3.361 \(\int \cot ^4(x) \csc ^3(x) \, dx\)

Optimal. Leaf size=38 \[ -\frac {1}{16} \tanh ^{-1}(\cos (x))-\frac {1}{6} \cot ^3(x) \csc ^3(x)+\frac {1}{8} \cot (x) \csc ^3(x)-\frac {1}{16} \cot (x) \csc (x) \]

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Rubi [A]  time = 0.05, antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2611, 3768, 3770} \[ -\frac {1}{16} \tanh ^{-1}(\cos (x))-\frac {1}{6} \cot ^3(x) \csc ^3(x)+\frac {1}{8} \cot (x) \csc ^3(x)-\frac {1}{16} \cot (x) \csc (x) \]

Antiderivative was successfully verified.

[In]

Int[Cot[x]^4*Csc[x]^3,x]

[Out]

-ArcTanh[Cos[x]]/16 - (Cot[x]*Csc[x])/16 + (Cot[x]*Csc[x]^3)/8 - (Cot[x]^3*Csc[x]^3)/6

Rule 2611

Int[((a_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*(a*Sec[e
+ f*x])^m*(b*Tan[e + f*x])^(n - 1))/(f*(m + n - 1)), x] - Dist[(b^2*(n - 1))/(m + n - 1), Int[(a*Sec[e + f*x])
^m*(b*Tan[e + f*x])^(n - 2), x], x] /; FreeQ[{a, b, e, f, m}, x] && GtQ[n, 1] && NeQ[m + n - 1, 0] && Integers
Q[2*m, 2*n]

Rule 3768

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> -Simp[(b*Cos[c + d*x]*(b*Csc[c + d*x])^(n - 1))/(d*(n -
1)), x] + Dist[(b^2*(n - 2))/(n - 1), Int[(b*Csc[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1
] && IntegerQ[2*n]

Rule 3770

Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]

Rubi steps

\begin {align*} \int \cot ^4(x) \csc ^3(x) \, dx &=-\frac {1}{6} \cot ^3(x) \csc ^3(x)-\frac {1}{2} \int \cot ^2(x) \csc ^3(x) \, dx\\ &=\frac {1}{8} \cot (x) \csc ^3(x)-\frac {1}{6} \cot ^3(x) \csc ^3(x)+\frac {1}{8} \int \csc ^3(x) \, dx\\ &=-\frac {1}{16} \cot (x) \csc (x)+\frac {1}{8} \cot (x) \csc ^3(x)-\frac {1}{6} \cot ^3(x) \csc ^3(x)+\frac {1}{16} \int \csc (x) \, dx\\ &=-\frac {1}{16} \tanh ^{-1}(\cos (x))-\frac {1}{16} \cot (x) \csc (x)+\frac {1}{8} \cot (x) \csc ^3(x)-\frac {1}{6} \cot ^3(x) \csc ^3(x)\\ \end {align*}

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Mathematica [B]  time = 0.02, size = 95, normalized size = 2.50 \[ -\frac {1}{384} \csc ^6\left (\frac {x}{2}\right )+\frac {1}{64} \csc ^4\left (\frac {x}{2}\right )-\frac {1}{64} \csc ^2\left (\frac {x}{2}\right )+\frac {1}{384} \sec ^6\left (\frac {x}{2}\right )-\frac {1}{64} \sec ^4\left (\frac {x}{2}\right )+\frac {1}{64} \sec ^2\left (\frac {x}{2}\right )+\frac {1}{16} \log \left (\sin \left (\frac {x}{2}\right )\right )-\frac {1}{16} \log \left (\cos \left (\frac {x}{2}\right )\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[Cot[x]^4*Csc[x]^3,x]

[Out]

-1/64*Csc[x/2]^2 + Csc[x/2]^4/64 - Csc[x/2]^6/384 - Log[Cos[x/2]]/16 + Log[Sin[x/2]]/16 + Sec[x/2]^2/64 - Sec[
x/2]^4/64 + Sec[x/2]^6/384

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \cot ^4(x) \csc ^3(x) \, dx \]

Verification is Not applicable to the result.

[In]

IntegrateAlgebraic[Cot[x]^4*Csc[x]^3,x]

[Out]

Could not integrate

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fricas [B]  time = 0.68, size = 93, normalized size = 2.45 \[ \frac {6 \, \cos \relax (x)^{5} + 16 \, \cos \relax (x)^{3} - 3 \, {\left (\cos \relax (x)^{6} - 3 \, \cos \relax (x)^{4} + 3 \, \cos \relax (x)^{2} - 1\right )} \log \left (\frac {1}{2} \, \cos \relax (x) + \frac {1}{2}\right ) + 3 \, {\left (\cos \relax (x)^{6} - 3 \, \cos \relax (x)^{4} + 3 \, \cos \relax (x)^{2} - 1\right )} \log \left (-\frac {1}{2} \, \cos \relax (x) + \frac {1}{2}\right ) - 6 \, \cos \relax (x)}{96 \, {\left (\cos \relax (x)^{6} - 3 \, \cos \relax (x)^{4} + 3 \, \cos \relax (x)^{2} - 1\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(x)^4*csc(x)^3,x, algorithm="fricas")

[Out]

1/96*(6*cos(x)^5 + 16*cos(x)^3 - 3*(cos(x)^6 - 3*cos(x)^4 + 3*cos(x)^2 - 1)*log(1/2*cos(x) + 1/2) + 3*(cos(x)^
6 - 3*cos(x)^4 + 3*cos(x)^2 - 1)*log(-1/2*cos(x) + 1/2) - 6*cos(x))/(cos(x)^6 - 3*cos(x)^4 + 3*cos(x)^2 - 1)

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giac [A]  time = 0.61, size = 44, normalized size = 1.16 \[ \frac {3 \, \cos \relax (x)^{5} + 8 \, \cos \relax (x)^{3} - 3 \, \cos \relax (x)}{48 \, {\left (\cos \relax (x)^{2} - 1\right )}^{3}} - \frac {1}{32} \, \log \left (\cos \relax (x) + 1\right ) + \frac {1}{32} \, \log \left (-\cos \relax (x) + 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(x)^4*csc(x)^3,x, algorithm="giac")

[Out]

1/48*(3*cos(x)^5 + 8*cos(x)^3 - 3*cos(x))/(cos(x)^2 - 1)^3 - 1/32*log(cos(x) + 1) + 1/32*log(-cos(x) + 1)

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maple [A]  time = 0.09, size = 52, normalized size = 1.37

method	result	size
default	\(-\frac {\cos ^{5}\relax (x )}{6 \sin \relax (x )^{6}}-\frac {\cos ^{5}\relax (x )}{24 \sin \relax (x )^{4}}+\frac {\cos ^{5}\relax (x )}{48 \sin \relax (x )^{2}}+\frac {\left (\cos ^{3}\relax (x )\right )}{48}+\frac {\cos \relax (x )}{16}+\frac {\ln \left (\csc \relax (x )-\cot \relax (x )\right )}{16}\)	\(52\)
risch	\(\frac {3 \,{\mathrm e}^{11 i x}+47 \,{\mathrm e}^{9 i x}+78 \,{\mathrm e}^{7 i x}+78 \,{\mathrm e}^{5 i x}+47 \,{\mathrm e}^{3 i x}+3 \,{\mathrm e}^{i x}}{24 \left ({\mathrm e}^{2 i x}-1\right )^{6}}-\frac {\ln \left ({\mathrm e}^{i x}+1\right )}{16}+\frac {\ln \left ({\mathrm e}^{i x}-1\right )}{16}\)	\(76\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cot(x)^4*csc(x)^3,x,method=_RETURNVERBOSE)

[Out]

-1/6/sin(x)^6*cos(x)^5-1/24/sin(x)^4*cos(x)^5+1/48/sin(x)^2*cos(x)^5+1/48*cos(x)^3+1/16*cos(x)+1/16*ln(csc(x)-
cot(x))

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maxima [A]  time = 0.44, size = 54, normalized size = 1.42 \[ \frac {3 \, \cos \relax (x)^{5} + 8 \, \cos \relax (x)^{3} - 3 \, \cos \relax (x)}{48 \, {\left (\cos \relax (x)^{6} - 3 \, \cos \relax (x)^{4} + 3 \, \cos \relax (x)^{2} - 1\right )}} - \frac {1}{32} \, \log \left (\cos \relax (x) + 1\right ) + \frac {1}{32} \, \log \left (\cos \relax (x) - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(x)^4*csc(x)^3,x, algorithm="maxima")

[Out]

1/48*(3*cos(x)^5 + 8*cos(x)^3 - 3*cos(x))/(cos(x)^6 - 3*cos(x)^4 + 3*cos(x)^2 - 1) - 1/32*log(cos(x) + 1) + 1/
32*log(cos(x) - 1)

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mupad [B]  time = 0.28, size = 57, normalized size = 1.50 \[ \frac {\ln \left (\mathrm {tan}\left (\frac {x}{2}\right )\right )}{16}+\frac {\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^4}{128}+\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^2}{128}-\frac {1}{384}}{{\mathrm {tan}\left (\frac {x}{2}\right )}^6}-\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^2}{128}-\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^4}{128}+\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^6}{384} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cot(x)^4/sin(x)^3,x)

[Out]

log(tan(x/2))/16 + (tan(x/2)^2/128 + tan(x/2)^4/128 - 1/384)/tan(x/2)^6 - tan(x/2)^2/128 - tan(x/2)^4/128 + ta
n(x/2)^6/384

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sympy [A]  time = 0.16, size = 56, normalized size = 1.47 \[ - \frac {- 3 \cos ^{5}{\relax (x )} - 8 \cos ^{3}{\relax (x )} + 3 \cos {\relax (x )}}{48 \cos ^{6}{\relax (x )} - 144 \cos ^{4}{\relax (x )} + 144 \cos ^{2}{\relax (x )} - 48} + \frac {\log {\left (\cos {\relax (x )} - 1 \right )}}{32} - \frac {\log {\left (\cos {\relax (x )} + 1 \right )}}{32} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(x)**4*csc(x)**3,x)

[Out]

-(-3*cos(x)**5 - 8*cos(x)**3 + 3*cos(x))/(48*cos(x)**6 - 144*cos(x)**4 + 144*cos(x)**2 - 48) + log(cos(x) - 1)
/32 - log(cos(x) + 1)/32

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