x)

[Out]

-1/4*arcsin(x^(1/2))/x^4-1/28*(1-x)^(1/2)/x^(7/2)-3/70*(1-x)^(1/2)/x^(5/2)-2/35*(1-x)^(1/2)/x^(3/2)-4/35*(1-x)
^(1/2)/x^(1/2)

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maxima [A]  time = 0.41, size = 58, normalized size = 0.67 \[ -\frac {4 \, \sqrt {-x + 1}}{35 \, \sqrt {x}} - \frac {2 \, \sqrt {-x + 1}}{35 \, x^{\frac {3}{2}}} - \frac {3 \, \sqrt {-x + 1}}{70 \, x^{\frac {5}{2}}} - \frac {\sqrt {-x + 1}}{28 \, x^{\frac {7}{2}}} - \frac {\arcsin \left (\sqrt {x}\right )}{4 \, x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arcsin(x^(1/2))/x^5,x, algorithm="maxima")

[Out]

-4/35*sqrt(-x + 1)/sqrt(x) - 2/35*sqrt(-x + 1)/x^(3/2) - 3/70*sqrt(-x + 1)/x^(5/2) - 1/28*sqrt(-x + 1)/x^(7/2)
- 1/4*arcsin(sqrt(x))/x^4

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\mathrm {asin}\left (\sqrt {x}\right )}{x^5} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(asin(x^(1/2))/x^5,x)

[Out]

int(asin(x^(1/2))/x^5, x)

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sympy [A]  time = 36.28, size = 70, normalized size = 0.81 \[ \frac {\begin {cases} - \frac {\sqrt {1 - x}}{\sqrt {x}} - \frac {\left (1 - x\right )^{\frac {3}{2}}}{x^{\frac {3}{2}}} - \frac {3 \left (1 - x\right )^{\frac {5}{2}}}{5 x^{\frac {5}{2}}} - \frac {\left (1 - x\right )^{\frac {7}{2}}}{7 x^{\frac {7}{2}}} & \text {for}\: x \geq 0 \wedge x < 1 \end {cases}}{4} - \frac {\operatorname {asin}{\left (\sqrt {x} \right )}}{4 x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(asin(x**(1/2))/x**5,x)

[Out]

Piecewise((-sqrt(1 - x)/sqrt(x) - (1 - x)**(3/2)/x**(3/2) - 3*(1 - x)**(5/2)/(5*x**(5/2)) - (1 - x)**(7/2)/(7*
x**(7/2)), (x >= 0) & (x < 1)))/4 - asin(sqrt(x))/(4*x**4)

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