3.134 \(\int \frac {1}{x \sqrt {-3+\log ^2(x)}} \, dx\)

Optimal. Leaf size=14 \[ \tanh ^{-1}\left (\frac {\log (x)}{\sqrt {\log ^2(x)-3}}\right ) \]

[Out]

arctanh(ln(x)/(-3+ln(x)^2)^(1/2))

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Rubi [A]  time = 0.03, antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {217, 206} \[ \tanh ^{-1}\left (\frac {\log (x)}{\sqrt {\log ^2(x)-3}}\right ) \]

Antiderivative was successfully verified.

[In]

Int[1/(x*Sqrt[-3 + Log[x]^2]),x]

[Out]

ArcTanh[Log[x]/Sqrt[-3 + Log[x]^2]]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
 /; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rubi steps

\begin {align*} \int \frac {1}{x \sqrt {-3+\log ^2(x)}} \, dx &=\operatorname {Subst}\left (\int \frac {1}{\sqrt {-3+x^2}} \, dx,x,\log (x)\right )\\ &=\operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {\log (x)}{\sqrt {-3+\log ^2(x)}}\right )\\ &=\tanh ^{-1}\left (\frac {\log (x)}{\sqrt {-3+\log ^2(x)}}\right )\\ \end {align*}

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Mathematica [B]  time = 0.02, size = 42, normalized size = 3.00 \[ \frac {1}{2} \log \left (\frac {\log (x)}{\sqrt {\log ^2(x)-3}}+1\right )-\frac {1}{2} \log \left (1-\frac {\log (x)}{\sqrt {\log ^2(x)-3}}\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x*Sqrt[-3 + Log[x]^2]),x]

[Out]

-1/2*Log[1 - Log[x]/Sqrt[-3 + Log[x]^2]] + Log[1 + Log[x]/Sqrt[-3 + Log[x]^2]]/2

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fricas [A]  time = 0.72, size = 16, normalized size = 1.14 \[ -\log \left (\sqrt {\log \relax (x)^{2} - 3} - \log \relax (x)\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(-3+log(x)^2)^(1/2),x, algorithm="fricas")

[Out]

-log(sqrt(log(x)^2 - 3) - log(x))

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giac [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(-3+log(x)^2)^(1/2),x, algorithm="giac")

[Out]

Timed out

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maple [A]  time = 0.07, size = 13, normalized size = 0.93 \[ \ln \left (\ln \relax (x )+\sqrt {\ln \relax (x )^{2}-3}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x/(-3+ln(x)^2)^(1/2),x)

[Out]

ln(ln(x)+(-3+ln(x)^2)^(1/2))

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maxima [A]  time = 0.51, size = 16, normalized size = 1.14 \[ \log \left (2 \, \sqrt {\log \relax (x)^{2} - 3} + 2 \, \log \relax (x)\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(-3+log(x)^2)^(1/2),x, algorithm="maxima")

[Out]

log(2*sqrt(log(x)^2 - 3) + 2*log(x))

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mupad [B]  time = 0.47, size = 12, normalized size = 0.86 \[ \ln \left (\ln \relax (x)+\sqrt {{\ln \relax (x)}^2-3}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x*(log(x)^2 - 3)^(1/2)),x)

[Out]

log(log(x) + (log(x)^2 - 3)^(1/2))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{x \sqrt {\log {\relax (x )}^{2} - 3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(-3+ln(x)**2)**(1/2),x)

[Out]

Integral(1/(x*sqrt(log(x)**2 - 3)), x)

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