3.10 \(\int \frac {(\sqrt {x}-\sqrt {-1+x^2})^2}{(1+x-x^2)^2 \sqrt {-1+x^2}} \, dx\)

Optimal. Leaf size=220 \[ \frac {2-4 x}{5 \left (\sqrt {x^2-1}+\sqrt {x}\right )}-\frac {1}{50} \sqrt {50 \sqrt {5}-110} \tan ^{-1}\left (\frac {\sqrt {2 \sqrt {5}-2} \sqrt {x^2-1}}{2-\left (1-\sqrt {5}\right ) x}\right )-\frac {1}{50} \sqrt {110+50 \sqrt {5}} \tanh ^{-1}\left (\frac {\sqrt {2+2 \sqrt {5}} \sqrt {x^2-1}}{-\sqrt {5} x-x+2}\right )+\frac {1}{25} \sqrt {50 \sqrt {5}-110} \tan ^{-1}\left (\frac {1}{2} \sqrt {2+2 \sqrt {5}} \sqrt {x}\right )-\frac {1}{25} \sqrt {110+50 \sqrt {5}} \tanh ^{-1}\left (\frac {1}{2} \sqrt {2 \sqrt {5}-2} \sqrt {x}\right ) \]

[Out]

1/5*(2-4*x)/(x^(1/2)+(x^2-1)^(1/2))-1/50*arctan((x^2-1)^(1/2)*(-2+2*5^(1/2))^(1/2)/(2-x*(-5^(1/2)+1)))*(-110+5
0*5^(1/2))^(1/2)+1/25*arctan(1/2*x^(1/2)*(2+2*5^(1/2))^(1/2))*(-110+50*5^(1/2))^(1/2)-1/25*arctanh(1/2*x^(1/2)
*(-2+2*5^(1/2))^(1/2))*(110+50*5^(1/2))^(1/2)-1/50*arctanh((x^2-1)^(1/2)*(2+2*5^(1/2))^(1/2)/(2-x-x*5^(1/2)))*
(110+50*5^(1/2))^(1/2)

________________________________________________________________________________________

Rubi [B]  time = 0.75, antiderivative size = 541, normalized size of antiderivative = 2.46, number of steps used = 25, number of rules used = 13, integrand size = 39, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {6742, 736, 826, 1166, 207, 203, 975, 1034, 725, 206, 204, 1018, 1065} \[ -\frac {\sqrt {x^2-1} (1-2 x)}{5 \left (-x^2+x+1\right )}+\frac {2 \sqrt {x} (1-2 x)}{5 \left (-x^2+x+1\right )}-\frac {(3-x) \sqrt {x^2-1}}{5 \left (-x^2+x+1\right )}+\frac {(x+2) \sqrt {x^2-1}}{5 \left (-x^2+x+1\right )}+\frac {1}{5} \sqrt {\frac {1}{5} \left (2+5 \sqrt {5}\right )} \tan ^{-1}\left (\frac {2-\left (1-\sqrt {5}\right ) x}{\sqrt {2 \left (\sqrt {5}-1\right )} \sqrt {x^2-1}}\right )-\frac {1}{5} \sqrt {\frac {1}{5} \left (5 \sqrt {5}-2\right )} \tan ^{-1}\left (\frac {2-\left (1-\sqrt {5}\right ) x}{\sqrt {2 \left (\sqrt {5}-1\right )} \sqrt {x^2-1}}\right )-\frac {1}{5} \sqrt {\frac {1}{10} \left (5 \sqrt {5}-11\right )} \tan ^{-1}\left (\frac {2-\left (1-\sqrt {5}\right ) x}{\sqrt {2 \left (\sqrt {5}-1\right )} \sqrt {x^2-1}}\right )+\frac {1}{5} \sqrt {\frac {1}{10} \left (11+5 \sqrt {5}\right )} \tanh ^{-1}\left (\frac {2-\left (1+\sqrt {5}\right ) x}{\sqrt {2 \left (1+\sqrt {5}\right )} \sqrt {x^2-1}}\right )-\frac {1}{5} \sqrt {\frac {1}{5} \left (2+5 \sqrt {5}\right )} \tanh ^{-1}\left (\frac {2-\left (1+\sqrt {5}\right ) x}{\sqrt {2 \left (1+\sqrt {5}\right )} \sqrt {x^2-1}}\right )-\frac {1}{5} \sqrt {\frac {1}{5} \left (5 \sqrt {5}-2\right )} \tanh ^{-1}\left (\frac {2-\left (1+\sqrt {5}\right ) x}{\sqrt {2 \left (1+\sqrt {5}\right )} \sqrt {x^2-1}}\right )+\frac {1}{5} \sqrt {\frac {2}{5} \left (5 \sqrt {5}-11\right )} \tan ^{-1}\left (\sqrt {\frac {2}{\sqrt {5}-1}} \sqrt {x}\right )-\frac {1}{5} \sqrt {\frac {2}{5} \left (11+5 \sqrt {5}\right )} \tanh ^{-1}\left (\sqrt {\frac {2}{1+\sqrt {5}}} \sqrt {x}\right ) \]

Warning: Unable to verify antiderivative.

[In]

Int[(Sqrt[x] - Sqrt[-1 + x^2])^2/((1 + x - x^2)^2*Sqrt[-1 + x^2]),x]

[Out]

(2*(1 - 2*x)*Sqrt[x])/(5*(1 + x - x^2)) - ((1 - 2*x)*Sqrt[-1 + x^2])/(5*(1 + x - x^2)) - ((3 - x)*Sqrt[-1 + x^
2])/(5*(1 + x - x^2)) + ((2 + x)*Sqrt[-1 + x^2])/(5*(1 + x - x^2)) + (Sqrt[(2*(-11 + 5*Sqrt[5]))/5]*ArcTan[Sqr
t[2/(-1 + Sqrt[5])]*Sqrt[x]])/5 - (Sqrt[(-11 + 5*Sqrt[5])/10]*ArcTan[(2 - (1 - Sqrt[5])*x)/(Sqrt[2*(-1 + Sqrt[
5])]*Sqrt[-1 + x^2])])/5 - (Sqrt[(-2 + 5*Sqrt[5])/5]*ArcTan[(2 - (1 - Sqrt[5])*x)/(Sqrt[2*(-1 + Sqrt[5])]*Sqrt
[-1 + x^2])])/5 + (Sqrt[(2 + 5*Sqrt[5])/5]*ArcTan[(2 - (1 - Sqrt[5])*x)/(Sqrt[2*(-1 + Sqrt[5])]*Sqrt[-1 + x^2]
)])/5 - (Sqrt[(2*(11 + 5*Sqrt[5]))/5]*ArcTanh[Sqrt[2/(1 + Sqrt[5])]*Sqrt[x]])/5 - (Sqrt[(-2 + 5*Sqrt[5])/5]*Ar
cTanh[(2 - (1 + Sqrt[5])*x)/(Sqrt[2*(1 + Sqrt[5])]*Sqrt[-1 + x^2])])/5 - (Sqrt[(2 + 5*Sqrt[5])/5]*ArcTanh[(2 -
 (1 + Sqrt[5])*x)/(Sqrt[2*(1 + Sqrt[5])]*Sqrt[-1 + x^2])])/5 + (Sqrt[(11 + 5*Sqrt[5])/10]*ArcTanh[(2 - (1 + Sq
rt[5])*x)/(Sqrt[2*(1 + Sqrt[5])]*Sqrt[-1 + x^2])])/5

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
 FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
 /; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 207

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTanh[(Rt[b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[b, 2]), x] /;
 FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 725

Int[1/(((d_) + (e_.)*(x_))*Sqrt[(a_) + (c_.)*(x_)^2]), x_Symbol] :> -Subst[Int[1/(c*d^2 + a*e^2 - x^2), x], x,
 (a*e - c*d*x)/Sqrt[a + c*x^2]] /; FreeQ[{a, c, d, e}, x]

Rule 736

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((d + e*x)^m*(b + 2*
c*x)*(a + b*x + c*x^2)^(p + 1))/((p + 1)*(b^2 - 4*a*c)), x] - Dist[1/((p + 1)*(b^2 - 4*a*c)), Int[(d + e*x)^(m
 - 1)*(b*e*m + 2*c*d*(2*p + 3) + 2*c*e*(m + 2*p + 3)*x)*(a + b*x + c*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d
, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ[2*c*d - b*e, 0] && LtQ[p, -1] && GtQ[m
, 0] && (LtQ[m, 1] || (ILtQ[m + 2*p + 3, 0] && NeQ[m, 2])) && IntQuadraticQ[a, b, c, d, e, m, p, x]

Rule 826

Int[((f_.) + (g_.)*(x_))/(Sqrt[(d_.) + (e_.)*(x_)]*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)), x_Symbol] :> Dist[2,
Subst[Int[(e*f - d*g + g*x^2)/(c*d^2 - b*d*e + a*e^2 - (2*c*d - b*e)*x^2 + c*x^4), x], x, Sqrt[d + e*x]], x] /
; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0]

Rule 975

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_)*((d_.) + (f_.)*(x_)^2)^(q_), x_Symbol] :> Simp[((b^3*f + b*c*(c*d
 - 3*a*f) + c*(2*c^2*d + b^2*f - c*(2*a*f))*x)*(a + b*x + c*x^2)^(p + 1)*(d + f*x^2)^(q + 1))/((b^2 - 4*a*c)*(
b^2*d*f + (c*d - a*f)^2)*(p + 1)), x] - Dist[1/((b^2 - 4*a*c)*(b^2*d*f + (c*d - a*f)^2)*(p + 1)), Int[(a + b*x
 + c*x^2)^(p + 1)*(d + f*x^2)^q*Simp[2*c*(b^2*d*f + (c*d - a*f)^2)*(p + 1) - (2*c^2*d + b^2*f - c*(2*a*f))*(a*
f*(p + 1) - c*d*(p + 2)) + (2*f*(b^3*f + b*c*(c*d - 3*a*f))*(p + q + 2) - (2*c^2*d + b^2*f - c*(2*a*f))*(b*f*(
p + 1)))*x + c*f*(2*c^2*d + b^2*f - c*(2*a*f))*(2*p + 2*q + 5)*x^2, x], x], x] /; FreeQ[{a, b, c, d, f, q}, x]
 && NeQ[b^2 - 4*a*c, 0] && LtQ[p, -1] && NeQ[b^2*d*f + (c*d - a*f)^2, 0] &&  !( !IntegerQ[p] && ILtQ[q, -1]) &
&  !IGtQ[q, 0]

Rule 1018

Int[((g_.) + (h_.)*(x_))*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_)*((d_) + (f_.)*(x_)^2)^(q_), x_Symbol] :> Simp
[((a + b*x + c*x^2)^(p + 1)*(d + f*x^2)^(q + 1)*((g*c)*(-(b*(c*d + a*f))) + (g*b - a*h)*(2*c^2*d + b^2*f - c*(
2*a*f)) + c*(g*(2*c^2*d + b^2*f - c*(2*a*f)) - h*(b*c*d + a*b*f))*x))/((b^2 - 4*a*c)*(b^2*d*f + (c*d - a*f)^2)
*(p + 1)), x] + Dist[1/((b^2 - 4*a*c)*(b^2*d*f + (c*d - a*f)^2)*(p + 1)), Int[(a + b*x + c*x^2)^(p + 1)*(d + f
*x^2)^q*Simp[(b*h - 2*g*c)*((c*d - a*f)^2 - (b*d)*(-(b*f)))*(p + 1) + (b^2*(g*f) - b*(h*c*d + a*h*f) + 2*(g*c*
(c*d - a*f)))*(a*f*(p + 1) - c*d*(p + 2)) - (2*f*((g*c)*(-(b*(c*d + a*f))) + (g*b - a*h)*(2*c^2*d + b^2*f - c*
(2*a*f)))*(p + q + 2) - (b^2*(g*f) - b*(h*c*d + a*h*f) + 2*(g*c*(c*d - a*f)))*(b*f*(p + 1)))*x - c*f*(b^2*(g*f
) - b*(h*c*d + a*h*f) + 2*(g*c*(c*d - a*f)))*(2*p + 2*q + 5)*x^2, x], x], x] /; FreeQ[{a, b, c, d, f, g, h, q}
, x] && NeQ[b^2 - 4*a*c, 0] && LtQ[p, -1] && NeQ[b^2*d*f + (c*d - a*f)^2, 0] &&  !( !IntegerQ[p] && ILtQ[q, -1
])

Rule 1034

Int[((g_.) + (h_.)*(x_))/(((a_) + (b_.)*(x_) + (c_.)*(x_)^2)*Sqrt[(d_) + (f_.)*(x_)^2]), x_Symbol] :> With[{q
= Rt[b^2 - 4*a*c, 2]}, Dist[(2*c*g - h*(b - q))/q, Int[1/((b - q + 2*c*x)*Sqrt[d + f*x^2]), x], x] - Dist[(2*c
*g - h*(b + q))/q, Int[1/((b + q + 2*c*x)*Sqrt[d + f*x^2]), x], x]] /; FreeQ[{a, b, c, d, f, g, h}, x] && NeQ[
b^2 - 4*a*c, 0] && PosQ[b^2 - 4*a*c]

Rule 1065

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_)*((A_.) + (C_.)*(x_)^2)*((d_) + (f_.)*(x_)^2)^(q_), x_Symbol] :> Si
mp[((a + b*x + c*x^2)^(p + 1)*(d + f*x^2)^(q + 1)*((A*c - a*C)*(-(b*(c*d + a*f))) + (A*b)*(2*c^2*d + b^2*f - c
*(2*a*f)) + c*(A*(2*c^2*d + b^2*f - c*(2*a*f)) + C*(b^2*d - 2*a*(c*d - a*f)))*x))/((b^2 - 4*a*c)*(b^2*d*f + (c
*d - a*f)^2)*(p + 1)), x] + Dist[1/((b^2 - 4*a*c)*(b^2*d*f + (c*d - a*f)^2)*(p + 1)), Int[(a + b*x + c*x^2)^(p
 + 1)*(d + f*x^2)^q*Simp[(-2*A*c - 2*a*C)*((c*d - a*f)^2 - (b*d)*(-(b*f)))*(p + 1) + (b^2*(C*d + A*f) + 2*(A*c
*(c*d - a*f) - a*(c*C*d - a*C*f)))*(a*f*(p + 1) - c*d*(p + 2)) - (2*f*((A*c - a*C)*(-(b*(c*d + a*f))) + (A*b)*
(2*c^2*d + b^2*f - c*(2*a*f)))*(p + q + 2) - (b^2*(C*d + A*f) + 2*(A*c*(c*d - a*f) - a*(c*C*d - a*C*f)))*(b*f*
(p + 1)))*x - c*f*(b^2*(C*d + A*f) + 2*(A*c*(c*d - a*f) - a*(c*C*d - a*C*f)))*(2*p + 2*q + 5)*x^2, x], x], x]
/; FreeQ[{a, b, c, d, f, A, C, q}, x] && NeQ[b^2 - 4*a*c, 0] && LtQ[p, -1] && NeQ[b^2*d*f + (c*d - a*f)^2, 0]
&&  !( !IntegerQ[p] && ILtQ[q, -1]) &&  !IGtQ[q, 0]

Rule 1166

Int[((d_) + (e_.)*(x_)^2)/((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Di
st[e/2 + (2*c*d - b*e)/(2*q), Int[1/(b/2 - q/2 + c*x^2), x], x] + Dist[e/2 - (2*c*d - b*e)/(2*q), Int[1/(b/2 +
 q/2 + c*x^2), x], x]] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - a*e^2, 0] && PosQ[b^
2 - 4*a*c]

Rule 6742

Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v]]

Rubi steps

\begin {align*} \int \frac {\left (\sqrt {x}-\sqrt {-1+x^2}\right )^2}{\left (1+x-x^2\right )^2 \sqrt {-1+x^2}} \, dx &=\int \left (-\frac {2 \sqrt {x}}{\left (-1-x+x^2\right )^2}-\frac {1}{\sqrt {-1+x^2} \left (-1-x+x^2\right )^2}+\frac {x}{\sqrt {-1+x^2} \left (-1-x+x^2\right )^2}+\frac {x^2}{\sqrt {-1+x^2} \left (-1-x+x^2\right )^2}\right ) \, dx\\ &=-\left (2 \int \frac {\sqrt {x}}{\left (-1-x+x^2\right )^2} \, dx\right )-\int \frac {1}{\sqrt {-1+x^2} \left (-1-x+x^2\right )^2} \, dx+\int \frac {x}{\sqrt {-1+x^2} \left (-1-x+x^2\right )^2} \, dx+\int \frac {x^2}{\sqrt {-1+x^2} \left (-1-x+x^2\right )^2} \, dx\\ &=\frac {2 (1-2 x) \sqrt {x}}{5 \left (1+x-x^2\right )}-\frac {(1-2 x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}-\frac {(3-x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}+\frac {(2+x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}+\frac {1}{5} \int \frac {1-3 x}{\sqrt {-1+x^2} \left (-1-x+x^2\right )} \, dx+\frac {1}{5} \int \frac {-3-x}{\sqrt {-1+x^2} \left (-1-x+x^2\right )} \, dx+\frac {1}{5} \int \frac {1+2 x}{\sqrt {-1+x^2} \left (-1-x+x^2\right )} \, dx-\frac {2}{5} \int \frac {-\frac {1}{2}-x}{\sqrt {x} \left (-1-x+x^2\right )} \, dx\\ &=\frac {2 (1-2 x) \sqrt {x}}{5 \left (1+x-x^2\right )}-\frac {(1-2 x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}-\frac {(3-x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}+\frac {(2+x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}-\frac {4}{5} \operatorname {Subst}\left (\int \frac {-\frac {1}{2}-x^2}{-1-x^2+x^4} \, dx,x,\sqrt {x}\right )+\frac {1}{25} \left (2 \left (5-2 \sqrt {5}\right )\right ) \int \frac {1}{\left (-1+\sqrt {5}+2 x\right ) \sqrt {-1+x^2}} \, dx+\frac {1}{25} \left (-15+\sqrt {5}\right ) \int \frac {1}{\left (-1+\sqrt {5}+2 x\right ) \sqrt {-1+x^2}} \, dx-\frac {1}{25} \left (15+\sqrt {5}\right ) \int \frac {1}{\left (-1-\sqrt {5}+2 x\right ) \sqrt {-1+x^2}} \, dx+\frac {1}{25} \left (2 \left (5+2 \sqrt {5}\right )\right ) \int \frac {1}{\left (-1-\sqrt {5}+2 x\right ) \sqrt {-1+x^2}} \, dx+\frac {1}{25} \left (-5+7 \sqrt {5}\right ) \int \frac {1}{\left (-1+\sqrt {5}+2 x\right ) \sqrt {-1+x^2}} \, dx-\frac {1}{25} \left (5+7 \sqrt {5}\right ) \int \frac {1}{\left (-1-\sqrt {5}+2 x\right ) \sqrt {-1+x^2}} \, dx\\ &=\frac {2 (1-2 x) \sqrt {x}}{5 \left (1+x-x^2\right )}-\frac {(1-2 x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}-\frac {(3-x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}+\frac {(2+x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}+\frac {1}{25} \left (5-7 \sqrt {5}\right ) \operatorname {Subst}\left (\int \frac {1}{-4+\left (-1+\sqrt {5}\right )^2-x^2} \, dx,x,\frac {-2-\left (-1+\sqrt {5}\right ) x}{\sqrt {-1+x^2}}\right )-\frac {1}{25} \left (2 \left (5-2 \sqrt {5}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{-4+\left (-1+\sqrt {5}\right )^2-x^2} \, dx,x,\frac {-2-\left (-1+\sqrt {5}\right ) x}{\sqrt {-1+x^2}}\right )+\frac {1}{25} \left (2 \left (5-2 \sqrt {5}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{-\frac {1}{2}+\frac {\sqrt {5}}{2}+x^2} \, dx,x,\sqrt {x}\right )+\frac {1}{25} \left (15-\sqrt {5}\right ) \operatorname {Subst}\left (\int \frac {1}{-4+\left (-1+\sqrt {5}\right )^2-x^2} \, dx,x,\frac {-2-\left (-1+\sqrt {5}\right ) x}{\sqrt {-1+x^2}}\right )+\frac {1}{25} \left (15+\sqrt {5}\right ) \operatorname {Subst}\left (\int \frac {1}{-4+\left (-1-\sqrt {5}\right )^2-x^2} \, dx,x,\frac {-2-\left (-1-\sqrt {5}\right ) x}{\sqrt {-1+x^2}}\right )-\frac {1}{25} \left (2 \left (5+2 \sqrt {5}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{-4+\left (-1-\sqrt {5}\right )^2-x^2} \, dx,x,\frac {-2-\left (-1-\sqrt {5}\right ) x}{\sqrt {-1+x^2}}\right )+\frac {1}{25} \left (2 \left (5+2 \sqrt {5}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{-\frac {1}{2}-\frac {\sqrt {5}}{2}+x^2} \, dx,x,\sqrt {x}\right )+\frac {1}{25} \left (5+7 \sqrt {5}\right ) \operatorname {Subst}\left (\int \frac {1}{-4+\left (-1-\sqrt {5}\right )^2-x^2} \, dx,x,\frac {-2-\left (-1-\sqrt {5}\right ) x}{\sqrt {-1+x^2}}\right )\\ &=\frac {2 (1-2 x) \sqrt {x}}{5 \left (1+x-x^2\right )}-\frac {(1-2 x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}-\frac {(3-x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}+\frac {(2+x) \sqrt {-1+x^2}}{5 \left (1+x-x^2\right )}+\frac {1}{5} \sqrt {\frac {2}{5} \left (-11+5 \sqrt {5}\right )} \tan ^{-1}\left (\sqrt {\frac {2}{-1+\sqrt {5}}} \sqrt {x}\right )-\frac {1}{5} \sqrt {\frac {1}{10} \left (-11+5 \sqrt {5}\right )} \tan ^{-1}\left (\frac {2-\left (1-\sqrt {5}\right ) x}{\sqrt {2 \left (-1+\sqrt {5}\right )} \sqrt {-1+x^2}}\right )-\frac {1}{5} \sqrt {\frac {1}{5} \left (-2+5 \sqrt {5}\right )} \tan ^{-1}\left (\frac {2-\left (1-\sqrt {5}\right ) x}{\sqrt {2 \left (-1+\sqrt {5}\right )} \sqrt {-1+x^2}}\right )+\frac {1}{5} \sqrt {\frac {1}{5} \left (2+5 \sqrt {5}\right )} \tan ^{-1}\left (\frac {2-\left (1-\sqrt {5}\right ) x}{\sqrt {2 \left (-1+\sqrt {5}\right )} \sqrt {-1+x^2}}\right )-\frac {1}{5} \sqrt {\frac {2}{5} \left (11+5 \sqrt {5}\right )} \tanh ^{-1}\left (\sqrt {\frac {2}{1+\sqrt {5}}} \sqrt {x}\right )-\frac {1}{5} \sqrt {\frac {1}{5} \left (-2+5 \sqrt {5}\right )} \tanh ^{-1}\left (\frac {2-\left (1+\sqrt {5}\right ) x}{\sqrt {2 \left (1+\sqrt {5}\right )} \sqrt {-1+x^2}}\right )-\frac {1}{5} \sqrt {\frac {1}{5} \left (2+5 \sqrt {5}\right )} \tanh ^{-1}\left (\frac {2-\left (1+\sqrt {5}\right ) x}{\sqrt {2 \left (1+\sqrt {5}\right )} \sqrt {-1+x^2}}\right )+\frac {1}{5} \sqrt {\frac {1}{10} \left (11+5 \sqrt {5}\right )} \tanh ^{-1}\left (\frac {2-\left (1+\sqrt {5}\right ) x}{\sqrt {2 \left (1+\sqrt {5}\right )} \sqrt {-1+x^2}}\right )\\ \end {align*}

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Mathematica [A]  time = 0.71, size = 311, normalized size = 1.41 \[ \frac {1}{25} \left (\sqrt {\frac {2}{1+\sqrt {5}}} \left (5+2 \sqrt {5}\right ) \tanh ^{-1}\left (\frac {\sqrt {5} x+x-2}{\sqrt {2 \left (1+\sqrt {5}\right )} \sqrt {x^2-1}}\right )+\frac {-20 x^{3/2}+20 \sqrt {x^2-1} x-10 \sqrt {x^2-1}+\sqrt {50 \sqrt {5}-110} \left (-x^2+x+1\right ) \tan ^{-1}\left (\sqrt {\frac {2}{\sqrt {5}-1}} \sqrt {x}\right )+\sqrt {10 \left (1+\sqrt {5}\right )} \left (-x^2+x+1\right ) \tan ^{-1}\left (\frac {-\sqrt {5} x+x-2}{\sqrt {2 \left (\sqrt {5}-1\right )} \sqrt {x^2-1}}\right )+5 \sqrt {\frac {2}{\sqrt {5}-1}} \left (x^2-x-1\right ) \tan ^{-1}\left (\frac {-\sqrt {5} x+x-2}{\sqrt {2 \left (\sqrt {5}-1\right )} \sqrt {x^2-1}}\right )+10 \sqrt {x}}{-x^2+x+1}-\sqrt {110+50 \sqrt {5}} \tanh ^{-1}\left (\sqrt {\frac {2}{1+\sqrt {5}}} \sqrt {x}\right )\right ) \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(Sqrt[x] - Sqrt[-1 + x^2])^2/((1 + x - x^2)^2*Sqrt[-1 + x^2]),x]

[Out]

((10*Sqrt[x] - 20*x^(3/2) - 10*Sqrt[-1 + x^2] + 20*x*Sqrt[-1 + x^2] + Sqrt[-110 + 50*Sqrt[5]]*(1 + x - x^2)*Ar
cTan[Sqrt[2/(-1 + Sqrt[5])]*Sqrt[x]] + Sqrt[10*(1 + Sqrt[5])]*(1 + x - x^2)*ArcTan[(-2 + x - Sqrt[5]*x)/(Sqrt[
2*(-1 + Sqrt[5])]*Sqrt[-1 + x^2])] + 5*Sqrt[2/(-1 + Sqrt[5])]*(-1 - x + x^2)*ArcTan[(-2 + x - Sqrt[5]*x)/(Sqrt
[2*(-1 + Sqrt[5])]*Sqrt[-1 + x^2])])/(1 + x - x^2) - Sqrt[110 + 50*Sqrt[5]]*ArcTanh[Sqrt[2/(1 + Sqrt[5])]*Sqrt
[x]] + Sqrt[2/(1 + Sqrt[5])]*(5 + 2*Sqrt[5])*ArcTanh[(-2 + x + Sqrt[5]*x)/(Sqrt[2*(1 + Sqrt[5])]*Sqrt[-1 + x^2
])])/25

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fricas [B]  time = 0.61, size = 424, normalized size = 1.93 \[ \frac {4 \, \sqrt {5} {\left (x^{2} - x - 1\right )} \sqrt {10 \, \sqrt {5} - 22} \arctan \left (\frac {1}{2} \, \sqrt {2 \, x^{2} - \sqrt {x^{2} - 1} {\left (2 \, x + \sqrt {5} - 1\right )} + \sqrt {5} x - x} \sqrt {10 \, \sqrt {5} - 22} {\left (\sqrt {5} + 2\right )} + \frac {1}{4} \, {\left (\sqrt {5} {\left (2 \, x + 1\right )} - 2 \, \sqrt {x^{2} - 1} {\left (\sqrt {5} + 2\right )} + 4 \, x + 3\right )} \sqrt {10 \, \sqrt {5} - 22}\right ) - 4 \, \sqrt {5} {\left (x^{2} - x - 1\right )} \sqrt {10 \, \sqrt {5} - 22} \arctan \left (\frac {1}{4} \, {\left (\sqrt {2} \sqrt {2 \, x + \sqrt {5} - 1} {\left (\sqrt {5} + 2\right )} - 2 \, \sqrt {x} {\left (\sqrt {5} + 2\right )}\right )} \sqrt {10 \, \sqrt {5} - 22}\right ) - \sqrt {5} {\left (x^{2} - x - 1\right )} \sqrt {10 \, \sqrt {5} + 22} \log \left (\sqrt {10 \, \sqrt {5} + 22} {\left (\sqrt {5} - 3\right )} - 4 \, x + 2 \, \sqrt {5} + 4 \, \sqrt {x^{2} - 1} + 2\right ) + \sqrt {5} {\left (x^{2} - x - 1\right )} \sqrt {10 \, \sqrt {5} + 22} \log \left (\sqrt {10 \, \sqrt {5} + 22} {\left (\sqrt {5} - 3\right )} + 4 \, \sqrt {x}\right ) + \sqrt {5} {\left (x^{2} - x - 1\right )} \sqrt {10 \, \sqrt {5} + 22} \log \left (-\sqrt {10 \, \sqrt {5} + 22} {\left (\sqrt {5} - 3\right )} - 4 \, x + 2 \, \sqrt {5} + 4 \, \sqrt {x^{2} - 1} + 2\right ) - \sqrt {5} {\left (x^{2} - x - 1\right )} \sqrt {10 \, \sqrt {5} + 22} \log \left (-\sqrt {10 \, \sqrt {5} + 22} {\left (\sqrt {5} - 3\right )} + 4 \, \sqrt {x}\right ) - 40 \, x^{2} - 20 \, \sqrt {x^{2} - 1} {\left (2 \, x - 1\right )} + 20 \, {\left (2 \, x - 1\right )} \sqrt {x} + 40 \, x + 40}{50 \, {\left (x^{2} - x - 1\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^(1/2)-(x^2-1)^(1/2))^2/(-x^2+x+1)^2/(x^2-1)^(1/2),x, algorithm="fricas")

[Out]

1/50*(4*sqrt(5)*(x^2 - x - 1)*sqrt(10*sqrt(5) - 22)*arctan(1/2*sqrt(2*x^2 - sqrt(x^2 - 1)*(2*x + sqrt(5) - 1)
+ sqrt(5)*x - x)*sqrt(10*sqrt(5) - 22)*(sqrt(5) + 2) + 1/4*(sqrt(5)*(2*x + 1) - 2*sqrt(x^2 - 1)*(sqrt(5) + 2)
+ 4*x + 3)*sqrt(10*sqrt(5) - 22)) - 4*sqrt(5)*(x^2 - x - 1)*sqrt(10*sqrt(5) - 22)*arctan(1/4*(sqrt(2)*sqrt(2*x
 + sqrt(5) - 1)*(sqrt(5) + 2) - 2*sqrt(x)*(sqrt(5) + 2))*sqrt(10*sqrt(5) - 22)) - sqrt(5)*(x^2 - x - 1)*sqrt(1
0*sqrt(5) + 22)*log(sqrt(10*sqrt(5) + 22)*(sqrt(5) - 3) - 4*x + 2*sqrt(5) + 4*sqrt(x^2 - 1) + 2) + sqrt(5)*(x^
2 - x - 1)*sqrt(10*sqrt(5) + 22)*log(sqrt(10*sqrt(5) + 22)*(sqrt(5) - 3) + 4*sqrt(x)) + sqrt(5)*(x^2 - x - 1)*
sqrt(10*sqrt(5) + 22)*log(-sqrt(10*sqrt(5) + 22)*(sqrt(5) - 3) - 4*x + 2*sqrt(5) + 4*sqrt(x^2 - 1) + 2) - sqrt
(5)*(x^2 - x - 1)*sqrt(10*sqrt(5) + 22)*log(-sqrt(10*sqrt(5) + 22)*(sqrt(5) - 3) + 4*sqrt(x)) - 40*x^2 - 20*sq
rt(x^2 - 1)*(2*x - 1) + 20*(2*x - 1)*sqrt(x) + 40*x + 40)/(x^2 - x - 1)

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giac [B]  time = 9.22, size = 358, normalized size = 1.63 \[ \frac {2}{5} \, \sqrt {\frac {1}{2} \, \sqrt {5} - \frac {11}{10}} \arctan \left (\frac {2 \, x + \sqrt {5} - 2 \, \sqrt {x^{2} - 1} - 1}{\sqrt {2 \, \sqrt {5} - 2}}\right ) + \frac {1}{25} \, \sqrt {50 \, \sqrt {5} - 110} \arctan \left (\frac {\sqrt {x}}{\sqrt {\frac {1}{2} \, \sqrt {5} - \frac {1}{2}}}\right ) - \frac {1}{50} \, \sqrt {50 \, \sqrt {5} + 110} \log \left (\sqrt {x} + \sqrt {\frac {1}{2} \, \sqrt {5} + \frac {1}{2}}\right ) - \frac {1}{5} \, \sqrt {\frac {1}{2} \, \sqrt {5} + \frac {11}{10}} \log \left ({\left | -520 \, x - 78 \, \sqrt {5} \sqrt {50 \, \sqrt {5} + 110} + 260 \, \sqrt {5} + 520 \, \sqrt {x^{2} - 1} + 130 \, \sqrt {50 \, \sqrt {5} + 110} + 260 \right |}\right ) + \frac {1}{5} \, \sqrt {\frac {1}{2} \, \sqrt {5} + \frac {11}{10}} \log \left ({\left | -1040 \, x + 156 \, \sqrt {5} \sqrt {50 \, \sqrt {5} + 110} + 520 \, \sqrt {5} + 1040 \, \sqrt {x^{2} - 1} - 260 \, \sqrt {50 \, \sqrt {5} + 110} + 520 \right |}\right ) + \frac {1}{50} \, \sqrt {50 \, \sqrt {5} + 110} \log \left ({\left | \sqrt {x} - \sqrt {\frac {1}{2} \, \sqrt {5} + \frac {1}{2}} \right |}\right ) + \frac {4 \, {\left ({\left (x - \sqrt {x^{2} - 1}\right )}^{3} + 2 \, {\left (x - \sqrt {x^{2} - 1}\right )}^{2} + 3 \, x - 3 \, \sqrt {x^{2} - 1} - 2\right )}}{5 \, {\left ({\left (x - \sqrt {x^{2} - 1}\right )}^{4} - 2 \, {\left (x - \sqrt {x^{2} - 1}\right )}^{3} - 2 \, {\left (x - \sqrt {x^{2} - 1}\right )}^{2} - 2 \, x + 2 \, \sqrt {x^{2} - 1} + 1\right )}} + \frac {2 \, {\left (2 \, x^{\frac {3}{2}} - \sqrt {x}\right )}}{5 \, {\left (x^{2} - x - 1\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^(1/2)-(x^2-1)^(1/2))^2/(-x^2+x+1)^2/(x^2-1)^(1/2),x, algorithm="giac")

[Out]

2/5*sqrt(1/2*sqrt(5) - 11/10)*arctan((2*x + sqrt(5) - 2*sqrt(x^2 - 1) - 1)/sqrt(2*sqrt(5) - 2)) + 1/25*sqrt(50
*sqrt(5) - 110)*arctan(sqrt(x)/sqrt(1/2*sqrt(5) - 1/2)) - 1/50*sqrt(50*sqrt(5) + 110)*log(sqrt(x) + sqrt(1/2*s
qrt(5) + 1/2)) - 1/5*sqrt(1/2*sqrt(5) + 11/10)*log(abs(-520*x - 78*sqrt(5)*sqrt(50*sqrt(5) + 110) + 260*sqrt(5
) + 520*sqrt(x^2 - 1) + 130*sqrt(50*sqrt(5) + 110) + 260)) + 1/5*sqrt(1/2*sqrt(5) + 11/10)*log(abs(-1040*x + 1
56*sqrt(5)*sqrt(50*sqrt(5) + 110) + 520*sqrt(5) + 1040*sqrt(x^2 - 1) - 260*sqrt(50*sqrt(5) + 110) + 520)) + 1/
50*sqrt(50*sqrt(5) + 110)*log(abs(sqrt(x) - sqrt(1/2*sqrt(5) + 1/2))) + 4/5*((x - sqrt(x^2 - 1))^3 + 2*(x - sq
rt(x^2 - 1))^2 + 3*x - 3*sqrt(x^2 - 1) - 2)/((x - sqrt(x^2 - 1))^4 - 2*(x - sqrt(x^2 - 1))^3 - 2*(x - sqrt(x^2
 - 1))^2 - 2*x + 2*sqrt(x^2 - 1) + 1) + 2/5*(2*x^(3/2) - sqrt(x))/(x^2 - x - 1)

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maple [B]  time = 0.02, size = 1542, normalized size = 7.01 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^(1/2)-(x^2-1)^(1/2))^2/(-x^2+x+1)^2/(x^2-1)^(1/2),x)

[Out]

-8/25/(-2+2*5^(1/2))^(1/2)*5^(1/2)*arctan(2/(-2+2*5^(1/2))^(1/2)*x^(1/2))-8/25/(2+2*5^(1/2))^(1/2)*arctanh(2/(
2+2*5^(1/2))^(1/2)*x^(1/2))*5^(1/2)-1/10/(1/2-1/2*5^(1/2))/(x+1/2*5^(1/2)-1/2)*((x+1/2*5^(1/2)-1/2)^2+(-5^(1/2
)+1)*(x+1/2*5^(1/2)-1/2)+1/2-1/2*5^(1/2))^(1/2)+4/25*5^(1/2)/(2+2*5^(1/2))^(1/2)*arctanh(2*(1+5^(1/2)+(5^(1/2)
+1)*(x-1/2*5^(1/2)-1/2))/(2+2*5^(1/2))^(1/2)/(4*(x-1/2*5^(1/2)-1/2)^2+4*(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+2+2*5^
(1/2))^(1/2))-1/10/(1/2+1/2*5^(1/2))/(x-1/2*5^(1/2)-1/2)*((x-1/2*5^(1/2)-1/2)^2+(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2
)+1/2+1/2*5^(1/2))^(1/2)+4/25*5^(1/2)/(-2+2*5^(1/2))^(1/2)*arctan(2*(1-5^(1/2)+(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2
))/(-2+2*5^(1/2))^(1/2)/(4*(x+1/2*5^(1/2)-1/2)^2+4*(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2)+2-2*5^(1/2))^(1/2))+4/5/(-
2+2*5^(1/2))^(1/2)*arctan(2/(-2+2*5^(1/2))^(1/2)*x^(1/2))+2/5/(x-1/2*5^(1/2)-1/2)*x^(1/2)-4/5/(2+2*5^(1/2))^(1
/2)*arctanh(2/(2+2*5^(1/2))^(1/2)*x^(1/2))+1/20/(1/2-1/2*5^(1/2))*(4*(x+1/2*5^(1/2)-1/2)^2+4*(-5^(1/2)+1)*(x+1
/2*5^(1/2)-1/2)+2-2*5^(1/2))^(1/2)-2/5/(-2+2*5^(1/2))^(1/2)*arctan(2*(1-5^(1/2)+(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/
2))/(-2+2*5^(1/2))^(1/2)/(4*(x+1/2*5^(1/2)-1/2)^2+4*(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2)+2-2*5^(1/2))^(1/2))+2/5/(
2+2*5^(1/2))^(1/2)*arctanh(2*(1+5^(1/2)+(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2))/(2+2*5^(1/2))^(1/2)/(4*(x-1/2*5^(1/2)
-1/2)^2+4*(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+2+2*5^(1/2))^(1/2))+1/25*5^(1/2)*(4*(x+1/2*5^(1/2)-1/2)^2+4*(-5^(1/2
)+1)*(x+1/2*5^(1/2)-1/2)+2-2*5^(1/2))^(1/2)+1/25*ln(x+((x+1/2*5^(1/2)-1/2)^2+(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2)+
1/2-1/2*5^(1/2))^(1/2))*5^(1/2)-1/25*5^(1/2)*(4*(x-1/2*5^(1/2)-1/2)^2+4*(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+2+2*5^
(1/2))^(1/2)-1/25*ln(x+((x-1/2*5^(1/2)-1/2)^2+(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+1/2+1/2*5^(1/2))^(1/2))*5^(1/2)+
1/10/(1/2+1/2*5^(1/2))*ln(x+((x-1/2*5^(1/2)-1/2)^2+(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+1/2+1/2*5^(1/2))^(1/2))+1/2
0/(1/2+1/2*5^(1/2))*(4*(x-1/2*5^(1/2)-1/2)^2+4*(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+2+2*5^(1/2))^(1/2)+1/10/(1/2-1/
2*5^(1/2))*ln(x+((x+1/2*5^(1/2)-1/2)^2+(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2)+1/2-1/2*5^(1/2))^(1/2))+2/5/(x+1/2*5^(
1/2)-1/2)*x^(1/2)+1/5/(1/2-1/2*5^(1/2))*x*((x+1/2*5^(1/2)-1/2)^2+(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2)+1/2-1/2*5^(1
/2))^(1/2)-1/5/(1/2+1/2*5^(1/2))/(x-1/2*5^(1/2)-1/2)*((x-1/2*5^(1/2)-1/2)^2+(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+1/
2+1/2*5^(1/2))^(3/2)-1/20/(1/2-1/2*5^(1/2))*5^(1/2)*(4*(x+1/2*5^(1/2)-1/2)^2+4*(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2
)+2-2*5^(1/2))^(1/2)-1/10/(1/2-1/2*5^(1/2))*ln(x+((x+1/2*5^(1/2)-1/2)^2+(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2)+1/2-1
/2*5^(1/2))^(1/2))*5^(1/2)+1/20/(1/2+1/2*5^(1/2))*5^(1/2)*(4*(x-1/2*5^(1/2)-1/2)^2+4*(5^(1/2)+1)*(x-1/2*5^(1/2
)-1/2)+2+2*5^(1/2))^(1/2)+1/10/(1/2+1/2*5^(1/2))*ln(x+((x-1/2*5^(1/2)-1/2)^2+(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+1
/2+1/2*5^(1/2))^(1/2))*5^(1/2)+1/5/(1/2+1/2*5^(1/2))*x*((x-1/2*5^(1/2)-1/2)^2+(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+
1/2+1/2*5^(1/2))^(1/2)-1/5/(1/2-1/2*5^(1/2))/(x+1/2*5^(1/2)-1/2)*((x+1/2*5^(1/2)-1/2)^2+(-5^(1/2)+1)*(x+1/2*5^
(1/2)-1/2)+1/2-1/2*5^(1/2))^(3/2)-1/5*ln(x+((x+1/2*5^(1/2)-1/2)^2+(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2)+1/2-1/2*5^(
1/2))^(1/2))-1/5*ln(x+((x-1/2*5^(1/2)-1/2)^2+(5^(1/2)+1)*(x-1/2*5^(1/2)-1/2)+1/2+1/2*5^(1/2))^(1/2))+1/10*5^(1
/2)/(1/2-1/2*5^(1/2))/(x+1/2*5^(1/2)-1/2)*((x+1/2*5^(1/2)-1/2)^2+(-5^(1/2)+1)*(x+1/2*5^(1/2)-1/2)+1/2-1/2*5^(1
/2))^(1/2)-1/10*5^(1/2)/(1/2+1/2*5^(1/2))/(x-1/2*5^(1/2)-1/2)*((x-1/2*5^(1/2)-1/2)^2+(5^(1/2)+1)*(x-1/2*5^(1/2
)-1/2)+1/2+1/2*5^(1/2))^(1/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {2 \, {\left (x^{\frac {5}{2}} - 3 \, x^{\frac {3}{2}}\right )}}{5 \, {\left (x^{2} - x - 1\right )}} + \int \frac {x^{\frac {3}{2}} + \sqrt {x}}{5 \, {\left (x^{2} - x - 1\right )}}\,{d x} + \int \frac {x^{2} + x - 1}{{\left (x^{4} - 2 \, x^{3} - x^{2} + 2 \, x + 1\right )} \sqrt {x + 1} \sqrt {x - 1}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x^(1/2)-(x^2-1)^(1/2))^2/(-x^2+x+1)^2/(x^2-1)^(1/2),x, algorithm="maxima")

[Out]

-2/5*(x^(5/2) - 3*x^(3/2))/(x^2 - x - 1) + integrate(1/5*(x^(3/2) + sqrt(x))/(x^2 - x - 1), x) + integrate((x^
2 + x - 1)/((x^4 - 2*x^3 - x^2 + 2*x + 1)*sqrt(x + 1)*sqrt(x - 1)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (\sqrt {x^2-1}-\sqrt {x}\right )}^2}{\sqrt {x^2-1}\,{\left (-x^2+x+1\right )}^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((x^2 - 1)^(1/2) - x^(1/2))^2/((x^2 - 1)^(1/2)*(x - x^2 + 1)^2),x)

[Out]

int(((x^2 - 1)^(1/2) - x^(1/2))^2/((x^2 - 1)^(1/2)*(x - x^2 + 1)^2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((x**(1/2)-(x**2-1)**(1/2))**2/(-x**2+x+1)**2/(x**2-1)**(1/2),x)

[Out]

Timed out

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