3.3 \(\int \frac {1}{(1+\cos (x))^2} \, dx\)

Optimal. Leaf size=25 \[ \frac {\sin (x)}{3 (\cos (x)+1)}+\frac {\sin (x)}{3 (\cos (x)+1)^2} \]

[Out]

1/3*sin(x)/(1+cos(x))^2+1/3*sin(x)/(1+cos(x))

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Rubi [A]  time = 0.01, antiderivative size = 25, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2650, 2648} \[ \frac {\sin (x)}{3 (\cos (x)+1)}+\frac {\sin (x)}{3 (\cos (x)+1)^2} \]

Antiderivative was successfully verified.

[In]

Int[(1 + Cos[x])^(-2),x]

[Out]

Sin[x]/(3*(1 + Cos[x])^2) + Sin[x]/(3*(1 + Cos[x]))

Rule 2648

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> -Simp[Cos[c + d*x]/(d*(b + a*Sin[c + d*x])), x]
/; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2, 0]

Rule 2650

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*Cos[c + d*x]*(a + b*Sin[c + d*x])^n)/(a*
d*(2*n + 1)), x] + Dist[(n + 1)/(a*(2*n + 1)), Int[(a + b*Sin[c + d*x])^(n + 1), x], x] /; FreeQ[{a, b, c, d},
x] && EqQ[a^2 - b^2, 0] && LtQ[n, -1] && IntegerQ[2*n]

Rubi steps

\begin {align*} \int \frac {1}{(1+\cos (x))^2} \, dx &=\frac {\sin (x)}{3 (1+\cos (x))^2}+\frac {1}{3} \int \frac {1}{1+\cos (x)} \, dx\\ &=\frac {\sin (x)}{3 (1+\cos (x))^2}+\frac {\sin (x)}{3 (1+\cos (x))}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 16, normalized size = 0.64 \[ \frac {\sin (x) (\cos (x)+2)}{3 (\cos (x)+1)^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(1 + Cos[x])^(-2),x]

[Out]

((2 + Cos[x])*Sin[x])/(3*(1 + Cos[x])^2)

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fricas [A]  time = 0.41, size = 20, normalized size = 0.80 \[ \frac {{\left (\cos \relax (x) + 2\right )} \sin \relax (x)}{3 \, {\left (\cos \relax (x)^{2} + 2 \, \cos \relax (x) + 1\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+cos(x))^2,x, algorithm="fricas")

[Out]

1/3*(cos(x) + 2)*sin(x)/(cos(x)^2 + 2*cos(x) + 1)

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giac [A]  time = 0.17, size = 15, normalized size = 0.60 \[ \frac {1}{6} \, \tan \left (\frac {1}{2} \, x\right )^{3} + \frac {1}{2} \, \tan \left (\frac {1}{2} \, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+cos(x))^2,x, algorithm="giac")

[Out]

1/6*tan(1/2*x)^3 + 1/2*tan(1/2*x)

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maple [A]  time = 0.02, size = 16, normalized size = 0.64 \[ \frac {\left (\tan ^{3}\left (\frac {x}{2}\right )\right )}{6}+\frac {\tan \left (\frac {x}{2}\right )}{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(1+cos(x))^2,x)

[Out]

1/6*tan(1/2*x)^3+1/2*tan(1/2*x)

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maxima [A]  time = 0.53, size = 23, normalized size = 0.92 \[ \frac {\sin \relax (x)}{2 \, {\left (\cos \relax (x) + 1\right )}} + \frac {\sin \relax (x)^{3}}{6 \, {\left (\cos \relax (x) + 1\right )}^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+cos(x))^2,x, algorithm="maxima")

[Out]

1/2*sin(x)/(cos(x) + 1) + 1/6*sin(x)^3/(cos(x) + 1)^3

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mupad [B]  time = 0.16, size = 14, normalized size = 0.56 \[ \frac {\mathrm {tan}\left (\frac {x}{2}\right )\,\left ({\mathrm {tan}\left (\frac {x}{2}\right )}^2+3\right )}{6} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(cos(x) + 1)^2,x)

[Out]

(tan(x/2)*(tan(x/2)^2 + 3))/6

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sympy [A]  time = 0.38, size = 14, normalized size = 0.56 \[ \frac {\tan ^{3}{\left (\frac {x}{2} \right )}}{6} + \frac {\tan {\left (\frac {x}{2} \right )}}{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+cos(x))**2,x)

[Out]

tan(x/2)**3/6 + tan(x/2)/2

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