3.471 \(\int \sqrt {a+b \sqrt {\frac {a^2}{b^2}+c x^2}} \, dx\)

Optimal. Leaf size=66 \[ \frac {2 a x}{\sqrt {b \sqrt {\frac {a^2}{b^2}+c x^2}+a}}+\frac {2 b^2 c x^3}{3 \left (b \sqrt {\frac {a^2}{b^2}+c x^2}+a\right )^{3/2}} \]

[Out]

2/3*b^2*c*x^3/(a+b*(1/b^2*a^2+c*x^2)^(1/2))^(3/2)+2*a*x/(a+b*(1/b^2*a^2+c*x^2)^(1/2))^(1/2)

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Rubi [A]  time = 0.03, antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.040, Rules used = {2129} \[ \frac {2 b^2 c x^3}{3 \left (b \sqrt {\frac {a^2}{b^2}+c x^2}+a\right )^{3/2}}+\frac {2 a x}{\sqrt {b \sqrt {\frac {a^2}{b^2}+c x^2}+a}} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[a + b*Sqrt[a^2/b^2 + c*x^2]],x]

[Out]

(2*b^2*c*x^3)/(3*(a + b*Sqrt[a^2/b^2 + c*x^2])^(3/2)) + (2*a*x)/Sqrt[a + b*Sqrt[a^2/b^2 + c*x^2]]

Rule 2129

Int[Sqrt[(a_) + (b_.)*Sqrt[(c_) + (d_.)*(x_)^2]], x_Symbol] :> Simp[(2*b^2*d*x^3)/(3*(a + b*Sqrt[c + d*x^2])^(
3/2)), x] + Simp[(2*a*x)/Sqrt[a + b*Sqrt[c + d*x^2]], x] /; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2*c, 0]

Rubi steps

\begin {align*} \int \sqrt {a+b \sqrt {\frac {a^2}{b^2}+c x^2}} \, dx &=\frac {2 b^2 c x^3}{3 \left (a+b \sqrt {\frac {a^2}{b^2}+c x^2}\right )^{3/2}}+\frac {2 a x}{\sqrt {a+b \sqrt {\frac {a^2}{b^2}+c x^2}}}\\ \end {align*}

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Mathematica [A]  time = 0.23, size = 55, normalized size = 0.83 \[ \frac {2 b x \sqrt {\frac {a^2}{b^2}+c x^2}+4 a x}{3 \sqrt {b \sqrt {\frac {a^2}{b^2}+c x^2}+a}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[a + b*Sqrt[a^2/b^2 + c*x^2]],x]

[Out]

(4*a*x + 2*b*x*Sqrt[a^2/b^2 + c*x^2])/(3*Sqrt[a + b*Sqrt[a^2/b^2 + c*x^2]])

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fricas [A]  time = 0.57, size = 70, normalized size = 1.06 \[ \frac {2 \, {\left (b^{2} c x^{2} + a b \sqrt {\frac {b^{2} c x^{2} + a^{2}}{b^{2}}} - a^{2}\right )} \sqrt {b \sqrt {\frac {b^{2} c x^{2} + a^{2}}{b^{2}}} + a}}{3 \, b^{2} c x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(1/b^2*a^2+c*x^2)^(1/2))^(1/2),x, algorithm="fricas")

[Out]

2/3*(b^2*c*x^2 + a*b*sqrt((b^2*c*x^2 + a^2)/b^2) - a^2)*sqrt(b*sqrt((b^2*c*x^2 + a^2)/b^2) + a)/(b^2*c*x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {\sqrt {c x^{2} + \frac {a^{2}}{b^{2}}} b + a}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(1/b^2*a^2+c*x^2)^(1/2))^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(sqrt(c*x^2 + a^2/b^2)*b + a), x)

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maple [F]  time = 0.04, size = 0, normalized size = 0.00 \[ \int \sqrt {a +\sqrt {c \,x^{2}+\frac {a^{2}}{b^{2}}}\, b}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*(a^2/b^2+c*x^2)^(1/2))^(1/2),x)

[Out]

int((a+b*(a^2/b^2+c*x^2)^(1/2))^(1/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {\sqrt {c x^{2} + \frac {a^{2}}{b^{2}}} b + a}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(1/b^2*a^2+c*x^2)^(1/2))^(1/2),x, algorithm="maxima")

[Out]

integrate(sqrt(sqrt(c*x^2 + a^2/b^2)*b + a), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \sqrt {a+b\,\sqrt {c\,x^2+\frac {a^2}{b^2}}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*(c*x^2 + a^2/b^2)^(1/2))^(1/2),x)

[Out]

int((a + b*(c*x^2 + a^2/b^2)^(1/2))^(1/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {a + b \sqrt {\frac {a^{2}}{b^{2}} + c x^{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*(a**2/b**2+c*x**2)**(1/2))**(1/2),x)

[Out]

Integral(sqrt(a + b*sqrt(a**2/b**2 + c*x**2)), x)

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