3.842 \(\int \frac {1}{\sqrt {15-2 x-x^2}} \, dx\)

Optimal. Leaf size=12 \[ -\sin ^{-1}\left (\frac {1}{4} (-x-1)\right ) \]

[Out]

arcsin(1/4+1/4*x)

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Rubi [A]  time = 0.01, antiderivative size = 12, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {619, 216} \[ -\sin ^{-1}\left (\frac {1}{4} (-x-1)\right ) \]

Antiderivative was successfully verified.

[In]

Int[1/Sqrt[15 - 2*x - x^2],x]

[Out]

-ArcSin[(-1 - x)/4]

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rule 619

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dist[1/(2*c*((-4*c)/(b^2 - 4*a*c))^p), Subst[Int[Si
mp[1 - x^2/(b^2 - 4*a*c), x]^p, x], x, b + 2*c*x], x] /; FreeQ[{a, b, c, p}, x] && GtQ[4*a - b^2/c, 0]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {15-2 x-x^2}} \, dx &=-\left (\frac {1}{8} \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^2}{64}}} \, dx,x,-2-2 x\right )\right )\\ &=-\sin ^{-1}\left (\frac {1}{4} (-1-x)\right )\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 12, normalized size = 1.00 \[ -\sin ^{-1}\left (\frac {1}{4} (-x-1)\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[1/Sqrt[15 - 2*x - x^2],x]

[Out]

-ArcSin[(-1 - x)/4]

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fricas [B]  time = 0.44, size = 29, normalized size = 2.42 \[ -\arctan \left (\frac {\sqrt {-x^{2} - 2 \, x + 15} {\left (x + 1\right )}}{x^{2} + 2 \, x - 15}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-x^2-2*x+15)^(1/2),x, algorithm="fricas")

[Out]

-arctan(sqrt(-x^2 - 2*x + 15)*(x + 1)/(x^2 + 2*x - 15))

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giac [A]  time = 0.42, size = 6, normalized size = 0.50 \[ \arcsin \left (\frac {1}{4} \, x + \frac {1}{4}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-x^2-2*x+15)^(1/2),x, algorithm="giac")

[Out]

arcsin(1/4*x + 1/4)

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maple [A]  time = 0.00, size = 7, normalized size = 0.58 \[ \arcsin \left (\frac {x}{4}+\frac {1}{4}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-x^2-2*x+15)^(1/2),x)

[Out]

arcsin(1/4+1/4*x)

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maxima [A]  time = 1.97, size = 8, normalized size = 0.67 \[ -\arcsin \left (-\frac {1}{4} \, x - \frac {1}{4}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-x^2-2*x+15)^(1/2),x, algorithm="maxima")

[Out]

-arcsin(-1/4*x - 1/4)

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mupad [B]  time = 3.12, size = 6, normalized size = 0.50 \[ \mathrm {asin}\left (\frac {x}{4}+\frac {1}{4}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(15 - x^2 - 2*x)^(1/2),x)

[Out]

asin(x/4 + 1/4)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {- x^{2} - 2 x + 15}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-x**2-2*x+15)**(1/2),x)

[Out]

Integral(1/sqrt(-x**2 - 2*x + 15), x)

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