Optimal. Leaf size=428 \[ -\frac{g \left (\frac{2 c d-b e}{\sqrt{b^2-4 a c}}+e\right ) \text{PolyLog}\left (2,-\frac{2 c e^{h+i x}}{b-\sqrt{b^2-4 a c}}\right )}{i^2 \left (b-\sqrt{b^2-4 a c}\right )}-\frac{g \left (e-\frac{2 c d-b e}{\sqrt{b^2-4 a c}}\right ) \text{PolyLog}\left (2,-\frac{2 c e^{h+i x}}{\sqrt{b^2-4 a c}+b}\right )}{i^2 \left (\sqrt{b^2-4 a c}+b\right )}-\frac{(f+g x) \left (\frac{2 c d-b e}{\sqrt{b^2-4 a c}}+e\right ) \log \left (\frac{2 c e^{h+i x}}{b-\sqrt{b^2-4 a c}}+1\right )}{i \left (b-\sqrt{b^2-4 a c}\right )}-\frac{(f+g x) \left (e-\frac{2 c d-b e}{\sqrt{b^2-4 a c}}\right ) \log \left (\frac{2 c e^{h+i x}}{\sqrt{b^2-4 a c}+b}+1\right )}{i \left (\sqrt{b^2-4 a c}+b\right )}+\frac{(f+g x)^2 \left (e-\frac{2 c d-b e}{\sqrt{b^2-4 a c}}\right )}{2 g \left (\sqrt{b^2-4 a c}+b\right )}+\frac{(f+g x)^2 \left (\frac{2 c d-b e}{\sqrt{b^2-4 a c}}+e\right )}{2 g \left (b-\sqrt{b^2-4 a c}\right )} \]
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Rubi [A] time = 0.980133, antiderivative size = 428, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 5, integrand size = 42, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.119 \[ -\frac{g \left (\frac{2 c d-b e}{\sqrt{b^2-4 a c}}+e\right ) \text{PolyLog}\left (2,-\frac{2 c e^{h+i x}}{b-\sqrt{b^2-4 a c}}\right )}{i^2 \left (b-\sqrt{b^2-4 a c}\right )}-\frac{g \left (e-\frac{2 c d-b e}{\sqrt{b^2-4 a c}}\right ) \text{PolyLog}\left (2,-\frac{2 c e^{h+i x}}{\sqrt{b^2-4 a c}+b}\right )}{i^2 \left (\sqrt{b^2-4 a c}+b\right )}-\frac{(f+g x) \left (\frac{2 c d-b e}{\sqrt{b^2-4 a c}}+e\right ) \log \left (\frac{2 c e^{h+i x}}{b-\sqrt{b^2-4 a c}}+1\right )}{i \left (b-\sqrt{b^2-4 a c}\right )}-\frac{(f+g x) \left (e-\frac{2 c d-b e}{\sqrt{b^2-4 a c}}\right ) \log \left (\frac{2 c e^{h+i x}}{\sqrt{b^2-4 a c}+b}+1\right )}{i \left (\sqrt{b^2-4 a c}+b\right )}+\frac{(f+g x)^2 \left (e-\frac{2 c d-b e}{\sqrt{b^2-4 a c}}\right )}{2 g \left (\sqrt{b^2-4 a c}+b\right )}+\frac{(f+g x)^2 \left (\frac{2 c d-b e}{\sqrt{b^2-4 a c}}+e\right )}{2 g \left (b-\sqrt{b^2-4 a c}\right )} \]
Antiderivative was successfully verified.
[In] Int[((d + e*E^(h + i*x))*(f + g*x))/(a + b*E^(h + i*x) + c*E^(2*h + 2*i*x)),x]
[Out]
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Rubi in Sympy [A] time = 84.7189, size = 314, normalized size = 0.73 \[ \frac{g \left (b e - 2 c d + e \sqrt{- 4 a c + b^{2}}\right ) \operatorname{Li}_{2}\left (- \frac{\left (b + \sqrt{- 4 a c + b^{2}}\right ) e^{- h - i x}}{2 c}\right )}{i^{2} \left (- 4 a c + b^{2} + b \sqrt{- 4 a c + b^{2}}\right )} + \frac{g \left (b e - 2 c d - e \sqrt{- 4 a c + b^{2}}\right ) \operatorname{Li}_{2}\left (- \frac{\left (b - \sqrt{- 4 a c + b^{2}}\right ) e^{- h - i x}}{2 c}\right )}{i^{2} \left (- 4 a c + b^{2} - b \sqrt{- 4 a c + b^{2}}\right )} - \frac{\left (f + g x\right ) \left (b e - 2 c d + e \sqrt{- 4 a c + b^{2}}\right ) \log{\left (1 + \frac{\left (b + \sqrt{- 4 a c + b^{2}}\right ) e^{- h - i x}}{2 c} \right )}}{i \left (- 4 a c + b^{2} + b \sqrt{- 4 a c + b^{2}}\right )} - \frac{\left (f + g x\right ) \left (b e - 2 c d - e \sqrt{- 4 a c + b^{2}}\right ) \log{\left (1 + \frac{\left (b - \sqrt{- 4 a c + b^{2}}\right ) e^{- h - i x}}{2 c} \right )}}{i \left (- 4 a c + b^{2} - b \sqrt{- 4 a c + b^{2}}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((d+e*exp(i*x+h))*(g*x+f)/(a+b*exp(i*x+h)+c*exp(2*i*x+2*h)),x)
[Out]
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Mathematica [A] time = 4.18702, size = 574, normalized size = 1.34 \[ -\frac{g \left (d \sqrt{-\left (b^2-4 a c\right )^2}+b d \sqrt{4 a c-b^2}-2 a e \sqrt{4 a c-b^2}\right ) \text{PolyLog}\left (2,\frac{2 c e^{h+i x}}{\sqrt{b^2-4 a c}-b}\right )+g \left (d \sqrt{-\left (b^2-4 a c\right )^2}-b d \sqrt{4 a c-b^2}+2 a e \sqrt{4 a c-b^2}\right ) \text{PolyLog}\left (2,-\frac{2 c e^{h+i x}}{\sqrt{b^2-4 a c}+b}\right )+i \left (2 f \sqrt{b^2-4 a c} (b d-2 a e) \tan ^{-1}\left (\frac{b+2 c e^{h+i x}}{\sqrt{4 a c-b^2}}\right )+g x \left (d \sqrt{-\left (b^2-4 a c\right )^2}+b d \sqrt{4 a c-b^2}-2 a e \sqrt{4 a c-b^2}\right ) \log \left (\frac{2 c e^{h+i x}}{b-\sqrt{b^2-4 a c}}+1\right )+d f \sqrt{-\left (b^2-4 a c\right )^2} \log \left (a+e^{h+i x} \left (b+c e^{h+i x}\right )\right )-2 d f i x \sqrt{-\left (b^2-4 a c\right )^2}+d g x \sqrt{-\left (b^2-4 a c\right )^2} \log \left (\frac{2 c e^{h+i x}}{\sqrt{b^2-4 a c}+b}+1\right )-b d g x \sqrt{4 a c-b^2} \log \left (\frac{2 c e^{h+i x}}{\sqrt{b^2-4 a c}+b}+1\right )+d g i x^2 \left (-\sqrt{-\left (b^2-4 a c\right )^2}\right )+2 a e g x \sqrt{4 a c-b^2} \log \left (\frac{2 c e^{h+i x}}{\sqrt{b^2-4 a c}+b}+1\right )\right )}{2 a i^2 \sqrt{-\left (b^2-4 a c\right )^2}} \]
Warning: Unable to verify antiderivative.
[In] Integrate[((d + e*E^(h + i*x))*(f + g*x))/(a + b*E^(h + i*x) + c*E^(2*h + 2*i*x)),x]
[Out]
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Maple [C] time = 0.055, size = 1261, normalized size = 3. \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((d+e*exp(i*x+h))*(g*x+f)/(a+b*exp(i*x+h)+c*exp(2*i*x+2*h)),x)
[Out]
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((g*x + f)*(e*e^(i*x + h) + d)/(c*e^(2*i*x + 2*h) + b*e^(i*x + h) + a),x, algorithm="maxima")
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Fricas [A] time = 0.284355, size = 936, normalized size = 2.19 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((g*x + f)*(e*e^(i*x + h) + d)/(c*e^(2*i*x + 2*h) + b*e^(i*x + h) + a),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((d+e*exp(i*x+h))*(g*x+f)/(a+b*exp(i*x+h)+c*exp(2*i*x+2*h)),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (g x + f\right )}{\left (e e^{\left (i x + h\right )} + d\right )}}{c e^{\left (2 \, i x + 2 \, h\right )} + b e^{\left (i x + h\right )} + a}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((g*x + f)*(e*e^(i*x + h) + d)/(c*e^(2*i*x + 2*h) + b*e^(i*x + h) + a),x, algorithm="giac")
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