3.79 \(\int \frac {1}{\sqrt [3]{1-x^2} (3+x^2)} \, dx\)
Optimal. Leaf size=113 \[ \frac {\tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{2\ 2^{2/3} \sqrt {3}}+\frac {\tanh ^{-1}\left (\frac {x}{\sqrt [3]{2} \sqrt [3]{1-x^2}+1}\right )}{2\ 2^{2/3}}+\frac {\tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{2\ 2^{2/3} \sqrt {3}}-\frac {\tanh ^{-1}(x)}{6\ 2^{2/3}} \]
[Out]
-1/12*arctanh(x)*2^(1/3)+1/4*arctanh(x/(1+2^(1/3)*(-x^2+1)^(1/3)))*2^(1/3)+1/12*arctan(3^(1/2)/x)*2^(1/3)*3^(1
/2)+1/12*arctan((1-2^(1/3)*(-x^2+1)^(1/3))*3^(1/2)/x)*2^(1/3)*3^(1/2)
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Rubi [A] time = 0.01, antiderivative size = 113, normalized size of antiderivative = 1.00,
number of steps used = 1, number of rules used = 1, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used =
{393} \[ \frac {\tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{2\ 2^{2/3} \sqrt {3}}+\frac {\tanh ^{-1}\left (\frac {x}{\sqrt [3]{2} \sqrt [3]{1-x^2}+1}\right )}{2\ 2^{2/3}}+\frac {\tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{2\ 2^{2/3} \sqrt {3}}-\frac {\tanh ^{-1}(x)}{6\ 2^{2/3}} \]
Antiderivative was successfully verified.
[In]
Int[1/((1 - x^2)^(1/3)*(3 + x^2)),x]
[Out]
ArcTan[Sqrt[3]/x]/(2*2^(2/3)*Sqrt[3]) + ArcTan[(Sqrt[3]*(1 - 2^(1/3)*(1 - x^2)^(1/3)))/x]/(2*2^(2/3)*Sqrt[3])
- ArcTanh[x]/(6*2^(2/3)) + ArcTanh[x/(1 + 2^(1/3)*(1 - x^2)^(1/3))]/(2*2^(2/3))
Rule 393
Int[1/(((a_) + (b_.)*(x_)^2)^(1/3)*((c_) + (d_.)*(x_)^2)), x_Symbol] :> With[{q = Rt[-(b/a), 2]}, Simp[(q*ArcT
an[Sqrt[3]/(q*x)])/(2*2^(2/3)*Sqrt[3]*a^(1/3)*d), x] + (Simp[(q*ArcTanh[(a^(1/3)*q*x)/(a^(1/3) + 2^(1/3)*(a +
b*x^2)^(1/3))])/(2*2^(2/3)*a^(1/3)*d), x] - Simp[(q*ArcTanh[q*x])/(6*2^(2/3)*a^(1/3)*d), x] + Simp[(q*ArcTan[(
Sqrt[3]*(a^(1/3) - 2^(1/3)*(a + b*x^2)^(1/3)))/(a^(1/3)*q*x)])/(2*2^(2/3)*Sqrt[3]*a^(1/3)*d), x])] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && EqQ[b*c + 3*a*d, 0] && NegQ[b/a]
Rubi steps
\begin {align*} \int \frac {1}{\sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx &=\frac {\tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{2\ 2^{2/3} \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{2\ 2^{2/3} \sqrt {3}}-\frac {\tanh ^{-1}(x)}{6\ 2^{2/3}}+\frac {\tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{2\ 2^{2/3}}\\ \end {align*}
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Mathematica [C] time = 0.07, size = 118, normalized size = 1.04 \[ -\frac {9 x F_1\left (\frac {1}{2};\frac {1}{3},1;\frac {3}{2};x^2,-\frac {x^2}{3}\right )}{\sqrt [3]{1-x^2} \left (x^2+3\right ) \left (2 x^2 \left (F_1\left (\frac {3}{2};\frac {1}{3},2;\frac {5}{2};x^2,-\frac {x^2}{3}\right )-F_1\left (\frac {3}{2};\frac {4}{3},1;\frac {5}{2};x^2,-\frac {x^2}{3}\right )\right )-9 F_1\left (\frac {1}{2};\frac {1}{3},1;\frac {3}{2};x^2,-\frac {x^2}{3}\right )\right )} \]
Warning: Unable to verify antiderivative.
[In]
Integrate[1/((1 - x^2)^(1/3)*(3 + x^2)),x]
[Out]
(-9*x*AppellF1[1/2, 1/3, 1, 3/2, x^2, -1/3*x^2])/((1 - x^2)^(1/3)*(3 + x^2)*(-9*AppellF1[1/2, 1/3, 1, 3/2, x^2
, -1/3*x^2] + 2*x^2*(AppellF1[3/2, 1/3, 2, 5/2, x^2, -1/3*x^2] - AppellF1[3/2, 4/3, 1, 5/2, x^2, -1/3*x^2])))
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fricas [B] time = 1.82, size = 1943, normalized size = 17.19 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/(-x^2+1)^(1/3)/(x^2+3),x, algorithm="fricas")
[Out]
-1/20736*432^(5/6)*sqrt(3)*log(10368*(6*2^(2/3)*(x^6 + 225*x^4 - 189*x^2 + 27) + 144*432^(1/6)*sqrt(3)*(x^5 -
x^3) + (432^(5/6)*sqrt(3)*(7*x^3 - 3*x) + 216*2^(1/3)*(x^4 + 3*x^2))*(-x^2 + 1)^(2/3) - 72*(x^5 + 18*x^4 + 24*
x^3 - 18*x^2 - 9*x)*(-x^2 + 1)^(1/3))/(x^6 + 9*x^4 + 27*x^2 + 27)) - 1/20736*432^(5/6)*sqrt(3)*log(2592*(6*2^(
2/3)*(x^6 + 225*x^4 - 189*x^2 + 27) + 144*432^(1/6)*sqrt(3)*(x^5 - x^3) + (432^(5/6)*sqrt(3)*(7*x^3 - 3*x) + 2
16*2^(1/3)*(x^4 + 3*x^2))*(-x^2 + 1)^(2/3) - 72*(x^5 + 18*x^4 + 24*x^3 - 18*x^2 - 9*x)*(-x^2 + 1)^(1/3))/(x^6
+ 9*x^4 + 27*x^2 + 27)) + 1/20736*432^(5/6)*sqrt(3)*log(10368*(6*2^(2/3)*(x^6 + 225*x^4 - 189*x^2 + 27) - 144*
432^(1/6)*sqrt(3)*(x^5 - x^3) - (432^(5/6)*sqrt(3)*(7*x^3 - 3*x) - 216*2^(1/3)*(x^4 + 3*x^2))*(-x^2 + 1)^(2/3)
+ 72*(x^5 - 18*x^4 + 24*x^3 + 18*x^2 - 9*x)*(-x^2 + 1)^(1/3))/(x^6 + 9*x^4 + 27*x^2 + 27)) + 1/20736*432^(5/6
)*sqrt(3)*log(2592*(6*2^(2/3)*(x^6 + 225*x^4 - 189*x^2 + 27) - 144*432^(1/6)*sqrt(3)*(x^5 - x^3) - (432^(5/6)*
sqrt(3)*(7*x^3 - 3*x) - 216*2^(1/3)*(x^4 + 3*x^2))*(-x^2 + 1)^(2/3) + 72*(x^5 - 18*x^4 + 24*x^3 + 18*x^2 - 9*x
)*(-x^2 + 1)^(1/3))/(x^6 + 9*x^4 + 27*x^2 + 27)) - 1/1296*432^(5/6)*arctan(1/36*(432^(5/6)*(x^5 - 18*x^3 + 9*x
)*(-x^2 + 1)^(1/3) + sqrt(3)*2^(1/3)*(432^(5/6)*(x^4 + 9*x^2)*(-x^2 + 1)^(2/3) - 288*sqrt(3)*(2*x^4 - 3*x^2)*(
-x^2 + 1)^(1/3) + 6*432^(1/6)*(x^6 + 141*x^4 - 153*x^2 + 27)) - 648*432^(1/6)*(3*x^3 - x)*(-x^2 + 1)^(2/3) - 7
2*sqrt(3)*(7*x^5 + 6*x^3 - 9*x))/(x^6 - 225*x^4 + 243*x^2 - 27)) - 1/2592*432^(5/6)*arctan(-1/18*(sqrt(2)*(18*
sqrt(3)*2^(2/3)*(29*x^11 + 879*x^9 - 12078*x^7 + 10638*x^5 - 3807*x^3 + 243*x) - 2*(-x^2 + 1)^(2/3)*(432^(5/6)
*(x^10 + 153*x^8 - 1701*x^6 + 459*x^4) - 216*sqrt(3)*2^(1/3)*(31*x^9 - 297*x^7 - 27*x^5 - 27*x^3)) - 36*(-x^2
+ 1)^(1/3)*(sqrt(3)*(x^11 + 1167*x^9 - 13158*x^7 + 17550*x^5 - 4779*x^3 + 243*x) - 8*sqrt(3)*(13*x^10 - 6*x^8
- 1404*x^6 + 1350*x^4 - 81*x^2)) - 3*432^(1/6)*(x^12 + 7620*x^10 - 92115*x^8 + 169776*x^6 - 109269*x^4 + 16524
*x^2 - 729))*sqrt((6*2^(2/3)*(x^6 + 225*x^4 - 189*x^2 + 27) + 144*432^(1/6)*sqrt(3)*(x^5 - x^3) + (432^(5/6)*s
qrt(3)*(7*x^3 - 3*x) + 216*2^(1/3)*(x^4 + 3*x^2))*(-x^2 + 1)^(2/3) - 72*(x^5 + 18*x^4 + 24*x^3 - 18*x^2 - 9*x)
*(-x^2 + 1)^(1/3))/(x^6 + 9*x^4 + 27*x^2 + 27)) - 216*(sqrt(3)*2^(2/3)*(x^10 + 144*x^8 - 918*x^6 + 2808*x^4 -
243*x^2) - 3*432^(1/6)*(31*x^9 - 568*x^7 + 1710*x^5 - 432*x^3 + 27*x))*(-x^2 + 1)^(2/3) - 18*sqrt(3)*(x^12 - 3
66*x^10 + 14535*x^8 - 42660*x^6 + 58239*x^4 - 14094*x^2 + 729) + 144*sqrt(3)*(11*x^11 - 807*x^9 + 4518*x^7 - 5
238*x^5 + 3807*x^3 - 243*x) - (-x^2 + 1)^(1/3)*(432^(5/6)*(x^11 - 1215*x^9 + 11754*x^7 - 21006*x^5 + 5589*x^3
- 243*x) - 432*sqrt(3)*2^(1/3)*(13*x^10 - 120*x^8 + 1242*x^6 - 1728*x^4 + 81*x^2)))/(x^12 - 8334*x^10 + 110727
*x^8 - 301860*x^6 + 187839*x^4 - 21870*x^2 + 729)) - 1/2592*432^(5/6)*arctan(1/18*(sqrt(2)*(18*sqrt(3)*2^(2/3)
*(29*x^11 + 879*x^9 - 12078*x^7 + 10638*x^5 - 3807*x^3 + 243*x) + 2*(-x^2 + 1)^(2/3)*(432^(5/6)*(x^10 + 153*x^
8 - 1701*x^6 + 459*x^4) + 216*sqrt(3)*2^(1/3)*(31*x^9 - 297*x^7 - 27*x^5 - 27*x^3)) - 36*(-x^2 + 1)^(1/3)*(sqr
t(3)*(x^11 + 1167*x^9 - 13158*x^7 + 17550*x^5 - 4779*x^3 + 243*x) + 8*sqrt(3)*(13*x^10 - 6*x^8 - 1404*x^6 + 13
50*x^4 - 81*x^2)) + 3*432^(1/6)*(x^12 + 7620*x^10 - 92115*x^8 + 169776*x^6 - 109269*x^4 + 16524*x^2 - 729))*sq
rt((6*2^(2/3)*(x^6 + 225*x^4 - 189*x^2 + 27) - 144*432^(1/6)*sqrt(3)*(x^5 - x^3) - (432^(5/6)*sqrt(3)*(7*x^3 -
3*x) - 216*2^(1/3)*(x^4 + 3*x^2))*(-x^2 + 1)^(2/3) + 72*(x^5 - 18*x^4 + 24*x^3 + 18*x^2 - 9*x)*(-x^2 + 1)^(1/
3))/(x^6 + 9*x^4 + 27*x^2 + 27)) - 216*(sqrt(3)*2^(2/3)*(x^10 + 144*x^8 - 918*x^6 + 2808*x^4 - 243*x^2) + 3*43
2^(1/6)*(31*x^9 - 568*x^7 + 1710*x^5 - 432*x^3 + 27*x))*(-x^2 + 1)^(2/3) - 18*sqrt(3)*(x^12 - 366*x^10 + 14535
*x^8 - 42660*x^6 + 58239*x^4 - 14094*x^2 + 729) - 144*sqrt(3)*(11*x^11 - 807*x^9 + 4518*x^7 - 5238*x^5 + 3807*
x^3 - 243*x) + (-x^2 + 1)^(1/3)*(432^(5/6)*(x^11 - 1215*x^9 + 11754*x^7 - 21006*x^5 + 5589*x^3 - 243*x) + 432*
sqrt(3)*2^(1/3)*(13*x^10 - 120*x^8 + 1242*x^6 - 1728*x^4 + 81*x^2)))/(x^12 - 8334*x^10 + 110727*x^8 - 301860*x
^6 + 187839*x^4 - 21870*x^2 + 729))
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (x^{2} + 3\right )} {\left (-x^{2} + 1\right )}^{\frac {1}{3}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/(-x^2+1)^(1/3)/(x^2+3),x, algorithm="giac")
[Out]
integrate(1/((x^2 + 3)*(-x^2 + 1)^(1/3)), x)
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maple [C] time = 50.76, size = 704, normalized size = 6.23 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(1/(-x^2+1)^(1/3)/(x^2+3),x)
[Out]
1/144*ln((-2*RootOf(_Z^6+108)^5*(-x^2+1)^(1/3)*x^2-RootOf(_Z^6+108)^4*x^3-3*RootOf(_Z^6+108)^4*x-36*RootOf(_Z^
6+108)^2*(-x^2+1)^(1/3)*x+216*(-x^2+1)^(2/3)*x-126*RootOf(_Z^6+108)*x^2+54*RootOf(_Z^6+108))/(RootOf(_Z^6+108)
^3*x-18)^2/(RootOf(_Z^6+108)^3*x+18))*RootOf(_Z^6+108)^4+1/24*ln((-2*RootOf(_Z^6+108)^5*(-x^2+1)^(1/3)*x^2-Roo
tOf(_Z^6+108)^4*x^3-3*RootOf(_Z^6+108)^4*x-36*RootOf(_Z^6+108)^2*(-x^2+1)^(1/3)*x+216*(-x^2+1)^(2/3)*x-126*Roo
tOf(_Z^6+108)*x^2+54*RootOf(_Z^6+108))/(RootOf(_Z^6+108)^3*x-18)^2/(RootOf(_Z^6+108)^3*x+18))*RootOf(_Z^6+108)
-1/216*RootOf(_Z^6+108)^4*ln((-RootOf(_Z^6+108)^4*x^6-225*RootOf(_Z^6+108)^4*x^4+72*x^5*RootOf(_Z^6+108)^4-129
6*x^5*RootOf(_Z^6+108)+486*RootOf(_Z^6+108)+189*RootOf(_Z^6+108)^4*x^2-3402*RootOf(_Z^6+108)*x^2+4050*RootOf(_
Z^6+108)*x^4-72*RootOf(_Z^6+108)^4*x^3+1296*RootOf(_Z^6+108)*x^3-27*RootOf(_Z^6+108)^4-108*RootOf(_Z^6+108)^5*
(-x^2+1)^(1/3)*x^2-324*RootOf(_Z^6+108)^2*(-x^2+1)^(1/3)*x-6*RootOf(_Z^6+108)^5*(-x^2+1)^(1/3)*x^5+108*RootOf(
_Z^6+108)^5*(-x^2+1)^(1/3)*x^4-144*RootOf(_Z^6+108)^5*(-x^2+1)^(1/3)*x^3+36*RootOf(_Z^6+108)^2*(-x^2+1)^(1/3)*
x^5+54*RootOf(_Z^6+108)^5*(-x^2+1)^(1/3)*x-648*RootOf(_Z^6+108)^2*(-x^2+1)^(1/3)*x^4+864*RootOf(_Z^6+108)^2*(-
x^2+1)^(1/3)*x^3+648*RootOf(_Z^6+108)^2*(-x^2+1)^(1/3)*x^2+3888*(-x^2+1)^(2/3)*x+1296*(-x^2+1)^(2/3)*x^4-9072*
(-x^2+1)^(2/3)*x^3+3888*(-x^2+1)^(2/3)*x^2+18*RootOf(_Z^6+108)*x^6)/(x^2+3)^3)
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (x^{2} + 3\right )} {\left (-x^{2} + 1\right )}^{\frac {1}{3}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/(-x^2+1)^(1/3)/(x^2+3),x, algorithm="maxima")
[Out]
integrate(1/((x^2 + 3)*(-x^2 + 1)^(1/3)), x)
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {1}{{\left (1-x^2\right )}^{1/3}\,\left (x^2+3\right )} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(1/((1 - x^2)^(1/3)*(x^2 + 3)),x)
[Out]
int(1/((1 - x^2)^(1/3)*(x^2 + 3)), x)
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt [3]{- \left (x - 1\right ) \left (x + 1\right )} \left (x^{2} + 3\right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(1/(-x**2+1)**(1/3)/(x**2+3),x)
[Out]
Integral(1/((-(x - 1)*(x + 1))**(1/3)*(x**2 + 3)), x)
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