3.374 \(\int \sin ^4(x) \, dx\)

Optimal. Leaf size=24 \[ \frac {3 x}{8}-\frac {1}{4} \sin ^3(x) \cos (x)-\frac {3}{8} \sin (x) \cos (x) \]

[Out]

3/8*x-3/8*cos(x)*sin(x)-1/4*cos(x)*sin(x)^3

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Rubi [A]  time = 0.01, antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {2635, 8} \[ \frac {3 x}{8}-\frac {1}{4} \sin ^3(x) \cos (x)-\frac {3}{8} \sin (x) \cos (x) \]

Antiderivative was successfully verified.

[In]

Int[Sin[x]^4,x]

[Out]

(3*x)/8 - (3*Cos[x]*Sin[x])/8 - (Cos[x]*Sin[x]^3)/4

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 2635

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> -Simp[(b*Cos[c + d*x]*(b*Sin[c + d*x])^(n - 1))/(d*n),
x] + Dist[(b^2*(n - 1))/n, Int[(b*Sin[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && Integer
Q[2*n]

Rubi steps

\begin {align*} \int \sin ^4(x) \, dx &=-\frac {1}{4} \cos (x) \sin ^3(x)+\frac {3}{4} \int \sin ^2(x) \, dx\\ &=-\frac {3}{8} \cos (x) \sin (x)-\frac {1}{4} \cos (x) \sin ^3(x)+\frac {3 \int 1 \, dx}{8}\\ &=\frac {3 x}{8}-\frac {3}{8} \cos (x) \sin (x)-\frac {1}{4} \cos (x) \sin ^3(x)\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 22, normalized size = 0.92 \[ \frac {3 x}{8}-\frac {1}{4} \sin (2 x)+\frac {1}{32} \sin (4 x) \]

Antiderivative was successfully verified.

[In]

Integrate[Sin[x]^4,x]

[Out]

(3*x)/8 - Sin[2*x]/4 + Sin[4*x]/32

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fricas [A]  time = 0.42, size = 19, normalized size = 0.79 \[ \frac {1}{8} \, {\left (2 \, \cos \relax (x)^{3} - 5 \, \cos \relax (x)\right )} \sin \relax (x) + \frac {3}{8} \, x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(x)^4,x, algorithm="fricas")

[Out]

1/8*(2*cos(x)^3 - 5*cos(x))*sin(x) + 3/8*x

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giac [A]  time = 0.90, size = 16, normalized size = 0.67 \[ \frac {3}{8} \, x + \frac {1}{32} \, \sin \left (4 \, x\right ) - \frac {1}{4} \, \sin \left (2 \, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(x)^4,x, algorithm="giac")

[Out]

3/8*x + 1/32*sin(4*x) - 1/4*sin(2*x)

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maple [A]  time = 0.00, size = 18, normalized size = 0.75 \[ \frac {3 x}{8}-\frac {\left (\sin ^{3}\relax (x )+\frac {3 \sin \relax (x )}{2}\right ) \cos \relax (x )}{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sin(x)^4,x)

[Out]

3/8*x-1/4*(sin(x)^3+3/2*sin(x))*cos(x)

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maxima [A]  time = 0.42, size = 16, normalized size = 0.67 \[ \frac {3}{8} \, x + \frac {1}{32} \, \sin \left (4 \, x\right ) - \frac {1}{4} \, \sin \left (2 \, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(x)^4,x, algorithm="maxima")

[Out]

3/8*x + 1/32*sin(4*x) - 1/4*sin(2*x)

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mupad [B]  time = 0.03, size = 16, normalized size = 0.67 \[ \frac {3\,x}{8}-\frac {\sin \left (2\,x\right )}{4}+\frac {\sin \left (4\,x\right )}{32} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sin(x)^4,x)

[Out]

(3*x)/8 - sin(2*x)/4 + sin(4*x)/32

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sympy [A]  time = 0.06, size = 24, normalized size = 1.00 \[ \frac {3 x}{8} - \frac {\sin ^{3}{\relax (x )} \cos {\relax (x )}}{4} - \frac {3 \sin {\relax (x )} \cos {\relax (x )}}{8} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(x)**4,x)

[Out]

3*x/8 - sin(x)**3*cos(x)/4 - 3*sin(x)*cos(x)/8

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