Optimal. Leaf size=281 \[ \frac {3}{112} \left (7+11 i \sqrt {7}\right ) \log \left (4 i x^2+\left (-\sqrt {7}+i\right ) x+4 i\right )+\frac {3}{112} \left (7-11 i \sqrt {7}\right ) \log \left (4 i x^2+\left (\sqrt {7}+i\right ) x+4 i\right )-\frac {35+9 i \sqrt {7}}{28 x}-\frac {35-9 i \sqrt {7}}{28 x}-\frac {3}{56} \left (7+11 i \sqrt {7}\right ) \log (x)-\frac {3}{56} \left (7-11 i \sqrt {7}\right ) \log (x)+\frac {11 \left (9+5 i \sqrt {7}\right ) \tanh ^{-1}\left (\frac {8 i x-\sqrt {7}+i}{\sqrt {2 \left (35-i \sqrt {7}\right )}}\right )}{4 \sqrt {14 \left (35-i \sqrt {7}\right )}}-\frac {11 \left (9-5 i \sqrt {7}\right ) \tanh ^{-1}\left (\frac {8 i x+\sqrt {7}+i}{\sqrt {2 \left (35+i \sqrt {7}\right )}}\right )}{4 \sqrt {14 \left (35+i \sqrt {7}\right )}} \]
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Rubi [A] time = 0.47, antiderivative size = 281, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 6, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.171, Rules used = {2087, 800, 634, 618, 206, 628} \[ \frac {3}{112} \left (7+11 i \sqrt {7}\right ) \log \left (4 i x^2+\left (-\sqrt {7}+i\right ) x+4 i\right )+\frac {3}{112} \left (7-11 i \sqrt {7}\right ) \log \left (4 i x^2+\left (\sqrt {7}+i\right ) x+4 i\right )-\frac {35+9 i \sqrt {7}}{28 x}-\frac {35-9 i \sqrt {7}}{28 x}-\frac {3}{56} \left (7+11 i \sqrt {7}\right ) \log (x)-\frac {3}{56} \left (7-11 i \sqrt {7}\right ) \log (x)+\frac {11 \left (9+5 i \sqrt {7}\right ) \tanh ^{-1}\left (\frac {8 i x-\sqrt {7}+i}{\sqrt {2 \left (35-i \sqrt {7}\right )}}\right )}{4 \sqrt {14 \left (35-i \sqrt {7}\right )}}-\frac {11 \left (9-5 i \sqrt {7}\right ) \tanh ^{-1}\left (\frac {8 i x+\sqrt {7}+i}{\sqrt {2 \left (35+i \sqrt {7}\right )}}\right )}{4 \sqrt {14 \left (35+i \sqrt {7}\right )}} \]
Antiderivative was successfully verified.
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Rule 206
Rule 618
Rule 628
Rule 634
Rule 800
Rule 2087
Rubi steps
\begin {align*} \int \frac {5+x+3 x^2+2 x^3}{x^2 \left (2+x+5 x^2+x^3+2 x^4\right )} \, dx &=\frac {i \int \frac {9-5 i \sqrt {7}+\left (10-2 i \sqrt {7}\right ) x}{x^2 \left (4+\left (1-i \sqrt {7}\right ) x+4 x^2\right )} \, dx}{\sqrt {7}}-\frac {i \int \frac {9+5 i \sqrt {7}+\left (10+2 i \sqrt {7}\right ) x}{x^2 \left (4+\left (1+i \sqrt {7}\right ) x+4 x^2\right )} \, dx}{\sqrt {7}}\\ &=-\frac {i \int \left (\frac {9+5 i \sqrt {7}}{4 x^2}+\frac {3 \left (11-i \sqrt {7}\right )}{8 x}+\frac {-7 \left (9 i-5 \sqrt {7}\right )-6 \left (11 i+\sqrt {7}\right ) x}{4 \left (4 i+\left (i-\sqrt {7}\right ) x+4 i x^2\right )}\right ) \, dx}{\sqrt {7}}+\frac {i \int \left (\frac {9-5 i \sqrt {7}}{4 x^2}+\frac {3 \left (11+i \sqrt {7}\right )}{8 x}+\frac {-7 \left (9 i+5 \sqrt {7}\right )-6 \left (11 i-\sqrt {7}\right ) x}{4 \left (4 i+\left (i+\sqrt {7}\right ) x+4 i x^2\right )}\right ) \, dx}{\sqrt {7}}\\ &=-\frac {35-9 i \sqrt {7}}{28 x}-\frac {35+9 i \sqrt {7}}{28 x}-\frac {3}{56} \left (7-11 i \sqrt {7}\right ) \log (x)-\frac {3}{56} \left (7+11 i \sqrt {7}\right ) \log (x)-\frac {i \int \frac {-7 \left (9 i-5 \sqrt {7}\right )-6 \left (11 i+\sqrt {7}\right ) x}{4 i+\left (i-\sqrt {7}\right ) x+4 i x^2} \, dx}{4 \sqrt {7}}+\frac {i \int \frac {-7 \left (9 i+5 \sqrt {7}\right )-6 \left (11 i-\sqrt {7}\right ) x}{4 i+\left (i+\sqrt {7}\right ) x+4 i x^2} \, dx}{4 \sqrt {7}}\\ &=-\frac {35-9 i \sqrt {7}}{28 x}-\frac {35+9 i \sqrt {7}}{28 x}-\frac {3}{56} \left (7-11 i \sqrt {7}\right ) \log (x)-\frac {3}{56} \left (7+11 i \sqrt {7}\right ) \log (x)-\frac {1}{56} \left (11 \left (35 i-9 \sqrt {7}\right )\right ) \int \frac {1}{4 i+\left (i+\sqrt {7}\right ) x+4 i x^2} \, dx+\frac {1}{112} \left (3 \left (7-11 i \sqrt {7}\right )\right ) \int \frac {i+\sqrt {7}+8 i x}{4 i+\left (i+\sqrt {7}\right ) x+4 i x^2} \, dx+\frac {1}{112} \left (3 \left (7+11 i \sqrt {7}\right )\right ) \int \frac {i-\sqrt {7}+8 i x}{4 i+\left (i-\sqrt {7}\right ) x+4 i x^2} \, dx-\frac {1}{56} \left (11 \left (35 i+9 \sqrt {7}\right )\right ) \int \frac {1}{4 i+\left (i-\sqrt {7}\right ) x+4 i x^2} \, dx\\ &=-\frac {35-9 i \sqrt {7}}{28 x}-\frac {35+9 i \sqrt {7}}{28 x}-\frac {3}{56} \left (7-11 i \sqrt {7}\right ) \log (x)-\frac {3}{56} \left (7+11 i \sqrt {7}\right ) \log (x)+\frac {3}{112} \left (7+11 i \sqrt {7}\right ) \log \left (4 i+\left (i-\sqrt {7}\right ) x+4 i x^2\right )+\frac {3}{112} \left (7-11 i \sqrt {7}\right ) \log \left (4 i+\left (i+\sqrt {7}\right ) x+4 i x^2\right )+\frac {1}{28} \left (11 \left (35 i-9 \sqrt {7}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{2 \left (35+i \sqrt {7}\right )-x^2} \, dx,x,i+\sqrt {7}+8 i x\right )+\frac {1}{28} \left (11 \left (35 i+9 \sqrt {7}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{2 \left (35-i \sqrt {7}\right )-x^2} \, dx,x,i-\sqrt {7}+8 i x\right )\\ &=-\frac {35-9 i \sqrt {7}}{28 x}-\frac {35+9 i \sqrt {7}}{28 x}+\frac {11 \left (9+5 i \sqrt {7}\right ) \tanh ^{-1}\left (\frac {i-\sqrt {7}+8 i x}{\sqrt {2 \left (35-i \sqrt {7}\right )}}\right )}{4 \sqrt {14 \left (35-i \sqrt {7}\right )}}-\frac {11 \left (9-5 i \sqrt {7}\right ) \tanh ^{-1}\left (\frac {i+\sqrt {7}+8 i x}{\sqrt {2 \left (35+i \sqrt {7}\right )}}\right )}{4 \sqrt {14 \left (35+i \sqrt {7}\right )}}-\frac {3}{56} \left (7-11 i \sqrt {7}\right ) \log (x)-\frac {3}{56} \left (7+11 i \sqrt {7}\right ) \log (x)+\frac {3}{112} \left (7+11 i \sqrt {7}\right ) \log \left (4 i+\left (i-\sqrt {7}\right ) x+4 i x^2\right )+\frac {3}{112} \left (7-11 i \sqrt {7}\right ) \log \left (4 i+\left (i+\sqrt {7}\right ) x+4 i x^2\right )\\ \end {align*}
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Mathematica [C] time = 0.02, size = 109, normalized size = 0.39 \[ \frac {1}{4} \text {RootSum}\left [2 \text {$\#$1}^4+\text {$\#$1}^3+5 \text {$\#$1}^2+\text {$\#$1}+2\& ,\frac {6 \text {$\#$1}^3 \log (x-\text {$\#$1})-17 \text {$\#$1}^2 \log (x-\text {$\#$1})+13 \text {$\#$1} \log (x-\text {$\#$1})-35 \log (x-\text {$\#$1})}{8 \text {$\#$1}^3+3 \text {$\#$1}^2+10 \text {$\#$1}+1}\& \right ]-\frac {5}{2 x}-\frac {3 \log (x)}{4} \]
Antiderivative was successfully verified.
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fricas [B] time = 3.27, size = 1245, normalized size = 4.43 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {2 \, x^{3} + 3 \, x^{2} + x + 5}{{\left (2 \, x^{4} + x^{3} + 5 \, x^{2} + x + 2\right )} x^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.01, size = 72, normalized size = 0.26 \[ -\frac {3 \ln \relax (x )}{4}+\frac {\left (6 \RootOf \left (2 \textit {\_Z}^{4}+\textit {\_Z}^{3}+5 \textit {\_Z}^{2}+\textit {\_Z} +2\right )^{3}-17 \RootOf \left (2 \textit {\_Z}^{4}+\textit {\_Z}^{3}+5 \textit {\_Z}^{2}+\textit {\_Z} +2\right )^{2}+13 \RootOf \left (2 \textit {\_Z}^{4}+\textit {\_Z}^{3}+5 \textit {\_Z}^{2}+\textit {\_Z} +2\right )-35\right ) \ln \left (-\RootOf \left (2 \textit {\_Z}^{4}+\textit {\_Z}^{3}+5 \textit {\_Z}^{2}+\textit {\_Z} +2\right )+x \right )}{32 \RootOf \left (2 \textit {\_Z}^{4}+\textit {\_Z}^{3}+5 \textit {\_Z}^{2}+\textit {\_Z} +2\right )^{3}+12 \RootOf \left (2 \textit {\_Z}^{4}+\textit {\_Z}^{3}+5 \textit {\_Z}^{2}+\textit {\_Z} +2\right )^{2}+40 \RootOf \left (2 \textit {\_Z}^{4}+\textit {\_Z}^{3}+5 \textit {\_Z}^{2}+\textit {\_Z} +2\right )+4}-\frac {5}{2 x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {5}{2 \, x} + \frac {1}{4} \, \int \frac {6 \, x^{3} - 17 \, x^{2} + 13 \, x - 35}{2 \, x^{4} + x^{3} + 5 \, x^{2} + x + 2}\,{d x} - \frac {3}{4} \, \log \relax (x) \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.30, size = 242, normalized size = 0.86 \[ \left (\sum _{k=1}^4\ln \left (\frac {1199\,\mathrm {root}\left (z^4-\frac {3\,z^3}{4}+\frac {16\,z^2}{7}+\frac {96\,z}{49}+\frac {128}{343},z,k\right )}{32}+25\,x+\frac {\mathrm {root}\left (z^4-\frac {3\,z^3}{4}+\frac {16\,z^2}{7}+\frac {96\,z}{49}+\frac {128}{343},z,k\right )\,x\,4169}{32}+\frac {{\mathrm {root}\left (z^4-\frac {3\,z^3}{4}+\frac {16\,z^2}{7}+\frac {96\,z}{49}+\frac {128}{343},z,k\right )}^2\,x\,43993}{256}+{\mathrm {root}\left (z^4-\frac {3\,z^3}{4}+\frac {16\,z^2}{7}+\frac {96\,z}{49}+\frac {128}{343},z,k\right )}^3\,x\,28+\frac {{\mathrm {root}\left (z^4-\frac {3\,z^3}{4}+\frac {16\,z^2}{7}+\frac {96\,z}{49}+\frac {128}{343},z,k\right )}^4\,x\,3675}{32}+\frac {11647\,{\mathrm {root}\left (z^4-\frac {3\,z^3}{4}+\frac {16\,z^2}{7}+\frac {96\,z}{49}+\frac {128}{343},z,k\right )}^2}{128}+\frac {7273\,{\mathrm {root}\left (z^4-\frac {3\,z^3}{4}+\frac {16\,z^2}{7}+\frac {96\,z}{49}+\frac {128}{343},z,k\right )}^3}{128}-\frac {441\,{\mathrm {root}\left (z^4-\frac {3\,z^3}{4}+\frac {16\,z^2}{7}+\frac {96\,z}{49}+\frac {128}{343},z,k\right )}^4}{32}+\frac {21}{4}\right )\,\mathrm {root}\left (z^4-\frac {3\,z^3}{4}+\frac {16\,z^2}{7}+\frac {96\,z}{49}+\frac {128}{343},z,k\right )\right )-\frac {3\,\ln \relax (x)}{4}-\frac {5}{2\,x} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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