Optimal. Leaf size=52 \[ \frac {\sqrt {x^3} \tan ^{-1}\left (\sqrt {x}\right )}{x^{3/2}}-\frac {\sqrt {x^3} \tanh ^{-1}\left (\sqrt {x}\right )}{x^{3/2}}+\tan ^{-1}\left (\sqrt {x}\right )+\tanh ^{-1}\left (\sqrt {x}\right ) \]
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Rubi [A] time = 0.18, antiderivative size = 52, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 8, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {1593, 6725, 329, 212, 206, 203, 15, 298} \[ \frac {\sqrt {x^3} \tan ^{-1}\left (\sqrt {x}\right )}{x^{3/2}}-\frac {\sqrt {x^3} \tanh ^{-1}\left (\sqrt {x}\right )}{x^{3/2}}+\tan ^{-1}\left (\sqrt {x}\right )+\tanh ^{-1}\left (\sqrt {x}\right ) \]
Antiderivative was successfully verified.
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Rule 15
Rule 203
Rule 206
Rule 212
Rule 298
Rule 329
Rule 1593
Rule 6725
Rubi steps
\begin {align*} \int \frac {\sqrt {x}-\sqrt {x^3}}{x-x^3} \, dx &=\int \frac {\sqrt {x}-\sqrt {x^3}}{x \left (1-x^2\right )} \, dx\\ &=\int \left (-\frac {1}{\sqrt {x} \left (-1+x^2\right )}+\frac {\sqrt {x^3}}{x \left (-1+x^2\right )}\right ) \, dx\\ &=-\int \frac {1}{\sqrt {x} \left (-1+x^2\right )} \, dx+\int \frac {\sqrt {x^3}}{x \left (-1+x^2\right )} \, dx\\ &=-\left (2 \operatorname {Subst}\left (\int \frac {1}{-1+x^4} \, dx,x,\sqrt {x}\right )\right )+\frac {\sqrt {x^3} \int \frac {\sqrt {x}}{-1+x^2} \, dx}{x^{3/2}}\\ &=\frac {\left (2 \sqrt {x^3}\right ) \operatorname {Subst}\left (\int \frac {x^2}{-1+x^4} \, dx,x,\sqrt {x}\right )}{x^{3/2}}+\operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\sqrt {x}\right )+\operatorname {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\sqrt {x}\right )\\ &=\tan ^{-1}\left (\sqrt {x}\right )+\tanh ^{-1}\left (\sqrt {x}\right )-\frac {\sqrt {x^3} \operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\sqrt {x}\right )}{x^{3/2}}+\frac {\sqrt {x^3} \operatorname {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\sqrt {x}\right )}{x^{3/2}}\\ &=\tan ^{-1}\left (\sqrt {x}\right )+\frac {\sqrt {x^3} \tan ^{-1}\left (\sqrt {x}\right )}{x^{3/2}}+\tanh ^{-1}\left (\sqrt {x}\right )-\frac {\sqrt {x^3} \tanh ^{-1}\left (\sqrt {x}\right )}{x^{3/2}}\\ \end {align*}
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Mathematica [A] time = 0.06, size = 49, normalized size = 0.94 \[ \frac {\left (x^{3/2}+\sqrt {x^3}\right ) \tan ^{-1}\left (\sqrt {x}\right )+\left (x^{3/2}-\sqrt {x^3}\right ) \tanh ^{-1}\left (\sqrt {x}\right )}{x^{3/2}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.41, size = 6, normalized size = 0.12 \[ 2 \, \arctan \left (\sqrt {x}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.32, size = 6, normalized size = 0.12 \[ 2 \, \arctan \left (\sqrt {x}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 41, normalized size = 0.79 \[ \arctanh \left (\sqrt {x}\right )+\arctan \left (\sqrt {x}\right )+\frac {\sqrt {x^{3}}\, \left (2 \arctan \left (\sqrt {x}\right )+\ln \left (\sqrt {x}-1\right )-\ln \left (\sqrt {x}+1\right )\right )}{2 x^{\frac {3}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \arctan \left (\sqrt {x}\right ) - \int \frac {\sqrt {x}}{2 \, {\left (x + 1\right )}}\,{d x} + \int \frac {1}{4 \, {\left (\sqrt {x} + 1\right )}}\,{d x} + \int \frac {1}{4 \, {\left (\sqrt {x} - 1\right )}}\,{d x} + \frac {1}{2} \, \log \left (\sqrt {x} + 1\right ) - \frac {1}{2} \, \log \left (\sqrt {x} - 1\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.02 \[ -\int \frac {\sqrt {x^3}-\sqrt {x}}{x-x^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ - \int \frac {\sqrt {x}}{x^{3} - x}\, dx - \int \left (- \frac {\sqrt {x^{3}}}{x^{3} - x}\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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