Optimal. Leaf size=109 \[ \frac{\left (7 (x-1)^2+26\right ) (x-1)}{432 \sqrt{-(x-1)^4-2 (x-1)^2+3}}+\frac{\left ((x-1)^2+5\right ) (x-1)}{72 \left (-(x-1)^4-2 (x-1)^2+3\right )^{3/2}}-\frac{11 F\left (\sin ^{-1}(1-x)|-\frac{1}{3}\right )}{144 \sqrt{3}}+\frac{7 E\left (\sin ^{-1}(1-x)|-\frac{1}{3}\right )}{144 \sqrt{3}} \]
[Out]
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Rubi [A] time = 0.201044, antiderivative size = 109, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.368 \[ -\frac{\left ((x-1)^2+5\right ) (1-x)}{72 \left (-(1-x)^4-2 (1-x)^2+3\right )^{3/2}}-\frac{\left (7 (1-x)^2+26\right ) (1-x)}{432 \sqrt{-(1-x)^4-2 (1-x)^2+3}}-\frac{11 F\left (\sin ^{-1}(1-x)|-\frac{1}{3}\right )}{144 \sqrt{3}}+\frac{7 E\left (\sin ^{-1}(1-x)|-\frac{1}{3}\right )}{144 \sqrt{3}} \]
Antiderivative was successfully verified.
[In] Int[((2 - x)*x*(4 - 2*x + x^2))^(-5/2),x]
[Out]
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Rubi in Sympy [A] time = 14.6772, size = 97, normalized size = 0.89 \[ \frac{\left (x - 1\right ) \left (2 \left (x - 1\right )^{2} + 10\right )}{144 \left (- \left (x - 1\right )^{4} - 2 \left (x - 1\right )^{2} + 3\right )^{\frac{3}{2}}} + \frac{\left (x - 1\right ) \left (112 \left (x - 1\right )^{2} + 416\right )}{6912 \sqrt{- \left (x - 1\right )^{4} - 2 \left (x - 1\right )^{2} + 3}} - \frac{7 \sqrt{3} E\left (\operatorname{asin}{\left (x - 1 \right )}\middle | - \frac{1}{3}\right )}{432} + \frac{11 \sqrt{3} F\left (\operatorname{asin}{\left (x - 1 \right )}\middle | - \frac{1}{3}\right )}{432} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/((2-x)*x*(x**2-2*x+4))**(5/2),x)
[Out]
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Mathematica [C] time = 1.4368, size = 327, normalized size = 3. \[ \frac{(x-2)^3 x^2 \left (x^2-2 x+4\right )^2 \left (-\frac{7 x \left (x^2-2 x+4\right )}{x-2}-19 i \sqrt{2} (x-2) \sqrt{\frac{i x}{\left (\sqrt{3}+i\right ) (x-2)}} \sqrt{\frac{x^2-2 x+4}{(x-2)^2}} F\left (\sin ^{-1}\left (\frac{\sqrt{\sqrt{3}-i-\frac{4 i}{x-2}}}{\sqrt{2} \sqrt [4]{3}}\right )|\frac{2 \sqrt{3}}{i+\sqrt{3}}\right )+\frac{7 i \sqrt{2} x \sqrt{\frac{x^2-2 x+4}{(x-2)^2}} E\left (\sin ^{-1}\left (\frac{\sqrt{\sqrt{3}-i-\frac{4 i}{x-2}}}{\sqrt{2} \sqrt [4]{3}}\right )|\frac{2 \sqrt{3}}{i+\sqrt{3}}\right )}{\sqrt{\frac{i x}{\left (\sqrt{3}+i\right ) (x-2)}}}+\frac{7 x^7-49 x^6+187 x^5-445 x^4+670 x^3-622 x^2+216 x+36}{(x-2)^2 x \left (x^2-2 x+4\right )}\right )}{432 \left (-x \left (x^3-4 x^2+8 x-8\right )\right )^{5/2}} \]
Warning: Unable to verify antiderivative.
[In] Integrate[((2 - x)*x*(4 - 2*x + x^2))^(-5/2),x]
[Out]
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Maple [B] time = 0.051, size = 1039, normalized size = 9.5 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/((2-x)*x*(x^2-2*x+4))^(5/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{\left (-{\left (x^{2} - 2 \, x + 4\right )}{\left (x - 2\right )} x\right )^{\frac{5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-(x^2 - 2*x + 4)*(x - 2)*x)^(-5/2),x, algorithm="maxima")
[Out]
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{1}{{\left (x^{8} - 8 \, x^{7} + 32 \, x^{6} - 80 \, x^{5} + 128 \, x^{4} - 128 \, x^{3} + 64 \, x^{2}\right )} \sqrt{-x^{4} + 4 \, x^{3} - 8 \, x^{2} + 8 \, x}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-(x^2 - 2*x + 4)*(x - 2)*x)^(-5/2),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((2-x)*x*(x**2-2*x+4))**(5/2),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{\left (-{\left (x^{2} - 2 \, x + 4\right )}{\left (x - 2\right )} x\right )^{\frac{5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-(x^2 - 2*x + 4)*(x - 2)*x)^(-5/2),x, algorithm="giac")
[Out]