Optimal. Leaf size=173 \[ \frac{5 c^2 (\text{b1} c-b \text{c1}) \tanh ^{-1}\left (\frac{b+c x}{\sqrt{b^2-a c}}\right )}{16 \left (b^2-a c\right )^{7/2}}-\frac{5 c (b+c x) (\text{b1} c-b \text{c1})}{16 \left (b^2-a c\right )^3 \left (a+2 b x+c x^2\right )}+\frac{5 (b+c x) (\text{b1} c-b \text{c1})}{24 \left (b^2-a c\right )^2 \left (a+2 b x+c x^2\right )^2}-\frac{-a \text{c1}+x (\text{b1} c-b \text{c1})+b \text{b1}}{6 \left (b^2-a c\right ) \left (a+2 b x+c x^2\right )^3} \]
[Out]
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Rubi [A] time = 0.254358, antiderivative size = 173, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.21 \[ \frac{5 c^2 (\text{b1} c-b \text{c1}) \tanh ^{-1}\left (\frac{b+c x}{\sqrt{b^2-a c}}\right )}{16 \left (b^2-a c\right )^{7/2}}-\frac{5 c (b+c x) (\text{b1} c-b \text{c1})}{16 \left (b^2-a c\right )^3 \left (a+2 b x+c x^2\right )}+\frac{5 (b+c x) (\text{b1} c-b \text{c1})}{24 \left (b^2-a c\right )^2 \left (a+2 b x+c x^2\right )^2}-\frac{-a \text{c1}+x (\text{b1} c-b \text{c1})+b \text{b1}}{6 \left (b^2-a c\right ) \left (a+2 b x+c x^2\right )^3} \]
Antiderivative was successfully verified.
[In] Int[(b1 + c1*x)/(a + 2*b*x + c*x^2)^4,x]
[Out]
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Rubi in Sympy [A] time = 13.2722, size = 165, normalized size = 0.95 \[ - \frac{5 c^{2} \left (b c_{1} - b_{1} c\right ) \operatorname{atanh}{\left (\frac{b + c x}{\sqrt{- a c + b^{2}}} \right )}}{16 \left (- a c + b^{2}\right )^{\frac{7}{2}}} + \frac{5 c \left (2 b + 2 c x\right ) \left (b c_{1} - b_{1} c\right )}{32 \left (- a c + b^{2}\right )^{3} \left (a + 2 b x + c x^{2}\right )} - \frac{5 \left (2 b + 2 c x\right ) \left (b c_{1} - b_{1} c\right )}{48 \left (- a c + b^{2}\right )^{2} \left (a + 2 b x + c x^{2}\right )^{2}} + \frac{2 a c_{1} - 2 b b_{1} + x \left (2 b c_{1} - 2 b_{1} c\right )}{12 \left (- a c + b^{2}\right ) \left (a + 2 b x + c x^{2}\right )^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((c1*x+b1)/(c*x**2+2*b*x+a)**4,x)
[Out]
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Mathematica [A] time = 0.350171, size = 168, normalized size = 0.97 \[ \frac{\frac{15 c^2 (b \text{c1}-\text{b1} c) \tan ^{-1}\left (\frac{b+c x}{\sqrt{a c-b^2}}\right )}{\sqrt{a c-b^2}}-\frac{10 \left (b^2-a c\right ) (b+c x) (b \text{c1}-\text{b1} c)}{(a+x (2 b+c x))^2}+\frac{8 \left (b^2-a c\right )^2 (a \text{c1}-b \text{b1}+b \text{c1} x-\text{b1} c x)}{(a+x (2 b+c x))^3}+\frac{15 c (b+c x) (b \text{c1}-\text{b1} c)}{a+x (2 b+c x)}}{48 \left (b^2-a c\right )^3} \]
Antiderivative was successfully verified.
[In] Integrate[(b1 + c1*x)/(a + 2*b*x + c*x^2)^4,x]
[Out]
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Maple [B] time = 0.008, size = 405, normalized size = 2.3 \[{\frac{ \left ( -2\,b{\it c1}+2\,{\it b1}\,c \right ) x+2\,b{\it b1}-2\,a{\it c1}}{ \left ( 12\,ac-12\,{b}^{2} \right ) \left ( c{x}^{2}+2\,bx+a \right ) ^{3}}}-{\frac{10\,cxb{\it c1}}{3\, \left ( 4\,ac-4\,{b}^{2} \right ) ^{2} \left ( c{x}^{2}+2\,bx+a \right ) ^{2}}}+{\frac{10\,x{c}^{2}{\it b1}}{3\, \left ( 4\,ac-4\,{b}^{2} \right ) ^{2} \left ( c{x}^{2}+2\,bx+a \right ) ^{2}}}-{\frac{10\,{b}^{2}{\it c1}}{3\, \left ( 4\,ac-4\,{b}^{2} \right ) ^{2} \left ( c{x}^{2}+2\,bx+a \right ) ^{2}}}+{\frac{10\,b{\it b1}\,c}{3\, \left ( 4\,ac-4\,{b}^{2} \right ) ^{2} \left ( c{x}^{2}+2\,bx+a \right ) ^{2}}}-20\,{\frac{x{c}^{2}b{\it c1}}{ \left ( 4\,ac-4\,{b}^{2} \right ) ^{3} \left ( c{x}^{2}+2\,bx+a \right ) }}+20\,{\frac{{c}^{3}x{\it b1}}{ \left ( 4\,ac-4\,{b}^{2} \right ) ^{3} \left ( c{x}^{2}+2\,bx+a \right ) }}-20\,{\frac{{b}^{2}c{\it c1}}{ \left ( 4\,ac-4\,{b}^{2} \right ) ^{3} \left ( c{x}^{2}+2\,bx+a \right ) }}+20\,{\frac{{\it b1}\,b{c}^{2}}{ \left ( 4\,ac-4\,{b}^{2} \right ) ^{3} \left ( c{x}^{2}+2\,bx+a \right ) }}-20\,{\frac{{\it c1}\,b{c}^{2}}{ \left ( 4\,ac-4\,{b}^{2} \right ) ^{3}\sqrt{ac-{b}^{2}}}\arctan \left ( 1/2\,{\frac{2\,cx+2\,b}{\sqrt{ac-{b}^{2}}}} \right ) }+20\,{\frac{{\it b1}\,{c}^{3}}{ \left ( 4\,ac-4\,{b}^{2} \right ) ^{3}\sqrt{ac-{b}^{2}}}\arctan \left ( 1/2\,{\frac{2\,cx+2\,b}{\sqrt{ac-{b}^{2}}}} \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((c1*x+b1)/(c*x^2+2*b*x+a)^4,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c1*x + b1)/(c*x^2 + 2*b*x + a)^4,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.228335, size = 1, normalized size = 0.01 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c1*x + b1)/(c*x^2 + 2*b*x + a)^4,x, algorithm="fricas")
[Out]
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Sympy [A] time = 7.61434, size = 1027, normalized size = 5.94 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c1*x+b1)/(c*x**2+2*b*x+a)**4,x)
[Out]
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GIAC/XCAS [A] time = 0.210147, size = 490, normalized size = 2.83 \[ -\frac{5 \,{\left (b_{1} c^{3} - b c^{2} c_{1}\right )} \arctan \left (\frac{c x + b}{\sqrt{-b^{2} + a c}}\right )}{16 \,{\left (b^{6} - 3 \, a b^{4} c + 3 \, a^{2} b^{2} c^{2} - a^{3} c^{3}\right )} \sqrt{-b^{2} + a c}} - \frac{15 \, b_{1} c^{5} x^{5} - 15 \, b c^{4} c_{1} x^{5} + 75 \, b b_{1} c^{4} x^{4} - 75 \, b^{2} c^{3} c_{1} x^{4} + 110 \, b^{2} b_{1} c^{3} x^{3} + 40 \, a b_{1} c^{4} x^{3} - 110 \, b^{3} c^{2} c_{1} x^{3} - 40 \, a b c^{3} c_{1} x^{3} + 30 \, b^{3} b_{1} c^{2} x^{2} + 120 \, a b b_{1} c^{3} x^{2} - 30 \, b^{4} c c_{1} x^{2} - 120 \, a b^{2} c^{2} c_{1} x^{2} - 12 \, b^{4} b_{1} c x + 54 \, a b^{2} b_{1} c^{2} x + 33 \, a^{2} b_{1} c^{3} x + 12 \, b^{5} c_{1} x - 54 \, a b^{3} c c_{1} x - 33 \, a^{2} b c^{2} c_{1} x + 8 \, b^{5} b_{1} - 26 \, a b^{3} b_{1} c + 33 \, a^{2} b b_{1} c^{2} + 2 \, a b^{4} c_{1} - 9 \, a^{2} b^{2} c c_{1} - 8 \, a^{3} c^{2} c_{1}}{48 \,{\left (b^{6} - 3 \, a b^{4} c + 3 \, a^{2} b^{2} c^{2} - a^{3} c^{3}\right )}{\left (c x^{2} + 2 \, b x + a\right )}^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((c1*x + b1)/(c*x^2 + 2*b*x + a)^4,x, algorithm="giac")
[Out]