Optimal. Leaf size=25 \[ \left (4 x+5 e^{-x \left (x+x^2\right )} x^2 (x+\log (5))\right )^2 \]
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Rubi [F] time = 3.14, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \left (32 e^{-2 x^2-2 x^3+2 x^2 (1+x)} x+150 e^{-2 x^2-2 x^3} x^5-100 e^{-2 x^2-2 x^3} x^7-150 e^{-2 x^2-2 x^3} x^8-50 e^{-2 x^2-2 x^3} x^4 \left (-5+4 x^2+6 x^3\right ) \log (5)-50 e^{-2 x^2-2 x^3} x^3 \left (-2+2 x^2+3 x^3\right ) \log ^2(5)+40 e^{-x^2-x^3} x^2 \left (4 x-3 x^4+3 \log (5)-x^2 \log (25)-x^3 (2+\log (125))\right )\right ) \, dx\\ &=32 \int e^{-2 x^2-2 x^3+2 x^2 (1+x)} x \, dx+40 \int e^{-x^2-x^3} x^2 \left (4 x-3 x^4+3 \log (5)-x^2 \log (25)-x^3 (2+\log (125))\right ) \, dx-100 \int e^{-2 x^2-2 x^3} x^7 \, dx+150 \int e^{-2 x^2-2 x^3} x^5 \, dx-150 \int e^{-2 x^2-2 x^3} x^8 \, dx-(50 \log (5)) \int e^{-2 x^2-2 x^3} x^4 \left (-5+4 x^2+6 x^3\right ) \, dx-\left (50 \log ^2(5)\right ) \int e^{-2 x^2-2 x^3} x^3 \left (-2+2 x^2+3 x^3\right ) \, dx\\ &=\frac {50 e^{-2 x^2-2 x^3} x^4 \left (2 x^2+3 x^3\right ) \log (5)}{2 x+3 x^2}+\frac {25 e^{-2 x^2-2 x^3} x^3 \left (2 x^2+3 x^3\right ) \log ^2(5)}{2 x+3 x^2}+\frac {40 e^{-x^2-x^3} x^2 \left (3 x^4+x^2 \log (25)+x^3 (2+\log (125))\right )}{2 x+3 x^2}+32 \int x \, dx-100 \int e^{-2 x^2-2 x^3} x^7 \, dx+150 \int e^{-2 x^2-2 x^3} x^5 \, dx-150 \int e^{-2 x^2-2 x^3} x^8 \, dx\\ &=16 x^2+\frac {50 e^{-2 x^2-2 x^3} x^4 \left (2 x^2+3 x^3\right ) \log (5)}{2 x+3 x^2}+\frac {25 e^{-2 x^2-2 x^3} x^3 \left (2 x^2+3 x^3\right ) \log ^2(5)}{2 x+3 x^2}+\frac {40 e^{-x^2-x^3} x^2 \left (3 x^4+x^2 \log (25)+x^3 (2+\log (125))\right )}{2 x+3 x^2}-100 \int e^{-2 x^2-2 x^3} x^7 \, dx+150 \int e^{-2 x^2-2 x^3} x^5 \, dx-150 \int e^{-2 x^2-2 x^3} x^8 \, dx\\ \end {aligned} \end {gather*}
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Mathematica [F] time = 0.51, size = 0, normalized size = 0.00 \begin {gather*} \int e^{-2 x^2-2 x^3} \left (32 e^{2 x^2+2 x^3} x+150 x^5-100 x^7-150 x^8+\left (250 x^4-200 x^6-300 x^7\right ) \log (5)+\left (100 x^3-100 x^5-150 x^6\right ) \log ^2(5)+e^{x^2+x^3} \left (160 x^3-80 x^5-120 x^6+\left (120 x^2-80 x^4-120 x^5\right ) \log (5)\right )\right ) \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [B] time = 1.02, size = 72, normalized size = 2.88 \begin {gather*} {\left (25 \, x^{6} + 50 \, x^{5} \log \relax (5) + 25 \, x^{4} \log \relax (5)^{2} + 16 \, x^{2} e^{\left (2 \, x^{3} + 2 \, x^{2}\right )} + 40 \, {\left (x^{4} + x^{3} \log \relax (5)\right )} e^{\left (x^{3} + x^{2}\right )}\right )} e^{\left (-2 \, x^{3} - 2 \, x^{2}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.20, size = 99, normalized size = 3.96 \begin {gather*} 25 \, x^{6} e^{\left (-2 \, x^{3} - 2 \, x^{2}\right )} + 50 \, x^{5} e^{\left (-2 \, x^{3} - 2 \, x^{2}\right )} \log \relax (5) + 25 \, x^{4} e^{\left (-2 \, x^{3} - 2 \, x^{2}\right )} \log \relax (5)^{2} + 40 \, x^{4} e^{\left (-x^{3} - x^{2}\right )} + 40 \, x^{3} e^{\left (-x^{3} - x^{2}\right )} \log \relax (5) + 16 \, x^{2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.10, size = 62, normalized size = 2.48
method | result | size |
risch | \(16 x^{2}+\left (40 x^{3} \ln \relax (5)+40 x^{4}\right ) {\mathrm e}^{-\left (x +1\right ) x^{2}}+\left (25 x^{4} \ln \relax (5)^{2}+50 x^{5} \ln \relax (5)+25 x^{6}\right ) {\mathrm e}^{-2 \left (x +1\right ) x^{2}}\) | \(62\) |
norman | \(\left (25 x^{6}+16 x^{2} {\mathrm e}^{2 x^{3}+2 x^{2}}+25 x^{4} \ln \relax (5)^{2}+50 x^{5} \ln \relax (5)+40 \,{\mathrm e}^{x^{3}+x^{2}} x^{4}+40 \ln \relax (5) {\mathrm e}^{x^{3}+x^{2}} x^{3}\right ) {\mathrm e}^{-2 x^{3}-2 x^{2}}\) | \(77\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.49, size = 64, normalized size = 2.56 \begin {gather*} 16 \, x^{2} + 5 \, {\left (5 \, {\left (x^{6} + 2 \, x^{5} \log \relax (5) + x^{4} \log \relax (5)^{2}\right )} e^{\left (-2 \, x^{3}\right )} + 8 \, {\left (x^{4} + x^{3} \log \relax (5)\right )} e^{\left (-x^{3} + x^{2}\right )}\right )} e^{\left (-2 \, x^{2}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.04 \begin {gather*} \int -{\mathrm {e}}^{-2\,x^3-2\,x^2}\,\left ({\ln \relax (5)}^2\,\left (150\,x^6+100\,x^5-100\,x^3\right )-32\,x\,{\mathrm {e}}^{2\,x^3+2\,x^2}+{\mathrm {e}}^{x^3+x^2}\,\left (\ln \relax (5)\,\left (120\,x^5+80\,x^4-120\,x^2\right )-160\,x^3+80\,x^5+120\,x^6\right )+\ln \relax (5)\,\left (300\,x^7+200\,x^6-250\,x^4\right )-150\,x^5+100\,x^7+150\,x^8\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 0.26, size = 65, normalized size = 2.60 \begin {gather*} 16 x^{2} + \left (40 x^{4} + 40 x^{3} \log {\relax (5 )}\right ) e^{- x^{3} - x^{2}} + \left (25 x^{6} + 50 x^{5} \log {\relax (5 )} + 25 x^{4} \log {\relax (5 )}^{2}\right ) e^{- 2 x^{3} - 2 x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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