Optimal. Leaf size=244 \[ -\frac {f^2 \left (4 a e-\frac {b^2 f^2}{e}\right ) \sqrt {f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}+d+e x}}{2 \left (2 d e-b f^2\right ) \left (2 e \left (f \sqrt {a+\frac {x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}+\frac {f^2 \left (4 a e^2-b^2 f^2\right ) \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt {e} \sqrt {f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}+d+e x}}{\sqrt {2 d e-b f^2}}\right )}{2 \sqrt {2} e^{3/2} \left (2 d e-b f^2\right )^{3/2}}+\frac {\sqrt {f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}+d+e x}}{e} \]
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Rubi [A] time = 0.29, antiderivative size = 244, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2116, 897, 1157, 388, 208} \[ -\frac {f^2 \left (4 a e-\frac {b^2 f^2}{e}\right ) \sqrt {f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}+d+e x}}{2 \left (2 d e-b f^2\right ) \left (2 e \left (f \sqrt {a+\frac {x \left (b f^2+e^2 x\right )}{f^2}}+e x\right )+b f^2\right )}+\frac {f^2 \left (4 a e^2-b^2 f^2\right ) \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt {e} \sqrt {f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}+d+e x}}{\sqrt {2 d e-b f^2}}\right )}{2 \sqrt {2} e^{3/2} \left (2 d e-b f^2\right )^{3/2}}+\frac {\sqrt {f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}+d+e x}}{e} \]
Antiderivative was successfully verified.
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Rule 208
Rule 388
Rule 897
Rule 1157
Rule 2116
Rubi steps
\begin {align*} \int \frac {1}{\sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}} \, dx &=2 \operatorname {Subst}\left (\int \frac {d^2 e-(b d-a e) f^2-\left (2 d e-b f^2\right ) x+e x^2}{\sqrt {x} \left (-2 d e+b f^2+2 e x\right )^2} \, dx,x,d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}\right )\\ &=4 \operatorname {Subst}\left (\int \frac {d^2 e-(b d-a e) f^2+\left (-2 d e+b f^2\right ) x^2+e x^4}{\left (-2 d e+b f^2+2 e x^2\right )^2} \, dx,x,\sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}\right )\\ &=-\frac {f^2 \left (4 a e-\frac {b^2 f^2}{e}\right ) \sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}}{2 \left (2 d e-b f^2\right ) \left (b f^2+2 e \left (e x+f \sqrt {a+\frac {x \left (b f^2+e^2 x\right )}{f^2}}\right )\right )}+\frac {2 \operatorname {Subst}\left (\int \frac {\frac {1}{4} \left (-8 d^2 e+8 b d f^2-4 a e f^2-\frac {b^2 f^4}{e}\right )+\left (2 d e-b f^2\right ) x^2}{-2 d e+b f^2+2 e x^2} \, dx,x,\sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}\right )}{2 d e-b f^2}\\ &=\frac {\sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}}{e}-\frac {f^2 \left (4 a e-\frac {b^2 f^2}{e}\right ) \sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}}{2 \left (2 d e-b f^2\right ) \left (b f^2+2 e \left (e x+f \sqrt {a+\frac {x \left (b f^2+e^2 x\right )}{f^2}}\right )\right )}-\frac {\left (f^2 \left (4 a e^2-b^2 f^2\right )\right ) \operatorname {Subst}\left (\int \frac {1}{-2 d e+b f^2+2 e x^2} \, dx,x,\sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}\right )}{2 e \left (2 d e-b f^2\right )}\\ &=\frac {\sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}}{e}-\frac {f^2 \left (4 a e-\frac {b^2 f^2}{e}\right ) \sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}}{2 \left (2 d e-b f^2\right ) \left (b f^2+2 e \left (e x+f \sqrt {a+\frac {x \left (b f^2+e^2 x\right )}{f^2}}\right )\right )}+\frac {f^2 \left (4 a e^2-b^2 f^2\right ) \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt {e} \sqrt {d+e x+f \sqrt {a+b x+\frac {e^2 x^2}{f^2}}}}{\sqrt {2 d e-b f^2}}\right )}{2 \sqrt {2} e^{3/2} \left (2 d e-b f^2\right )^{3/2}}\\ \end {align*}
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Mathematica [A] time = 0.57, size = 238, normalized size = 0.98 \[ \frac {f^2 \left (b^2 f^2-4 a e^2\right ) \sqrt {f \sqrt {a+x \left (b+\frac {e^2 x}{f^2}\right )}+d+e x}}{2 e \left (2 d e-b f^2\right ) \left (2 e \left (f \sqrt {a+x \left (b+\frac {e^2 x}{f^2}\right )}+e x\right )+b f^2\right )}+\frac {f^2 \left (4 a e^2-b^2 f^2\right ) \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt {e} \sqrt {f \sqrt {a+x \left (b+\frac {e^2 x}{f^2}\right )}+d+e x}}{\sqrt {2 d e-b f^2}}\right )}{2 \sqrt {2} e^{3/2} \left (2 d e-b f^2\right )^{3/2}}+\frac {\sqrt {f \sqrt {a+x \left (b+\frac {e^2 x}{f^2}\right )}+d+e x}}{e} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.71, size = 716, normalized size = 2.93 \[ \left [\frac {{\left (b^{2} f^{4} - 4 \, a e^{2} f^{2}\right )} \sqrt {-2 \, b e f^{2} + 4 \, d e^{2}} \log \left (-b^{2} f^{4} + 4 \, {\left (b d e - a e^{2}\right )} f^{2} - 4 \, {\left (b e^{2} f^{2} - 2 \, d e^{3}\right )} x + 2 \, {\left (2 \, \sqrt {-2 \, b e f^{2} + 4 \, d e^{2}} e f \sqrt {\frac {b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}} - \sqrt {-2 \, b e f^{2} + 4 \, d e^{2}} {\left (b f^{2} + 2 \, e^{2} x\right )}\right )} \sqrt {e x + f \sqrt {\frac {b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}} + d} + 4 \, {\left (b e f^{3} - 2 \, d e^{2} f\right )} \sqrt {\frac {b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}}\right ) + 4 \, {\left (b^{2} e f^{4} - 6 \, b d e^{2} f^{2} + 8 \, d^{2} e^{3} - 2 \, {\left (b e^{3} f^{2} - 2 \, d e^{4}\right )} x + 2 \, {\left (b e^{2} f^{3} - 2 \, d e^{3} f\right )} \sqrt {\frac {b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}}\right )} \sqrt {e x + f \sqrt {\frac {b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}} + d}}{8 \, {\left (b^{2} e^{2} f^{4} - 4 \, b d e^{3} f^{2} + 4 \, d^{2} e^{4}\right )}}, \frac {{\left (b^{2} f^{4} - 4 \, a e^{2} f^{2}\right )} \sqrt {2 \, b e f^{2} - 4 \, d e^{2}} \arctan \left (\frac {\sqrt {e x + f \sqrt {\frac {b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}} + d} {\left (\sqrt {2 \, b e f^{2} - 4 \, d e^{2}} f \sqrt {\frac {b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}} - \sqrt {2 \, b e f^{2} - 4 \, d e^{2}} {\left (e x + d\right )}\right )}}{2 \, {\left (a e f^{2} - d^{2} e + {\left (b e f^{2} - 2 \, d e^{2}\right )} x\right )}}\right ) + 2 \, {\left (b^{2} e f^{4} - 6 \, b d e^{2} f^{2} + 8 \, d^{2} e^{3} - 2 \, {\left (b e^{3} f^{2} - 2 \, d e^{4}\right )} x + 2 \, {\left (b e^{2} f^{3} - 2 \, d e^{3} f\right )} \sqrt {\frac {b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}}\right )} \sqrt {e x + f \sqrt {\frac {b f^{2} x + e^{2} x^{2} + a f^{2}}{f^{2}}} + d}}{4 \, {\left (b^{2} e^{2} f^{4} - 4 \, b d e^{3} f^{2} + 4 \, d^{2} e^{4}\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {e x + \sqrt {b x + \frac {e^{2} x^{2}}{f^{2}} + a} f + d}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.02, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {e x +d +\sqrt {b x +\frac {e^{2} x^{2}}{f^{2}}+a}\, f}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {e x + \sqrt {b x + \frac {e^{2} x^{2}}{f^{2}} + a} f + d}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {1}{\sqrt {d+e\,x+f\,\sqrt {a+b\,x+\frac {e^2\,x^2}{f^2}}}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {d + e x + f \sqrt {a + b x + \frac {e^{2} x^{2}}{f^{2}}}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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