Optimal. Leaf size=120 \[ -\frac{c^2 \log ^2(f) \text{ExpIntegralEi}\left (\frac{c \log (f)}{a+b x}\right )}{2 b^2}+\frac{a c \log (f) \text{ExpIntegralEi}\left (\frac{c \log (f)}{a+b x}\right )}{b^2}+\frac{(a+b x)^2 f^{\frac{c}{a+b x}}}{2 b^2}-\frac{a (a+b x) f^{\frac{c}{a+b x}}}{b^2}+\frac{c \log (f) (a+b x) f^{\frac{c}{a+b x}}}{2 b^2} \]
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Rubi [A] time = 0.19117, antiderivative size = 120, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.308 \[ -\frac{c^2 \log ^2(f) \text{ExpIntegralEi}\left (\frac{c \log (f)}{a+b x}\right )}{2 b^2}+\frac{a c \log (f) \text{ExpIntegralEi}\left (\frac{c \log (f)}{a+b x}\right )}{b^2}+\frac{(a+b x)^2 f^{\frac{c}{a+b x}}}{2 b^2}-\frac{a (a+b x) f^{\frac{c}{a+b x}}}{b^2}+\frac{c \log (f) (a+b x) f^{\frac{c}{a+b x}}}{2 b^2} \]
Antiderivative was successfully verified.
[In] Int[f^(c/(a + b*x))*x,x]
[Out]
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Rubi in Sympy [A] time = 15.992, size = 109, normalized size = 0.91 \[ \frac{a c \log{\left (f \right )} \operatorname{Ei}{\left (\frac{c \log{\left (f \right )}}{a + b x} \right )}}{b^{2}} - \frac{a f^{\frac{c}{a + b x}} \left (a + b x\right )}{b^{2}} - \frac{c^{2} \log{\left (f \right )}^{2} \operatorname{Ei}{\left (\frac{c \log{\left (f \right )}}{a + b x} \right )}}{2 b^{2}} + \frac{c f^{\frac{c}{a + b x}} \left (a + b x\right ) \log{\left (f \right )}}{2 b^{2}} + \frac{f^{\frac{c}{a + b x}} \left (a + b x\right )^{2}}{2 b^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(f**(c/(b*x+a))*x,x)
[Out]
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Mathematica [A] time = 0.0764587, size = 82, normalized size = 0.68 \[ \frac{c \log (f) (2 a-c \log (f)) \text{ExpIntegralEi}\left (\frac{c \log (f)}{a+b x}\right )+b x f^{\frac{c}{a+b x}} (b x+c \log (f))}{2 b^2}-\frac{a (a-c \log (f)) f^{\frac{c}{a+b x}}}{2 b^2} \]
Antiderivative was successfully verified.
[In] Integrate[f^(c/(a + b*x))*x,x]
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Maple [A] time = 0.03, size = 126, normalized size = 1.1 \[{\frac{{x}^{2}}{2}{f}^{{\frac{c}{bx+a}}}}-{\frac{{a}^{2}}{2\,{b}^{2}}{f}^{{\frac{c}{bx+a}}}}+{\frac{c\ln \left ( f \right ) x}{2\,b}{f}^{{\frac{c}{bx+a}}}}+{\frac{ac\ln \left ( f \right ) }{2\,{b}^{2}}{f}^{{\frac{c}{bx+a}}}}+{\frac{{c}^{2} \left ( \ln \left ( f \right ) \right ) ^{2}}{2\,{b}^{2}}{\it Ei} \left ( 1,-{\frac{c\ln \left ( f \right ) }{bx+a}} \right ) }-{\frac{ac\ln \left ( f \right ) }{{b}^{2}}{\it Ei} \left ( 1,-{\frac{c\ln \left ( f \right ) }{bx+a}} \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(f^(c/(b*x+a))*x,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \frac{{\left (b x^{2} + c x \log \left (f\right )\right )} f^{\frac{c}{b x + a}}}{2 \, b} - \int \frac{{\left (a^{2} c \log \left (f\right ) -{\left (b c^{2} \log \left (f\right )^{2} - 2 \, a b c \log \left (f\right )\right )} x\right )} f^{\frac{c}{b x + a}}}{2 \,{\left (b^{3} x^{2} + 2 \, a b^{2} x + a^{2} b\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(f^(c/(b*x + a))*x,x, algorithm="maxima")
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Fricas [A] time = 0.269991, size = 96, normalized size = 0.8 \[ \frac{{\left (b^{2} x^{2} - a^{2} +{\left (b c x + a c\right )} \log \left (f\right )\right )} f^{\frac{c}{b x + a}} -{\left (c^{2} \log \left (f\right )^{2} - 2 \, a c \log \left (f\right )\right )}{\rm Ei}\left (\frac{c \log \left (f\right )}{b x + a}\right )}{2 \, b^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(f^(c/(b*x + a))*x,x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int f^{\frac{c}{a + b x}} x\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(f**(c/(b*x+a))*x,x)
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int f^{\frac{c}{b x + a}} x\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(f^(c/(b*x + a))*x,x, algorithm="giac")
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