3.380 \(\int \frac {x}{13+\frac {2}{x}+15 x} \, dx\)

Optimal. Leaf size=26 \[ \frac {x}{15}-\frac {4}{63} \log (3 x+2)+\frac {1}{175} \log (5 x+1) \]

[Out]

1/15*x-4/63*ln(2+3*x)+1/175*ln(1+5*x)

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Rubi [A]  time = 0.01, antiderivative size = 26, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {1386, 703, 632, 31} \[ \frac {x}{15}-\frac {4}{63} \log (3 x+2)+\frac {1}{175} \log (5 x+1) \]

Antiderivative was successfully verified.

[In]

Int[x/(13 + 2/x + 15*x),x]

[Out]

x/15 - (4*Log[2 + 3*x])/63 + Log[1 + 5*x]/175

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 632

Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Dist[
(c*d - e*(b/2 - q/2))/q, Int[1/(b/2 - q/2 + c*x), x], x] - Dist[(c*d - e*(b/2 + q/2))/q, Int[1/(b/2 + q/2 + c*
x), x], x]] /; FreeQ[{a, b, c, d, e}, x] && NeQ[2*c*d - b*e, 0] && NeQ[b^2 - 4*a*c, 0] && NiceSqrtQ[b^2 - 4*a*
c]

Rule 703

Int[((d_.) + (e_.)*(x_))^(m_)/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(e*(d + e*x)^(m - 1))/(c*
(m - 1)), x] + Dist[1/c, Int[((d + e*x)^(m - 2)*Simp[c*d^2 - a*e^2 + e*(2*c*d - b*e)*x, x])/(a + b*x + c*x^2),
x], x] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ[2*c*d - b*
e, 0] && GtQ[m, 1]

Rule 1386

Int[(x_)^(m_.)*((a_) + (c_.)*(x_)^(n_.) + (b_.)*(x_)^(mn_))^(p_.), x_Symbol] :> Int[x^(m - n*p)*(b + a*x^n + c
*x^(2*n))^p, x] /; FreeQ[{a, b, c, m, n}, x] && EqQ[mn, -n] && IntegerQ[p] && PosQ[n]

Rubi steps

\begin {align*} \int \frac {x}{13+\frac {2}{x}+15 x} \, dx &=\int \frac {x^2}{2+13 x+15 x^2} \, dx\\ &=\frac {x}{15}+\frac {1}{15} \int \frac {-2-13 x}{2+13 x+15 x^2} \, dx\\ &=\frac {x}{15}+\frac {3}{35} \int \frac {1}{3+15 x} \, dx-\frac {20}{21} \int \frac {1}{10+15 x} \, dx\\ &=\frac {x}{15}-\frac {4}{63} \log (2+3 x)+\frac {1}{175} \log (1+5 x)\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 26, normalized size = 1.00 \[ \frac {x}{15}-\frac {4}{63} \log (3 x+2)+\frac {1}{175} \log (5 x+1) \]

Antiderivative was successfully verified.

[In]

Integrate[x/(13 + 2/x + 15*x),x]

[Out]

x/15 - (4*Log[2 + 3*x])/63 + Log[1 + 5*x]/175

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fricas [A]  time = 0.83, size = 20, normalized size = 0.77 \[ \frac {1}{15} \, x + \frac {1}{175} \, \log \left (5 \, x + 1\right ) - \frac {4}{63} \, \log \left (3 \, x + 2\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(13+2/x+15*x),x, algorithm="fricas")

[Out]

1/15*x + 1/175*log(5*x + 1) - 4/63*log(3*x + 2)

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giac [A]  time = 0.27, size = 22, normalized size = 0.85 \[ \frac {1}{15} \, x + \frac {1}{175} \, \log \left ({\left | 5 \, x + 1 \right |}\right ) - \frac {4}{63} \, \log \left ({\left | 3 \, x + 2 \right |}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(13+2/x+15*x),x, algorithm="giac")

[Out]

1/15*x + 1/175*log(abs(5*x + 1)) - 4/63*log(abs(3*x + 2))

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maple [A]  time = 0.01, size = 21, normalized size = 0.81 \[ \frac {x}{15}+\frac {\ln \left (5 x +1\right )}{175}-\frac {4 \ln \left (3 x +2\right )}{63} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(13+2/x+15*x),x)

[Out]

1/15*x-4/63*ln(3*x+2)+1/175*ln(5*x+1)

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maxima [A]  time = 1.03, size = 20, normalized size = 0.77 \[ \frac {1}{15} \, x + \frac {1}{175} \, \log \left (5 \, x + 1\right ) - \frac {4}{63} \, \log \left (3 \, x + 2\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(13+2/x+15*x),x, algorithm="maxima")

[Out]

1/15*x + 1/175*log(5*x + 1) - 4/63*log(3*x + 2)

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mupad [B]  time = 2.12, size = 16, normalized size = 0.62 \[ \frac {x}{15}-\frac {4\,\ln \left (x+\frac {2}{3}\right )}{63}+\frac {\ln \left (x+\frac {1}{5}\right )}{175} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(15*x + 2/x + 13),x)

[Out]

x/15 - (4*log(x + 2/3))/63 + log(x + 1/5)/175

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sympy [A]  time = 0.12, size = 20, normalized size = 0.77 \[ \frac {x}{15} + \frac {\log {\left (x + \frac {1}{5} \right )}}{175} - \frac {4 \log {\left (x + \frac {2}{3} \right )}}{63} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(13+2/x+15*x),x)

[Out]

x/15 + log(x + 1/5)/175 - 4*log(x + 2/3)/63

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