3.342 \(\int \cot ^5(x) \, dx\)

Optimal. Leaf size=20 \[ -\frac {1}{4} \cot ^4(x)+\frac {\cot ^2(x)}{2}+\log (\sin (x)) \]

________________________________________________________________________________________

Rubi [A]  time = 0.02, antiderivative size = 20, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {3473, 3475} \[ -\frac {1}{4} \cot ^4(x)+\frac {\cot ^2(x)}{2}+\log (\sin (x)) \]

Antiderivative was successfully verified.

[In]

Int[Cot[x]^5,x]

[Out]

Cot[x]^2/2 - Cot[x]^4/4 + Log[Sin[x]]

Rule 3473

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*(b*Tan[c + d*x])^(n - 1))/(d*(n - 1)), x] - Dis
t[b^2, Int[(b*Tan[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1]

Rule 3475

Int[tan[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[Log[RemoveContent[Cos[c + d*x], x]]/d, x] /; FreeQ[{c, d}, x]

Rubi steps

\begin {align*} \int \cot ^5(x) \, dx &=-\frac {1}{4} \cot ^4(x)-\int \cot ^3(x) \, dx\\ &=\frac {\cot ^2(x)}{2}-\frac {\cot ^4(x)}{4}+\int \cot (x) \, dx\\ &=\frac {\cot ^2(x)}{2}-\frac {\cot ^4(x)}{4}+\log (\sin (x))\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.00, size = 16, normalized size = 0.80 \[ -\frac {1}{4} \csc ^4(x)+\csc ^2(x)+\log (\sin (x)) \]

Antiderivative was successfully verified.

[In]

Integrate[Cot[x]^5,x]

[Out]

Csc[x]^2 - Csc[x]^4/4 + Log[Sin[x]]

________________________________________________________________________________________

IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \cot ^5(x) \, dx \]

Verification is Not applicable to the result.

[In]

IntegrateAlgebraic[Cot[x]^5,x]

[Out]

Could not integrate

________________________________________________________________________________________

fricas [B]  time = 0.94, size = 40, normalized size = 2.00 \[ \frac {2 \, \log \left (\frac {\tan \relax (x)^{2}}{\tan \relax (x)^{2} + 1}\right ) \tan \relax (x)^{4} + 3 \, \tan \relax (x)^{4} + 2 \, \tan \relax (x)^{2} - 1}{4 \, \tan \relax (x)^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/tan(x)^5,x, algorithm="fricas")

[Out]

1/4*(2*log(tan(x)^2/(tan(x)^2 + 1))*tan(x)^4 + 3*tan(x)^4 + 2*tan(x)^2 - 1)/tan(x)^4

________________________________________________________________________________________

giac [B]  time = 0.83, size = 37, normalized size = 1.85 \[ -\frac {3 \, \tan \relax (x)^{4} - 2 \, \tan \relax (x)^{2} + 1}{4 \, \tan \relax (x)^{4}} - \frac {1}{2} \, \log \left (\tan \relax (x)^{2} + 1\right ) + \frac {1}{2} \, \log \left (\tan \relax (x)^{2}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/tan(x)^5,x, algorithm="giac")

[Out]

-1/4*(3*tan(x)^4 - 2*tan(x)^2 + 1)/tan(x)^4 - 1/2*log(tan(x)^2 + 1) + 1/2*log(tan(x)^2)

________________________________________________________________________________________

maple [A]  time = 0.06, size = 26, normalized size = 1.30

method	result	size
derivativedivides	\(-\frac {\ln \left (1+\tan ^{2}\relax (x )\right )}{2}-\frac {1}{4 \tan \relax (x )^{4}}+\ln \left (\tan \relax (x )\right )+\frac {1}{2 \tan \relax (x )^{2}}\)	\(26\)
default	\(-\frac {\ln \left (1+\tan ^{2}\relax (x )\right )}{2}-\frac {1}{4 \tan \relax (x )^{4}}+\ln \left (\tan \relax (x )\right )+\frac {1}{2 \tan \relax (x )^{2}}\)	\(26\)
norman	\(\frac {-\frac {1}{4}+\frac {\left (\tan ^{2}\relax (x )\right )}{2}}{\tan \relax (x )^{4}}-\frac {\ln \left (1+\tan ^{2}\relax (x )\right )}{2}+\ln \left (\tan \relax (x )\right )\)	\(27\)
risch	\(-i x -\frac {4 \left ({\mathrm e}^{6 i x}-{\mathrm e}^{4 i x}+{\mathrm e}^{2 i x}\right )}{\left ({\mathrm e}^{2 i x}-1\right )^{4}}+\ln \left ({\mathrm e}^{2 i x}-1\right )\)	\(43\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/tan(x)^5,x,method=_RETURNVERBOSE)

[Out]

-1/2*ln(1+tan(x)^2)-1/4/tan(x)^4+ln(tan(x))+1/2/tan(x)^2

________________________________________________________________________________________

maxima [A]  time = 0.61, size = 22, normalized size = 1.10 \[ \frac {4 \, \sin \relax (x)^{2} - 1}{4 \, \sin \relax (x)^{4}} + \frac {1}{2} \, \log \left (\sin \relax (x)^{2}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/tan(x)^5,x, algorithm="maxima")

[Out]

1/4*(4*sin(x)^2 - 1)/sin(x)^4 + 1/2*log(sin(x)^2)

________________________________________________________________________________________

mupad [B]  time = 0.27, size = 26, normalized size = 1.30 \[ \ln \left (\mathrm {tan}\relax (x)\right )-\frac {\ln \left ({\mathrm {tan}\relax (x)}^2+1\right )}{2}+\frac {\frac {{\mathrm {tan}\relax (x)}^2}{2}-\frac {1}{4}}{{\mathrm {tan}\relax (x)}^4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/tan(x)^5,x)

[Out]

log(tan(x)) - log(tan(x)^2 + 1)/2 + (tan(x)^2/2 - 1/4)/tan(x)^4

________________________________________________________________________________________

sympy [A]  time = 0.11, size = 19, normalized size = 0.95 \[ \frac {4 \sin ^{2}{\relax (x )} - 1}{4 \sin ^{4}{\relax (x )}} + \log {\left (\sin {\relax (x )} \right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/tan(x)**5,x)

[Out]

(4*sin(x)**2 - 1)/(4*sin(x)**4) + log(sin(x))

________________________________________________________________________________________