3.38 \(\int \sqrt {x} (1+x)^{5/2} \, dx\)

Optimal. Leaf size=75 \[ \frac {1}{4} x^{3/2} (x+1)^{5/2}+\frac {5}{24} x^{3/2} (x+1)^{3/2}+\frac {5}{32} x^{3/2} \sqrt {x+1}+\frac {5}{64} \sqrt {x} \sqrt {x+1}-\frac {5}{64} \sinh ^{-1}\left (\sqrt {x}\right ) \]

[Out]

5/24*x^(3/2)*(1+x)^(3/2)+1/4*x^(3/2)*(1+x)^(5/2)-5/64*arcsinh(x^(1/2))+5/32*x^(3/2)*(1+x)^(1/2)+5/64*x^(1/2)*(
1+x)^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {50, 54, 215} \[ \frac {1}{4} x^{3/2} (x+1)^{5/2}+\frac {5}{24} x^{3/2} (x+1)^{3/2}+\frac {5}{32} x^{3/2} \sqrt {x+1}+\frac {5}{64} \sqrt {x} \sqrt {x+1}-\frac {5}{64} \sinh ^{-1}\left (\sqrt {x}\right ) \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[x]*(1 + x)^(5/2),x]

[Out]

(5*Sqrt[x]*Sqrt[1 + x])/64 + (5*x^(3/2)*Sqrt[1 + x])/32 + (5*x^(3/2)*(1 + x)^(3/2))/24 + (x^(3/2)*(1 + x)^(5/2
))/4 - (5*ArcSinh[Sqrt[x]])/64

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 215

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[(Rt[b, 2]*x)/Sqrt[a]]/Rt[b, 2], x] /; FreeQ[{a, b},
x] && GtQ[a, 0] && PosQ[b]

Rubi steps

\begin {align*} \int \sqrt {x} (1+x)^{5/2} \, dx &=\frac {1}{4} x^{3/2} (1+x)^{5/2}+\frac {5}{8} \int \sqrt {x} (1+x)^{3/2} \, dx\\ &=\frac {5}{24} x^{3/2} (1+x)^{3/2}+\frac {1}{4} x^{3/2} (1+x)^{5/2}+\frac {5}{16} \int \sqrt {x} \sqrt {1+x} \, dx\\ &=\frac {5}{32} x^{3/2} \sqrt {1+x}+\frac {5}{24} x^{3/2} (1+x)^{3/2}+\frac {1}{4} x^{3/2} (1+x)^{5/2}+\frac {5}{64} \int \frac {\sqrt {x}}{\sqrt {1+x}} \, dx\\ &=\frac {5}{64} \sqrt {x} \sqrt {1+x}+\frac {5}{32} x^{3/2} \sqrt {1+x}+\frac {5}{24} x^{3/2} (1+x)^{3/2}+\frac {1}{4} x^{3/2} (1+x)^{5/2}-\frac {5}{128} \int \frac {1}{\sqrt {x} \sqrt {1+x}} \, dx\\ &=\frac {5}{64} \sqrt {x} \sqrt {1+x}+\frac {5}{32} x^{3/2} \sqrt {1+x}+\frac {5}{24} x^{3/2} (1+x)^{3/2}+\frac {1}{4} x^{3/2} (1+x)^{5/2}-\frac {5}{64} \operatorname {Subst}\left (\int \frac {1}{\sqrt {1+x^2}} \, dx,x,\sqrt {x}\right )\\ &=\frac {5}{64} \sqrt {x} \sqrt {1+x}+\frac {5}{32} x^{3/2} \sqrt {1+x}+\frac {5}{24} x^{3/2} (1+x)^{3/2}+\frac {1}{4} x^{3/2} (1+x)^{5/2}-\frac {5}{64} \sinh ^{-1}\left (\sqrt {x}\right )\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 41, normalized size = 0.55 \[ \frac {1}{192} \left (\sqrt {x} \sqrt {x+1} \left (48 x^3+136 x^2+118 x+15\right )-15 \sinh ^{-1}\left (\sqrt {x}\right )\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[x]*(1 + x)^(5/2),x]

[Out]

(Sqrt[x]*Sqrt[1 + x]*(15 + 118*x + 136*x^2 + 48*x^3) - 15*ArcSinh[Sqrt[x]])/192

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fricas [A]  time = 0.41, size = 44, normalized size = 0.59 \[ \frac {1}{192} \, {\left (48 \, x^{3} + 136 \, x^{2} + 118 \, x + 15\right )} \sqrt {x + 1} \sqrt {x} + \frac {5}{128} \, \log \left (2 \, \sqrt {x + 1} \sqrt {x} - 2 \, x - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(1/2)*(1+x)^(5/2),x, algorithm="fricas")

[Out]

1/192*(48*x^3 + 136*x^2 + 118*x + 15)*sqrt(x + 1)*sqrt(x) + 5/128*log(2*sqrt(x + 1)*sqrt(x) - 2*x - 1)

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giac [A]  time = 1.16, size = 90, normalized size = 1.20 \[ \frac {1}{192} \, {\left (2 \, {\left (4 \, {\left (6 \, x - 19\right )} {\left (x + 1\right )} + 163\right )} {\left (x + 1\right )} - 279\right )} \sqrt {x + 1} \sqrt {x} + \frac {1}{8} \, {\left (2 \, {\left (4 \, x - 9\right )} {\left (x + 1\right )} + 33\right )} \sqrt {x + 1} \sqrt {x} + \frac {3}{4} \, {\left (2 \, x - 3\right )} \sqrt {x + 1} \sqrt {x} + \sqrt {x + 1} \sqrt {x} + \frac {5}{64} \, \log \left (\sqrt {x + 1} - \sqrt {x}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(1/2)*(1+x)^(5/2),x, algorithm="giac")

[Out]

1/192*(2*(4*(6*x - 19)*(x + 1) + 163)*(x + 1) - 279)*sqrt(x + 1)*sqrt(x) + 1/8*(2*(4*x - 9)*(x + 1) + 33)*sqrt
(x + 1)*sqrt(x) + 3/4*(2*x - 3)*sqrt(x + 1)*sqrt(x) + sqrt(x + 1)*sqrt(x) + 5/64*log(sqrt(x + 1) - sqrt(x))

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maple [A]  time = 0.00, size = 70, normalized size = 0.93 \[ \frac {\left (x +1\right )^{\frac {7}{2}} \sqrt {x}}{4}-\frac {\left (x +1\right )^{\frac {5}{2}} \sqrt {x}}{24}-\frac {5 \left (x +1\right )^{\frac {3}{2}} \sqrt {x}}{96}-\frac {5 \sqrt {x +1}\, \sqrt {x}}{64}-\frac {5 \sqrt {\left (x +1\right ) x}\, \ln \left (x +\frac {1}{2}+\sqrt {x^{2}+x}\right )}{128 \sqrt {x +1}\, \sqrt {x}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(1/2)*(x+1)^(5/2),x)

[Out]

1/4*x^(1/2)*(x+1)^(7/2)-1/24*x^(1/2)*(x+1)^(5/2)-5/96*x^(1/2)*(x+1)^(3/2)-5/64*(x+1)^(1/2)*x^(1/2)-5/128*((x+1
)*x)^(1/2)/(x+1)^(1/2)/x^(1/2)*ln(x+1/2+(x^2+x)^(1/2))

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maxima [B]  time = 0.53, size = 113, normalized size = 1.51 \[ \frac {\frac {15 \, {\left (x + 1\right )}^{\frac {7}{2}}}{x^{\frac {7}{2}}} + \frac {73 \, {\left (x + 1\right )}^{\frac {5}{2}}}{x^{\frac {5}{2}}} - \frac {55 \, {\left (x + 1\right )}^{\frac {3}{2}}}{x^{\frac {3}{2}}} + \frac {15 \, \sqrt {x + 1}}{\sqrt {x}}}{192 \, {\left (\frac {{\left (x + 1\right )}^{4}}{x^{4}} - \frac {4 \, {\left (x + 1\right )}^{3}}{x^{3}} + \frac {6 \, {\left (x + 1\right )}^{2}}{x^{2}} - \frac {4 \, {\left (x + 1\right )}}{x} + 1\right )}} - \frac {5}{128} \, \log \left (\frac {\sqrt {x + 1}}{\sqrt {x}} + 1\right ) + \frac {5}{128} \, \log \left (\frac {\sqrt {x + 1}}{\sqrt {x}} - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(1/2)*(1+x)^(5/2),x, algorithm="maxima")

[Out]

1/192*(15*(x + 1)^(7/2)/x^(7/2) + 73*(x + 1)^(5/2)/x^(5/2) - 55*(x + 1)^(3/2)/x^(3/2) + 15*sqrt(x + 1)/sqrt(x)
)/((x + 1)^4/x^4 - 4*(x + 1)^3/x^3 + 6*(x + 1)^2/x^2 - 4*(x + 1)/x + 1) - 5/128*log(sqrt(x + 1)/sqrt(x) + 1) +
5/128*log(sqrt(x + 1)/sqrt(x) - 1)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \sqrt {x}\,{\left (x+1\right )}^{5/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(1/2)*(x + 1)^(5/2),x)

[Out]

int(x^(1/2)*(x + 1)^(5/2), x)

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sympy [A]  time = 8.75, size = 190, normalized size = 2.53 \[ \begin {cases} - \frac {5 \operatorname {acosh}{\left (\sqrt {x + 1} \right )}}{64} + \frac {\left (x + 1\right )^{\frac {9}{2}}}{4 \sqrt {x}} - \frac {7 \left (x + 1\right )^{\frac {7}{2}}}{24 \sqrt {x}} - \frac {\left (x + 1\right )^{\frac {5}{2}}}{96 \sqrt {x}} - \frac {5 \left (x + 1\right )^{\frac {3}{2}}}{192 \sqrt {x}} + \frac {5 \sqrt {x + 1}}{64 \sqrt {x}} & \text {for}\: \left |{x + 1}\right | > 1 \\\frac {5 i \operatorname {asin}{\left (\sqrt {x + 1} \right )}}{64} - \frac {i \left (x + 1\right )^{\frac {9}{2}}}{4 \sqrt {- x}} + \frac {7 i \left (x + 1\right )^{\frac {7}{2}}}{24 \sqrt {- x}} + \frac {i \left (x + 1\right )^{\frac {5}{2}}}{96 \sqrt {- x}} + \frac {5 i \left (x + 1\right )^{\frac {3}{2}}}{192 \sqrt {- x}} - \frac {5 i \sqrt {x + 1}}{64 \sqrt {- x}} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(1/2)*(1+x)**(5/2),x)

[Out]

Piecewise((-5*acosh(sqrt(x + 1))/64 + (x + 1)**(9/2)/(4*sqrt(x)) - 7*(x + 1)**(7/2)/(24*sqrt(x)) - (x + 1)**(5
/2)/(96*sqrt(x)) - 5*(x + 1)**(3/2)/(192*sqrt(x)) + 5*sqrt(x + 1)/(64*sqrt(x)), Abs(x + 1) > 1), (5*I*asin(sqr
t(x + 1))/64 - I*(x + 1)**(9/2)/(4*sqrt(-x)) + 7*I*(x + 1)**(7/2)/(24*sqrt(-x)) + I*(x + 1)**(5/2)/(96*sqrt(-x
)) + 5*I*(x + 1)**(3/2)/(192*sqrt(-x)) - 5*I*sqrt(x + 1)/(64*sqrt(-x)), True))

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