3.153 \(\int \frac {x}{\sqrt {1+x+x^2}} \, dx\)

Optimal. Leaf size=27 \[ \sqrt {x^2+x+1}-\frac {1}{2} \sinh ^{-1}\left (\frac {2 x+1}{\sqrt {3}}\right ) \]

[Out]

-1/2*arcsinh(1/3*(1+2*x)*3^(1/2))+(x^2+x+1)^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 27, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {640, 619, 215} \[ \sqrt {x^2+x+1}-\frac {1}{2} \sinh ^{-1}\left (\frac {2 x+1}{\sqrt {3}}\right ) \]

Antiderivative was successfully verified.

[In]

Int[x/Sqrt[1 + x + x^2],x]

[Out]

Sqrt[1 + x + x^2] - ArcSinh[(1 + 2*x)/Sqrt[3]]/2

Rule 215

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[(Rt[b, 2]*x)/Sqrt[a]]/Rt[b, 2], x] /; FreeQ[{a, b},
x] && GtQ[a, 0] && PosQ[b]

Rule 619

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dist[1/(2*c*((-4*c)/(b^2 - 4*a*c))^p), Subst[Int[Si
mp[1 - x^2/(b^2 - 4*a*c), x]^p, x], x, b + 2*c*x], x] /; FreeQ[{a, b, c, p}, x] && GtQ[4*a - b^2/c, 0]

Rule 640

Int[((d_.) + (e_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e*(a + b*x + c*x^2)^(p +
1))/(2*c*(p + 1)), x] + Dist[(2*c*d - b*e)/(2*c), Int[(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, p}
, x] && NeQ[2*c*d - b*e, 0] && NeQ[p, -1]

Rubi steps

\begin {align*} \int \frac {x}{\sqrt {1+x+x^2}} \, dx &=\sqrt {1+x+x^2}-\frac {1}{2} \int \frac {1}{\sqrt {1+x+x^2}} \, dx\\ &=\sqrt {1+x+x^2}-\frac {\operatorname {Subst}\left (\int \frac {1}{\sqrt {1+\frac {x^2}{3}}} \, dx,x,1+2 x\right )}{2 \sqrt {3}}\\ &=\sqrt {1+x+x^2}-\frac {1}{2} \sinh ^{-1}\left (\frac {1+2 x}{\sqrt {3}}\right )\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 27, normalized size = 1.00 \[ \sqrt {x^2+x+1}-\frac {1}{2} \sinh ^{-1}\left (\frac {2 x+1}{\sqrt {3}}\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[x/Sqrt[1 + x + x^2],x]

[Out]

Sqrt[1 + x + x^2] - ArcSinh[(1 + 2*x)/Sqrt[3]]/2

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fricas [A]  time = 0.39, size = 27, normalized size = 1.00 \[ \sqrt {x^{2} + x + 1} + \frac {1}{2} \, \log \left (-2 \, x + 2 \, \sqrt {x^{2} + x + 1} - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(x^2+x+1)^(1/2),x, algorithm="fricas")

[Out]

sqrt(x^2 + x + 1) + 1/2*log(-2*x + 2*sqrt(x^2 + x + 1) - 1)

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giac [A]  time = 0.03, size = 27, normalized size = 1.00 \[ \sqrt {x^{2} + x + 1} + \frac {1}{2} \, \log \left (-2 \, x + 2 \, \sqrt {x^{2} + x + 1} - 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(x^2+x+1)^(1/2),x, algorithm="giac")

[Out]

sqrt(x^2 + x + 1) + 1/2*log(-2*x + 2*sqrt(x^2 + x + 1) - 1)

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maple [A]  time = 0.01, size = 21, normalized size = 0.78 \[ -\frac {\arcsinh \left (\frac {2 \sqrt {3}\, \left (x +\frac {1}{2}\right )}{3}\right )}{2}+\sqrt {x^{2}+x +1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(x^2+x+1)^(1/2),x)

[Out]

(x^2+x+1)^(1/2)-1/2*arcsinh(2/3*3^(1/2)*(x+1/2))

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maxima [A]  time = 1.20, size = 22, normalized size = 0.81 \[ \sqrt {x^{2} + x + 1} - \frac {1}{2} \, \operatorname {arsinh}\left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x + 1\right )}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(x^2+x+1)^(1/2),x, algorithm="maxima")

[Out]

sqrt(x^2 + x + 1) - 1/2*arcsinh(1/3*sqrt(3)*(2*x + 1))

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mupad [B]  time = 0.05, size = 23, normalized size = 0.85 \[ \sqrt {x^2+x+1}-\frac {\ln \left (x+\sqrt {x^2+x+1}+\frac {1}{2}\right )}{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(x + x^2 + 1)^(1/2),x)

[Out]

(x + x^2 + 1)^(1/2) - log(x + (x + x^2 + 1)^(1/2) + 1/2)/2

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x}{\sqrt {x^{2} + x + 1}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(x**2+x+1)**(1/2),x)

[Out]

Integral(x/sqrt(x**2 + x + 1), x)

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