3.17 \(\int \frac {(a m x^m+b n q \log ^{-1+q}(c x^n)) (a x^m+b \log ^q(c x^n))^2}{x} \, dx\)

Optimal. Leaf size=22 \[ \frac {1}{3} \left (a x^m+b \log ^q\left (c x^n\right )\right )^3 \]

[Out]

1/3*(a*x^m+b*ln(c*x^n)^q)^3

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Rubi [A]  time = 0.17, antiderivative size = 22, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 43, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.023, Rules used = {2544} \[ \frac {1}{3} \left (a x^m+b \log ^q\left (c x^n\right )\right )^3 \]

Antiderivative was successfully verified.

[In]

Int[((a*m*x^m + b*n*q*Log[c*x^n]^(-1 + q))*(a*x^m + b*Log[c*x^n]^q)^2)/x,x]

[Out]

(a*x^m + b*Log[c*x^n]^q)^3/3

Rule 2544

Int[((Log[(c_.)*(x_)^(n_.)]^(q_)*(b_.) + (a_.)*(x_)^(m_.))^(p_.)*(Log[(c_.)*(x_)^(n_.)]^(r_.)*(e_.) + (d_.)*(x
_)^(m_.)))/(x_), x_Symbol] :> Simp[(e*(a*x^m + b*Log[c*x^n]^q)^(p + 1))/(b*n*q*(p + 1)), x] /; FreeQ[{a, b, c,
d, e, m, n, p, q, r}, x] && EqQ[r, q - 1] && NeQ[p, -1] && EqQ[a*e*m - b*d*n*q, 0]

Rubi steps

\begin {align*} \int \frac {\left (a m x^m+b n q \log ^{-1+q}\left (c x^n\right )\right ) \left (a x^m+b \log ^q\left (c x^n\right )\right )^2}{x} \, dx &=\frac {1}{3} \left (a x^m+b \log ^q\left (c x^n\right )\right )^3\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 22, normalized size = 1.00 \[ \frac {1}{3} \left (a x^m+b \log ^q\left (c x^n\right )\right )^3 \]

Antiderivative was successfully verified.

[In]

Integrate[((a*m*x^m + b*n*q*Log[c*x^n]^(-1 + q))*(a*x^m + b*Log[c*x^n]^q)^2)/x,x]

[Out]

(a*x^m + b*Log[c*x^n]^q)^3/3

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fricas [B]  time = 0.44, size = 65, normalized size = 2.95 \[ {\left (n \log \relax (x) + \log \relax (c)\right )}^{q} a^{2} b x^{2 \, m} + {\left (n \log \relax (x) + \log \relax (c)\right )}^{2 \, q} a b^{2} x^{m} + \frac {1}{3} \, {\left (n \log \relax (x) + \log \relax (c)\right )}^{3 \, q} b^{3} + \frac {1}{3} \, a^{3} x^{3 \, m} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*m*x^m+b*n*q*log(c*x^n)^(-1+q))*(a*x^m+b*log(c*x^n)^q)^2/x,x, algorithm="fricas")

[Out]

(n*log(x) + log(c))^q*a^2*b*x^(2*m) + (n*log(x) + log(c))^(2*q)*a*b^2*x^m + 1/3*(n*log(x) + log(c))^(3*q)*b^3
+ 1/3*a^3*x^(3*m)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b n q \log \left (c x^{n}\right )^{q - 1} + a m x^{m}\right )} {\left (a x^{m} + b \log \left (c x^{n}\right )^{q}\right )}^{2}}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*m*x^m+b*n*q*log(c*x^n)^(-1+q))*(a*x^m+b*log(c*x^n)^q)^2/x,x, algorithm="giac")

[Out]

integrate((b*n*q*log(c*x^n)^(q - 1) + a*m*x^m)*(a*x^m + b*log(c*x^n)^q)^2/x, x)

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maple [C]  time = 0.66, size = 204, normalized size = 9.27 \[ a^{2} b \,x^{2 m} \left (-\frac {i \pi \left (\mathrm {csgn}\left (i c \right )-\mathrm {csgn}\left (i c \,x^{n}\right )\right ) \left (\mathrm {csgn}\left (i x^{n}\right )-\mathrm {csgn}\left (i c \,x^{n}\right )\right ) \mathrm {csgn}\left (i c \,x^{n}\right )}{2}+\ln \relax (c )+\ln \left (x^{n}\right )\right )^{q}+a \,b^{2} x^{m} \left (-\frac {i \pi \left (\mathrm {csgn}\left (i c \right )-\mathrm {csgn}\left (i c \,x^{n}\right )\right ) \left (\mathrm {csgn}\left (i x^{n}\right )-\mathrm {csgn}\left (i c \,x^{n}\right )\right ) \mathrm {csgn}\left (i c \,x^{n}\right )}{2}+\ln \relax (c )+\ln \left (x^{n}\right )\right )^{2 q}+\frac {a^{3} x^{3 m}}{3}+\frac {b^{3} \left (-\frac {i \pi \left (\mathrm {csgn}\left (i c \right )-\mathrm {csgn}\left (i c \,x^{n}\right )\right ) \left (\mathrm {csgn}\left (i x^{n}\right )-\mathrm {csgn}\left (i c \,x^{n}\right )\right ) \mathrm {csgn}\left (i c \,x^{n}\right )}{2}+\ln \relax (c )+\ln \left (x^{n}\right )\right )^{3 q}}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*n*q*ln(c*x^n)^(q-1)+a*m*x^m)*(a*x^m+b*ln(c*x^n)^q)^2/x,x)

[Out]

1/3*a^3*(x^m)^3+1/3*b^3*((ln(c)+ln(x^n)-1/2*I*Pi*csgn(I*c*x^n)*(-csgn(I*c*x^n)+csgn(I*c))*(-csgn(I*c*x^n)+csgn
(I*x^n)))^q)^3+a*b^2*x^m*((ln(c)+ln(x^n)-1/2*I*Pi*csgn(I*c*x^n)*(-csgn(I*c*x^n)+csgn(I*c))*(-csgn(I*c*x^n)+csg
n(I*x^n)))^q)^2+a^2*b*(x^m)^2*(ln(c)+ln(x^n)-1/2*I*Pi*csgn(I*c*x^n)*(-csgn(I*c*x^n)+csgn(I*c))*(-csgn(I*c*x^n)
+csgn(I*x^n)))^q

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*m*x^m+b*n*q*log(c*x^n)^(-1+q))*(a*x^m+b*log(c*x^n)^q)^2/x,x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: In function CAR, the value of the first argument is  0which is not
of the expected type LIST

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mupad [B]  time = 0.70, size = 20, normalized size = 0.91 \[ \frac {{\left (a\,x^m+b\,{\ln \left (c\,x^n\right )}^q\right )}^3}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a*m*x^m + b*n*q*log(c*x^n)^(q - 1))*(a*x^m + b*log(c*x^n)^q)^2)/x,x)

[Out]

(a*x^m + b*log(c*x^n)^q)^3/3

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*m*x**m+b*n*q*ln(c*x**n)**(-1+q))*(a*x**m+b*ln(c*x**n)**q)**2/x,x)

[Out]

Timed out

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