3.54 \(\int \frac {1}{1+2 x+x^2} \, dx\)

Optimal. Leaf size=7 \[ -\frac {1}{x+1} \]

[Out]

-1/(1+x)

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Rubi [A]  time = 0.00, antiderivative size = 7, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {27, 32} \[ -\frac {1}{x+1} \]

Antiderivative was successfully verified.

[In]

Int[(1 + 2*x + x^2)^(-1),x]

[Out]

-(1 + x)^(-1)

Rule 27

Int[(u_.)*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[u*Cancel[(b/2 + c*x)^(2*p)/c^p], x] /; Fr
eeQ[{a, b, c}, x] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 32

Int[((a_.) + (b_.)*(x_))^(m_), x_Symbol] :> Simp[(a + b*x)^(m + 1)/(b*(m + 1)), x] /; FreeQ[{a, b, m}, x] && N
eQ[m, -1]

Rubi steps

\begin {align*} \int \frac {1}{1+2 x+x^2} \, dx &=\int \frac {1}{(1+x)^2} \, dx\\ &=-\frac {1}{1+x}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 7, normalized size = 1.00 \[ -\frac {1}{x+1} \]

Antiderivative was successfully verified.

[In]

Integrate[(1 + 2*x + x^2)^(-1),x]

[Out]

-(1 + x)^(-1)

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fricas [A]  time = 0.39, size = 7, normalized size = 1.00 \[ -\frac {1}{x + 1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x^2+2*x+1),x, algorithm="fricas")

[Out]

-1/(x + 1)

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giac [A]  time = 1.05, size = 7, normalized size = 1.00 \[ -\frac {1}{x + 1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x^2+2*x+1),x, algorithm="giac")

[Out]

-1/(x + 1)

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maple [A]  time = 0.00, size = 8, normalized size = 1.14 \[ -\frac {1}{x +1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^2+2*x+1),x)

[Out]

-1/(x+1)

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maxima [A]  time = 0.53, size = 7, normalized size = 1.00 \[ -\frac {1}{x + 1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x^2+2*x+1),x, algorithm="maxima")

[Out]

-1/(x + 1)

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mupad [B]  time = 0.02, size = 7, normalized size = 1.00 \[ -\frac {1}{x+1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(2*x + x^2 + 1),x)

[Out]

-1/(x + 1)

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sympy [A]  time = 0.08, size = 5, normalized size = 0.71 \[ - \frac {1}{x + 1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(x**2+2*x+1),x)

[Out]

-1/(x + 1)

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