Optimal. Leaf size=104 \[ 4 i x \operatorname {PolyLog}\left (2,-e^{2 i x}\right )-2 \operatorname {PolyLog}\left (3,-e^{2 i x}\right )+\frac {x^4}{4}+\frac {4 i x^3}{3}+\frac {1}{3} x^3 \tan ^3(x)-x^3 \tan (x)-\frac {x^2}{2}-4 x^2 \log \left (1+e^{2 i x}\right )-\frac {1}{2} x^2 \tan ^2(x)+x \tan (x)+\log (\cos (x)) \]
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Rubi [A] time = 0.23, antiderivative size = 104, normalized size of antiderivative = 1.00, number of steps used = 17, number of rules used = 8, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.000, Rules used = {3720, 3475, 30, 3719, 2190, 2531, 2282, 6589} \[ 4 i x \text {PolyLog}\left (2,-e^{2 i x}\right )-2 \text {PolyLog}\left (3,-e^{2 i x}\right )+\frac {x^4}{4}+\frac {4 i x^3}{3}-\frac {x^2}{2}-4 x^2 \log \left (1+e^{2 i x}\right )+\frac {1}{3} x^3 \tan ^3(x)-\frac {1}{2} x^2 \tan ^2(x)-x^3 \tan (x)+x \tan (x)+\log (\cos (x)) \]
Antiderivative was successfully verified.
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Rule 30
Rule 2190
Rule 2282
Rule 2531
Rule 3475
Rule 3719
Rule 3720
Rule 6589
Rubi steps
\begin {align*} \int x^3 \tan ^4(x) \, dx &=\frac {1}{3} x^3 \tan ^3(x)-\int x^3 \tan ^2(x) \, dx-\int x^2 \tan ^3(x) \, dx\\ &=-x^3 \tan (x)-\frac {1}{2} x^2 \tan ^2(x)+\frac {1}{3} x^3 \tan ^3(x)+3 \int x^2 \tan (x) \, dx+\int x^3 \, dx+\int x^2 \tan (x) \, dx+\int x \tan ^2(x) \, dx\\ &=\frac {4 i x^3}{3}+\frac {x^4}{4}+x \tan (x)-x^3 \tan (x)-\frac {1}{2} x^2 \tan ^2(x)+\frac {1}{3} x^3 \tan ^3(x)-2 i \int \frac {e^{2 i x} x^2}{1+e^{2 i x}} \, dx-6 i \int \frac {e^{2 i x} x^2}{1+e^{2 i x}} \, dx-\int x \, dx-\int \tan (x) \, dx\\ &=-\frac {x^2}{2}+\frac {4 i x^3}{3}+\frac {x^4}{4}-4 x^2 \log \left (1+e^{2 i x}\right )+\log (\cos (x))+x \tan (x)-x^3 \tan (x)-\frac {1}{2} x^2 \tan ^2(x)+\frac {1}{3} x^3 \tan ^3(x)+2 \int x \log \left (1+e^{2 i x}\right ) \, dx+6 \int x \log \left (1+e^{2 i x}\right ) \, dx\\ &=-\frac {x^2}{2}+\frac {4 i x^3}{3}+\frac {x^4}{4}-4 x^2 \log \left (1+e^{2 i x}\right )+\log (\cos (x))+4 i x \text {Li}_2\left (-e^{2 i x}\right )+x \tan (x)-x^3 \tan (x)-\frac {1}{2} x^2 \tan ^2(x)+\frac {1}{3} x^3 \tan ^3(x)-i \int \text {Li}_2\left (-e^{2 i x}\right ) \, dx-3 i \int \text {Li}_2\left (-e^{2 i x}\right ) \, dx\\ &=-\frac {x^2}{2}+\frac {4 i x^3}{3}+\frac {x^4}{4}-4 x^2 \log \left (1+e^{2 i x}\right )+\log (\cos (x))+4 i x \text {Li}_2\left (-e^{2 i x}\right )+x \tan (x)-x^3 \tan (x)-\frac {1}{2} x^2 \tan ^2(x)+\frac {1}{3} x^3 \tan ^3(x)-\frac {1}{2} \operatorname {Subst}\left (\int \frac {\text {Li}_2(-x)}{x} \, dx,x,e^{2 i x}\right )-\frac {3}{2} \operatorname {Subst}\left (\int \frac {\text {Li}_2(-x)}{x} \, dx,x,e^{2 i x}\right )\\ &=-\frac {x^2}{2}+\frac {4 i x^3}{3}+\frac {x^4}{4}-4 x^2 \log \left (1+e^{2 i x}\right )+\log (\cos (x))+4 i x \text {Li}_2\left (-e^{2 i x}\right )-2 \text {Li}_3\left (-e^{2 i x}\right )+x \tan (x)-x^3 \tan (x)-\frac {1}{2} x^2 \tan ^2(x)+\frac {1}{3} x^3 \tan ^3(x)\\ \end {align*}
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Mathematica [A] time = 0.15, size = 101, normalized size = 0.97 \[ 4 i x \operatorname {PolyLog}\left (2,-e^{2 i x}\right )-2 \operatorname {PolyLog}\left (3,-e^{2 i x}\right )+\frac {x^4}{4}+\frac {4 i x^3}{3}-\frac {4}{3} x^3 \tan (x)+\frac {1}{3} x^3 \tan (x) \sec ^2(x)-4 x^2 \log \left (1+e^{2 i x}\right )-\frac {1}{2} x^2 \sec ^2(x)+x \tan (x)+\log (\cos (x)) \]
Antiderivative was successfully verified.
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fricas [C] time = 0.46, size = 182, normalized size = 1.75 \[ \frac {1}{3} \, x^{3} \tan \relax (x)^{3} + \frac {1}{4} \, x^{4} - \frac {1}{2} \, x^{2} \tan \relax (x)^{2} - \frac {1}{2} \, x^{2} - 2 i \, x {\rm Li}_2\left (\frac {2 \, {\left (i \, \tan \relax (x) - 1\right )}}{\tan \relax (x)^{2} + 1} + 1\right ) + 2 i \, x {\rm Li}_2\left (\frac {2 \, {\left (-i \, \tan \relax (x) - 1\right )}}{\tan \relax (x)^{2} + 1} + 1\right ) - \frac {1}{2} \, {\left (4 \, x^{2} - 1\right )} \log \left (-\frac {2 \, {\left (i \, \tan \relax (x) - 1\right )}}{\tan \relax (x)^{2} + 1}\right ) - \frac {1}{2} \, {\left (4 \, x^{2} - 1\right )} \log \left (-\frac {2 \, {\left (-i \, \tan \relax (x) - 1\right )}}{\tan \relax (x)^{2} + 1}\right ) - {\left (x^{3} - x\right )} \tan \relax (x) - {\rm polylog}\left (3, \frac {\tan \relax (x)^{2} + 2 i \, \tan \relax (x) - 1}{\tan \relax (x)^{2} + 1}\right ) - {\rm polylog}\left (3, \frac {\tan \relax (x)^{2} - 2 i \, \tan \relax (x) - 1}{\tan \relax (x)^{2} + 1}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{3} \tan \relax (x)^{4}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.09, size = 138, normalized size = 1.33 \[ \frac {x^{4}}{4}+\frac {8 i x^{3}}{3}-4 x^{2} \ln \left ({\mathrm e}^{2 i x}+1\right )+4 i x \polylog \left (2, -{\mathrm e}^{2 i x}\right )-\frac {2 i \left (6 x^{2} {\mathrm e}^{2 i x}+6 x^{2} {\mathrm e}^{4 i x}+4 x^{2}-3 i x \,{\mathrm e}^{2 i x}-3 i x \,{\mathrm e}^{4 i x}-6 \,{\mathrm e}^{2 i x}-3 \,{\mathrm e}^{4 i x}-3\right ) x}{3 \left ({\mathrm e}^{2 i x}+1\right )^{3}}-2 \polylog \left (3, -{\mathrm e}^{2 i x}\right )+\ln \left ({\mathrm e}^{2 i x}+1\right )-2 \ln \left ({\mathrm e}^{i x}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 1.26, size = 485, normalized size = 4.66 \[ -\frac {3 i \, x^{4} + {\left (48 \, x^{2} + 12 \, {\left (4 \, x^{2} - 1\right )} \cos \left (6 \, x\right ) + 36 \, {\left (4 \, x^{2} - 1\right )} \cos \left (4 \, x\right ) + 36 \, {\left (4 \, x^{2} - 1\right )} \cos \left (2 \, x\right ) + {\left (48 i \, x^{2} - 12 i\right )} \sin \left (6 \, x\right ) + {\left (144 i \, x^{2} - 36 i\right )} \sin \left (4 \, x\right ) + {\left (144 i \, x^{2} - 36 i\right )} \sin \left (2 \, x\right ) - 12\right )} \arctan \left (\sin \left (2 \, x\right ), \cos \left (2 \, x\right ) + 1\right ) + {\left (3 i \, x^{4} - 32 \, x^{3} + 24 \, x\right )} \cos \left (6 \, x\right ) + {\left (9 i \, x^{4} - 48 \, x^{3} - 24 i \, x^{2} + 48 \, x\right )} \cos \left (4 \, x\right ) + {\left (9 i \, x^{4} - 48 \, x^{3} - 24 i \, x^{2} + 24 \, x\right )} \cos \left (2 \, x\right ) - {\left (48 \, x \cos \left (6 \, x\right ) + 144 \, x \cos \left (4 \, x\right ) + 144 \, x \cos \left (2 \, x\right ) + 48 i \, x \sin \left (6 \, x\right ) + 144 i \, x \sin \left (4 \, x\right ) + 144 i \, x \sin \left (2 \, x\right ) + 48 \, x\right )} {\rm Li}_2\left (-e^{\left (2 i \, x\right )}\right ) + {\left (-24 i \, x^{2} + {\left (-24 i \, x^{2} + 6 i\right )} \cos \left (6 \, x\right ) + {\left (-72 i \, x^{2} + 18 i\right )} \cos \left (4 \, x\right ) + {\left (-72 i \, x^{2} + 18 i\right )} \cos \left (2 \, x\right ) + 6 \, {\left (4 \, x^{2} - 1\right )} \sin \left (6 \, x\right ) + 18 \, {\left (4 \, x^{2} - 1\right )} \sin \left (4 \, x\right ) + 18 \, {\left (4 \, x^{2} - 1\right )} \sin \left (2 \, x\right ) + 6 i\right )} \log \left (\cos \left (2 \, x\right )^{2} + \sin \left (2 \, x\right )^{2} + 2 \, \cos \left (2 \, x\right ) + 1\right ) + {\left (-24 i \, \cos \left (6 \, x\right ) - 72 i \, \cos \left (4 \, x\right ) - 72 i \, \cos \left (2 \, x\right ) + 24 \, \sin \left (6 \, x\right ) + 72 \, \sin \left (4 \, x\right ) + 72 \, \sin \left (2 \, x\right ) - 24 i\right )} {\rm Li}_{3}(-e^{\left (2 i \, x\right )}) - {\left (3 \, x^{4} + 32 i \, x^{3} - 24 i \, x\right )} \sin \left (6 \, x\right ) - {\left (9 \, x^{4} + 48 i \, x^{3} - 24 \, x^{2} - 48 i \, x\right )} \sin \left (4 \, x\right ) - {\left (9 \, x^{4} + 48 i \, x^{3} - 24 \, x^{2} - 24 i \, x\right )} \sin \left (2 \, x\right )}{-12 i \, \cos \left (6 \, x\right ) - 36 i \, \cos \left (4 \, x\right ) - 36 i \, \cos \left (2 \, x\right ) + 12 \, \sin \left (6 \, x\right ) + 36 \, \sin \left (4 \, x\right ) + 36 \, \sin \left (2 \, x\right ) - 12 i} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int x^3\,{\mathrm {tan}\relax (x)}^4 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{3} \tan ^{4}{\relax (x )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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