Optimal. Leaf size=24 \[ \left (-x+e^{2-\frac {1}{x}} (3-\log (4+x))\right )^4 \]
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Rubi [F] time = 12.21, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {16 x^5+4 x^6+e^{\frac {3 (-1+2 x)}{x}} \left (-1296 x-756 x^2\right )+e^{\frac {4 (-1+2 x)}{x}} \left (1296+324 x-108 x^2\right )+e^{\frac {2 (-1+2 x)}{x}} \left (432 x^2+540 x^3+72 x^4\right )+e^{\frac {-1+2 x}{x}} \left (-48 x^3-156 x^4-32 x^5\right )+\left (e^{\frac {4 (-1+2 x)}{x}} \left (-1728-432 x+108 x^2\right )+e^{\frac {3 (-1+2 x)}{x}} \left (1296 x+756 x^2+36 x^3\right )+e^{\frac {2 (-1+2 x)}{x}} \left (-288 x^2-360 x^3-60 x^4\right )+e^{\frac {-1+2 x}{x}} \left (16 x^3+52 x^4+12 x^5\right )\right ) \log (4+x)+\left (e^{\frac {4 (-1+2 x)}{x}} \left (864+216 x-36 x^2\right )+e^{\frac {3 (-1+2 x)}{x}} \left (-432 x-252 x^2-24 x^3\right )+e^{\frac {2 (-1+2 x)}{x}} \left (48 x^2+60 x^3+12 x^4\right )\right ) \log ^2(4+x)+\left (e^{\frac {4 (-1+2 x)}{x}} \left (-192-48 x+4 x^2\right )+e^{\frac {3 (-1+2 x)}{x}} \left (48 x+28 x^2+4 x^3\right )\right ) \log ^3(4+x)+e^{\frac {4 (-1+2 x)}{x}} (16+4 x) \log ^4(4+x)}{4 x^2+x^3} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {16 x^5+4 x^6+e^{\frac {3 (-1+2 x)}{x}} \left (-1296 x-756 x^2\right )+e^{\frac {4 (-1+2 x)}{x}} \left (1296+324 x-108 x^2\right )+e^{\frac {2 (-1+2 x)}{x}} \left (432 x^2+540 x^3+72 x^4\right )+e^{\frac {-1+2 x}{x}} \left (-48 x^3-156 x^4-32 x^5\right )+\left (e^{\frac {4 (-1+2 x)}{x}} \left (-1728-432 x+108 x^2\right )+e^{\frac {3 (-1+2 x)}{x}} \left (1296 x+756 x^2+36 x^3\right )+e^{\frac {2 (-1+2 x)}{x}} \left (-288 x^2-360 x^3-60 x^4\right )+e^{\frac {-1+2 x}{x}} \left (16 x^3+52 x^4+12 x^5\right )\right ) \log (4+x)+\left (e^{\frac {4 (-1+2 x)}{x}} \left (864+216 x-36 x^2\right )+e^{\frac {3 (-1+2 x)}{x}} \left (-432 x-252 x^2-24 x^3\right )+e^{\frac {2 (-1+2 x)}{x}} \left (48 x^2+60 x^3+12 x^4\right )\right ) \log ^2(4+x)+\left (e^{\frac {4 (-1+2 x)}{x}} \left (-192-48 x+4 x^2\right )+e^{\frac {3 (-1+2 x)}{x}} \left (48 x+28 x^2+4 x^3\right )\right ) \log ^3(4+x)+e^{\frac {4 (-1+2 x)}{x}} (16+4 x) \log ^4(4+x)}{x^2 (4+x)} \, dx\\ &=\int \frac {4 e^{-4/x} \left (3 e^2-e^{\frac {1}{x}} x-e^2 \log (4+x)\right )^3 \left (-e^{\frac {1}{x}} x^2 (4+x)-e^2 \left (-12-3 x+x^2\right )-e^2 (4+x) \log (4+x)\right )}{x^2 (4+x)} \, dx\\ &=4 \int \frac {e^{-4/x} \left (3 e^2-e^{\frac {1}{x}} x-e^2 \log (4+x)\right )^3 \left (-e^{\frac {1}{x}} x^2 (4+x)-e^2 \left (-12-3 x+x^2\right )-e^2 (4+x) \log (4+x)\right )}{x^2 (4+x)} \, dx\\ &=4 \int \left (x^3+\frac {e^{8-\frac {4}{x}} (-3+\log (4+x))^3 \left (-12-3 x+x^2+4 \log (4+x)+x \log (4+x)\right )}{x^2 (4+x)}+\frac {3 e^{4-\frac {2}{x}} (-3+\log (4+x)) \left (-12-15 x-2 x^2+4 \log (4+x)+5 x \log (4+x)+x^2 \log (4+x)\right )}{4+x}+\frac {e^{6-\frac {3}{x}} (-3+\log (4+x))^2 \left (-36-21 x+12 \log (4+x)+7 x \log (4+x)+x^2 \log (4+x)\right )}{x (4+x)}+\frac {e^{2-\frac {1}{x}} x \left (-12-39 x-8 x^2+4 \log (4+x)+13 x \log (4+x)+3 x^2 \log (4+x)\right )}{4+x}\right ) \, dx\\ &=x^4+4 \int \frac {e^{8-\frac {4}{x}} (-3+\log (4+x))^3 \left (-12-3 x+x^2+4 \log (4+x)+x \log (4+x)\right )}{x^2 (4+x)} \, dx+4 \int \frac {e^{6-\frac {3}{x}} (-3+\log (4+x))^2 \left (-36-21 x+12 \log (4+x)+7 x \log (4+x)+x^2 \log (4+x)\right )}{x (4+x)} \, dx+4 \int \frac {e^{2-\frac {1}{x}} x \left (-12-39 x-8 x^2+4 \log (4+x)+13 x \log (4+x)+3 x^2 \log (4+x)\right )}{4+x} \, dx+12 \int \frac {e^{4-\frac {2}{x}} (-3+\log (4+x)) \left (-12-15 x-2 x^2+4 \log (4+x)+5 x \log (4+x)+x^2 \log (4+x)\right )}{4+x} \, dx\\ &=x^4+\frac {e^{8-\frac {4}{x}} (3-\log (4+x))^3 (12+3 x-4 \log (4+x)-x \log (4+x))}{4+x}+4 \int \left (-\frac {e^{2-\frac {1}{x}} x \left (12+39 x+8 x^2\right )}{4+x}+e^{2-\frac {1}{x}} x (1+3 x) \log (4+x)\right ) \, dx+4 \int \left (-\frac {27 e^{6-\frac {3}{x}} (12+7 x)}{x (4+x)}+\frac {9 e^{6-\frac {3}{x}} \left (36+21 x+x^2\right ) \log (4+x)}{x (4+x)}-\frac {3 e^{6-\frac {3}{x}} \left (36+21 x+2 x^2\right ) \log ^2(4+x)}{x (4+x)}+\frac {e^{6-\frac {3}{x}} (3+x) \log ^3(4+x)}{x}\right ) \, dx+12 \int \left (\frac {3 e^{4-\frac {2}{x}} \left (12+15 x+2 x^2\right )}{4+x}-\frac {e^{4-\frac {2}{x}} \left (24+30 x+5 x^2\right ) \log (4+x)}{4+x}+e^{4-\frac {2}{x}} (1+x) \log ^2(4+x)\right ) \, dx\\ &=x^4+\frac {e^{8-\frac {4}{x}} (3-\log (4+x))^3 (12+3 x-4 \log (4+x)-x \log (4+x))}{4+x}-4 \int \frac {e^{2-\frac {1}{x}} x \left (12+39 x+8 x^2\right )}{4+x} \, dx+4 \int e^{2-\frac {1}{x}} x (1+3 x) \log (4+x) \, dx+4 \int \frac {e^{6-\frac {3}{x}} (3+x) \log ^3(4+x)}{x} \, dx-12 \int \frac {e^{4-\frac {2}{x}} \left (24+30 x+5 x^2\right ) \log (4+x)}{4+x} \, dx+12 \int e^{4-\frac {2}{x}} (1+x) \log ^2(4+x) \, dx-12 \int \frac {e^{6-\frac {3}{x}} \left (36+21 x+2 x^2\right ) \log ^2(4+x)}{x (4+x)} \, dx+36 \int \frac {e^{4-\frac {2}{x}} \left (12+15 x+2 x^2\right )}{4+x} \, dx+36 \int \frac {e^{6-\frac {3}{x}} \left (36+21 x+x^2\right ) \log (4+x)}{x (4+x)} \, dx-108 \int \frac {e^{6-\frac {3}{x}} (12+7 x)}{x (4+x)} \, dx\\ &=x^4+36 e^{6-\frac {3}{x}} x \log (4+x)-60 e^{4-\frac {2}{x}} x \log (4+x)-30 e^{4-\frac {2}{x}} x^2 \log (4+x)+4 e^{2-\frac {1}{x}} x^3 \log (4+x)-504 e^6 \text {Ei}\left (-\frac {3}{x}\right ) \log (4+x)-312 e^4 \text {Ei}\left (-\frac {2}{x}\right ) \log (4+x)+288 e^{27/4} \text {Ei}\left (-\frac {3 (4+x)}{4 x}\right ) \log (4+x)+192 e^{9/2} \text {Ei}\left (-\frac {4+x}{2 x}\right ) \log (4+x)+\frac {e^{8-\frac {4}{x}} (3-\log (4+x))^3 (12+3 x-4 \log (4+x)-x \log (4+x))}{4+x}-4 \int \frac {e^{2-\frac {1}{x}} x^3}{4+x} \, dx-4 \int \left (-16 e^{2-\frac {1}{x}}+7 e^{2-\frac {1}{x}} x+8 e^{2-\frac {1}{x}} x^2+\frac {64 e^{2-\frac {1}{x}}}{4+x}\right ) \, dx+4 \int \left (e^{6-\frac {3}{x}} \log ^3(4+x)+\frac {3 e^{6-\frac {3}{x}} \log ^3(4+x)}{x}\right ) \, dx+12 \int \frac {e^4 \left (5 e^{-2/x} x (2+x)+52 \text {Ei}\left (-\frac {2}{x}\right )-32 \sqrt {e} \text {Ei}\left (-\frac {4+x}{2 x}\right )\right )}{2 (4+x)} \, dx-12 \int \left (2 e^{6-\frac {3}{x}} \log ^2(4+x)+\frac {9 e^{6-\frac {3}{x}} \log ^2(4+x)}{x}+\frac {4 e^{6-\frac {3}{x}} \log ^2(4+x)}{4+x}\right ) \, dx+12 \int \left (-3 e^{4-\frac {2}{x}} \log ^2(4+x)+e^{4-\frac {2}{x}} (4+x) \log ^2(4+x)\right ) \, dx+36 \int \left (7 e^{4-\frac {2}{x}}+2 e^{4-\frac {2}{x}} x-\frac {16 e^{4-\frac {2}{x}}}{4+x}\right ) \, dx-36 \int \frac {e^6 \left (e^{-3/x} x-14 \text {Ei}\left (-\frac {3}{x}\right )+8 e^{3/4} \text {Ei}\left (-\frac {3 (4+x)}{4 x}\right )\right )}{4+x} \, dx-108 \int \left (\frac {3 e^{6-\frac {3}{x}}}{x}+\frac {4 e^{6-\frac {3}{x}}}{4+x}\right ) \, dx\\ &=x^4+36 e^{6-\frac {3}{x}} x \log (4+x)-60 e^{4-\frac {2}{x}} x \log (4+x)-30 e^{4-\frac {2}{x}} x^2 \log (4+x)+4 e^{2-\frac {1}{x}} x^3 \log (4+x)-504 e^6 \text {Ei}\left (-\frac {3}{x}\right ) \log (4+x)-312 e^4 \text {Ei}\left (-\frac {2}{x}\right ) \log (4+x)+288 e^{27/4} \text {Ei}\left (-\frac {3 (4+x)}{4 x}\right ) \log (4+x)+192 e^{9/2} \text {Ei}\left (-\frac {4+x}{2 x}\right ) \log (4+x)+\frac {e^{8-\frac {4}{x}} (3-\log (4+x))^3 (12+3 x-4 \log (4+x)-x \log (4+x))}{4+x}-4 \int \left (16 e^{2-\frac {1}{x}}-4 e^{2-\frac {1}{x}} x+e^{2-\frac {1}{x}} x^2-\frac {64 e^{2-\frac {1}{x}}}{4+x}\right ) \, dx+4 \int e^{6-\frac {3}{x}} \log ^3(4+x) \, dx+12 \int e^{4-\frac {2}{x}} (4+x) \log ^2(4+x) \, dx+12 \int \frac {e^{6-\frac {3}{x}} \log ^3(4+x)}{x} \, dx-24 \int e^{6-\frac {3}{x}} \log ^2(4+x) \, dx-28 \int e^{2-\frac {1}{x}} x \, dx-32 \int e^{2-\frac {1}{x}} x^2 \, dx-36 \int e^{4-\frac {2}{x}} \log ^2(4+x) \, dx-48 \int \frac {e^{6-\frac {3}{x}} \log ^2(4+x)}{4+x} \, dx+64 \int e^{2-\frac {1}{x}} \, dx+72 \int e^{4-\frac {2}{x}} x \, dx-108 \int \frac {e^{6-\frac {3}{x}} \log ^2(4+x)}{x} \, dx+252 \int e^{4-\frac {2}{x}} \, dx-256 \int \frac {e^{2-\frac {1}{x}}}{4+x} \, dx-324 \int \frac {e^{6-\frac {3}{x}}}{x} \, dx-432 \int \frac {e^{6-\frac {3}{x}}}{4+x} \, dx-576 \int \frac {e^{4-\frac {2}{x}}}{4+x} \, dx+\left (6 e^4\right ) \int \frac {5 e^{-2/x} x (2+x)+52 \text {Ei}\left (-\frac {2}{x}\right )-32 \sqrt {e} \text {Ei}\left (-\frac {4+x}{2 x}\right )}{4+x} \, dx-\left (36 e^6\right ) \int \frac {e^{-3/x} x-14 \text {Ei}\left (-\frac {3}{x}\right )+8 e^{3/4} \text {Ei}\left (-\frac {3 (4+x)}{4 x}\right )}{4+x} \, dx\\ &=252 e^{4-\frac {2}{x}} x+64 e^{2-\frac {1}{x}} x+36 e^{4-\frac {2}{x}} x^2-14 e^{2-\frac {1}{x}} x^2-\frac {32}{3} e^{2-\frac {1}{x}} x^3+x^4+324 e^6 \text {Ei}\left (-\frac {3}{x}\right )+36 e^{6-\frac {3}{x}} x \log (4+x)-60 e^{4-\frac {2}{x}} x \log (4+x)-30 e^{4-\frac {2}{x}} x^2 \log (4+x)+4 e^{2-\frac {1}{x}} x^3 \log (4+x)-504 e^6 \text {Ei}\left (-\frac {3}{x}\right ) \log (4+x)-312 e^4 \text {Ei}\left (-\frac {2}{x}\right ) \log (4+x)+288 e^{27/4} \text {Ei}\left (-\frac {3 (4+x)}{4 x}\right ) \log (4+x)+192 e^{9/2} \text {Ei}\left (-\frac {4+x}{2 x}\right ) \log (4+x)+\frac {e^{8-\frac {4}{x}} (3-\log (4+x))^3 (12+3 x-4 \log (4+x)-x \log (4+x))}{4+x}-4 \int e^{2-\frac {1}{x}} x^2 \, dx+4 \int e^{6-\frac {3}{x}} \log ^3(4+x) \, dx+\frac {32}{3} \int e^{2-\frac {1}{x}} x \, dx+12 \int e^{4-\frac {2}{x}} (4+x) \log ^2(4+x) \, dx+12 \int \frac {e^{6-\frac {3}{x}} \log ^3(4+x)}{x} \, dx+14 \int e^{2-\frac {1}{x}} \, dx+16 \int e^{2-\frac {1}{x}} x \, dx-24 \int e^{6-\frac {3}{x}} \log ^2(4+x) \, dx-36 \int e^{4-\frac {2}{x}} \log ^2(4+x) \, dx-48 \int \frac {e^{6-\frac {3}{x}} \log ^2(4+x)}{4+x} \, dx-64 \int e^{2-\frac {1}{x}} \, dx-64 \int \frac {e^{2-\frac {1}{x}}}{x} \, dx-72 \int e^{4-\frac {2}{x}} \, dx-108 \int \frac {e^{6-\frac {3}{x}} \log ^2(4+x)}{x} \, dx-256 \int \frac {e^{2-\frac {1}{x}}}{x} \, dx+256 \int \frac {e^{2-\frac {1}{x}}}{4+x} \, dx-432 \int \frac {e^{6-\frac {3}{x}}}{x} \, dx-504 \int \frac {e^{4-\frac {2}{x}}}{x} \, dx-576 \int \frac {e^{4-\frac {2}{x}}}{x} \, dx+1024 \int \frac {e^{2-\frac {1}{x}}}{x (4+x)} \, dx+1728 \int \frac {e^{6-\frac {3}{x}}}{x (4+x)} \, dx+2304 \int \frac {e^{4-\frac {2}{x}}}{x (4+x)} \, dx+\left (6 e^4\right ) \int \left (\frac {5 e^{-2/x} x (2+x)}{4+x}-\frac {4 \left (-13 \text {Ei}\left (-\frac {2}{x}\right )+8 \sqrt {e} \text {Ei}\left (-\frac {4+x}{2 x}\right )\right )}{4+x}\right ) \, dx-\left (36 e^6\right ) \int \left (\frac {e^{-3/x} x}{4+x}+\frac {2 \left (-7 \text {Ei}\left (-\frac {3}{x}\right )+4 e^{3/4} \text {Ei}\left (-\frac {3 (4+x)}{4 x}\right )\right )}{4+x}\right ) \, dx\\ &=\text {Rest of rules removed due to large latex content} \end {aligned} \end {gather*}
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Mathematica [A] time = 1.46, size = 31, normalized size = 1.29 \begin {gather*} e^{-4/x} \left (-3 e^2+e^{\frac {1}{x}} x+e^2 \log (4+x)\right )^4 \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 0.53, size = 230, normalized size = 9.58 \begin {gather*} e^{\left (\frac {4 \, {\left (2 \, x - 1\right )}}{x}\right )} \log \left (x + 4\right )^{4} + x^{4} - 12 \, x^{3} e^{\left (\frac {2 \, x - 1}{x}\right )} + 4 \, {\left (x e^{\left (\frac {3 \, {\left (2 \, x - 1\right )}}{x}\right )} - 3 \, e^{\left (\frac {4 \, {\left (2 \, x - 1\right )}}{x}\right )}\right )} \log \left (x + 4\right )^{3} + 54 \, x^{2} e^{\left (\frac {2 \, {\left (2 \, x - 1\right )}}{x}\right )} + 6 \, {\left (x^{2} e^{\left (\frac {2 \, {\left (2 \, x - 1\right )}}{x}\right )} - 6 \, x e^{\left (\frac {3 \, {\left (2 \, x - 1\right )}}{x}\right )} + 9 \, e^{\left (\frac {4 \, {\left (2 \, x - 1\right )}}{x}\right )}\right )} \log \left (x + 4\right )^{2} - 108 \, x e^{\left (\frac {3 \, {\left (2 \, x - 1\right )}}{x}\right )} + 4 \, {\left (x^{3} e^{\left (\frac {2 \, x - 1}{x}\right )} - 9 \, x^{2} e^{\left (\frac {2 \, {\left (2 \, x - 1\right )}}{x}\right )} + 27 \, x e^{\left (\frac {3 \, {\left (2 \, x - 1\right )}}{x}\right )} - 27 \, e^{\left (\frac {4 \, {\left (2 \, x - 1\right )}}{x}\right )}\right )} \log \left (x + 4\right ) + 81 \, e^{\left (\frac {4 \, {\left (2 \, x - 1\right )}}{x}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.20, size = 231, normalized size = 9.62
method | result | size |
risch | \({\mathrm e}^{\frac {8 x -4}{x}} \ln \left (4+x \right )^{4}+\left (4 \,{\mathrm e}^{\frac {6 x -3}{x}} x -12 \,{\mathrm e}^{\frac {8 x -4}{x}}\right ) \ln \left (4+x \right )^{3}+\left (6 \,{\mathrm e}^{\frac {4 x -2}{x}} x^{2}-36 \,{\mathrm e}^{\frac {6 x -3}{x}} x +54 \,{\mathrm e}^{\frac {8 x -4}{x}}\right ) \ln \left (4+x \right )^{2}+\left (4 \,{\mathrm e}^{\frac {2 x -1}{x}} x^{3}-36 \,{\mathrm e}^{\frac {4 x -2}{x}} x^{2}+108 \,{\mathrm e}^{\frac {6 x -3}{x}} x -108 \,{\mathrm e}^{\frac {8 x -4}{x}}\right ) \ln \left (4+x \right )+x^{4}-12 \,{\mathrm e}^{\frac {2 x -1}{x}} x^{3}+54 \,{\mathrm e}^{\frac {4 x -2}{x}} x^{2}-108 \,{\mathrm e}^{\frac {6 x -3}{x}} x +81 \,{\mathrm e}^{\frac {8 x -4}{x}}\) | \(231\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.43, size = 162, normalized size = 6.75 \begin {gather*} x^{4} + 4 \, {\left (x^{3} e^{2} \log \left (x + 4\right ) - 3 \, x^{3} e^{2}\right )} e^{\left (-\frac {1}{x}\right )} + 6 \, {\left (x^{2} e^{4} \log \left (x + 4\right )^{2} - 6 \, x^{2} e^{4} \log \left (x + 4\right ) + 9 \, x^{2} e^{4}\right )} e^{\left (-\frac {2}{x}\right )} + 4 \, {\left (x e^{6} \log \left (x + 4\right )^{3} - 9 \, x e^{6} \log \left (x + 4\right )^{2} + 27 \, x e^{6} \log \left (x + 4\right ) - 27 \, x e^{6}\right )} e^{\left (-\frac {3}{x}\right )} + {\left (e^{8} \log \left (x + 4\right )^{4} - 12 \, e^{8} \log \left (x + 4\right )^{3} + 54 \, e^{8} \log \left (x + 4\right )^{2} - 108 \, e^{8} \log \left (x + 4\right ) + 81 \, e^{8}\right )} e^{\left (-\frac {4}{x}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.04 \begin {gather*} \int \frac {{\ln \left (x+4\right )}^2\,\left ({\mathrm {e}}^{\frac {2\,\left (2\,x-1\right )}{x}}\,\left (12\,x^4+60\,x^3+48\,x^2\right )+{\mathrm {e}}^{\frac {4\,\left (2\,x-1\right )}{x}}\,\left (-36\,x^2+216\,x+864\right )-{\mathrm {e}}^{\frac {3\,\left (2\,x-1\right )}{x}}\,\left (24\,x^3+252\,x^2+432\,x\right )\right )-{\mathrm {e}}^{\frac {2\,x-1}{x}}\,\left (32\,x^5+156\,x^4+48\,x^3\right )+{\mathrm {e}}^{\frac {2\,\left (2\,x-1\right )}{x}}\,\left (72\,x^4+540\,x^3+432\,x^2\right )+{\mathrm {e}}^{\frac {4\,\left (2\,x-1\right )}{x}}\,\left (-108\,x^2+324\,x+1296\right )-{\mathrm {e}}^{\frac {3\,\left (2\,x-1\right )}{x}}\,\left (756\,x^2+1296\,x\right )+16\,x^5+4\,x^6-{\ln \left (x+4\right )}^3\,\left ({\mathrm {e}}^{\frac {4\,\left (2\,x-1\right )}{x}}\,\left (-4\,x^2+48\,x+192\right )-{\mathrm {e}}^{\frac {3\,\left (2\,x-1\right )}{x}}\,\left (4\,x^3+28\,x^2+48\,x\right )\right )+\ln \left (x+4\right )\,\left ({\mathrm {e}}^{\frac {2\,x-1}{x}}\,\left (12\,x^5+52\,x^4+16\,x^3\right )-{\mathrm {e}}^{\frac {2\,\left (2\,x-1\right )}{x}}\,\left (60\,x^4+360\,x^3+288\,x^2\right )-{\mathrm {e}}^{\frac {4\,\left (2\,x-1\right )}{x}}\,\left (-108\,x^2+432\,x+1728\right )+{\mathrm {e}}^{\frac {3\,\left (2\,x-1\right )}{x}}\,\left (36\,x^3+756\,x^2+1296\,x\right )\right )+{\ln \left (x+4\right )}^4\,{\mathrm {e}}^{\frac {4\,\left (2\,x-1\right )}{x}}\,\left (4\,x+16\right )}{x^3+4\,x^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 80.88, size = 143, normalized size = 5.96 \begin {gather*} x^{4} + \left (4 x^{3} \log {\left (x + 4 \right )} - 12 x^{3}\right ) e^{\frac {2 x - 1}{x}} + \left (6 x^{2} \log {\left (x + 4 \right )}^{2} - 36 x^{2} \log {\left (x + 4 \right )} + 54 x^{2}\right ) e^{\frac {2 \left (2 x - 1\right )}{x}} + \left (4 x \log {\left (x + 4 \right )}^{3} - 36 x \log {\left (x + 4 \right )}^{2} + 108 x \log {\left (x + 4 \right )} - 108 x\right ) e^{\frac {3 \left (2 x - 1\right )}{x}} + \left (\log {\left (x + 4 \right )}^{4} - 12 \log {\left (x + 4 \right )}^{3} + 54 \log {\left (x + 4 \right )}^{2} - 108 \log {\left (x + 4 \right )} + 81\right ) e^{\frac {4 \left (2 x - 1\right )}{x}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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