Optimal. Leaf size=135 \[ \frac {\left (d^3+e^3 x^3\right )^p \left (1+\frac {2 (d+e x)}{\left (-3+i \sqrt {3}\right ) d}\right )^{-p} \left (1-\frac {2 (d+e x)}{\left (3+i \sqrt {3}\right ) d}\right )^{-p} F_1\left (p;-p,-p;p+1;-\frac {2 (d+e x)}{\left (-3+i \sqrt {3}\right ) d},\frac {2 (d+e x)}{\left (3+i \sqrt {3}\right ) d}\right )}{e p} \]
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Rubi [F] time = 0.09, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\left (d^3+e^3 x^3\right )^p}{d+e x} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin {align*} \int \frac {\left (d^3+e^3 x^3\right )^p}{d+e x} \, dx &=\int \frac {\left (d^3+e^3 x^3\right )^p}{d+e x} \, dx\\ \end {align*}
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Mathematica [F] time = 0.05, size = 0, normalized size = 0.00 \[ \int \frac {\left (d^3+e^3 x^3\right )^p}{d+e x} \, dx \]
Verification is Not applicable to the result.
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fricas [F] time = 0.46, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (e^{3} x^{3} + d^{3}\right )}^{p}}{e x + d}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (e^{3} x^{3} + d^{3}\right )}^{p}}{e x + d}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.07, size = 0, normalized size = 0.00 \[ \int \frac {\left (e^{3} x^{3}+d^{3}\right )^{p}}{e x +d}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (e^{3} x^{3} + d^{3}\right )}^{p}}{e x + d}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (d^3+e^3\,x^3\right )}^p}{d+e\,x} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 30.80, size = 636, normalized size = 4.71 \[ \frac {0^{p} \log {\left (1 + \frac {e^{3} x^{3}}{d^{3}} \right )} \Gamma \left (- \frac {2}{3}\right ) \Gamma \left (- \frac {1}{3}\right ) \Gamma \left (\frac {4}{3}\right ) \Gamma \left (\frac {5}{3}\right )}{4 \pi ^{2} e} + \frac {0^{p} e^{\frac {i \pi }{3}} \log {\left (1 - \frac {e x e^{\frac {i \pi }{3}}}{d} \right )} \Gamma \left (- \frac {1}{3}\right ) \Gamma \left (\frac {1}{3}\right ) \Gamma ^{2}\left (\frac {2}{3}\right ) \Gamma \left (\frac {4}{3}\right )}{6 \pi ^{2} e \Gamma \left (\frac {5}{3}\right )} + \frac {0^{p} e^{\frac {2 i \pi }{3}} \log {\left (1 - \frac {e x e^{\frac {i \pi }{3}}}{d} \right )} \Gamma ^{3}\left (\frac {1}{3}\right ) \Gamma ^{2}\left (\frac {2}{3}\right )}{12 \pi ^{2} e \Gamma \left (\frac {4}{3}\right )} - \frac {0^{p} \log {\left (1 - \frac {e x e^{i \pi }}{d} \right )} \Gamma \left (- \frac {1}{3}\right ) \Gamma \left (\frac {1}{3}\right ) \Gamma ^{2}\left (\frac {2}{3}\right ) \Gamma \left (\frac {4}{3}\right )}{6 \pi ^{2} e \Gamma \left (\frac {5}{3}\right )} + \frac {0^{p} \log {\left (1 - \frac {e x e^{i \pi }}{d} \right )} \Gamma ^{3}\left (\frac {1}{3}\right ) \Gamma ^{2}\left (\frac {2}{3}\right )}{12 \pi ^{2} e \Gamma \left (\frac {4}{3}\right )} + \frac {0^{p} e^{- \frac {2 i \pi }{3}} \log {\left (1 - \frac {e x e^{\frac {5 i \pi }{3}}}{d} \right )} \Gamma ^{3}\left (\frac {1}{3}\right ) \Gamma ^{2}\left (\frac {2}{3}\right )}{12 \pi ^{2} e \Gamma \left (\frac {4}{3}\right )} + \frac {0^{p} e^{- \frac {i \pi }{3}} \log {\left (1 - \frac {e x e^{\frac {5 i \pi }{3}}}{d} \right )} \Gamma \left (- \frac {1}{3}\right ) \Gamma \left (\frac {1}{3}\right ) \Gamma ^{2}\left (\frac {2}{3}\right ) \Gamma \left (\frac {4}{3}\right )}{6 \pi ^{2} e \Gamma \left (\frac {5}{3}\right )} - \frac {d^{2} e^{3 p} p x^{3 p} \Gamma \left (- \frac {2}{3}\right ) \Gamma \left (- \frac {1}{3}\right ) \Gamma \left (\frac {4}{3}\right ) \Gamma \left (\frac {5}{3}\right ) \Gamma \relax (p) \Gamma \left (\frac {2}{3} - p\right ) {{}_{2}F_{1}\left (\begin {matrix} 1 - p, \frac {2}{3} - p \\ \frac {5}{3} - p \end {matrix}\middle | {\frac {d^{3} e^{i \pi }}{e^{3} x^{3}}} \right )}}{4 \pi ^{2} e^{3} x^{2} \Gamma \left (\frac {5}{3} - p\right ) \Gamma \left (p + 1\right )} - \frac {d e^{3 p} p x^{3 p} \Gamma \left (- \frac {1}{3}\right ) \Gamma \left (\frac {1}{3}\right ) \Gamma \left (\frac {2}{3}\right ) \Gamma \left (\frac {4}{3}\right ) \Gamma \relax (p) \Gamma \left (\frac {1}{3} - p\right ) {{}_{2}F_{1}\left (\begin {matrix} 1 - p, \frac {1}{3} - p \\ \frac {4}{3} - p \end {matrix}\middle | {\frac {d^{3} e^{i \pi }}{e^{3} x^{3}}} \right )}}{4 \pi ^{2} e^{2} x \Gamma \left (\frac {4}{3} - p\right ) \Gamma \left (p + 1\right )} - \frac {d^{3 p} e^{2} x^{3} \Gamma ^{2}\left (\frac {1}{3}\right ) \Gamma ^{2}\left (\frac {2}{3}\right ) \Gamma \relax (p) \Gamma \left (1 - p\right ) {{}_{3}F_{2}\left (\begin {matrix} 2, 1, 1 - p \\ 2, 2 \end {matrix}\middle | {\frac {e^{3} x^{3} e^{i \pi }}{d^{3}}} \right )}}{4 \pi ^{2} d^{3} \Gamma \left (- p\right ) \Gamma \left (p + 1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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