3.109 \(\int \frac {x^2}{-2+x^2+x^4} \, dx\)

Optimal. Leaf size=24 \[ \frac {1}{3} \sqrt {2} \tan ^{-1}\left (\frac {x}{\sqrt {2}}\right )-\frac {1}{3} \tanh ^{-1}(x) \]

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Rubi [A]  time = 0.01, antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {1130, 203, 207} \[ \frac {1}{3} \sqrt {2} \tan ^{-1}\left (\frac {x}{\sqrt {2}}\right )-\frac {1}{3} \tanh ^{-1}(x) \]

Antiderivative was successfully verified.

[In]

Int[x^2/(-2 + x^2 + x^4),x]

[Out]

(Sqrt[2]*ArcTan[x/Sqrt[2]])/3 - ArcTanh[x]/3

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 207

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTanh[(Rt[b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 1130

Int[((d_.)*(x_))^(m_)/((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Dist[(
d^2*(b/q + 1))/2, Int[(d*x)^(m - 2)/(b/2 + q/2 + c*x^2), x], x] - Dist[(d^2*(b/q - 1))/2, Int[(d*x)^(m - 2)/(b
/2 - q/2 + c*x^2), x], x]] /; FreeQ[{a, b, c, d}, x] && NeQ[b^2 - 4*a*c, 0] && GeQ[m, 2]

Rubi steps

\begin {align*} \int \frac {x^2}{-2+x^2+x^4} \, dx &=\frac {1}{3} \int \frac {1}{-1+x^2} \, dx+\frac {2}{3} \int \frac {1}{2+x^2} \, dx\\ &=\frac {1}{3} \sqrt {2} \tan ^{-1}\left (\frac {x}{\sqrt {2}}\right )-\frac {1}{3} \tanh ^{-1}(x)\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 32, normalized size = 1.33 \[ \frac {1}{6} \left (\log (1-x)-\log (x+1)+2 \sqrt {2} \tan ^{-1}\left (\frac {x}{\sqrt {2}}\right )\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[x^2/(-2 + x^2 + x^4),x]

[Out]

(2*Sqrt[2]*ArcTan[x/Sqrt[2]] + Log[1 - x] - Log[1 + x])/6

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IntegrateAlgebraic [A]  time = 0.02, size = 24, normalized size = 1.00 \[ \frac {1}{3} \sqrt {2} \tan ^{-1}\left (\frac {x}{\sqrt {2}}\right )-\frac {1}{3} \tanh ^{-1}(x) \]

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x^2/(-2 + x^2 + x^4),x]

[Out]

(Sqrt[2]*ArcTan[x/Sqrt[2]])/3 - ArcTanh[x]/3

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fricas [A]  time = 0.68, size = 25, normalized size = 1.04 \[ \frac {1}{3} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} x\right ) - \frac {1}{6} \, \log \left (x + 1\right ) + \frac {1}{6} \, \log \left (x - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(x^4+x^2-2),x, algorithm="fricas")

[Out]

1/3*sqrt(2)*arctan(1/2*sqrt(2)*x) - 1/6*log(x + 1) + 1/6*log(x - 1)

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giac [A]  time = 0.96, size = 27, normalized size = 1.12 \[ \frac {1}{3} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} x\right ) - \frac {1}{6} \, \log \left ({\left | x + 1 \right |}\right ) + \frac {1}{6} \, \log \left ({\left | x - 1 \right |}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(x^4+x^2-2),x, algorithm="giac")

[Out]

1/3*sqrt(2)*arctan(1/2*sqrt(2)*x) - 1/6*log(abs(x + 1)) + 1/6*log(abs(x - 1))

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maple [A]  time = 0.04, size = 26, normalized size = 1.08

method	result	size
default	\(\frac {\arctan \left (\frac {x \sqrt {2}}{2}\right ) \sqrt {2}}{3}+\frac {\ln \left (-1+x \right )}{6}-\frac {\ln \left (1+x \right )}{6}\)	\(26\)
risch	\(\frac {\arctan \left (\frac {x \sqrt {2}}{2}\right ) \sqrt {2}}{3}+\frac {\ln \left (-1+x \right )}{6}-\frac {\ln \left (1+x \right )}{6}\)	\(26\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(x^4+x^2-2),x,method=_RETURNVERBOSE)

[Out]

1/3*arctan(1/2*x*2^(1/2))*2^(1/2)+1/6*ln(-1+x)-1/6*ln(1+x)

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maxima [A]  time = 0.97, size = 25, normalized size = 1.04 \[ \frac {1}{3} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} x\right ) - \frac {1}{6} \, \log \left (x + 1\right ) + \frac {1}{6} \, \log \left (x - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(x^4+x^2-2),x, algorithm="maxima")

[Out]

1/3*sqrt(2)*arctan(1/2*sqrt(2)*x) - 1/6*log(x + 1) + 1/6*log(x - 1)

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mupad [B]  time = 0.06, size = 17, normalized size = 0.71 \[ \frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,x}{2}\right )}{3}-\frac {\mathrm {atanh}\relax (x)}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(x^2 + x^4 - 2),x)

[Out]

(2^(1/2)*atan((2^(1/2)*x)/2))/3 - atanh(x)/3

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sympy [A]  time = 0.16, size = 29, normalized size = 1.21 \[ \frac {\log {\left (x - 1 \right )}}{6} - \frac {\log {\left (x + 1 \right )}}{6} + \frac {\sqrt {2} \operatorname {atan}{\left (\frac {\sqrt {2} x}{2} \right )}}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2/(x**4+x**2-2),x)

[Out]

log(x - 1)/6 - log(x + 1)/6 + sqrt(2)*atan(sqrt(2)*x/2)/3

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