3.638 \(\int \frac {\log (-1+x)}{x^3} \, dx\)

Optimal. Leaf size=35 \[ -\frac {\log (x-1)}{2 x^2}+\frac {1}{2 x}+\frac {1}{2} \log (1-x)-\frac {\log (x)}{2} \]

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Rubi [A]  time = 0.01, antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2395, 44} \[ -\frac {\log (x-1)}{2 x^2}+\frac {1}{2 x}+\frac {1}{2} \log (1-x)-\frac {\log (x)}{2} \]

Antiderivative was successfully verified.

[In]

Int[Log[-1 + x]/x^3,x]

[Out]

1/(2*x) + Log[1 - x]/2 - Log[-1 + x]/(2*x^2) - Log[x]/2

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 2395

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[((f + g
*x)^(q + 1)*(a + b*Log[c*(d + e*x)^n]))/(g*(q + 1)), x] - Dist[(b*e*n)/(g*(q + 1)), Int[(f + g*x)^(q + 1)/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*f - d*g, 0] && NeQ[q, -1]

Rubi steps

\begin {align*} \int \frac {\log (-1+x)}{x^3} \, dx &=-\frac {\log (-1+x)}{2 x^2}+\frac {1}{2} \int \frac {1}{(-1+x) x^2} \, dx\\ &=-\frac {\log (-1+x)}{2 x^2}+\frac {1}{2} \int \left (\frac {1}{-1+x}-\frac {1}{x^2}-\frac {1}{x}\right ) \, dx\\ &=\frac {1}{2 x}+\frac {1}{2} \log (1-x)-\frac {\log (-1+x)}{2 x^2}-\frac {\log (x)}{2}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 27, normalized size = 0.77 \[ \frac {1}{2} \left (-\frac {\log (x-1)}{x^2}+\frac {1}{x}+\log (1-x)-\log (x)\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[Log[-1 + x]/x^3,x]

[Out]

(x^(-1) + Log[1 - x] - Log[-1 + x]/x^2 - Log[x])/2

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\log (-1+x)}{x^3} \, dx \]

Verification is Not applicable to the result.

[In]

IntegrateAlgebraic[Log[-1 + x]/x^3,x]

[Out]

Could not integrate

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fricas [A]  time = 0.78, size = 26, normalized size = 0.74 \[ -\frac {x^{2} \log \relax (x) - {\left (x^{2} - 1\right )} \log \left (x - 1\right ) - x}{2 \, x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(-1+x)/x^3,x, algorithm="fricas")

[Out]

-1/2*(x^2*log(x) - (x^2 - 1)*log(x - 1) - x)/x^2

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giac [A]  time = 0.79, size = 27, normalized size = 0.77 \[ \frac {1}{2 \, x} - \frac {\log \left (x - 1\right )}{2 \, x^{2}} + \frac {1}{2} \, \log \left ({\left | x - 1 \right |}\right ) - \frac {1}{2} \, \log \left ({\left | x \right |}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(-1+x)/x^3,x, algorithm="giac")

[Out]

1/2/x - 1/2*log(x - 1)/x^2 + 1/2*log(abs(x - 1)) - 1/2*log(abs(x))

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maple [A]  time = 0.04, size = 26, normalized size = 0.74

method	result	size
derivativedivides	\(\frac {1}{2 x}-\frac {\ln \relax (x )}{2}+\frac {\ln \left (-1+x \right ) \left (-1+x \right ) \left (1+x \right )}{2 x^{2}}\)	\(26\)
default	\(\frac {1}{2 x}-\frac {\ln \relax (x )}{2}+\frac {\ln \left (-1+x \right ) \left (-1+x \right ) \left (1+x \right )}{2 x^{2}}\)	\(26\)
norman	\(\frac {\frac {x}{2}+\frac {x^{2} \ln \left (-1+x \right )}{2}-\frac {\ln \left (-1+x \right )}{2}}{x^{2}}-\frac {\ln \relax (x )}{2}\)	\(29\)
risch	\(-\frac {\ln \left (-1+x \right )}{2 x^{2}}+\frac {\ln \left (-1+x \right ) x -x \ln \relax (x )+1}{2 x}\)	\(29\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(ln(-1+x)/x^3,x,method=_RETURNVERBOSE)

[Out]

1/2/x-1/2*ln(x)+1/2*ln(-1+x)*(-1+x)*(1+x)/x^2

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maxima [A]  time = 0.43, size = 25, normalized size = 0.71 \[ \frac {1}{2 \, x} - \frac {\log \left (x - 1\right )}{2 \, x^{2}} + \frac {1}{2} \, \log \left (x - 1\right ) - \frac {1}{2} \, \log \relax (x) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(-1+x)/x^3,x, algorithm="maxima")

[Out]

1/2/x - 1/2*log(x - 1)/x^2 + 1/2*log(x - 1) - 1/2*log(x)

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mupad [B]  time = 0.06, size = 25, normalized size = 0.71 \[ \frac {x-\ln \left (x-1\right )+x^2\,\ln \left (1-\frac {1}{x}\right )}{2\,x^2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(log(x - 1)/x^3,x)

[Out]

(x - log(x - 1) + x^2*log(1 - 1/x))/(2*x^2)

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sympy [A]  time = 0.14, size = 26, normalized size = 0.74 \[ - \frac {\log {\relax (x )}}{2} + \frac {\log {\left (x - 1 \right )}}{2} + \frac {1}{2 x} - \frac {\log {\left (x - 1 \right )}}{2 x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(ln(-1+x)/x**3,x)

[Out]

-log(x)/2 + log(x - 1)/2 + 1/(2*x) - log(x - 1)/(2*x**2)

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