3.250 \(\int (c e+d e x)^3 (a+b \sin ^{-1}(c+d x))^{5/2} \, dx\)

Optimal. Leaf size=475 \[ \frac {15 \sqrt {\frac {\pi }{2}} b^{5/2} e^3 \cos \left (\frac {4 a}{b}\right ) C\left (\frac {2 \sqrt {\frac {2}{\pi }} \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b}}\right )}{4096 d}-\frac {15 \sqrt {\pi } b^{5/2} e^3 \cos \left (\frac {2 a}{b}\right ) C\left (\frac {2 \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b} \sqrt {\pi }}\right )}{256 d}-\frac {15 \sqrt {\pi } b^{5/2} e^3 \sin \left (\frac {2 a}{b}\right ) S\left (\frac {2 \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b} \sqrt {\pi }}\right )}{256 d}+\frac {15 \sqrt {\frac {\pi }{2}} b^{5/2} e^3 \sin \left (\frac {4 a}{b}\right ) S\left (\frac {2 \sqrt {\frac {2}{\pi }} \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b}}\right )}{4096 d}-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}-\frac {45 b^2 e^3 (c+d x)^2 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {225 b^2 e^3 \sqrt {a+b \sin ^{-1}(c+d x)}}{2048 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}+\frac {5 b e^3 \sqrt {1-(c+d x)^2} (c+d x)^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac {15 b e^3 \sqrt {1-(c+d x)^2} (c+d x) \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}-\frac {3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{32 d} \]

[Out]

-3/32*e^3*(a+b*arcsin(d*x+c))^(5/2)/d+1/4*e^3*(d*x+c)^4*(a+b*arcsin(d*x+c))^(5/2)/d+15/8192*b^(5/2)*e^3*cos(4*
a/b)*FresnelC(2*2^(1/2)/Pi^(1/2)*(a+b*arcsin(d*x+c))^(1/2)/b^(1/2))*2^(1/2)*Pi^(1/2)/d+15/8192*b^(5/2)*e^3*Fre
snelS(2*2^(1/2)/Pi^(1/2)*(a+b*arcsin(d*x+c))^(1/2)/b^(1/2))*sin(4*a/b)*2^(1/2)*Pi^(1/2)/d-15/256*b^(5/2)*e^3*c
os(2*a/b)*FresnelC(2*(a+b*arcsin(d*x+c))^(1/2)/b^(1/2)/Pi^(1/2))*Pi^(1/2)/d-15/256*b^(5/2)*e^3*FresnelS(2*(a+b
*arcsin(d*x+c))^(1/2)/b^(1/2)/Pi^(1/2))*sin(2*a/b)*Pi^(1/2)/d+15/64*b*e^3*(d*x+c)*(a+b*arcsin(d*x+c))^(3/2)*(1
-(d*x+c)^2)^(1/2)/d+5/32*b*e^3*(d*x+c)^3*(a+b*arcsin(d*x+c))^(3/2)*(1-(d*x+c)^2)^(1/2)/d+225/2048*b^2*e^3*(a+b
*arcsin(d*x+c))^(1/2)/d-45/256*b^2*e^3*(d*x+c)^2*(a+b*arcsin(d*x+c))^(1/2)/d-15/256*b^2*e^3*(d*x+c)^4*(a+b*arc
sin(d*x+c))^(1/2)/d

________________________________________________________________________________________

Rubi [A]  time = 1.60, antiderivative size = 475, normalized size of antiderivative = 1.00, number of steps used = 29, number of rules used = 12, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.480, Rules used = {4805, 12, 4629, 4707, 4641, 4723, 3312, 3306, 3305, 3351, 3304, 3352} \[ \frac {15 \sqrt {\frac {\pi }{2}} b^{5/2} e^3 \cos \left (\frac {4 a}{b}\right ) \text {FresnelC}\left (\frac {2 \sqrt {\frac {2}{\pi }} \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b}}\right )}{4096 d}-\frac {15 \sqrt {\pi } b^{5/2} e^3 \cos \left (\frac {2 a}{b}\right ) \text {FresnelC}\left (\frac {2 \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {\pi } \sqrt {b}}\right )}{256 d}-\frac {15 \sqrt {\pi } b^{5/2} e^3 \sin \left (\frac {2 a}{b}\right ) S\left (\frac {2 \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b} \sqrt {\pi }}\right )}{256 d}+\frac {15 \sqrt {\frac {\pi }{2}} b^{5/2} e^3 \sin \left (\frac {4 a}{b}\right ) S\left (\frac {2 \sqrt {\frac {2}{\pi }} \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b}}\right )}{4096 d}-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}-\frac {45 b^2 e^3 (c+d x)^2 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {225 b^2 e^3 \sqrt {a+b \sin ^{-1}(c+d x)}}{2048 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}+\frac {5 b e^3 \sqrt {1-(c+d x)^2} (c+d x)^3 \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac {15 b e^3 \sqrt {1-(c+d x)^2} (c+d x) \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}-\frac {3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{32 d} \]

Antiderivative was successfully verified.

[In]

Int[(c*e + d*e*x)^3*(a + b*ArcSin[c + d*x])^(5/2),x]

[Out]

(225*b^2*e^3*Sqrt[a + b*ArcSin[c + d*x]])/(2048*d) - (45*b^2*e^3*(c + d*x)^2*Sqrt[a + b*ArcSin[c + d*x]])/(256
*d) - (15*b^2*e^3*(c + d*x)^4*Sqrt[a + b*ArcSin[c + d*x]])/(256*d) + (15*b*e^3*(c + d*x)*Sqrt[1 - (c + d*x)^2]
*(a + b*ArcSin[c + d*x])^(3/2))/(64*d) + (5*b*e^3*(c + d*x)^3*Sqrt[1 - (c + d*x)^2]*(a + b*ArcSin[c + d*x])^(3
/2))/(32*d) - (3*e^3*(a + b*ArcSin[c + d*x])^(5/2))/(32*d) + (e^3*(c + d*x)^4*(a + b*ArcSin[c + d*x])^(5/2))/(
4*d) + (15*b^(5/2)*e^3*Sqrt[Pi/2]*Cos[(4*a)/b]*FresnelC[(2*Sqrt[2/Pi]*Sqrt[a + b*ArcSin[c + d*x]])/Sqrt[b]])/(
4096*d) - (15*b^(5/2)*e^3*Sqrt[Pi]*Cos[(2*a)/b]*FresnelC[(2*Sqrt[a + b*ArcSin[c + d*x]])/(Sqrt[b]*Sqrt[Pi])])/
(256*d) - (15*b^(5/2)*e^3*Sqrt[Pi]*FresnelS[(2*Sqrt[a + b*ArcSin[c + d*x]])/(Sqrt[b]*Sqrt[Pi])]*Sin[(2*a)/b])/
(256*d) + (15*b^(5/2)*e^3*Sqrt[Pi/2]*FresnelS[(2*Sqrt[2/Pi]*Sqrt[a + b*ArcSin[c + d*x]])/Sqrt[b]]*Sin[(4*a)/b]
)/(4096*d)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 3304

Int[sin[Pi/2 + (e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[Cos[(f*x^2)/d],
x], x, Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]

Rule 3305

Int[sin[(e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[Sin[(f*x^2)/d], x], x,
Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]

Rule 3306

Int[sin[(e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[Cos[(d*e - c*f)/d], Int[Sin[(c*f)/d +
f*x]/Sqrt[c + d*x], x], x] + Dist[Sin[(d*e - c*f)/d], Int[Cos[(c*f)/d + f*x]/Sqrt[c + d*x], x], x] /; FreeQ[{c
, d, e, f}, x] && ComplexFreeQ[f] && NeQ[d*e - c*f, 0]

Rule 3312

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 3351

Int[Sin[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelS[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rule 3352

Int[Cos[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelC[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rule 4629

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(x^(m + 1)*(a + b*ArcSin[c*x])^n)/(m
+ 1), x] - Dist[(b*c*n)/(m + 1), Int[(x^(m + 1)*(a + b*ArcSin[c*x])^(n - 1))/Sqrt[1 - c^2*x^2], x], x] /; Fre
eQ[{a, b, c}, x] && IGtQ[m, 0] && GtQ[n, 0]

Rule 4641

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(a + b*ArcSin[c*x])^
(n + 1)/(b*c*Sqrt[d]*(n + 1)), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && GtQ[d, 0] && NeQ[n,
-1]

Rule 4707

Int[(((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[
(f*(f*x)^(m - 1)*Sqrt[d + e*x^2]*(a + b*ArcSin[c*x])^n)/(e*m), x] + (Dist[(f^2*(m - 1))/(c^2*m), Int[((f*x)^(m
- 2)*(a + b*ArcSin[c*x])^n)/Sqrt[d + e*x^2], x], x] + Dist[(b*f*n*Sqrt[1 - c^2*x^2])/(c*m*Sqrt[d + e*x^2]), I
nt[(f*x)^(m - 1)*(a + b*ArcSin[c*x])^(n - 1), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[c^2*d + e, 0] &&
GtQ[n, 0] && GtQ[m, 1] && IntegerQ[m]

Rule 4723

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[d^p/c^(
m + 1), Subst[Int[(a + b*x)^n*Sin[x]^m*Cos[x]^(2*p + 1), x], x, ArcSin[c*x]], x] /; FreeQ[{a, b, c, d, e, n},
x] && EqQ[c^2*d + e, 0] && IntegerQ[2*p] && GtQ[p, -1] && IGtQ[m, 0] && (IntegerQ[p] || GtQ[d, 0])

Rule 4805

Int[((a_.) + ArcSin[(c_) + (d_.)*(x_)]*(b_.))^(n_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Dist[1/d, Subst[I
nt[((d*e - c*f)/d + (f*x)/d)^m*(a + b*ArcSin[x])^n, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x]

Rubi steps

\begin {align*} \int (c e+d e x)^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2} \, dx &=\frac {\operatorname {Subst}\left (\int e^3 x^3 \left (a+b \sin ^{-1}(x)\right )^{5/2} \, dx,x,c+d x\right )}{d}\\ &=\frac {e^3 \operatorname {Subst}\left (\int x^3 \left (a+b \sin ^{-1}(x)\right )^{5/2} \, dx,x,c+d x\right )}{d}\\ &=\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}-\frac {\left (5 b e^3\right ) \operatorname {Subst}\left (\int \frac {x^4 \left (a+b \sin ^{-1}(x)\right )^{3/2}}{\sqrt {1-x^2}} \, dx,x,c+d x\right )}{8 d}\\ &=\frac {5 b e^3 (c+d x)^3 \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}-\frac {\left (15 b e^3\right ) \operatorname {Subst}\left (\int \frac {x^2 \left (a+b \sin ^{-1}(x)\right )^{3/2}}{\sqrt {1-x^2}} \, dx,x,c+d x\right )}{32 d}-\frac {\left (15 b^2 e^3\right ) \operatorname {Subst}\left (\int x^3 \sqrt {a+b \sin ^{-1}(x)} \, dx,x,c+d x\right )}{64 d}\\ &=-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {15 b e^3 (c+d x) \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}+\frac {5 b e^3 (c+d x)^3 \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}-\frac {\left (15 b e^3\right ) \operatorname {Subst}\left (\int \frac {\left (a+b \sin ^{-1}(x)\right )^{3/2}}{\sqrt {1-x^2}} \, dx,x,c+d x\right )}{64 d}-\frac {\left (45 b^2 e^3\right ) \operatorname {Subst}\left (\int x \sqrt {a+b \sin ^{-1}(x)} \, dx,x,c+d x\right )}{128 d}+\frac {\left (15 b^3 e^3\right ) \operatorname {Subst}\left (\int \frac {x^4}{\sqrt {1-x^2} \sqrt {a+b \sin ^{-1}(x)}} \, dx,x,c+d x\right )}{512 d}\\ &=-\frac {45 b^2 e^3 (c+d x)^2 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {15 b e^3 (c+d x) \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}+\frac {5 b e^3 (c+d x)^3 \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}-\frac {3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}+\frac {\left (15 b^3 e^3\right ) \operatorname {Subst}\left (\int \frac {\sin ^4(x)}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{512 d}+\frac {\left (45 b^3 e^3\right ) \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {1-x^2} \sqrt {a+b \sin ^{-1}(x)}} \, dx,x,c+d x\right )}{512 d}\\ &=-\frac {45 b^2 e^3 (c+d x)^2 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {15 b e^3 (c+d x) \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}+\frac {5 b e^3 (c+d x)^3 \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}-\frac {3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}+\frac {\left (15 b^3 e^3\right ) \operatorname {Subst}\left (\int \left (\frac {3}{8 \sqrt {a+b x}}-\frac {\cos (2 x)}{2 \sqrt {a+b x}}+\frac {\cos (4 x)}{8 \sqrt {a+b x}}\right ) \, dx,x,\sin ^{-1}(c+d x)\right )}{512 d}+\frac {\left (45 b^3 e^3\right ) \operatorname {Subst}\left (\int \frac {\sin ^2(x)}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{512 d}\\ &=\frac {45 b^2 e^3 \sqrt {a+b \sin ^{-1}(c+d x)}}{2048 d}-\frac {45 b^2 e^3 (c+d x)^2 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {15 b e^3 (c+d x) \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}+\frac {5 b e^3 (c+d x)^3 \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}-\frac {3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}+\frac {\left (15 b^3 e^3\right ) \operatorname {Subst}\left (\int \frac {\cos (4 x)}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{4096 d}-\frac {\left (15 b^3 e^3\right ) \operatorname {Subst}\left (\int \frac {\cos (2 x)}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{1024 d}+\frac {\left (45 b^3 e^3\right ) \operatorname {Subst}\left (\int \left (\frac {1}{2 \sqrt {a+b x}}-\frac {\cos (2 x)}{2 \sqrt {a+b x}}\right ) \, dx,x,\sin ^{-1}(c+d x)\right )}{512 d}\\ &=\frac {225 b^2 e^3 \sqrt {a+b \sin ^{-1}(c+d x)}}{2048 d}-\frac {45 b^2 e^3 (c+d x)^2 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {15 b e^3 (c+d x) \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}+\frac {5 b e^3 (c+d x)^3 \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}-\frac {3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}-\frac {\left (45 b^3 e^3\right ) \operatorname {Subst}\left (\int \frac {\cos (2 x)}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{1024 d}-\frac {\left (15 b^3 e^3 \cos \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \frac {\cos \left (\frac {2 a}{b}+2 x\right )}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{1024 d}+\frac {\left (15 b^3 e^3 \cos \left (\frac {4 a}{b}\right )\right ) \operatorname {Subst}\left (\int \frac {\cos \left (\frac {4 a}{b}+4 x\right )}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{4096 d}-\frac {\left (15 b^3 e^3 \sin \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \frac {\sin \left (\frac {2 a}{b}+2 x\right )}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{1024 d}+\frac {\left (15 b^3 e^3 \sin \left (\frac {4 a}{b}\right )\right ) \operatorname {Subst}\left (\int \frac {\sin \left (\frac {4 a}{b}+4 x\right )}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{4096 d}\\ &=\frac {225 b^2 e^3 \sqrt {a+b \sin ^{-1}(c+d x)}}{2048 d}-\frac {45 b^2 e^3 (c+d x)^2 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {15 b e^3 (c+d x) \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}+\frac {5 b e^3 (c+d x)^3 \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}-\frac {3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}-\frac {\left (15 b^2 e^3 \cos \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \cos \left (\frac {2 x^2}{b}\right ) \, dx,x,\sqrt {a+b \sin ^{-1}(c+d x)}\right )}{512 d}-\frac {\left (45 b^3 e^3 \cos \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \frac {\cos \left (\frac {2 a}{b}+2 x\right )}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{1024 d}+\frac {\left (15 b^2 e^3 \cos \left (\frac {4 a}{b}\right )\right ) \operatorname {Subst}\left (\int \cos \left (\frac {4 x^2}{b}\right ) \, dx,x,\sqrt {a+b \sin ^{-1}(c+d x)}\right )}{2048 d}-\frac {\left (15 b^2 e^3 \sin \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \sin \left (\frac {2 x^2}{b}\right ) \, dx,x,\sqrt {a+b \sin ^{-1}(c+d x)}\right )}{512 d}-\frac {\left (45 b^3 e^3 \sin \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \frac {\sin \left (\frac {2 a}{b}+2 x\right )}{\sqrt {a+b x}} \, dx,x,\sin ^{-1}(c+d x)\right )}{1024 d}+\frac {\left (15 b^2 e^3 \sin \left (\frac {4 a}{b}\right )\right ) \operatorname {Subst}\left (\int \sin \left (\frac {4 x^2}{b}\right ) \, dx,x,\sqrt {a+b \sin ^{-1}(c+d x)}\right )}{2048 d}\\ &=\frac {225 b^2 e^3 \sqrt {a+b \sin ^{-1}(c+d x)}}{2048 d}-\frac {45 b^2 e^3 (c+d x)^2 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {15 b e^3 (c+d x) \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}+\frac {5 b e^3 (c+d x)^3 \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}-\frac {3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}+\frac {15 b^{5/2} e^3 \sqrt {\frac {\pi }{2}} \cos \left (\frac {4 a}{b}\right ) C\left (\frac {2 \sqrt {\frac {2}{\pi }} \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b}}\right )}{4096 d}-\frac {15 b^{5/2} e^3 \sqrt {\pi } \cos \left (\frac {2 a}{b}\right ) C\left (\frac {2 \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b} \sqrt {\pi }}\right )}{1024 d}-\frac {15 b^{5/2} e^3 \sqrt {\pi } S\left (\frac {2 \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b} \sqrt {\pi }}\right ) \sin \left (\frac {2 a}{b}\right )}{1024 d}+\frac {15 b^{5/2} e^3 \sqrt {\frac {\pi }{2}} S\left (\frac {2 \sqrt {\frac {2}{\pi }} \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b}}\right ) \sin \left (\frac {4 a}{b}\right )}{4096 d}-\frac {\left (45 b^2 e^3 \cos \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \cos \left (\frac {2 x^2}{b}\right ) \, dx,x,\sqrt {a+b \sin ^{-1}(c+d x)}\right )}{512 d}-\frac {\left (45 b^2 e^3 \sin \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \sin \left (\frac {2 x^2}{b}\right ) \, dx,x,\sqrt {a+b \sin ^{-1}(c+d x)}\right )}{512 d}\\ &=\frac {225 b^2 e^3 \sqrt {a+b \sin ^{-1}(c+d x)}}{2048 d}-\frac {45 b^2 e^3 (c+d x)^2 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}-\frac {15 b^2 e^3 (c+d x)^4 \sqrt {a+b \sin ^{-1}(c+d x)}}{256 d}+\frac {15 b e^3 (c+d x) \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{64 d}+\frac {5 b e^3 (c+d x)^3 \sqrt {1-(c+d x)^2} \left (a+b \sin ^{-1}(c+d x)\right )^{3/2}}{32 d}-\frac {3 e^3 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sin ^{-1}(c+d x)\right )^{5/2}}{4 d}+\frac {15 b^{5/2} e^3 \sqrt {\frac {\pi }{2}} \cos \left (\frac {4 a}{b}\right ) C\left (\frac {2 \sqrt {\frac {2}{\pi }} \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b}}\right )}{4096 d}-\frac {15 b^{5/2} e^3 \sqrt {\pi } \cos \left (\frac {2 a}{b}\right ) C\left (\frac {2 \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b} \sqrt {\pi }}\right )}{256 d}-\frac {15 b^{5/2} e^3 \sqrt {\pi } S\left (\frac {2 \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b} \sqrt {\pi }}\right ) \sin \left (\frac {2 a}{b}\right )}{256 d}+\frac {15 b^{5/2} e^3 \sqrt {\frac {\pi }{2}} S\left (\frac {2 \sqrt {\frac {2}{\pi }} \sqrt {a+b \sin ^{-1}(c+d x)}}{\sqrt {b}}\right ) \sin \left (\frac {4 a}{b}\right )}{4096 d}\\ \end {align*}

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Mathematica [C]  time = 0.32, size = 269, normalized size = 0.57 \[ -\frac {e^3 e^{-\frac {4 i a}{b}} \left (a+b \sin ^{-1}(c+d x)\right )^{5/2} \left (-16 \sqrt {2} e^{\frac {2 i a}{b}} \sqrt {\frac {i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \Gamma \left (\frac {7}{2},-\frac {2 i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )-16 \sqrt {2} e^{\frac {6 i a}{b}} \sqrt {-\frac {i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \Gamma \left (\frac {7}{2},\frac {2 i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )+\sqrt {\frac {i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \Gamma \left (\frac {7}{2},-\frac {4 i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )+e^{\frac {8 i a}{b}} \sqrt {-\frac {i \left (a+b \sin ^{-1}(c+d x)\right )}{b}} \Gamma \left (\frac {7}{2},\frac {4 i \left (a+b \sin ^{-1}(c+d x)\right )}{b}\right )\right )}{2048 d \left (\frac {\left (a+b \sin ^{-1}(c+d x)\right )^2}{b^2}\right )^{3/2}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(c*e + d*e*x)^3*(a + b*ArcSin[c + d*x])^(5/2),x]

[Out]

-1/2048*(e^3*(a + b*ArcSin[c + d*x])^(5/2)*(-16*Sqrt[2]*E^(((2*I)*a)/b)*Sqrt[(I*(a + b*ArcSin[c + d*x]))/b]*Ga
mma[7/2, ((-2*I)*(a + b*ArcSin[c + d*x]))/b] - 16*Sqrt[2]*E^(((6*I)*a)/b)*Sqrt[((-I)*(a + b*ArcSin[c + d*x]))/
b]*Gamma[7/2, ((2*I)*(a + b*ArcSin[c + d*x]))/b] + Sqrt[(I*(a + b*ArcSin[c + d*x]))/b]*Gamma[7/2, ((-4*I)*(a +
b*ArcSin[c + d*x]))/b] + E^(((8*I)*a)/b)*Sqrt[((-I)*(a + b*ArcSin[c + d*x]))/b]*Gamma[7/2, ((4*I)*(a + b*ArcS
in[c + d*x]))/b]))/(d*E^(((4*I)*a)/b)*((a + b*ArcSin[c + d*x])^2/b^2)^(3/2))

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)^3*(a+b*arcsin(d*x+c))^(5/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

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giac [B]  time = 3.57, size = 3439, normalized size = 7.24 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)^3*(a+b*arcsin(d*x+c))^(5/2),x, algorithm="giac")

[Out]

-1/16*sqrt(pi)*a^3*b^3*i*erf(sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x
+ c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/((sqrt(2)*b^(9/2)*i/abs(b) - sqrt(2)*b^(7/2))*d) + 1/8*sqrt(pi)*a^3*b^2*i*
erf(-sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4*
a*i/b + 3)/((sqrt(2)*b^(7/2)*i/abs(b) + sqrt(2)*b^(5/2))*d) - 1/8*sqrt(pi)*a^3*b^2*i*erf(sqrt(2)*sqrt(b*arcsin
(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/((sqrt(2)*b^(7
/2)*i/abs(b) - sqrt(2)*b^(5/2))*d) - 3/16*sqrt(pi)*a^3*b^(3/2)*i*erf(-sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt
(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4*a*i/b + 3)/((sqrt(2)*b^3*i/abs(b) + sqrt(2)*b
^2)*d) + 1/8*sqrt(pi)*a^3*b^(3/2)*i*erf(-sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c)
+ a)/sqrt(b))*e^(2*a*i/b + 3)/((b^3*i/abs(b) + b^2)*d) + 1/8*sqrt(pi)*a^3*b^(3/2)*i*erf(sqrt(b*arcsin(d*x + c
) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-2*a*i/b + 3)/((b^3*i/abs(b) - b^2)*d) + 1/8
*sqrt(pi)*a^3*b^(3/2)*i*erf(sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x +
c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/((sqrt(2)*b^3*i/abs(b) - sqrt(2)*b^2)*d) + 3/128*sqrt(pi)*a^2*b^3*erf(-sqrt
(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4*a*i/b + 3
)/((sqrt(2)*b^(7/2)*i/abs(b) + sqrt(2)*b^(5/2))*d) + 1/16*sqrt(pi)*a^3*b*i*erf(-sqrt(2)*sqrt(b*arcsin(d*x + c)
+ a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4*a*i/b + 3)/((sqrt(2)*b^(5/2)*i/abs(
b) + sqrt(2)*b^(3/2))*d) + 9/1024*sqrt(pi)*a*b^3*i*erf(-sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) -
sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4*a*i/b + 3)/((sqrt(2)*b^(5/2)*i/abs(b) + sqrt(2)*b^(3/2))*d)
- 9/128*sqrt(pi)*a*b^3*i*erf(-sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt
(b))*e^(2*a*i/b + 3)/((b^(5/2)*i/abs(b) + b^(3/2))*d) - 1/8*sqrt(pi)*a^3*b*i*erf(sqrt(b*arcsin(d*x + c) + a)*s
qrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-2*a*i/b + 3)/((b^(5/2)*i/abs(b) - b^(3/2))*d) - 9/1
28*sqrt(pi)*a*b^3*i*erf(sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^
(-2*a*i/b + 3)/((b^(5/2)*i/abs(b) - b^(3/2))*d) - 3/64*sqrt(pi)*a^2*b^3*erf(sqrt(2)*sqrt(b*arcsin(d*x + c) + a
)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/((sqrt(2)*b^(7/2)*i/abs(b)
- sqrt(2)*b^(5/2))*d) + 1/16*sqrt(pi)*a^3*b*i*erf(sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(
2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/((sqrt(2)*b^(5/2)*i/abs(b) - sqrt(2)*b^(3/2))*d) + 3/
128*sqrt(pi)*a^2*b^(5/2)*erf(-sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x
+ c) + a)/sqrt(b))*e^(4*a*i/b + 3)/((sqrt(2)*b^3*i/abs(b) + sqrt(2)*b^2)*d) - 9/1024*sqrt(pi)*a*b^(5/2)*i*erf
(-sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4*a*i
/b + 3)/((sqrt(2)*b^2*i/abs(b) + sqrt(2)*b)*d) - 3/16*sqrt(pi)*a^2*b^(5/2)*erf(-sqrt(b*arcsin(d*x + c) + a)*sq
rt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(2*a*i/b + 3)/((b^3*i/abs(b) + b^2)*d) - 1/8*sqrt(pi)*
a^3*sqrt(b)*i*erf(-sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(2*a*
i/b + 3)/((b^2*i/abs(b) + b)*d) + 9/128*sqrt(pi)*a*b^(5/2)*i*erf(-sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b)
- sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(2*a*i/b + 3)/((b^2*i/abs(b) + b)*d) + 3/16*sqrt(pi)*a^2*b^(5/2)*erf
(sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-2*a*i/b + 3)/((b^3*i/
abs(b) - b^2)*d) + 9/128*sqrt(pi)*a*b^(5/2)*i*erf(sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin
(d*x + c) + a)/sqrt(b))*e^(-2*a*i/b + 3)/((b^2*i/abs(b) - b)*d) + 5/512*sqrt(b*arcsin(d*x + c) + a)*b^2*i*arcs
in(d*x + c)*e^(4*i*arcsin(d*x + c) + 3)/d + 1/64*sqrt(b*arcsin(d*x + c) + a)*b^2*arcsin(d*x + c)^2*e^(4*i*arcs
in(d*x + c) + 3)/d - 5/64*sqrt(b*arcsin(d*x + c) + a)*b^2*i*arcsin(d*x + c)*e^(2*i*arcsin(d*x + c) + 3)/d - 1/
16*sqrt(b*arcsin(d*x + c) + a)*b^2*arcsin(d*x + c)^2*e^(2*i*arcsin(d*x + c) + 3)/d + 5/64*sqrt(b*arcsin(d*x +
c) + a)*b^2*i*arcsin(d*x + c)*e^(-2*i*arcsin(d*x + c) + 3)/d - 1/16*sqrt(b*arcsin(d*x + c) + a)*b^2*arcsin(d*x
+ c)^2*e^(-2*i*arcsin(d*x + c) + 3)/d - 5/512*sqrt(b*arcsin(d*x + c) + a)*b^2*i*arcsin(d*x + c)*e^(-4*i*arcsi
n(d*x + c) + 3)/d + 1/64*sqrt(b*arcsin(d*x + c) + a)*b^2*arcsin(d*x + c)^2*e^(-4*i*arcsin(d*x + c) + 3)/d - 3/
64*sqrt(pi)*a^2*b^2*erf(-sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c)
+ a)/sqrt(b))*e^(4*a*i/b + 3)/((sqrt(2)*b^(5/2)*i/abs(b) + sqrt(2)*b^(3/2))*d) - 15/8192*sqrt(pi)*b^4*erf(-sq
rt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(4*a*i/b +
3)/((sqrt(2)*b^(5/2)*i/abs(b) + sqrt(2)*b^(3/2))*d) + 3/16*sqrt(pi)*a^2*b^2*erf(-sqrt(b*arcsin(d*x + c) + a)*
sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(2*a*i/b + 3)/((b^(5/2)*i/abs(b) + b^(3/2))*d) - 3/1
6*sqrt(pi)*a^2*b^2*erf(sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(
-2*a*i/b + 3)/((b^(5/2)*i/abs(b) - b^(3/2))*d) + 3/64*sqrt(pi)*a^2*b^2*erf(sqrt(2)*sqrt(b*arcsin(d*x + c) + a)
*sqrt(b)*i/abs(b) - sqrt(2)*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/((sqrt(2)*b^(5/2)*i/abs(b) -
sqrt(2)*b^(3/2))*d) + 15/8192*sqrt(pi)*b^4*erf(sqrt(2)*sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(2)
*sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-4*a*i/b + 3)/((sqrt(2)*b^(5/2)*i/abs(b) - sqrt(2)*b^(3/2))*d) + 15/5
12*sqrt(pi)*b^(7/2)*erf(-sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e
^(2*a*i/b + 3)/((b^2*i/abs(b) + b)*d) - 15/512*sqrt(pi)*b^(7/2)*erf(sqrt(b*arcsin(d*x + c) + a)*sqrt(b)*i/abs(
b) - sqrt(b*arcsin(d*x + c) + a)/sqrt(b))*e^(-2*a*i/b + 3)/((b^2*i/abs(b) - b)*d) + 5/512*sqrt(b*arcsin(d*x +
c) + a)*a*b*i*e^(4*i*arcsin(d*x + c) + 3)/d + 1/32*sqrt(b*arcsin(d*x + c) + a)*a*b*arcsin(d*x + c)*e^(4*i*arcs
in(d*x + c) + 3)/d - 5/64*sqrt(b*arcsin(d*x + c) + a)*a*b*i*e^(2*i*arcsin(d*x + c) + 3)/d - 1/8*sqrt(b*arcsin(
d*x + c) + a)*a*b*arcsin(d*x + c)*e^(2*i*arcsin(d*x + c) + 3)/d + 5/64*sqrt(b*arcsin(d*x + c) + a)*a*b*i*e^(-2
*i*arcsin(d*x + c) + 3)/d - 1/8*sqrt(b*arcsin(d*x + c) + a)*a*b*arcsin(d*x + c)*e^(-2*i*arcsin(d*x + c) + 3)/d
- 5/512*sqrt(b*arcsin(d*x + c) + a)*a*b*i*e^(-4*i*arcsin(d*x + c) + 3)/d + 1/32*sqrt(b*arcsin(d*x + c) + a)*a
*b*arcsin(d*x + c)*e^(-4*i*arcsin(d*x + c) + 3)/d + 1/64*sqrt(b*arcsin(d*x + c) + a)*a^2*e^(4*i*arcsin(d*x + c
) + 3)/d - 15/4096*sqrt(b*arcsin(d*x + c) + a)*b^2*e^(4*i*arcsin(d*x + c) + 3)/d - 1/16*sqrt(b*arcsin(d*x + c)
+ a)*a^2*e^(2*i*arcsin(d*x + c) + 3)/d + 15/256*sqrt(b*arcsin(d*x + c) + a)*b^2*e^(2*i*arcsin(d*x + c) + 3)/d
- 1/16*sqrt(b*arcsin(d*x + c) + a)*a^2*e^(-2*i*arcsin(d*x + c) + 3)/d + 15/256*sqrt(b*arcsin(d*x + c) + a)*b^
2*e^(-2*i*arcsin(d*x + c) + 3)/d + 1/64*sqrt(b*arcsin(d*x + c) + a)*a^2*e^(-4*i*arcsin(d*x + c) + 3)/d - 15/40
96*sqrt(b*arcsin(d*x + c) + a)*b^2*e^(-4*i*arcsin(d*x + c) + 3)/d

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maple [B]  time = 0.39, size = 864, normalized size = 1.82 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*e*x+c*e)^3*(a+b*arcsin(d*x+c))^(5/2),x)

[Out]

-1/8192/d*e^3*(-15*2^(1/2)*Pi^(1/2)*(1/b)^(1/2)*cos(4*a/b)*FresnelC(2*2^(1/2)/Pi^(1/2)/(1/b)^(1/2)*(a+b*arcsin
(d*x+c))^(1/2)/b)*(a+b*arcsin(d*x+c))^(1/2)*b^3-15*2^(1/2)*Pi^(1/2)*(1/b)^(1/2)*sin(4*a/b)*FresnelS(2*2^(1/2)/
Pi^(1/2)/(1/b)^(1/2)*(a+b*arcsin(d*x+c))^(1/2)/b)*(a+b*arcsin(d*x+c))^(1/2)*b^3+480*(1/b)^(1/2)*Pi^(1/2)*(a+b*
arcsin(d*x+c))^(1/2)*cos(2*a/b)*FresnelC(2/Pi^(1/2)/(1/b)^(1/2)*(a+b*arcsin(d*x+c))^(1/2)/b)*b^3+480*(1/b)^(1/
2)*Pi^(1/2)*(a+b*arcsin(d*x+c))^(1/2)*sin(2*a/b)*FresnelS(2/Pi^(1/2)/(1/b)^(1/2)*(a+b*arcsin(d*x+c))^(1/2)/b)*
b^3+1024*arcsin(d*x+c)^3*cos(2*(a+b*arcsin(d*x+c))/b-2*a/b)*b^3-256*arcsin(d*x+c)^3*cos(4*(a+b*arcsin(d*x+c))/
b-4*a/b)*b^3+3072*arcsin(d*x+c)^2*cos(2*(a+b*arcsin(d*x+c))/b-2*a/b)*a*b^2-1280*arcsin(d*x+c)^2*sin(2*(a+b*arc
sin(d*x+c))/b-2*a/b)*b^3-768*arcsin(d*x+c)^2*cos(4*(a+b*arcsin(d*x+c))/b-4*a/b)*a*b^2+160*arcsin(d*x+c)^2*sin(
4*(a+b*arcsin(d*x+c))/b-4*a/b)*b^3+3072*arcsin(d*x+c)*cos(2*(a+b*arcsin(d*x+c))/b-2*a/b)*a^2*b-960*arcsin(d*x+
c)*cos(2*(a+b*arcsin(d*x+c))/b-2*a/b)*b^3-2560*arcsin(d*x+c)*sin(2*(a+b*arcsin(d*x+c))/b-2*a/b)*a*b^2-768*arcs
in(d*x+c)*cos(4*(a+b*arcsin(d*x+c))/b-4*a/b)*a^2*b+60*arcsin(d*x+c)*cos(4*(a+b*arcsin(d*x+c))/b-4*a/b)*b^3+320
*arcsin(d*x+c)*sin(4*(a+b*arcsin(d*x+c))/b-4*a/b)*a*b^2+1024*cos(2*(a+b*arcsin(d*x+c))/b-2*a/b)*a^3-960*cos(2*
(a+b*arcsin(d*x+c))/b-2*a/b)*a*b^2-1280*sin(2*(a+b*arcsin(d*x+c))/b-2*a/b)*a^2*b-256*cos(4*(a+b*arcsin(d*x+c))
/b-4*a/b)*a^3+60*cos(4*(a+b*arcsin(d*x+c))/b-4*a/b)*a*b^2+160*sin(4*(a+b*arcsin(d*x+c))/b-4*a/b)*a^2*b)/(a+b*a
rcsin(d*x+c))^(1/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (d e x + c e\right )}^{3} {\left (b \arcsin \left (d x + c\right ) + a\right )}^{\frac {5}{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)^3*(a+b*arcsin(d*x+c))^(5/2),x, algorithm="maxima")

[Out]

integrate((d*e*x + c*e)^3*(b*arcsin(d*x + c) + a)^(5/2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (c\,e+d\,e\,x\right )}^3\,{\left (a+b\,\mathrm {asin}\left (c+d\,x\right )\right )}^{5/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*e + d*e*x)^3*(a + b*asin(c + d*x))^(5/2),x)

[Out]

int((c*e + d*e*x)^3*(a + b*asin(c + d*x))^(5/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)**3*(a+b*asin(d*x+c))**(5/2),x)

[Out]

Timed out

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