3.229 \(\int \frac {1}{(-3-2 x+x^2)^{5/2}} \, dx\)

Optimal. Leaf size=43 \[ \frac {1-x}{12 \left (x^2-2 x-3\right )^{3/2}}-\frac {1-x}{24 \sqrt {x^2-2 x-3}} \]

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Rubi [A]  time = 0.01, antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {614, 613} \[ \frac {1-x}{12 \left (x^2-2 x-3\right )^{3/2}}-\frac {1-x}{24 \sqrt {x^2-2 x-3}} \]

Antiderivative was successfully verified.

[In]

Int[(-3 - 2*x + x^2)^(-5/2),x]

[Out]

(1 - x)/(12*(-3 - 2*x + x^2)^(3/2)) - (1 - x)/(24*Sqrt[-3 - 2*x + x^2])

Rule 613

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-3/2), x_Symbol] :> Simp[(-2*(b + 2*c*x))/((b^2 - 4*a*c)*Sqrt[a + b*x
+ c*x^2]), x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 614

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((b + 2*c*x)*(a + b*x + c*x^2)^(p + 1))/((p +
1)*(b^2 - 4*a*c)), x] - Dist[(2*c*(2*p + 3))/((p + 1)*(b^2 - 4*a*c)), Int[(a + b*x + c*x^2)^(p + 1), x], x] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0] && LtQ[p, -1] && NeQ[p, -3/2] && IntegerQ[4*p]

Rubi steps

\begin {align*} \int \frac {1}{\left (-3-2 x+x^2\right )^{5/2}} \, dx &=\frac {1-x}{12 \left (-3-2 x+x^2\right )^{3/2}}-\frac {1}{6} \int \frac {1}{\left (-3-2 x+x^2\right )^{3/2}} \, dx\\ &=\frac {1-x}{12 \left (-3-2 x+x^2\right )^{3/2}}-\frac {1-x}{24 \sqrt {-3-2 x+x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 27, normalized size = 0.63 \[ \frac {(x-1) \left (x^2-2 x-5\right )}{24 \left (x^2-2 x-3\right )^{3/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(-3 - 2*x + x^2)^(-5/2),x]

[Out]

((-1 + x)*(-5 - 2*x + x^2))/(24*(-3 - 2*x + x^2)^(3/2))

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IntegrateAlgebraic [A]  time = 0.27, size = 39, normalized size = 0.91 \[ \frac {\sqrt {x^2-2 x-3} \left (x^3-3 x^2-3 x+5\right )}{24 (x-3)^2 (x+1)^2} \]

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(-3 - 2*x + x^2)^(-5/2),x]

[Out]

(Sqrt[-3 - 2*x + x^2]*(5 - 3*x - 3*x^2 + x^3))/(24*(-3 + x)^2*(1 + x)^2)

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fricas [B]  time = 1.07, size = 64, normalized size = 1.49 \[ \frac {x^{4} - 4 \, x^{3} - 2 \, x^{2} + {\left (x^{3} - 3 \, x^{2} - 3 \, x + 5\right )} \sqrt {x^{2} - 2 \, x - 3} + 12 \, x + 9}{24 \, {\left (x^{4} - 4 \, x^{3} - 2 \, x^{2} + 12 \, x + 9\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x^2-2*x-3)^(5/2),x, algorithm="fricas")

[Out]

1/24*(x^4 - 4*x^3 - 2*x^2 + (x^3 - 3*x^2 - 3*x + 5)*sqrt(x^2 - 2*x - 3) + 12*x + 9)/(x^4 - 4*x^3 - 2*x^2 + 12*
x + 9)

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giac [A]  time = 0.66, size = 23, normalized size = 0.53 \[ \frac {{\left ({\left (x - 3\right )} x - 3\right )} x + 5}{24 \, {\left (x^{2} - 2 \, x - 3\right )}^{\frac {3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x^2-2*x-3)^(5/2),x, algorithm="giac")

[Out]

1/24*(((x - 3)*x - 3)*x + 5)/(x^2 - 2*x - 3)^(3/2)

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maple [A]  time = 0.33, size = 26, normalized size = 0.60

method	result	size
trager	\(\frac {x^{3}-3 x^{2}-3 x +5}{24 \left (x^{2}-2 x -3\right )^{\frac {3}{2}}}\)	\(26\)
risch	\(\frac {x^{3}-3 x^{2}-3 x +5}{24 \left (x^{2}-2 x -3\right )^{\frac {3}{2}}}\)	\(26\)
gosper	\(\frac {\left (1+x \right ) \left (-3+x \right ) \left (x^{3}-3 x^{2}-3 x +5\right )}{24 \left (x^{2}-2 x -3\right )^{\frac {5}{2}}}\)	\(32\)
default	\(-\frac {2 x -2}{24 \left (x^{2}-2 x -3\right )^{\frac {3}{2}}}+\frac {2 x -2}{48 \sqrt {x^{2}-2 x -3}}\)	\(36\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^2-2*x-3)^(5/2),x,method=_RETURNVERBOSE)

[Out]

1/24*(x^3-3*x^2-3*x+5)/(x^2-2*x-3)^(3/2)

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maxima [A]  time = 0.53, size = 51, normalized size = 1.19 \[ \frac {x}{24 \, \sqrt {x^{2} - 2 \, x - 3}} - \frac {1}{24 \, \sqrt {x^{2} - 2 \, x - 3}} - \frac {x}{12 \, {\left (x^{2} - 2 \, x - 3\right )}^{\frac {3}{2}}} + \frac {1}{12 \, {\left (x^{2} - 2 \, x - 3\right )}^{\frac {3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x^2-2*x-3)^(5/2),x, algorithm="maxima")

[Out]

1/24*x/sqrt(x^2 - 2*x - 3) - 1/24/sqrt(x^2 - 2*x - 3) - 1/12*x/(x^2 - 2*x - 3)^(3/2) + 1/12/(x^2 - 2*x - 3)^(3
/2)

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mupad [B]  time = 0.05, size = 27, normalized size = 0.63 \[ -\frac {\left (4\,x-4\right )\,\left (-8\,x^2+16\,x+40\right )}{768\,{\left (x^2-2\,x-3\right )}^{3/2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^2 - 2*x - 3)^(5/2),x)

[Out]

-((4*x - 4)*(16*x - 8*x^2 + 40))/(768*(x^2 - 2*x - 3)^(3/2))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (x^{2} - 2 x - 3\right )^{\frac {5}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x**2-2*x-3)**(5/2),x)

[Out]

Integral((x**2 - 2*x - 3)**(-5/2), x)

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