3.247 \(\int \frac {1+2 x}{\sqrt {-1+6 x+x^2} (4+4 x+3 x^2)} \, dx\)

Optimal. Leaf size=70 \[ -\frac {5 \tan ^{-1}\left (\frac {\sqrt {\frac {7}{2}} (2-x)}{2 \sqrt {x^2+6 x-1}}\right )}{6 \sqrt {14}}-\frac {\tanh ^{-1}\left (\frac {\sqrt {7} (x+1)}{\sqrt {x^2+6 x-1}}\right )}{3 \sqrt {7}} \]

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Rubi [A]  time = 0.06, antiderivative size = 70, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {1035, 1029, 207, 203} \[ -\frac {5 \tan ^{-1}\left (\frac {\sqrt {\frac {7}{2}} (2-x)}{2 \sqrt {x^2+6 x-1}}\right )}{6 \sqrt {14}}-\frac {\tanh ^{-1}\left (\frac {\sqrt {7} (x+1)}{\sqrt {x^2+6 x-1}}\right )}{3 \sqrt {7}} \]

Antiderivative was successfully verified.

[In]

Int[(1 + 2*x)/(Sqrt[-1 + 6*x + x^2]*(4 + 4*x + 3*x^2)),x]

[Out]

(-5*ArcTan[(Sqrt[7/2]*(2 - x))/(2*Sqrt[-1 + 6*x + x^2])])/(6*Sqrt[14]) - ArcTanh[(Sqrt[7]*(1 + x))/Sqrt[-1 + 6
*x + x^2]]/(3*Sqrt[7])

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 207

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTanh[(Rt[b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 1029

Int[((g_.) + (h_.)*(x_))/(((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)*Sqrt[(d_.) + (e_.)*(x_) + (f_.)*(x_)^2]), x_Symb
ol] :> Dist[-2*g*(g*b - 2*a*h), Subst[Int[1/Simp[g*(g*b - 2*a*h)*(b^2 - 4*a*c) - (b*d - a*e)*x^2, x], x], x, S
imp[g*b - 2*a*h - (b*h - 2*g*c)*x, x]/Sqrt[d + e*x + f*x^2]], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && NeQ[
b^2 - 4*a*c, 0] && NeQ[e^2 - 4*d*f, 0] && NeQ[b*d - a*e, 0] && EqQ[h^2*(b*d - a*e) - 2*g*h*(c*d - a*f) + g^2*(
c*e - b*f), 0]

Rule 1035

Int[((g_.) + (h_.)*(x_))/(((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)*Sqrt[(d_.) + (e_.)*(x_) + (f_.)*(x_)^2]), x_Symb
ol] :> With[{q = Rt[(c*d - a*f)^2 - (b*d - a*e)*(c*e - b*f), 2]}, Dist[1/(2*q), Int[Simp[h*(b*d - a*e) - g*(c*
d - a*f - q) - (g*(c*e - b*f) - h*(c*d - a*f + q))*x, x]/((a + b*x + c*x^2)*Sqrt[d + e*x + f*x^2]), x], x] - D
ist[1/(2*q), Int[Simp[h*(b*d - a*e) - g*(c*d - a*f + q) - (g*(c*e - b*f) - h*(c*d - a*f - q))*x, x]/((a + b*x
+ c*x^2)*Sqrt[d + e*x + f*x^2]), x], x]] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[e
^2 - 4*d*f, 0] && NeQ[b*d - a*e, 0] && NegQ[b^2 - 4*a*c]

Rubi steps

\begin {align*} \int \frac {1+2 x}{\sqrt {-1+6 x+x^2} \left (4+4 x+3 x^2\right )} \, dx &=-\left (\frac {1}{42} \int \frac {-70-70 x}{\sqrt {-1+6 x+x^2} \left (4+4 x+3 x^2\right )} \, dx\right )+\frac {1}{42} \int \frac {-28+14 x}{\sqrt {-1+6 x+x^2} \left (4+4 x+3 x^2\right )} \, dx\\ &=-\left (\frac {896}{3} \operatorname {Subst}\left (\int \frac {1}{-200704+28 x^2} \, dx,x,\frac {-224-224 x}{\sqrt {-1+6 x+x^2}}\right )\right )-\frac {2800}{3} \operatorname {Subst}\left (\int \frac {1}{627200+28 x^2} \, dx,x,\frac {280-140 x}{\sqrt {-1+6 x+x^2}}\right )\\ &=-\frac {5 \tan ^{-1}\left (\frac {\sqrt {\frac {7}{2}} (2-x)}{2 \sqrt {-1+6 x+x^2}}\right )}{6 \sqrt {14}}-\frac {\tanh ^{-1}\left (\frac {\sqrt {7} (1+x)}{\sqrt {-1+6 x+x^2}}\right )}{3 \sqrt {7}}\\ \end {align*}

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Mathematica [C]  time = 0.45, size = 174, normalized size = 2.49 \[ -\frac {\sqrt {7-4 i \sqrt {2}} \left (8 \sqrt {2}+13 i\right ) \tan ^{-1}\left (\frac {\left (-7-2 i \sqrt {2}\right ) x-6 i \sqrt {2}+9}{\sqrt {7 \left (7-4 i \sqrt {2}\right )} \sqrt {x^2+6 x-1}}\right )+\sqrt {7+4 i \sqrt {2}} \left (8 \sqrt {2}-13 i\right ) \tan ^{-1}\left (\frac {\left (-7+2 i \sqrt {2}\right ) x+6 i \sqrt {2}+9}{\sqrt {7 \left (7+4 i \sqrt {2}\right )} \sqrt {x^2+6 x-1}}\right )}{108 \sqrt {14}} \]

Antiderivative was successfully verified.

[In]

Integrate[(1 + 2*x)/(Sqrt[-1 + 6*x + x^2]*(4 + 4*x + 3*x^2)),x]

[Out]

-1/108*(Sqrt[7 - (4*I)*Sqrt[2]]*(13*I + 8*Sqrt[2])*ArcTan[(9 - (6*I)*Sqrt[2] + (-7 - (2*I)*Sqrt[2])*x)/(Sqrt[7
*(7 - (4*I)*Sqrt[2])]*Sqrt[-1 + 6*x + x^2])] + Sqrt[7 + (4*I)*Sqrt[2]]*(-13*I + 8*Sqrt[2])*ArcTan[(9 + (6*I)*S
qrt[2] + (-7 + (2*I)*Sqrt[2])*x)/(Sqrt[7*(7 + (4*I)*Sqrt[2])]*Sqrt[-1 + 6*x + x^2])])/Sqrt[14]

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IntegrateAlgebraic [C]  time = 0.30, size = 123, normalized size = 1.76 \[ \text {RootSum}\left [3 \text {$\#$1}^4-8 \text {$\#$1}^3+46 \text {$\#$1}^2-104 \text {$\#$1}+171\& ,\frac {\text {$\#$1}^2 \log \left (-\text {$\#$1}+\sqrt {x^2+6 x-1}-x\right )-\text {$\#$1} \log \left (-\text {$\#$1}+\sqrt {x^2+6 x-1}-x\right )+4 \log \left (-\text {$\#$1}+\sqrt {x^2+6 x-1}-x\right )}{3 \text {$\#$1}^3-6 \text {$\#$1}^2+23 \text {$\#$1}-26}\& \right ] \]

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(1 + 2*x)/(Sqrt[-1 + 6*x + x^2]*(4 + 4*x + 3*x^2)),x]

[Out]

RootSum[171 - 104*#1 + 46*#1^2 - 8*#1^3 + 3*#1^4 & , (4*Log[-x + Sqrt[-1 + 6*x + x^2] - #1] - Log[-x + Sqrt[-1
+ 6*x + x^2] - #1]*#1 + Log[-x + Sqrt[-1 + 6*x + x^2] - #1]*#1^2)/(-26 + 23*#1 - 6*#1^2 + 3*#1^3) & ]

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fricas [B]  time = 1.19, size = 311, normalized size = 4.44 \[ \frac {1}{84} \, \sqrt {14} \sqrt {2} \log \left (13068 \, \sqrt {14} \sqrt {2} {\left (x - 2\right )} + 78408 \, x^{2} - 13068 \, \sqrt {x^{2} + 6 \, x - 1} {\left (\sqrt {14} \sqrt {2} + 6 \, x + 4\right )} + 287496 \, x + 287496\right ) - \frac {1}{84} \, \sqrt {14} \sqrt {2} \log \left (-13068 \, \sqrt {14} \sqrt {2} {\left (x - 2\right )} + 78408 \, x^{2} + 13068 \, \sqrt {x^{2} + 6 \, x - 1} {\left (\sqrt {14} \sqrt {2} - 6 \, x - 4\right )} + 287496 \, x + 287496\right ) - \frac {5}{42} \, \sqrt {14} \arctan \left (\frac {1}{24} \, \sqrt {3} \sqrt {\sqrt {14} \sqrt {2} {\left (x - 2\right )} + 6 \, x^{2} - \sqrt {x^{2} + 6 \, x - 1} {\left (\sqrt {14} \sqrt {2} + 6 \, x + 4\right )} + 22 \, x + 22} {\left (\sqrt {14} + \sqrt {2}\right )} + \frac {1}{8} \, \sqrt {2} {\left (x + 3\right )} + \frac {1}{8} \, \sqrt {14} {\left (x + 1\right )} - \frac {1}{8} \, \sqrt {x^{2} + 6 \, x - 1} {\left (\sqrt {14} + \sqrt {2}\right )}\right ) - \frac {5}{42} \, \sqrt {14} \arctan \left (-\frac {1}{8} \, \sqrt {2} {\left (x + 3\right )} + \frac {1}{8} \, \sqrt {14} {\left (x + 1\right )} + \frac {1}{1584} \, \sqrt {-13068 \, \sqrt {14} \sqrt {2} {\left (x - 2\right )} + 78408 \, x^{2} + 13068 \, \sqrt {x^{2} + 6 \, x - 1} {\left (\sqrt {14} \sqrt {2} - 6 \, x - 4\right )} + 287496 \, x + 287496} {\left (\sqrt {14} - \sqrt {2}\right )} - \frac {1}{8} \, \sqrt {x^{2} + 6 \, x - 1} {\left (\sqrt {14} - \sqrt {2}\right )}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+2*x)/(3*x^2+4*x+4)/(x^2+6*x-1)^(1/2),x, algorithm="fricas")

[Out]

1/84*sqrt(14)*sqrt(2)*log(13068*sqrt(14)*sqrt(2)*(x - 2) + 78408*x^2 - 13068*sqrt(x^2 + 6*x - 1)*(sqrt(14)*sqr
t(2) + 6*x + 4) + 287496*x + 287496) - 1/84*sqrt(14)*sqrt(2)*log(-13068*sqrt(14)*sqrt(2)*(x - 2) + 78408*x^2 +
13068*sqrt(x^2 + 6*x - 1)*(sqrt(14)*sqrt(2) - 6*x - 4) + 287496*x + 287496) - 5/42*sqrt(14)*arctan(1/24*sqrt(
3)*sqrt(sqrt(14)*sqrt(2)*(x - 2) + 6*x^2 - sqrt(x^2 + 6*x - 1)*(sqrt(14)*sqrt(2) + 6*x + 4) + 22*x + 22)*(sqrt
(14) + sqrt(2)) + 1/8*sqrt(2)*(x + 3) + 1/8*sqrt(14)*(x + 1) - 1/8*sqrt(x^2 + 6*x - 1)*(sqrt(14) + sqrt(2))) -
5/42*sqrt(14)*arctan(-1/8*sqrt(2)*(x + 3) + 1/8*sqrt(14)*(x + 1) + 1/1584*sqrt(-13068*sqrt(14)*sqrt(2)*(x - 2
) + 78408*x^2 + 13068*sqrt(x^2 + 6*x - 1)*(sqrt(14)*sqrt(2) - 6*x - 4) + 287496*x + 287496)*(sqrt(14) - sqrt(2
)) - 1/8*sqrt(x^2 + 6*x - 1)*(sqrt(14) - sqrt(2)))

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giac [B]  time = 0.66, size = 257, normalized size = 3.67 \[ -\frac {5}{84} \, \sqrt {7} \sqrt {2} {\left (\arctan \relax (2) + \arctan \left (\frac {1}{8} \, {\left (x - \sqrt {x^{2} + 6 \, x - 1}\right )} {\left (\sqrt {14} + \sqrt {2}\right )} + \frac {1}{8} \, \sqrt {14} + \frac {3}{8} \, \sqrt {2}\right )\right )} + \frac {5}{84} \, \sqrt {7} \sqrt {2} {\left (\arctan \left (\frac {1}{2}\right ) + \arctan \left (-\frac {1}{8} \, {\left (x - \sqrt {x^{2} + 6 \, x - 1}\right )} {\left (\sqrt {14} - \sqrt {2}\right )} - \frac {1}{8} \, \sqrt {14} + \frac {3}{8} \, \sqrt {2}\right )\right )} + \frac {1}{42} \, \sqrt {7} \log \left (4 \, {\left (4 \, \sqrt {7} \sqrt {2} + 3 \, x + \sqrt {7} - 4 \, \sqrt {2} - 3 \, \sqrt {x^{2} + 6 \, x - 1} + 2\right )}^{2} + 16 \, {\left (\sqrt {7} \sqrt {2} - 3 \, x - \sqrt {7} - \sqrt {2} + 3 \, \sqrt {x^{2} + 6 \, x - 1} - 2\right )}^{2}\right ) - \frac {1}{42} \, \sqrt {7} \log \left (4 \, {\left (4 \, \sqrt {7} \sqrt {2} + 3 \, x - \sqrt {7} + 4 \, \sqrt {2} - 3 \, \sqrt {x^{2} + 6 \, x - 1} + 2\right )}^{2} + 16 \, {\left (\sqrt {7} \sqrt {2} - 3 \, x + \sqrt {7} + \sqrt {2} + 3 \, \sqrt {x^{2} + 6 \, x - 1} - 2\right )}^{2}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+2*x)/(3*x^2+4*x+4)/(x^2+6*x-1)^(1/2),x, algorithm="giac")

[Out]

-5/84*sqrt(7)*sqrt(2)*(arctan(2) + arctan(1/8*(x - sqrt(x^2 + 6*x - 1))*(sqrt(14) + sqrt(2)) + 1/8*sqrt(14) +
3/8*sqrt(2))) + 5/84*sqrt(7)*sqrt(2)*(arctan(1/2) + arctan(-1/8*(x - sqrt(x^2 + 6*x - 1))*(sqrt(14) - sqrt(2))
- 1/8*sqrt(14) + 3/8*sqrt(2))) + 1/42*sqrt(7)*log(4*(4*sqrt(7)*sqrt(2) + 3*x + sqrt(7) - 4*sqrt(2) - 3*sqrt(x
^2 + 6*x - 1) + 2)^2 + 16*(sqrt(7)*sqrt(2) - 3*x - sqrt(7) - sqrt(2) + 3*sqrt(x^2 + 6*x - 1) - 2)^2) - 1/42*sq
rt(7)*log(4*(4*sqrt(7)*sqrt(2) + 3*x - sqrt(7) + 4*sqrt(2) - 3*sqrt(x^2 + 6*x - 1) + 2)^2 + 16*(sqrt(7)*sqrt(2
) - 3*x + sqrt(7) + sqrt(2) + 3*sqrt(x^2 + 6*x - 1) - 2)^2)

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maple [B]  time = 0.95, size = 158, normalized size = 2.26

method	result	size
default	\(-\frac {\sqrt {-\frac {6 \left (-2+x \right )^{2}}{\left (-1-x \right )^{2}}+15}\, \left (4 \sqrt {7}\, \arctanh \left (\frac {\sqrt {-\frac {6 \left (-2+x \right )^{2}}{\left (-1-x \right )^{2}}+15}\, \sqrt {7}}{21}\right )-5 \sqrt {14}\, \arctan \left (\frac {\sqrt {14}\, \sqrt {-\frac {6 \left (-2+x \right )^{2}}{\left (-1-x \right )^{2}}+15}\, \left (-2+x \right )}{4 \left (\frac {2 \left (-2+x \right )^{2}}{\left (-1-x \right )^{2}}-5\right ) \left (-1-x \right )}\right )\right )}{84 \sqrt {-\frac {3 \left (\frac {2 \left (-2+x \right )^{2}}{\left (-1-x \right )^{2}}-5\right )}{\left (1+\frac {-2+x}{-1-x}\right )^{2}}}\, \left (1+\frac {-2+x}{-1-x}\right )}\)	\(158\)
trager	\(\RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right ) \ln \left (-\frac {1568802816 x \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{5}+6019776 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{3} x [phone] \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{3}+3171168 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{2} \sqrt {x^{2}+6 x -1}+5768 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right ) x +73542 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )+50611 \sqrt {x^{2}+6 x -1}}{2016 x \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{2}-3 x -40}\right )-\frac {672 \ln \left (\frac {159860736 x \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{5}+2221632 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{3} x -4044096 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{3}+352352 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{2} \sqrt {x^{2}+6 x -1}-2340 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right ) x +3978 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )+319 \sqrt {x^{2}+6 x -1}}{2016 x \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{2}+37 x +40}\right ) \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{3}}{11}-\frac {34 \ln \left (\frac {159860736 x \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{5}+2221632 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{3} x -4044096 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{3}+352352 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{2} \sqrt {x^{2}+6 x -1}-2340 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right ) x +3978 \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )+319 \sqrt {x^{2}+6 x -1}}{2016 x \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )^{2}+37 x +40}\right ) \RootOf \left (451584 \textit {\_Z}^{4}+7616 \textit {\_Z}^{2}+121\right )}{33}\)	\(502\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1+2*x)/(3*x^2+4*x+4)/(x^2+6*x-1)^(1/2),x,method=_RETURNVERBOSE)

[Out]

-1/84*(-6*(-2+x)^2/(-1-x)^2+15)^(1/2)*(4*7^(1/2)*arctanh(1/21*(-6*(-2+x)^2/(-1-x)^2+15)^(1/2)*7^(1/2))-5*14^(1
/2)*arctan(1/4*14^(1/2)*(-6*(-2+x)^2/(-1-x)^2+15)^(1/2)/(2*(-2+x)^2/(-1-x)^2-5)*(-2+x)/(-1-x)))/(-3*(2*(-2+x)^
2/(-1-x)^2-5)/(1+(-2+x)/(-1-x))^2)^(1/2)/(1+(-2+x)/(-1-x))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {2 \, x + 1}{{\left (3 \, x^{2} + 4 \, x + 4\right )} \sqrt {x^{2} + 6 \, x - 1}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+2*x)/(3*x^2+4*x+4)/(x^2+6*x-1)^(1/2),x, algorithm="maxima")

[Out]

integrate((2*x + 1)/((3*x^2 + 4*x + 4)*sqrt(x^2 + 6*x - 1)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {2\,x+1}{\sqrt {x^2+6\,x-1}\,\left (3\,x^2+4\,x+4\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*x + 1)/((6*x + x^2 - 1)^(1/2)*(4*x + 3*x^2 + 4)),x)

[Out]

int((2*x + 1)/((6*x + x^2 - 1)^(1/2)*(4*x + 3*x^2 + 4)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {2 x + 1}{\sqrt {x^{2} + 6 x - 1} \left (3 x^{2} + 4 x + 4\right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1+2*x)/(3*x**2+4*x+4)/(x**2+6*x-1)**(1/2),x)

[Out]

Integral((2*x + 1)/(sqrt(x**2 + 6*x - 1)*(3*x**2 + 4*x + 4)), x)

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