Optimal. Leaf size=32 \[ 10 \left (-3+5 \left (\log \left (\frac {1-x}{3}\right )+\frac {1}{\log (x) \left (3-\log \left (x^2\right )\right )}\right )\right ) \]
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Rubi [F] time = 0.20, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {150-150 x+(-100+100 x) \log (x)+450 x \log ^2(x)+\left (-50+50 x-300 x \log ^2(x)\right ) \log \left (x^2\right )+50 x \log ^2(x) \log ^2\left (x^2\right )}{\left (-9 x+9 x^2\right ) \log ^2(x)+\left (6 x-6 x^2\right ) \log ^2(x) \log \left (x^2\right )+\left (-x+x^2\right ) \log ^2(x) \log ^2\left (x^2\right )} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int 50 \left (\frac {1}{-1+x}+\frac {2}{x \log (x) \left (-3+\log \left (x^2\right )\right )^2}+\frac {1}{x \log ^2(x) \left (-3+\log \left (x^2\right )\right )}\right ) \, dx\\ &=50 \int \left (\frac {1}{-1+x}+\frac {2}{x \log (x) \left (-3+\log \left (x^2\right )\right )^2}+\frac {1}{x \log ^2(x) \left (-3+\log \left (x^2\right )\right )}\right ) \, dx\\ &=50 \log (1-x)+50 \int \frac {1}{x \log ^2(x) \left (-3+\log \left (x^2\right )\right )} \, dx+100 \int \frac {1}{x \log (x) \left (-3+\log \left (x^2\right )\right )^2} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 0.08, size = 22, normalized size = 0.69 \begin {gather*} 50 \left (\log (-1+x)+\frac {1}{3 \log (x)-\log (x) \log \left (x^2\right )}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.58, size = 35, normalized size = 1.09 \begin {gather*} \frac {50 \, {\left (2 \, \log \left (x - 1\right ) \log \relax (x)^{2} - 3 \, \log \left (x - 1\right ) \log \relax (x) - 1\right )}}{2 \, \log \relax (x)^{2} - 3 \, \log \relax (x)} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.21, size = 23, normalized size = 0.72 \begin {gather*} -\frac {100}{3 \, {\left (2 \, \log \relax (x) - 3\right )}} + \frac {50}{3 \, \log \relax (x)} + 50 \, \log \left (x - 1\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.11, size = 69, normalized size = 2.16
method | result | size |
risch | \(50 \ln \left (x -1\right )-\frac {100 i}{\left (\pi \mathrm {csgn}\left (i x \right )^{2} \mathrm {csgn}\left (i x^{2}\right )-2 \pi \,\mathrm {csgn}\left (i x \right ) \mathrm {csgn}\left (i x^{2}\right )^{2}+\pi \mathrm {csgn}\left (i x^{2}\right )^{3}+4 i \ln \relax (x )-6 i\right ) \ln \relax (x )}\) | \(69\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.44, size = 22, normalized size = 0.69 \begin {gather*} -\frac {50}{2 \, \log \relax (x)^{2} - 3 \, \log \relax (x)} + 50 \, \log \left (x - 1\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.30, size = 21, normalized size = 0.66 \begin {gather*} 50\,\ln \left (x-1\right )-\frac {50}{\ln \relax (x)\,\left (\ln \left (x^2\right )-3\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.27, size = 19, normalized size = 0.59 \begin {gather*} 50 \log {\left (x - 1 \right )} - \frac {50}{2 \log {\relax (x )}^{2} - 3 \log {\relax (x )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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