Optimal. Leaf size=263 \[ \frac {1}{4} \sqrt {\frac {3}{13}} \tan ^{-1}\left (\frac {-5 x^2+12 x+8}{\sqrt {39} x^2}\right )-\frac {1}{8} \sqrt {\frac {235 \sqrt {517}-5167}{40326}} \log \left (\left (\frac {4}{x}+3\right )^2-\sqrt {2 \left (19+\sqrt {517}\right )} \left (\frac {4}{x}+3\right )+\sqrt {517}\right )+\frac {1}{8} \sqrt {\frac {235 \sqrt {517}-5167}{40326}} \log \left (\left (\frac {4}{x}+3\right )^2+\sqrt {2 \left (19+\sqrt {517}\right )} \left (\frac {4}{x}+3\right )+\sqrt {517}\right )-\frac {1}{4} \sqrt {\frac {5167+235 \sqrt {517}}{40326}} \tan ^{-1}\left (\frac {\frac {8}{x}-\sqrt {2 \left (19+\sqrt {517}\right )}+6}{\sqrt {2 \left (\sqrt {517}-19\right )}}\right )-\frac {1}{4} \sqrt {\frac {5167+235 \sqrt {517}}{40326}} \tan ^{-1}\left (\frac {\frac {8}{x}+\sqrt {2 \left (19+\sqrt {517}\right )}+6}{\sqrt {2 \left (\sqrt {517}-19\right )}}\right ) \]
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Rubi [A] time = 0.49, antiderivative size = 263, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 9, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.409, Rules used = {2069, 12, 1673, 1169, 634, 618, 204, 628, 1107} \[ \frac {1}{4} \sqrt {\frac {3}{13}} \tan ^{-1}\left (\frac {-5 x^2+12 x+8}{\sqrt {39} x^2}\right )-\frac {1}{8} \sqrt {\frac {235 \sqrt {517}-5167}{40326}} \log \left (\left (\frac {4}{x}+3\right )^2-\sqrt {2 \left (19+\sqrt {517}\right )} \left (\frac {4}{x}+3\right )+\sqrt {517}\right )+\frac {1}{8} \sqrt {\frac {235 \sqrt {517}-5167}{40326}} \log \left (\left (\frac {4}{x}+3\right )^2+\sqrt {2 \left (19+\sqrt {517}\right )} \left (\frac {4}{x}+3\right )+\sqrt {517}\right )-\frac {1}{4} \sqrt {\frac {5167+235 \sqrt {517}}{40326}} \tan ^{-1}\left (\frac {\frac {8}{x}-\sqrt {2 \left (19+\sqrt {517}\right )}+6}{\sqrt {2 \left (\sqrt {517}-19\right )}}\right )-\frac {1}{4} \sqrt {\frac {5167+235 \sqrt {517}}{40326}} \tan ^{-1}\left (\frac {\frac {8}{x}+\sqrt {2 \left (19+\sqrt {517}\right )}+6}{\sqrt {2 \left (\sqrt {517}-19\right )}}\right ) \]
Antiderivative was successfully verified.
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Rule 12
Rule 204
Rule 618
Rule 628
Rule 634
Rule 1107
Rule 1169
Rule 1673
Rule 2069
Rubi steps
\begin {align*} \int \frac {1}{8+24 x+8 x^2-15 x^3+8 x^4} \, dx &=-\left (1024 \operatorname {Subst}\left (\int \frac {(24-32 x)^2}{8 \left (2117632-2490368 x^2+1048576 x^4\right )} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )\right )\\ &=-\left (128 \operatorname {Subst}\left (\int \frac {(24-32 x)^2}{2117632-2490368 x^2+1048576 x^4} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )\right )\\ &=-\left (128 \operatorname {Subst}\left (\int -\frac {1536 x}{2117632-2490368 x^2+1048576 x^4} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )\right )-128 \operatorname {Subst}\left (\int \frac {576+1024 x^2}{2117632-2490368 x^2+1048576 x^4} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )\\ &=196608 \operatorname {Subst}\left (\int \frac {x}{2117632-2490368 x^2+1048576 x^4} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )-\frac {\operatorname {Subst}\left (\int \frac {144 \sqrt {2 \left (19+\sqrt {517}\right )}-\left (576-64 \sqrt {517}\right ) x}{\frac {\sqrt {517}}{16}-\frac {1}{2} \sqrt {\frac {1}{2} \left (19+\sqrt {517}\right )} x+x^2} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )}{256 \sqrt {1034 \left (19+\sqrt {517}\right )}}-\frac {\operatorname {Subst}\left (\int \frac {144 \sqrt {2 \left (19+\sqrt {517}\right )}+\left (576-64 \sqrt {517}\right ) x}{\frac {\sqrt {517}}{16}+\frac {1}{2} \sqrt {\frac {1}{2} \left (19+\sqrt {517}\right )} x+x^2} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )}{256 \sqrt {1034 \left (19+\sqrt {517}\right )}}\\ &=98304 \operatorname {Subst}\left (\int \frac {1}{2117632-2490368 x+1048576 x^2} \, dx,x,\left (\frac {3}{4}+\frac {1}{x}\right )^2\right )-\frac {\left (517+9 \sqrt {517}\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {517}}{16}-\frac {1}{2} \sqrt {\frac {1}{2} \left (19+\sqrt {517}\right )} x+x^2} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )}{16544}-\frac {\left (517+9 \sqrt {517}\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {517}}{16}+\frac {1}{2} \sqrt {\frac {1}{2} \left (19+\sqrt {517}\right )} x+x^2} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )}{16544}-\frac {1}{8} \sqrt {\frac {-5167+235 \sqrt {517}}{40326}} \operatorname {Subst}\left (\int \frac {-\frac {1}{2} \sqrt {\frac {1}{2} \left (19+\sqrt {517}\right )}+2 x}{\frac {\sqrt {517}}{16}-\frac {1}{2} \sqrt {\frac {1}{2} \left (19+\sqrt {517}\right )} x+x^2} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )+\frac {1}{8} \sqrt {\frac {-5167+235 \sqrt {517}}{40326}} \operatorname {Subst}\left (\int \frac {\frac {1}{2} \sqrt {\frac {1}{2} \left (19+\sqrt {517}\right )}+2 x}{\frac {\sqrt {517}}{16}+\frac {1}{2} \sqrt {\frac {1}{2} \left (19+\sqrt {517}\right )} x+x^2} \, dx,x,\frac {3}{4}+\frac {1}{x}\right )\\ &=-\frac {1}{8} \sqrt {\frac {-5167+235 \sqrt {517}}{40326}} \log \left (\sqrt {517}-\sqrt {2 \left (19+\sqrt {517}\right )} \left (3+\frac {4}{x}\right )+\left (3+\frac {4}{x}\right )^2\right )+\frac {1}{8} \sqrt {\frac {-5167+235 \sqrt {517}}{40326}} \log \left (\sqrt {517}+\sqrt {2 \left (19+\sqrt {517}\right )} \left (3+\frac {4}{x}\right )+\left (3+\frac {4}{x}\right )^2\right )-196608 \operatorname {Subst}\left (\int \frac {1}{-2680059592704-x^2} \, dx,x,-2490368+2097152 \left (\frac {3}{4}+\frac {1}{x}\right )^2\right )+\frac {\left (517+9 \sqrt {517}\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {1}{8} \left (19-\sqrt {517}\right )-x^2} \, dx,x,-\frac {1}{2} \sqrt {\frac {1}{2} \left (19+\sqrt {517}\right )}+2 \left (\frac {3}{4}+\frac {1}{x}\right )\right )}{8272}+\frac {\left (517+9 \sqrt {517}\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {1}{8} \left (19-\sqrt {517}\right )-x^2} \, dx,x,\frac {1}{4} \left (6+\sqrt {2 \left (19+\sqrt {517}\right )}+\frac {8}{x}\right )\right )}{8272}\\ &=-\frac {1}{4} \sqrt {\frac {3}{13}} \tan ^{-1}\left (\frac {19-\left (3+\frac {4}{x}\right )^2}{2 \sqrt {39}}\right )-\frac {1}{4} \sqrt {\frac {5167+235 \sqrt {517}}{40326}} \tan ^{-1}\left (\frac {6+\sqrt {2 \left (19+\sqrt {517}\right )}+\frac {8}{x}}{\sqrt {2 \left (-19+\sqrt {517}\right )}}\right )-\frac {1}{4} \sqrt {\frac {5167+235 \sqrt {517}}{40326}} \tan ^{-1}\left (\frac {8+\left (6-\sqrt {2 \left (19+\sqrt {517}\right )}\right ) x}{\sqrt {2 \left (-19+\sqrt {517}\right )} x}\right )-\frac {1}{8} \sqrt {\frac {-5167+235 \sqrt {517}}{40326}} \log \left (\sqrt {517}-\sqrt {2 \left (19+\sqrt {517}\right )} \left (3+\frac {4}{x}\right )+\left (3+\frac {4}{x}\right )^2\right )+\frac {1}{8} \sqrt {\frac {-5167+235 \sqrt {517}}{40326}} \log \left (\sqrt {517}+\sqrt {2 \left (19+\sqrt {517}\right )} \left (3+\frac {4}{x}\right )+\left (3+\frac {4}{x}\right )^2\right )\\ \end {align*}
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Mathematica [C] time = 0.01, size = 55, normalized size = 0.21 \[ \text {RootSum}\left [8 \text {$\#$1}^4-15 \text {$\#$1}^3+8 \text {$\#$1}^2+24 \text {$\#$1}+8\& ,\frac {\log (x-\text {$\#$1})}{32 \text {$\#$1}^3-45 \text {$\#$1}^2+16 \text {$\#$1}+24}\& \right ] \]
Antiderivative was successfully verified.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{8 \, x^{4} - 15 \, x^{3} + 8 \, x^{2} + 24 \, x + 8}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.01, size = 49, normalized size = 0.19 \[ \frac {\ln \left (-\RootOf \left (8 \textit {\_Z}^{4}-15 \textit {\_Z}^{3}+8 \textit {\_Z}^{2}+24 \textit {\_Z} +8\right )+x \right )}{32 \RootOf \left (8 \textit {\_Z}^{4}-15 \textit {\_Z}^{3}+8 \textit {\_Z}^{2}+24 \textit {\_Z} +8\right )^{3}-45 \RootOf \left (8 \textit {\_Z}^{4}-15 \textit {\_Z}^{3}+8 \textit {\_Z}^{2}+24 \textit {\_Z} +8\right )^{2}+16 \RootOf \left (8 \textit {\_Z}^{4}-15 \textit {\_Z}^{3}+8 \textit {\_Z}^{2}+24 \textit {\_Z} +8\right )+24} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{8 \, x^{4} - 15 \, x^{3} + 8 \, x^{2} + 24 \, x + 8}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.41, size = 123, normalized size = 0.47 \[ \sum _{k=1}^4\ln \left (-\frac {\mathrm {root}\left (z^4+\frac {2455\,z^2}{161304}+\frac {109\,z}{430144}+\frac {1}{786357},z,k\right )\,\left (2184\,\mathrm {root}\left (z^4+\frac {2455\,z^2}{161304}+\frac {109\,z}{430144}+\frac {1}{786357},z,k\right )+256\,x+\mathrm {root}\left (z^4+\frac {2455\,z^2}{161304}+\frac {109\,z}{430144}+\frac {1}{786357},z,k\right )\,x\,38259+{\mathrm {root}\left (z^4+\frac {2455\,z^2}{161304}+\frac {109\,z}{430144}+\frac {1}{786357},z,k\right )}^2\,x\,1531920+805896\,{\mathrm {root}\left (z^4+\frac {2455\,z^2}{161304}+\frac {109\,z}{430144}+\frac {1}{786357},z,k\right )}^2-120\right )}{4096}\right )\,\mathrm {root}\left (z^4+\frac {2455\,z^2}{161304}+\frac {109\,z}{430144}+\frac {1}{786357},z,k\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 2.37, size = 41, normalized size = 0.16 \[ \operatorname {RootSum} {\left (50326848 t^{4} + 765960 t^{2} + 12753 t + 64, \left (t \mapsto t \log {\left (\frac {100785893208 t^{3}}{4758335} - \frac {1430512512 t^{2}}{4758335} + \frac {72982352521 t}{223641745} + x + \frac {2270349121}{1789133960} \right )} \right )\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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