Optimal. Leaf size=239 \[ -\frac {24 a^4 \cos (e+f x) \log (1-\sin (e+f x))}{c^3 f \sqrt {a \sin (e+f x)+a} \sqrt {c-c \sin (e+f x)}}-\frac {12 a^3 \cos (e+f x) \sqrt {a \sin (e+f x)+a}}{c^3 f \sqrt {c-c \sin (e+f x)}}-\frac {3 a^2 \cos (e+f x) (a \sin (e+f x)+a)^{3/2}}{c^3 f \sqrt {c-c \sin (e+f x)}}-\frac {2 a \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{c^2 f (c-c \sin (e+f x))^{3/2}}+\frac {\cos (e+f x) (a \sin (e+f x)+a)^{7/2}}{2 c f (c-c \sin (e+f x))^{5/2}} \]
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Rubi [A] time = 0.76, antiderivative size = 239, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 38, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {2841, 2739, 2740, 2737, 2667, 31} \[ -\frac {12 a^3 \cos (e+f x) \sqrt {a \sin (e+f x)+a}}{c^3 f \sqrt {c-c \sin (e+f x)}}-\frac {3 a^2 \cos (e+f x) (a \sin (e+f x)+a)^{3/2}}{c^3 f \sqrt {c-c \sin (e+f x)}}-\frac {24 a^4 \cos (e+f x) \log (1-\sin (e+f x))}{c^3 f \sqrt {a \sin (e+f x)+a} \sqrt {c-c \sin (e+f x)}}-\frac {2 a \cos (e+f x) (a \sin (e+f x)+a)^{5/2}}{c^2 f (c-c \sin (e+f x))^{3/2}}+\frac {\cos (e+f x) (a \sin (e+f x)+a)^{7/2}}{2 c f (c-c \sin (e+f x))^{5/2}} \]
Antiderivative was successfully verified.
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Rule 31
Rule 2667
Rule 2737
Rule 2739
Rule 2740
Rule 2841
Rubi steps
\begin {align*} \int \frac {\cos ^2(e+f x) (a+a \sin (e+f x))^{7/2}}{(c-c \sin (e+f x))^{7/2}} \, dx &=\frac {\int \frac {(a+a \sin (e+f x))^{9/2}}{(c-c \sin (e+f x))^{5/2}} \, dx}{a c}\\ &=\frac {\cos (e+f x) (a+a \sin (e+f x))^{7/2}}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {2 \int \frac {(a+a \sin (e+f x))^{7/2}}{(c-c \sin (e+f x))^{3/2}} \, dx}{c^2}\\ &=\frac {\cos (e+f x) (a+a \sin (e+f x))^{7/2}}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {2 a \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{c^2 f (c-c \sin (e+f x))^{3/2}}+\frac {(6 a) \int \frac {(a+a \sin (e+f x))^{5/2}}{\sqrt {c-c \sin (e+f x)}} \, dx}{c^3}\\ &=\frac {\cos (e+f x) (a+a \sin (e+f x))^{7/2}}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {2 a \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{c^2 f (c-c \sin (e+f x))^{3/2}}-\frac {3 a^2 \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{c^3 f \sqrt {c-c \sin (e+f x)}}+\frac {\left (12 a^2\right ) \int \frac {(a+a \sin (e+f x))^{3/2}}{\sqrt {c-c \sin (e+f x)}} \, dx}{c^3}\\ &=\frac {\cos (e+f x) (a+a \sin (e+f x))^{7/2}}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {2 a \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{c^2 f (c-c \sin (e+f x))^{3/2}}-\frac {12 a^3 \cos (e+f x) \sqrt {a+a \sin (e+f x)}}{c^3 f \sqrt {c-c \sin (e+f x)}}-\frac {3 a^2 \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{c^3 f \sqrt {c-c \sin (e+f x)}}+\frac {\left (24 a^3\right ) \int \frac {\sqrt {a+a \sin (e+f x)}}{\sqrt {c-c \sin (e+f x)}} \, dx}{c^3}\\ &=\frac {\cos (e+f x) (a+a \sin (e+f x))^{7/2}}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {2 a \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{c^2 f (c-c \sin (e+f x))^{3/2}}-\frac {12 a^3 \cos (e+f x) \sqrt {a+a \sin (e+f x)}}{c^3 f \sqrt {c-c \sin (e+f x)}}-\frac {3 a^2 \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{c^3 f \sqrt {c-c \sin (e+f x)}}+\frac {\left (24 a^4 \cos (e+f x)\right ) \int \frac {\cos (e+f x)}{c-c \sin (e+f x)} \, dx}{c^2 \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}\\ &=\frac {\cos (e+f x) (a+a \sin (e+f x))^{7/2}}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {2 a \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{c^2 f (c-c \sin (e+f x))^{3/2}}-\frac {12 a^3 \cos (e+f x) \sqrt {a+a \sin (e+f x)}}{c^3 f \sqrt {c-c \sin (e+f x)}}-\frac {3 a^2 \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{c^3 f \sqrt {c-c \sin (e+f x)}}-\frac {\left (24 a^4 \cos (e+f x)\right ) \operatorname {Subst}\left (\int \frac {1}{c+x} \, dx,x,-c \sin (e+f x)\right )}{c^3 f \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}\\ &=\frac {\cos (e+f x) (a+a \sin (e+f x))^{7/2}}{2 c f (c-c \sin (e+f x))^{5/2}}-\frac {2 a \cos (e+f x) (a+a \sin (e+f x))^{5/2}}{c^2 f (c-c \sin (e+f x))^{3/2}}-\frac {24 a^4 \cos (e+f x) \log (1-\sin (e+f x))}{c^3 f \sqrt {a+a \sin (e+f x)} \sqrt {c-c \sin (e+f x)}}-\frac {12 a^3 \cos (e+f x) \sqrt {a+a \sin (e+f x)}}{c^3 f \sqrt {c-c \sin (e+f x)}}-\frac {3 a^2 \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{c^3 f \sqrt {c-c \sin (e+f x)}}\\ \end {align*}
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Mathematica [A] time = 6.55, size = 223, normalized size = 0.93 \[ \frac {a^3 \sqrt {a (\sin (e+f x)+1)} \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )^3 \left (-320 \sin (e+f x)-24 \sin (3 (e+f x))+\cos (4 (e+f x))+\cos (2 (e+f x)) \left (106-384 \log \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )\right )+1152 \log \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )-1536 \sin (e+f x) \log \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )+273\right )}{16 c^3 f (\sin (e+f x)-1)^3 \sqrt {c-c \sin (e+f x)} \left (\sin \left (\frac {1}{2} (e+f x)\right )+\cos \left (\frac {1}{2} (e+f x)\right )\right )} \]
Antiderivative was successfully verified.
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fricas [F] time = 2.28, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {{\left (3 \, a^{3} \cos \left (f x + e\right )^{4} - 4 \, a^{3} \cos \left (f x + e\right )^{2} + {\left (a^{3} \cos \left (f x + e\right )^{4} - 4 \, a^{3} \cos \left (f x + e\right )^{2}\right )} \sin \left (f x + e\right )\right )} \sqrt {a \sin \left (f x + e\right ) + a} \sqrt {-c \sin \left (f x + e\right ) + c}}{c^{4} \cos \left (f x + e\right )^{4} - 8 \, c^{4} \cos \left (f x + e\right )^{2} + 8 \, c^{4} + 4 \, {\left (c^{4} \cos \left (f x + e\right )^{2} - 2 \, c^{4}\right )} \sin \left (f x + e\right )}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.42, size = 365, normalized size = 1.53 \[ -\frac {\left (-\left (\cos ^{4}\left (f x +e \right )\right )+12 \left (\cos ^{2}\left (f x +e \right )\right ) \sin \left (f x +e \right )+96 \left (\cos ^{2}\left (f x +e \right )\right ) \ln \left (-\frac {-1+\cos \left (f x +e \right )+\sin \left (f x +e \right )}{\sin \left (f x +e \right )}\right )-48 \left (\cos ^{2}\left (f x +e \right )\right ) \ln \left (\frac {2}{\cos \left (f x +e \right )+1}\right )+192 \sin \left (f x +e \right ) \ln \left (-\frac {-1+\cos \left (f x +e \right )+\sin \left (f x +e \right )}{\sin \left (f x +e \right )}\right )-96 \sin \left (f x +e \right ) \ln \left (\frac {2}{\cos \left (f x +e \right )+1}\right )-73 \left (\cos ^{2}\left (f x +e \right )\right )-58 \sin \left (f x +e \right )-192 \ln \left (-\frac {-1+\cos \left (f x +e \right )+\sin \left (f x +e \right )}{\sin \left (f x +e \right )}\right )+96 \ln \left (\frac {2}{\cos \left (f x +e \right )+1}\right )+74\right ) \left (\sin \left (f x +e \right ) \cos \left (f x +e \right )-\left (\cos ^{2}\left (f x +e \right )\right )-2 \sin \left (f x +e \right )-\cos \left (f x +e \right )+2\right ) \left (a \left (1+\sin \left (f x +e \right )\right )\right )^{\frac {7}{2}}}{2 f \left (\sin \left (f x +e \right ) \left (\cos ^{3}\left (f x +e \right )\right )+\cos ^{4}\left (f x +e \right )-4 \left (\cos ^{2}\left (f x +e \right )\right ) \sin \left (f x +e \right )+3 \left (\cos ^{3}\left (f x +e \right )\right )-4 \sin \left (f x +e \right ) \cos \left (f x +e \right )-8 \left (\cos ^{2}\left (f x +e \right )\right )+8 \sin \left (f x +e \right )-4 \cos \left (f x +e \right )+8\right ) \left (-c \left (\sin \left (f x +e \right )-1\right )\right )^{\frac {7}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.54, size = 1396, normalized size = 5.84 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\cos \left (e+f\,x\right )}^2\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^{7/2}}{{\left (c-c\,\sin \left (e+f\,x\right )\right )}^{7/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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