∫ 1______ (cos(x)+2 sec(x))2 dx

Optimal. Leaf size=55 \[ \frac {x}{6 \sqrt {6}}+\frac {\tan (x)}{6 \left (2 \tan ^2(x)+3\right )}-\frac {\tan ^{-1}\left (\frac {\sin (x) \cos (x)}{\cos ^2(x)+\sqrt {6}+2}\right )}{6 \sqrt {6}} \]

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Rubi [A] time = 0.03, antiderivative size = 55, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {199, 203} \[ \frac {x}{6 \sqrt {6}}+\frac {\tan (x)}{6 \left (2 \tan ^2(x)+3\right )}-\frac {\tan ^{-1}\left (\frac {\sin (x) \cos (x)}{\cos ^2(x)+\sqrt {6}+2}\right )}{6 \sqrt {6}} \]

x/(6*Sqrt[6]) - ArcTan[(Cos[x]*Sin[x])/(2 + Sqrt[6] + Cos[x]^2)]/(6*Sqrt[6]) + Tan[x]/(6*(3 + 2*Tan[x]^2))

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[(x*(a + b*x^n)^(p + 1))/(a*n*(p + 1)), x] + Dist[(n*(p +

1) + 1)/(a*n*(p + 1)), Int[(a + b*x^n)^(p + 1), x], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[p, -1] && (In

tegerQ[2*p] || (n == 2 && IntegerQ[4*p]) || (n == 2 && IntegerQ[3*p]) || Denominator[p + 1/n] < Denominator[p]

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;

\begin {align*} \int \frac {1}{(\cos (x)+2 \sec (x))^2} \, dx &=\operatorname {Subst}\left (\int \frac {1}{\left (3+2 x^2\right )^2} \, dx,x,\tan (x)\right )\\ &=\frac {\tan (x)}{6 \left (3+2 \tan ^2(x)\right )}+\frac {1}{6} \operatorname {Subst}\left (\int \frac {1}{3+2 x^2} \, dx,x,\tan (x)\right )\\ &=\frac {x}{6 \sqrt {6}}-\frac {\tan ^{-1}\left (\frac {\cos (x) \sin (x)}{2+\sqrt {6}+\cos ^2(x)}\right )}{6 \sqrt {6}}+\frac {\tan (x)}{6 \left (3+2 \tan ^2(x)\right )}\\ \end {align*}

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Mathematica [A] time = 0.09, size = 54, normalized size = 0.98 \[ \frac {(\cos (2 x)+5) \sec ^4(x) \left (6 \sin (2 x)+\sqrt {6} (\cos (2 x)+5) \tan ^{-1}\left (\sqrt {\frac {2}{3}} \tan (x)\right )\right )}{144 \left (2 \sec ^2(x)+1\right )^2} \]

((5 + Cos[2*x])*Sec[x]^4*(Sqrt[6]*ArcTan[Sqrt[2/3]*Tan[x]]*(5 + Cos[2*x]) + 6*Sin[2*x]))/(144*(1 + 2*Sec[x]^2)

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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{(\cos (x)+2 \sec (x))^2} \, dx \]

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fricas [A] time = 1.24, size = 58, normalized size = 1.05 \[ -\frac {{\left (\sqrt {6} \cos \relax (x)^{2} + 2 \, \sqrt {6}\right )} \arctan \left (\frac {5 \, \sqrt {6} \cos \relax (x)^{2} - 2 \, \sqrt {6}}{12 \, \cos \relax (x) \sin \relax (x)}\right ) - 12 \, \cos \relax (x) \sin \relax (x)}{72 \, {\left (\cos \relax (x)^{2} + 2\right )}} \]

-1/72*((sqrt(6)*cos(x)^2 + 2*sqrt(6))*arctan(1/12*(5*sqrt(6)*cos(x)^2 - 2*sqrt(6))/(cos(x)*sin(x))) - 12*cos(x

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giac [A] time = 0.63, size = 61, normalized size = 1.11 \[ \frac {1}{36} \, \sqrt {6} {\left (x + \arctan \left (-\frac {\sqrt {6} \sin \left (2 \, x\right ) - 2 \, \sin \left (2 \, x\right )}{\sqrt {6} \cos \left (2 \, x\right ) + \sqrt {6} - 2 \, \cos \left (2 \, x\right ) + 2}\right )\right )} + \frac {\tan \relax (x)}{6 \, {\left (2 \, \tan \relax (x)^{2} + 3\right )}} \]

1/36*sqrt(6)*(x + arctan(-(sqrt(6)*sin(2*x) - 2*sin(2*x))/(sqrt(6)*cos(2*x) + sqrt(6) - 2*cos(2*x) + 2))) + 1/

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method	result	size

default	\(\frac {\tan \relax (x )}{18+12 \left (\tan ^{2}\relax (x )\right )}+\frac {\sqrt {6}\, \arctan \left (\frac {\tan \relax (x ) \sqrt {6}}{3}\right )}{36}\)	\(29\)
risch	\(\frac {i \left (5 \,{\mathrm e}^{2 i x}+1\right )}{3 \,{\mathrm e}^{4 i x}+30 \,{\mathrm e}^{2 i x}+3}+\frac {i \sqrt {6}\, \ln \left ({\mathrm e}^{2 i x}+2 \sqrt {6}+5\right )}{72}-\frac {i \sqrt {6}\, \ln \left ({\mathrm e}^{2 i x}-2 \sqrt {6}+5\right )}{72}\)	\(68\)

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maxima [A] time = 0.97, size = 28, normalized size = 0.51 \[ \frac {1}{36} \, \sqrt {6} \arctan \left (\frac {1}{3} \, \sqrt {6} \tan \relax (x)\right ) + \frac {\tan \relax (x)}{6 \, {\left (2 \, \tan \relax (x)^{2} + 3\right )}} \]

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mupad [B] time = 0.39, size = 77, normalized size = 1.40 \[ \frac {\sqrt {6}\,\left (2\,\mathrm {atan}\left (\frac {\sqrt {6}\,{\mathrm {tan}\left (\frac {x}{2}\right )}^3}{4}+\frac {5\,\sqrt {6}\,\mathrm {tan}\left (\frac {x}{2}\right )}{12}\right )+2\,\mathrm {atan}\left (\frac {\sqrt {6}\,\mathrm {tan}\left (\frac {x}{2}\right )}{4}\right )\right )}{72}+\frac {\frac {\mathrm {tan}\left (\frac {x}{2}\right )}{9}-\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^3}{9}}{{\mathrm {tan}\left (\frac {x}{2}\right )}^4+\frac {2\,{\mathrm {tan}\left (\frac {x}{2}\right )}^2}{3}+1} \]

(6^(1/2)*(2*atan((5*6^(1/2)*tan(x/2))/12 + (6^(1/2)*tan(x/2)^3)/4) + 2*atan((6^(1/2)*tan(x/2))/4)))/72 + (tan(

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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (\cos {\relax (x )} + 2 \sec {\relax (x )}\right )^{2}}\, dx \]

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3.381 \(\int \frac {1}{(\cos (x)+2 \sec (x))^2} \, dx\)