3.599 \(\int \frac {\sqrt {b-\frac {a}{x^2}}}{x \sqrt {a-b x^2}} \, dx\)

Optimal. Leaf size=26 \[ -\frac {\sqrt {b-\frac {a}{x^2}}}{\sqrt {a-b x^2}} \]

[Out]

-(b-a/x^2)^(1/2)/(-b*x^2+a)^(1/2)

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Rubi [A]  time = 0.03, antiderivative size = 26, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.107, Rules used = {515, 23, 30} \[ -\frac {\sqrt {b-\frac {a}{x^2}}}{\sqrt {a-b x^2}} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[b - a/x^2]/(x*Sqrt[a - b*x^2]),x]

[Out]

-(Sqrt[b - a/x^2]/Sqrt[a - b*x^2])

Rule 23

Int[(u_.)*((a_) + (b_.)*(v_))^(m_)*((c_) + (d_.)*(v_))^(n_), x_Symbol] :> Dist[(a + b*v)^m/(c + d*v)^m, Int[u*
(c + d*v)^(m + n), x], x] /; FreeQ[{a, b, c, d, m, n}, x] && EqQ[b*c - a*d, 0] &&  !(IntegerQ[m] || IntegerQ[n
] || GtQ[b/d, 0])

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 515

Int[(x_)^(m_.)*((c_) + (d_.)*(x_)^(mn_.))^(q_)*((a_) + (b_.)*(x_)^(n_.))^(p_.), x_Symbol] :> Dist[(x^(n*FracPa
rt[q])*(c + d/x^n)^FracPart[q])/(d + c*x^n)^FracPart[q], Int[x^(m - n*q)*(a + b*x^n)^p*(d + c*x^n)^q, x], x] /
; FreeQ[{a, b, c, d, m, n, p, q}, x] && EqQ[mn, -n] &&  !IntegerQ[q] &&  !IntegerQ[p]

Rubi steps

\begin {align*} \int \frac {\sqrt {b-\frac {a}{x^2}}}{x \sqrt {a-b x^2}} \, dx &=\frac {\left (\sqrt {b-\frac {a}{x^2}} x\right ) \int \frac {\sqrt {-a+b x^2}}{x^2 \sqrt {a-b x^2}} \, dx}{\sqrt {-a+b x^2}}\\ &=\frac {\left (\sqrt {b-\frac {a}{x^2}} x\right ) \int \frac {1}{x^2} \, dx}{\sqrt {a-b x^2}}\\ &=-\frac {\sqrt {b-\frac {a}{x^2}}}{\sqrt {a-b x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 26, normalized size = 1.00 \[ -\frac {\sqrt {b-\frac {a}{x^2}}}{\sqrt {a-b x^2}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[b - a/x^2]/(x*Sqrt[a - b*x^2]),x]

[Out]

-(Sqrt[b - a/x^2]/Sqrt[a - b*x^2])

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fricas [A]  time = 0.40, size = 41, normalized size = 1.58 \[ -\frac {\sqrt {-b x^{2} + a} {\left (x - 1\right )} \sqrt {\frac {b x^{2} - a}{x^{2}}}}{b x^{2} - a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b-a/x^2)^(1/2)/x/(-b*x^2+a)^(1/2),x, algorithm="fricas")

[Out]

-sqrt(-b*x^2 + a)*(x - 1)*sqrt((b*x^2 - a)/x^2)/(b*x^2 - a)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {b - \frac {a}{x^{2}}}}{\sqrt {-b x^{2} + a} x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b-a/x^2)^(1/2)/x/(-b*x^2+a)^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(b - a/x^2)/(sqrt(-b*x^2 + a)*x), x)

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maple [A]  time = 0.01, size = 28, normalized size = 1.08 \[ -\frac {\sqrt {-\frac {-b \,x^{2}+a}{x^{2}}}}{\sqrt {-b \,x^{2}+a}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b-a/x^2)^(1/2)/x/(-b*x^2+a)^(1/2),x)

[Out]

-(-(-b*x^2+a)/x^2)^(1/2)/(-b*x^2+a)^(1/2)

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maxima [C]  time = 1.11, size = 7, normalized size = 0.27 \[ \frac {i}{\sqrt {x^{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b-a/x^2)^(1/2)/x/(-b*x^2+a)^(1/2),x, algorithm="maxima")

[Out]

I/sqrt(x^2)

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mupad [B]  time = 3.34, size = 22, normalized size = 0.85 \[ -\frac {\sqrt {b-\frac {a}{x^2}}}{\sqrt {a-b\,x^2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b - a/x^2)^(1/2)/(x*(a - b*x^2)^(1/2)),x)

[Out]

-(b - a/x^2)^(1/2)/(a - b*x^2)^(1/2)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {- \frac {a}{x^{2}} + b}}{x \sqrt {a - b x^{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b-a/x**2)**(1/2)/x/(-b*x**2+a)**(1/2),x)

[Out]

Integral(sqrt(-a/x**2 + b)/(x*sqrt(a - b*x**2)), x)

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