Optimal. Leaf size=72 \[ -2 x \text{PolyLog}\left (2,-e^x\right )+2 \text{PolyLog}\left (2,-e^x\right )+2 \text{PolyLog}\left (3,-e^x\right )+\frac{x^3}{3}+\frac{x^2}{e^x+1}-x^2-x^2 \log \left (e^x+1\right )+2 x \log \left (e^x+1\right ) \]
[Out]
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Rubi [A] time = 0.341545, antiderivative size = 72, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 10, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.556 \[ -2 x \text{PolyLog}\left (2,-e^x\right )+2 \text{PolyLog}\left (2,-e^x\right )+2 \text{PolyLog}\left (3,-e^x\right )+\frac{x^3}{3}+\frac{x^2}{e^x+1}-x^2-x^2 \log \left (e^x+1\right )+2 x \log \left (e^x+1\right ) \]
Antiderivative was successfully verified.
[In] Int[x^2/(1 + 2*E^x + E^(2*x)),x]
[Out]
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Rubi in Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{2}}{e^{2 x} + 2 e^{x} + 1}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**2/(1+2*exp(x)+exp(2*x)),x)
[Out]
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Mathematica [A] time = 0.13834, size = 57, normalized size = 0.79 \[ -2 (x-1) \text{PolyLog}\left (2,-e^x\right )+2 \text{PolyLog}\left (3,-e^x\right )+\frac{\left (e^x (x-3)+x\right ) x^2}{3 \left (e^x+1\right )}-(x-2) x \log \left (e^x+1\right ) \]
Antiderivative was successfully verified.
[In] Integrate[x^2/(1 + 2*E^x + E^(2*x)),x]
[Out]
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Maple [A] time = 0.044, size = 65, normalized size = 0.9 \[ -{x}^{2}+{\frac{{x}^{2}}{1+{{\rm e}^{x}}}}+{\frac{{x}^{3}}{3}}+2\,x\ln \left ( 1+{{\rm e}^{x}} \right ) -{x}^{2}\ln \left ( 1+{{\rm e}^{x}} \right ) +2\,{\it polylog} \left ( 2,-{{\rm e}^{x}} \right ) -2\,x{\it polylog} \left ( 2,-{{\rm e}^{x}} \right ) +2\,{\it polylog} \left ( 3,-{{\rm e}^{x}} \right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^2/(1+2*exp(x)+exp(2*x)),x)
[Out]
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Maxima [A] time = 0.845112, size = 84, normalized size = 1.17 \[ \frac{1}{3} \, x^{3} - x^{2} \log \left (e^{x} + 1\right ) - x^{2} - 2 \, x{\rm Li}_2\left (-e^{x}\right ) + 2 \, x \log \left (e^{x} + 1\right ) + \frac{x^{2}}{e^{x} + 1} + 2 \,{\rm Li}_2\left (-e^{x}\right ) + 2 \,{\rm Li}_{3}(-e^{x}) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^2/(e^(2*x) + 2*e^x + 1),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.254305, size = 103, normalized size = 1.43 \[ \frac{x^{3} - 6 \,{\left ({\left (x - 1\right )} e^{x} + x - 1\right )}{\rm Li}_2\left (-e^{x}\right ) +{\left (x^{3} - 3 \, x^{2}\right )} e^{x} - 3 \,{\left (x^{2} +{\left (x^{2} - 2 \, x\right )} e^{x} - 2 \, x\right )} \log \left (e^{x} + 1\right ) + 6 \,{\left (e^{x} + 1\right )}{\rm Li}_{3}(-e^{x})}{3 \,{\left (e^{x} + 1\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^2/(e^(2*x) + 2*e^x + 1),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \frac{x^{2}}{e^{x} + 1} + \int \frac{x \left (x - 2\right )}{e^{x} + 1}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**2/(1+2*exp(x)+exp(2*x)),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{2}}{e^{\left (2 \, x\right )} + 2 \, e^{x} + 1}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^2/(e^(2*x) + 2*e^x + 1),x, algorithm="giac")
[Out]